What is wrong with law &order game

What is wrong with the law& order game ? I played the game and bought it for 12.99  but now the game is gone all I get is a gray screen can anyone help me I want to play this game on y IPad 2

Have you tried closing the game completely and seeing if it works when you re-open it ? From the home screen (i.e. not with the Law & Order game 'open' on-screen) double-click the home button to bring up the taskbar, then press and hold any of the apps on the taskbar for a couple of seconds or so until they start shaking, then press the '-' in the top left of the app to close it, and touch any part of the screen above the taskbar so as to stop the shaking and close the taskbar.
If that doesn't work then you could try a reset : press and hold both the sleep and home buttons for about 10 to 15 seconds (ignore the red slider), after which the Apple logo should appear - you won't lose any content, it's the iPad equivalent of a reboot.

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    float deirdre = START;
    printf("Daphne invests $100 at 10 percent simple interest. Deirdre invests $100 at 5 percent interest compounded annually.
    When will Deirdre's account value exceed Daphne's?
    Let\'s find out.
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    ", daphne, deirdre);
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    ", counter, daphne, deirdre);
    counter++;
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    *Daphne invests $100 at 10 percent simple interest. Deirdre invests $100 at 5 percent interest compounded annually.*
    *When will Deirdre's account value exceed Daphne's?*
    *Let's find out.*
    *By the end of year 1, Deirdre's account has surpassed Daphne's in value.*
    What's wrong with it?
    Message was edited by: musicwind95
    Message was edited by: musicwind95

    John hadn't responded at the time I started typing this, but I'll keep it posted anyways in order to expand on John's answer a little bit. The answer to your last question is that the loop's condition has to return true for it to run the first time around. To examine this further, let's take a look at the way you had the while loop before:
    while (daphne > deirdre)
    Now, a while loop will run the code between its braces as long as the condition inside the parenthesis (daphne > deirdre, in this case) is true. So, if the condition is false the first time the code reaches the while statement, then the loop will never run at all (it won't even run through it once -- it will skip over it). And since, before the while loop, both variables (daphne and dierdre) are set equal to the same value (START (100.00), in this case), both variables are equal at the point when the code first reaches the while statement. Since they are equal, daphne is NOT greater than dierdre, and therefore the condition returns false. Since the condition is false the first time the code reaches it, the code inside the loop's braces is skipped over and never run. As John recommended in the previous post, changing it to this:
    while (daphne >= deirdre)
    fixes the problem because now the condition is true. The use of the "greater than or equal to" operator (>=) instead of the "great than" operator (>) means that the condition can now be returned true even if daphne is equal to deirdre, not just if it's greater than deirdre. And since daphne and deirdre are equal (they are both 100.00) when the code first reaches the while loop, the condition is now returned true and the code inside the loop's braces will be run. Once the program reaches the end of the code inside the loop's braces, it will check to see if the condition is still true and, if it is, it will run the loop's code again (and again and again and again, checking to see if the condition is still true each time), and if it's not true, it will skip over the loop's bottom brace and continue on with the rest of the program.
    Hope this helped clear this up for you. Please ask if you have any more questions.

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