What can be done to solve the wifi problem in iphone 4s

There is a problem in my iphone 4s. The wifi connection gets disconnected now and then. Why is it so? What should I do?

Hello prajwal13,
Thanks for using Apple Support Communities.
To troubleshoot issues with connecting via Wi-Fi start with these steps:
Be sure you're in range of your Wi-Fi router (access point).
Tap Settings > Wi-Fi and turn Wi-Fi off and on. If your Wi-Fi setting is dimmed, follow these steps.
Confirm that your Wi-Fi router and cable or DSL modem are connected to power, turned on, and connected to the Internet. If not, refer to your network administrator or Internet service provider (ISP) for assistance.
Restart your iOS device.
Tap Settings > Wi-Fi and locate the Wi-Fi network to which you're connected.
Tap and Forget this Network.
Try to connect to your desired Wi-Fi network.
Note: You may need to enter your Wi-Fi password again if your network requires one.
Turn your Wi-Fi router off and on2. If your ISP also provides cable or phone service, check with them before attempting this step to avoid interruption of service.
Update your device to the latest version of software.
Update your Wi-Fi router to the latest firmware2. For AirPort Base Stations, install updates using the AirPort Utility.
If you still experience these random disconnects from your Wi-Fi network, please follow below:
Move closer to the Wi-Fi router (access point).
Check for sources of potential interference.
Remove any case, stand, or other accessories from your iOS device and see if signal strength improves.
Reset network settings by tapping Settings > General > Reset > Reset Network Settings. Note: This will reset all network settings including
previously connected Wi-Fi networks and passwords
recently used Bluetooth accessories
VPN and APN settings
iOS: Troubleshooting Wi-Fi networks and connections
http://support.apple.com/kb/TS1398
Take care,
Alex H.

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FYI.
4 puertos LAN de 10/100Mbps
1 puerto WAN 10/100Mbps
Botón
Botón de configuración rápida de seguridad
Botón de reinicio
Suministro de Energía Externa
9VDC / 0.6A
Estándares Inalámbricos
IEEE 802.11n*, IEEE 802.11g, IEEE 802.11b
Antena
omnidireccional fijo de 5dBi
Dimensiones (Largo x Ancho x Alto)
6.9 x 4.6 x 1.3 in. (174 x 118 x 33 mm)
Frecuencia
2.4-2.4835GHz
Velocidad de Señal
11n: Hasta 150Mbps (dinámico)
11g: hasta 54Mbps (dinámico)
11b: hasta 11Mbps (dinámico)
EIRP
<20dBm(EIRP)
Sensibilidad de Recepción
130M: -68dBm@10% PER
108M: -68dBm@10% PER
54M: -68dBm@10% PER
11M: -85dBm@8% PER
6M: -88dBm@10% PER
1M: -90dBm@8% PER
Funciones Inalámbricas
Activar / Desactivar radio inalámbrica, WDS Bridge, WMM, estadísticas inalámbricas
Seguridad Inalámbrica
64/128/152-bit WEP / WPA / WPA2,WPA-PSK / WPA2-PSK
Tipo WAN
IP dinámica / IP estática / PPPoE /
PPTP (Acceso dual) / L2TP (Acceso dual) / BigPond
DHCP
Servidor, cliente, lista de cliente DHCP,
Reserva de dirección
Calidad de Servicio
WMM, Control de Ancho de Banda
Redireccionamiento de Puertos
servidor virtual, Port Triggering, UPnP, DMZ
DNS Dinámico
DynDns, Comexe, NO-IP
Puerto de Transferencia VPN
PPTP, L2TP, IPSec (ESP Head)
Control de Acceso
Control Parental, Control de Manejo Local, Lista de anfitriones, la Lista de acceso, manejo de reglas
Seguridad Firewall (cortafuegos)
DoS, SPI Firewall
Dirección IP Filtro / Filtro de dirección MAC / filtro de dominio
Conexiones de direcciones IP y MAC
Management
Control de acceso
Manejo Local
Manejo remoto
Certificación
CE, FCC, RoHS
Contenido del Paquete
TL-WR740N
1 fijo antenas omnidireccionales
Fuente de alimentación
CD de recursos
Guía de instalación rápida
Requisitos del Sistema
Microsoft ® Windows ® 98SE, NT, 2000, XP, Vista ™ o Windows 7, Mac ® OS, NetWare ®, UNIX ® o Linux.
Ambiente
Temperatura de funcionamiento: 0¿ ~ 40¿ (32¿ ~ 104¿)
Temperatura de almacenamiento: -40¿ ~ 70¿ (-40¿ ~ 158¿)
Humedad de funcionamiento: 10% ~ 90% sin condensación
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well... sorry but i Thought that you knew it.
Just google and you'll know that i'm correct.
There's a lot of people that have a problem with wi-fi on their iPhone 4S. The connection crash and don't let us todo things like download some applications. Wi-fi restarts, has cuts..
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Guys
Insightful wisdoms herein, the following small problem has landed with me.
Suppose I run a bank and there is a big table of financial transactions. Every credit card therein gains points for every dollar they spend. Keep it simple, 1 point for $1.
A third party company sells gifts in exchange for the points, and we send a file every night of the number of points that must be added to our member's account over at their store.. Joe Schmoe spent $200 today, add 200 points to his account. This part is easy
Problem comes when something is refunded with us (the "bank"), the points balance at the third party CANNOT be decremented (dumb, I know), so that $1000 purchase of a TV netted Joe 1000 points even though he took the TV back a week later and got his money back. Refunds can occur at any time, and you cannot assume that an item will be refunded properly between two runs of the report that prepares the points file (i.e. before sending over the points, you can't add up all the spends, add up all the refunds and send the difference as the points, because some refunds won't have happened yet).
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500
300
150
90
then the last transaction for $90 on day 4 clears his outstanding points debt of -50 points and we should send 40 points over to the third party company
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with t as (
select 1 id, sysdate - 5 dte, -1000 amount from dual UNION ALL
select 1, sysdate - 4, -500 from dual UNION ALL
select 1, sysdate - 3, 500 from dual UNION ALL
select 1, sysdate - 2, -250 from dual UNION ALL
select 1, sysdate - 1, -300 from dual)
select * from t;
ID                     DTE                       AMOUNT
1                      28-FEB-09                 -1000
1                      01-MAR-09                 -500
1                      02-MAR-09                 500
1                      03-MAR-09                 -250
1                      04-MAR-09                 -300
5 rows selectedFirst step is to get the actual number of points the customer should have at each date.
with t as (
select 1 id, sysdate - 5 dte, -1000 amount from dual UNION ALL
select 1, sysdate - 4, -500 from dual UNION ALL
select 1, sysdate - 3, 500 from dual UNION ALL
select 1, sysdate - 2, -250 from dual UNION ALL
select 1, sysdate - 1, -300 from dual)
select t.*,
       sum(-amount) over (partition by id order by dte rows unbounded preceding) actual
from t;
ID                     DTE                       AMOUNT                 ACTUAL
1                      28-FEB-09                 -1000                  1000
1                      01-MAR-09                 -500                   1500
1                      02-MAR-09                 500                    1000
1                      03-MAR-09                 -250                   1250
1                      04-MAR-09                 -300                   1550
5 rows selectedThe next step is slightly more tricky - I am going to use the max() analytic function combined with a sliding window so we can eliminate the reduction in the actual. See below:
with t as (
select 1 id, sysdate - 5 dte, -1000 amount from dual UNION ALL
select 1, sysdate - 4, -500 from dual UNION ALL
select 1, sysdate - 3, 500 from dual UNION ALL
select 1, sysdate - 2, -250 from dual UNION ALL
select 1, sysdate - 1, -300 from dual)
select b.*,
       max(actual) over (partition by id order by dte rows unbounded preceding) curr
from (select t.*,
             sum(-amount) over (partition by id order by dte rows unbounded preceding) actual
      from t) b;
ID                     DTE                       AMOUNT                 ACTUAL                 CURR
1                      28-FEB-09                 -1000                  1000                   1000
1                      01-MAR-09                 -500                   1500                   1500
1                      02-MAR-09                 500                    1000                   1500
1                      03-MAR-09                 -250                   1250                   1500
1                      04-MAR-09                 -300                   1550                   1550
5 rows selectedSo as you can see, this gives the total number of points at each date that should have been sent to the customer.
And so finally, we use lag on that result and find the difference (using NVL to handle the first case):
with t as (
select 1 id, sysdate - 5 dte, -1000 amount from dual UNION ALL
select 1, sysdate - 4, -500 from dual UNION ALL
select 1, sysdate - 3, 500 from dual UNION ALL
select 1, sysdate - 2, -250 from dual UNION ALL
select 1, sysdate - 1, -300 from dual)
select id,
       dte,
       amount,
       curr - nvl(lag(curr) over (partition by id order by dte),0) diff
from (select b.*,
             max(actual) over (partition by id order by dte rows unbounded preceding) curr
      from (select t.*,
                   sum(-amount) over (partition by id order by dte rows unbounded preceding) actual
            from t) b) d;
ID                     DTE                       AMOUNT                 DIFF
1                      28-FEB-09                 -1000                  1000
1                      01-MAR-09                 -500                   500
1                      02-MAR-09                 500                    0
1                      03-MAR-09                 -250                   0
1                      04-MAR-09                 -300                   50
5 rows selectedAnd that should give the points to send at each date.

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