What Is The Difference In The Following Code Snippet?

Question

public class Test12 {
     Test12(){
          Test12();//Compiler Error
and
public class Test12 {
     Test12(){
          new Test12();//Runtime Error after the 1GB of Ram space is used
}Can you please explain as to what is the difference b\w the above code snippet?
Edited by: The_Matrix on Feb 15, 2008 8:19 AM

Answer 1

public class Test12 {
     Test12(){
          Test12();//Compiler Error
}This is not valid because you cannot call a contractor this way. However you can replace it with following code and it will work but it is a infinite recursion.
public class Test12 {
     Test12(){
          this(); // We have now no error. Yahooo...
}The second part of code is also an infinite recursion. I mean following one
public class Test12 {
     Test12(){
          new Test12();//Runtime Error after the 1GB of Ram space is used
}Edited by: HowToDoIt on Feb 15, 2008 8:52 AM