What's the tick to swiping up?

About one time in 10 (if I'm lucky), when I try to swipe up to get then new menu in IOS 7, I get that menu.    What am I doing wrong?
I try changing my speed, I try changing the starting position.   But usually nothing happens at all.

Ahh, taking the case off fixes the problem.  I have a black rubber case designed to keep the phone from slipping and (hopefully) protecting it from drops.   The rubber covers the button on my 4s.   I used it with my iPhone 4 before.

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    Attachments:
    continuously measure period buffered_singlechannel_forum Nov 13.vi ‏33 KB

    HI dav2010,
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    BorderLayout
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    Choice 2  
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    Choice 3  
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    Choice 4  
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    Choice 2  
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    Choice 3  
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    Choice 4  
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    Choice 4  
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    Choice 2  
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    Choice 3  
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    Choice 2  
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    Choice 3  
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    Choice 4  
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    Choice 2  
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    Choice 4  
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    Choice 1  
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    Choice 2  
    It is the first method run when a class is run with the Java Interpreter. 
    Choice 3  
    It serves no specific function. It is a residual method from Java 1.0. 
    Choice 4  
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    Choice 5  
    To process command-line parameters when running the Java Interpreter 
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    Choice 2  
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    Choice 3  
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    Choice 4  
    JMenuItem save = new JMenuItem("Save");
    save.setMnemonic("Ctrl+S"); 
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    Choice 2  
    Grid position 1,2 
    Choice 3  
    Grid position 1, 1 
    Choice 4  
    Grid position 10, 1 
    Choice 5  
    Grid position 1, 3 
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    Choice 1  
    Grid position 2,1 
    Choice 2  
    Grid position 1,2 
    Choice 3  
    Grid position 1, 1 
    Choice 4  
    Grid position 10, 1 
    Choice 5  
    Grid position 1, 3 
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    Choice 1  
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    Choice 2  
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    Choice 3  
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    Choice 4  
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    Choice 5  
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    Choice 2  
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    Choice 3  
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    Choice 4  
    jcb.add("Java"); 
    Choice 5  
    jcb.addItem("Java");

    I'll have a go but I am not saying they are all correct...
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    BorderLayout
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    GridBagLayout
    GridLayout
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    Question 4
    public void drawText(Graphics2D g, String text)
         Font f = new Font("Century Gothic", Font.BOLD, 10);  
         g.setFont(f);  
         g.drawString(text, 20, 20);
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    Choice 5 A default Font object is returned and is used
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    How must do you interact with a JTextField in order to generate an ActionEvent?
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    public class TimerTest implements ActionListener
         public static void main(String[] args)
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               javax.swing.Timer timer = new javax.swing.Timer(100,test);  
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    Reward if useful
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