What's wrong with FaceTime I can't connect a video call to anyone

What's wrong with FaceTime I can't connect a video call to anyone

If you are having issues with Facetime, and your device is running iOS 7.1, and you have followed the troubleshooting procedures (http://support.apple.com/kb/TS3367), contact apple support.
The http://www.apple.com/support/systemstatus/ page states that if you are experiencing an issue not listed, to contact support .

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    I have a similar problem.  I restored my iPhone 5 to the latest available OS.  After completing the process the phone never restarted.  The phone was fully charged when I restored it but now refuses to charge past the red battery icon.  I have been able to get the phone in UFD mode several times and have been able to load the new OS on the phone.  The Apple logo does come on and the software fully loads.  iTunes tells me the phone will restart but never does.  I left it to charge all night but it never appeared to load the battery.  This morning I went to the Grand Central Terminal apple store for help.  A woman at the store plugged the phone in but it never charged.  She absolutely refused to believe that I got my phone in UFD mode and loaded any software on.  I don't think it is a battery issue.  The only solution I was given was to buy a new phone.  Repairing it was out of the question.  At this point the phone is completely useless.  Thanks in advance for the help.

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    When is it going to start back working? What's wrong with it?

    If you are having issues with Facetime, and your device is running iOS 7.1, and you have followed the troubleshooting procedures (http://support.apple.com/kb/TS3367), contact apple support.
    The http://www.apple.com/support/systemstatus/ page states that if you are experiencing an issue not listed, to contact support .

  • What's wrong with Safari (I can't send anything)

    Hi,
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    Thanks.

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    The http://www.apple.com/support/systemstatus/ page states that if you are experiencing an issue not listed, to contact support .

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    Your phone is probably broken.

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    public void run()
    try
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    5
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  • What is wrong with my facetime,i am using an ipad everytime i placed a call i can't hear it ringing and the person i am calling can't recieve my call as well,i did everything possible forced off my ipad,on and of facetime on settings,change id's.

    What is wrong with my facetime,i am using an ipad everytime i placed a call i can't hear it ringing and the person i am calling can't recieve my call as well,i did everything possible forced off my ipad,on and off facetime on settings,change id's, mute,unmuted,reset network settings!! But nothing change,i mean is there a problem with my ipad or the facetime has a problem right now?my friend seems doesnt have a problem with her ipad,it just happen suddenly yesterday it was ok but today when i tried calling my husband this is what happens, can anyone please help me!!

    - Try cleaning out/blowing out the headphone jack. Try inserting/removing the plug a dozen times or so.
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  • I can't figure out what's wrong with this code

    First i want this program to allow me to enter a number with the EasyReader class and depending on the number entered it will show that specific line of this peom:
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    Five six pick up sticks
    Seven eight lay them straight
    Nine ten this is the end.
    The error message i got was an illegal start of expression. I can't figure out why it is giving me this error because i have if (n = 1) || (n = 2) statements. My code is:
    public class PoemSeventeen
    public static void main(String[] args)
    EasyReader console = new EasyReader();
    System.out.println("Enter a number for the poem (0 to quit): ");
    int n = console.readInt();
    if (n = 1) || (n = 2)
    System.out.println("One, two, buckle your shoe");
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    System.out.println("Three, four, shut the door");
    else if (n = 5) || (n = 6)
    System.out.println("Five, six, pick up sticks");
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    System.out.println("Seven, eight, lay them straight");
    else if (n = 9) || (n = 10)
    System.out.println("Nine, ten, this is the end");
    else if (n = 0)
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    The EasyReader class code:
    // package com.skylit.io;
    import java.io.*;
    * @author Gary Litvin
    * @version 1.2, 5/30/02
    * Written as part of
    * <i>Java Methods: An Introduction to Object-Oriented Programming</i>
    * (Skylight Publishing 2001, ISBN 0-9654853-7-4)
    * and
    * <i>Java Methods AB: Data Structures</i>
    * (Skylight Publishing 2003, ISBN 0-9654853-1-5)
    * EasyReader provides simple methods for reading the console and
    * for opening and reading text files. All exceptions are handled
    * inside the class and are hidden from the user.
    * <xmp>
    * Example:
    * =======
    * EasyReader console = new EasyReader();
    * System.out.print("Enter input file name: ");
    * String fileName = console.readLine();
    * EasyReader inFile = new EasyReader(fileName);
    * if (inFile.bad())
    * System.err.println("Can't open " + fileName);
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    * String firstLine = inFile.readLine();
    * if (!inFile.eof()) // or: if (firstLine != null)
    * System.out.println("The first line is : " + firstLine);
    * System.out.print("Enter the maximum number of integers to read: ");
    * int maxCount = console.readInt();
    * int k, count = 0;
    * while (count < maxCount && !inFile.eof())
    * k = inFile.readInt();
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    * inFile.close(); // optional
    * System.out.println(count + " numbers read");
    * </xmp>
    public class EasyReader
    protected String myFileName;
    protected BufferedReader myInFile;
    protected int myErrorFlags = 0;
    protected static final int OPENERROR = 0x0001;
    protected static final int CLOSEERROR = 0x0002;
    protected static final int READERROR = 0x0004;
    protected static final int EOF = 0x0100;
    * Constructor. Prepares console (System.in) for reading
    public EasyReader()
    myFileName = null;
    myErrorFlags = 0;
    myInFile = new BufferedReader(
    new InputStreamReader(System.in), 128);
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    * @param fileName the name or pathname of the file
    public EasyReader(String fileName)
    myFileName = fileName;
    myErrorFlags = 0;
    try
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    catch (FileNotFoundException e)
    myErrorFlags |= OPENERROR;
    myFileName = null;
    * Closes the file
    public void close()
    if (myFileName == null)
    return;
    try
    myInFile.close();
    catch (IOException e)
    System.err.println("Error closing " + myFileName + "\n");
    myErrorFlags |= CLOSEERROR;
    * Checks the status of the file
    * @return true if en error occurred opening or reading the file,
    * false otherwise
    public boolean bad()
    return myErrorFlags != 0;
    * Checks the EOF status of the file
    * @return true if EOF was encountered in the previous read
    * operation, false otherwise
    public boolean eof()
    return (myErrorFlags & EOF) != 0;
    private boolean ready() throws IOException
    return myFileName == null || myInFile.ready();
    * Reads the next character from a file (any character including
    * a space or a newline character).
    * @return character read or <code>null</code> character
    * (Unicode 0) if trying to read beyond the EOF
    public char readChar()
    char ch = '\u0000';
    try
    if (ready())
    ch = (char)myInFile.read();
    catch (IOException e)
    if (myFileName != null)
    System.err.println("Error reading " + myFileName + "\n");
    myErrorFlags |= READERROR;
    if (ch == '\u0000')
    myErrorFlags |= EOF;
    return ch;
    * Reads from the current position in the file up to and including
    * the next newline character. The newline character is thrown away
    * @return the read string (excluding the newline character) or
    * null if trying to read beyond the EOF
    public String readLine()
    String s = null;
    try
    s = myInFile.readLine();
    catch (IOException e)
    if (myFileName != null)
    System.err.println("Error reading " + myFileName + "\n");
    myErrorFlags |= READERROR;
    if (s == null)
    myErrorFlags |= EOF;
    return s;
    * Skips whitespace and reads the next word (a string of consecutive
    * non-whitespace characters (up to but excluding the next space,
    * newline, etc.)
    * @return the read string or null if trying to read beyond the EOF
    public String readWord()
    StringBuffer buffer = new StringBuffer(128);
    char ch = ' ';
    int count = 0;
    String s = null;
    try
    while (ready() && Character.isWhitespace(ch))
    ch = (char)myInFile.read();
    while (ready() && !Character.isWhitespace(ch))
    count++;
    buffer.append(ch);
    myInFile.mark(1);
    ch = (char)myInFile.read();
    if (count > 0)
    myInFile.reset();
    s = buffer.toString();
    else
    myErrorFlags |= EOF;
    catch (IOException e)
    if (myFileName != null)
    System.err.println("Error reading " + myFileName + "\n");
    myErrorFlags |= READERROR;
    return s;
    * Reads the next integer (without validating its format)
    * @return the integer read or 0 if trying to read beyond the EOF
    public int readInt()
    String s = readWord();
    if (s != null)
    return Integer.parseInt(s);
    else
    return 0;
    * Reads the next double (without validating its format)
    * @return the number read or 0 if trying to read beyond the EOF
    public double readDouble()
    String s = readWord();
    if (s != null)
    return Double.parseDouble(s);
    // in Java 1, use: return Double.valueOf(s).doubleValue();
    else
    return 0.0;
    Can anybody please tell me what's wrong with this code? Thanks

    String[] message = {
        "One, two, buckle your shoe",
        "One, two, buckle your shoe",
        "Three, four, shut the door",
        "Three, four, shut the door",
        "Five, six, pick up sticks",
        "Five, six, pick up sticks",
        "Seven, eight, lay them straight",
        "Seven, eight, lay them straight",
        "Nine, ten, this is the end",
        "Nine, ten, this is the end"
    if(n>0)
        System.out.println(message[n]);
    else
        System.exit(0);

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