What's up with this update re: Java? Do I have it? If not, do I need to get it and from where?

What's up with this update re: Java?
Do I have it?
If not, do I need to get it and from where?
Thanks

You don't have it unless you have downloaded and installed it either manually or via Software Update.
The update should be installed to protect you from possible malware exploits via Java. However, if you don't use Java programming or run Java applets in your browser, then you do not need the update. But you must turn Java off in your browser's security preferences (it will be a checkbox.)

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What is wrong with this update statement

Hi all,
I am trying to create a simple update program that allows user to enter table name, key fields and one field to update and its value.
But report goes into dump at update statement?
Here is the code:
REPORT ZTABLE_UPDATE.
parameters: tabname(18).
PARAMETERS: key1(15),"use at where condition
            key1val(20),
            key2(15),"use at where condition
            key2val(20),
            field2(15)."field to be updated
PARAMETERS: yenideg1(20),
            yenideg2(20).
CONDENSE: tabname, field2,
          yenideg1, yenideg2,
          key1val, key2val,
          key1, key2.
data: wa like tabname.
*update (tabname) SET field2 = yenideg1*
                 *WHERE key1 like key1val and key2 like key2val.*if sy-subrc eq 0.
SELECT SINGLE * FROM (tabname) INTO wa
                  WHERE key1 like key1val
                    and key2 like key2val.
    WRITE / wa. "to test whether replacement is ok.
endif.
Thanks in advance.
Deniz

Hi:
follows is ok:
DATA: dy_table TYPE REF TO data,
      dy_line TYPE REF TO data,
      ifc TYPE lvc_t_fcat,
      xfc TYPE lvc_s_fcat.
DATA: it_clrs_fields LIKE TABLE OF dfies WITH HEADER LINE.
DATA: cond(72) TYPE c,
      itab LIKE TABLE OF cond,
      itab2 LIKE TABLE OF cond.
FIELD-SYMBOLS: <dyn_table> TYPE STANDARD TABLE,
             <dyn_wa>,
             <dyn_field>,
             <fs>.
PARAMETERS: tabname TYPE ddobjname OBLIGATORY.
PARAMETERS: key1(15) OBLIGATORY,"use at where condition
            key1val(20) OBLIGATORY,
            key2(15),"use at where condition
            key2val(20),
            field2(15)."field to be updated
PARAMETERS: yenideg1(20),
            yenideg2(20).
***START
CONDENSE: tabname, field2,
          yenideg1, yenideg2,
          key1val, key2val,
          key1, key2.
CALL FUNCTION 'DDIF_FIELDINFO_GET'
EXPORTING
    tabname              = tabname
TABLES
   dfies_tab            = it_clrs_fields[]
FIXED_VALUES         =
EXCEPTIONS
   not_found            = 1
   internal_error       = 2
   OTHERS               = 3
LOOP AT it_clrs_fields .
MOVE-CORRESPONDING it_clrs_fields TO xfc.
APPEND xfc TO ifc.
CLEAR: xfc.
ENDLOOP.
CALL METHOD cl_alv_table_create=>create_dynamic_table
EXPORTING
    it_fieldcatalog = ifc
IMPORTING
    ep_table        = dy_table.
ASSIGN dy_table->* TO <dyn_table>.
CREATE DATA dy_line LIKE LINE OF <dyn_table>.
ASSIGN dy_line->* TO <dyn_wa>.
CLEAR COND.
CONCATENATE key1 ' = ''' key1val '''' 'AND' INTO cond.
APPEND cond TO itab.
CLEAR COND.
CONCATENATE key2 ' = ''' key2val '''' INTO cond.
APPEND cond TO itab.
SELECT *
INTO <dyn_wa>
FROM (tabname)
   WHERE (itab).
ENDSELECT.
IF sy-subrc <> 0.
WRITE / 'no this data in dbtab'.
EXIT.
ENDIF.
CLEAR COND.
CONCATENATE field2 ' = ''' yenideg1 '''' INTO cond.
UPDATE (tabname) SET (cond)
                WHERE (itab).
IF sy-subrc EQ 0.
SELECT SINGLE * FROM (tabname) INTO <dyn_wa>
                  WHERE (itab).
WRITE / <dyn_wa>. "to test whether replacement is ok.
ENDIF.
you alse can use:
FM: VIEW_MAINTENANCE_CALL can used to do table maintenance.
note:
1.to do Table Maintenance Generator.
2.be authorized to to use tansaction sm30.
好运,
启明星

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I can't figure out what's wrong with this code

First i want this program to allow me to enter a number with the EasyReader class and depending on the number entered it will show that specific line of this peom:
One two buckle your shoe
Three four shut the door
Five six pick up sticks
Seven eight lay them straight
Nine ten this is the end.
The error message i got was an illegal start of expression. I can't figure out why it is giving me this error because i have if (n = 1) || (n = 2) statements. My code is:
public class PoemSeventeen
public static void main(String[] args)
EasyReader console = new EasyReader();
System.out.println("Enter a number for the poem (0 to quit): ");
int n = console.readInt();
if (n = 1) || (n = 2)
System.out.println("One, two, buckle your shoe");
else if (n = 3) || (n = 4)
System.out.println("Three, four, shut the door");
else if (n = 5) || (n = 6)
System.out.println("Five, six, pick up sticks");
else if (n = 7) || (n = 8)
System.out.println("Seven, eight, lay them straight");
else if (n = 9) || (n = 10)
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else if (n = 0)
System.out.println("You may exit now");
else
System.out.println("Put in a number between 0 and 10");
I messed around with a few other thing because i had some weird errors before but now i have narrowed it down to just this 1 error.
The EasyReader class code:
// package com.skylit.io;
import java.io.*;
* @author Gary Litvin
* @version 1.2, 5/30/02
* Written as part of
* <i>Java Methods: An Introduction to Object-Oriented Programming</i>
* (Skylight Publishing 2001, ISBN 0-9654853-7-4)
* and
* <i>Java Methods AB: Data Structures</i>
* (Skylight Publishing 2003, ISBN 0-9654853-1-5)
* EasyReader provides simple methods for reading the console and
* for opening and reading text files. All exceptions are handled
* inside the class and are hidden from the user.
* <xmp>
* Example:
* =======
* EasyReader console = new EasyReader();
* System.out.print("Enter input file name: ");
* String fileName = console.readLine();
* EasyReader inFile = new EasyReader(fileName);
* if (inFile.bad())
* System.err.println("Can't open " + fileName);
* System.exit(1);
* String firstLine = inFile.readLine();
* if (!inFile.eof()) // or: if (firstLine != null)
* System.out.println("The first line is : " + firstLine);
* System.out.print("Enter the maximum number of integers to read: ");
* int maxCount = console.readInt();
* int k, count = 0;
* while (count < maxCount && !inFile.eof())
* k = inFile.readInt();
* if (!inFile.eof())
* // process or store this number
* count++;
* inFile.close(); // optional
* System.out.println(count + " numbers read");
* </xmp>
public class EasyReader
protected String myFileName;
protected BufferedReader myInFile;
protected int myErrorFlags = 0;
protected static final int OPENERROR = 0x0001;
protected static final int CLOSEERROR = 0x0002;
protected static final int READERROR = 0x0004;
protected static final int EOF = 0x0100;
* Constructor. Prepares console (System.in) for reading
public EasyReader()
myFileName = null;
myErrorFlags = 0;
myInFile = new BufferedReader(
new InputStreamReader(System.in), 128);
* Constructor. opens a file for reading
* @param fileName the name or pathname of the file
public EasyReader(String fileName)
myFileName = fileName;
myErrorFlags = 0;
try
myInFile = new BufferedReader(new FileReader(fileName), 1024);
catch (FileNotFoundException e)
myErrorFlags |= OPENERROR;
myFileName = null;
* Closes the file
public void close()
if (myFileName == null)
return;
try
myInFile.close();
catch (IOException e)
System.err.println("Error closing " + myFileName + "\n");
myErrorFlags |= CLOSEERROR;
* Checks the status of the file
* @return true if en error occurred opening or reading the file,
* false otherwise
public boolean bad()
return myErrorFlags != 0;
* Checks the EOF status of the file
* @return true if EOF was encountered in the previous read
* operation, false otherwise
public boolean eof()
return (myErrorFlags & EOF) != 0;
private boolean ready() throws IOException
return myFileName == null || myInFile.ready();
* Reads the next character from a file (any character including
* a space or a newline character).
* @return character read or <code>null</code> character
* (Unicode 0) if trying to read beyond the EOF
public char readChar()
char ch = '\u0000';
try
if (ready())
ch = (char)myInFile.read();
catch (IOException e)
if (myFileName != null)
System.err.println("Error reading " + myFileName + "\n");
myErrorFlags |= READERROR;
if (ch == '\u0000')
myErrorFlags |= EOF;
return ch;
* Reads from the current position in the file up to and including
* the next newline character. The newline character is thrown away
* @return the read string (excluding the newline character) or
* null if trying to read beyond the EOF
public String readLine()
String s = null;
try
s = myInFile.readLine();
catch (IOException e)
if (myFileName != null)
System.err.println("Error reading " + myFileName + "\n");
myErrorFlags |= READERROR;
if (s == null)
myErrorFlags |= EOF;
return s;
* Skips whitespace and reads the next word (a string of consecutive
* non-whitespace characters (up to but excluding the next space,
* newline, etc.)
* @return the read string or null if trying to read beyond the EOF
public String readWord()
StringBuffer buffer = new StringBuffer(128);
char ch = ' ';
int count = 0;
String s = null;
try
while (ready() && Character.isWhitespace(ch))
ch = (char)myInFile.read();
while (ready() && !Character.isWhitespace(ch))
count++;
buffer.append(ch);
myInFile.mark(1);
ch = (char)myInFile.read();
if (count > 0)
myInFile.reset();
s = buffer.toString();
else
myErrorFlags |= EOF;
catch (IOException e)
if (myFileName != null)
System.err.println("Error reading " + myFileName + "\n");
myErrorFlags |= READERROR;
return s;
* Reads the next integer (without validating its format)
* @return the integer read or 0 if trying to read beyond the EOF
public int readInt()
String s = readWord();
if (s != null)
return Integer.parseInt(s);
else
return 0;
* Reads the next double (without validating its format)
* @return the number read or 0 if trying to read beyond the EOF
public double readDouble()
String s = readWord();
if (s != null)
return Double.parseDouble(s);
// in Java 1, use: return Double.valueOf(s).doubleValue();
else
return 0.0;
Can anybody please tell me what's wrong with this code? Thanks

String[] message = {
    "One, two, buckle your shoe",
    "One, two, buckle your shoe",
    "Three, four, shut the door",
    "Three, four, shut the door",
    "Five, six, pick up sticks",
    "Five, six, pick up sticks",
    "Seven, eight, lay them straight",
    "Seven, eight, lay them straight",
    "Nine, ten, this is the end",
    "Nine, ten, this is the end"
if(n>0)
    System.out.println(message[n]);
else
    System.exit(0);

I'm trying to download the latest version of iTunes and get the message "There is a problem with this Windows Installer package. A program required for this install to complete could not be run." I have no clue what to do with this.

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What's up with this update re: Java? Do I have it? If not, do I need to get it and from where?

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