What is windows service self-aware

Question

Hi
How to make windows service self-aware
I tried single ton pattern but no use
Issue is :http://social.msdn.microsoft.com/Forums/office/en-US/5031074e-bab7-4659-b4b3-909a7d32ec6f/exchange-web-service-error-while-moving-mail-to-other-folder?forum=exchangesvrdevelopment 
Regards,
Jagdish
Jagdish

Answer 1

I
got the Answer 
Threading with Mutex (Mutual exclusion):
When two or more threads need to access a shared resource at the same time, the system needs a synchronization mechanism to ensure that only one thread at a time uses the resource. Mutex is
a synchronization primitive that grants exclusive access to the shared resource to only one thread. If a thread acquires a mutex, the second thread that wants to acquire that mutex is suspended until the first thread releases the mutex.
Steps:
Instantiating a new Mutex object that's accessible from each thread.
Wrapping whatever code you want to be executed in the critical section with that object's WaitOne() and ReleaseMutex() methods in each thread
Implementation:
Add class
SingleGlobalInstance to your project
class
SingleGlobalInstance :
IDisposable
    public
bool hasHandle = false;
    Mutex
mutex;
    private
void
InitMutex()
        string
appGuid = ((GuidAttribute)Assembly.GetExecutingAssembly().GetCustomAttributes(typeof(GuidAttribute),
false).GetValue(0)).Value.ToString();
        string
mutexId = string.Format("Global\\{{{0}}}",
appGuid);
        mutex =
new
Mutex(false,
mutexId);
        var
allowEveryoneRule = new
MutexAccessRule(new
SecurityIdentifier(WellKnownSidType.WorldSid,
null),
MutexRights.FullControl,
AccessControlType.Allow);
        var
securitySettings = new
MutexSecurity();
        securitySettings.AddAccessRule(allowEveryoneRule);
        mutex.SetAccessControl(securitySettings);
    public
SingleGlobalInstance(int
TimeOut)
        InitMutex();
        try
            if(TimeOut
<= 0)
                hasHandle = mutex.WaitOne(Timeout.Infinite,
false);
            else
                hasHandle = mutex.WaitOne(TimeOut,
false);
            if
(hasHandle == false)
                throw
new
TimeoutException("Timeout
waiting for exclusive access on SingleInstance");
        catch
(AbandonedMutexException)
            hasHandle =
true;
    public
void
Dispose()
        if
(mutex != null)
            if
(hasHandle)
                mutex.ReleaseMutex();
            mutex.Dispose();
Add following condition to check whether thread is already running
using (new
SingleGlobalInstance(1000))
//code which should be executed in single thread
Regards,
Jagdish Kotian
Jagdish