What's wrong with Imatch as of now?

What is wrong with ITunes and Imatch? I can't find my music in the ICloud on either the IPhone or on my Windows 7 laptop.

What is wrong with ITunes and Imatch? I can't find my music in the ICloud on either the IPhone or on my Windows 7 laptop.

Similar Messages

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    Now it just brings up a blue screen and it won't
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  • Ever since I got the new update 5.1 my iPod's been dying faster. It used to last for at least 3 hours, now it won't even last one hour and dies for no reason(even when it's in sleep mode, and not in use) What's wrong with it? Is it the update? lagging too

    Ever since I got the new update 5.1 my iPod's been dying faster, even after I charge it. It used to last for at least 3 hours, now it won't even last one hour and dies for no reason (even when it's in sleep mode, and not in use) What's wrong with it? Is it the update? It's lagging as well..

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  • HT201210 Hi All,  Just had my iphone repaired after dropping it in a puddle but it won't now connect with iTunes. It says the iphone "iphone" could not be restored. An unknown error occurred (23).   Any thoughts on what is wrong with it?

    Hi All,  Just had my iphone repaired after dropping it in a puddle but it won't now connect with iTunes. It says the iphone "iphone" could not be restored. An unknown error occurred (23).   Any thoughts on what is wrong with it?

    https://discussions.apple.com/message/22965383#22965383
    https://discussions.apple.com/thread/4012266?tstart=0

  • My optical drive will not read any music cds now or recognize a blank cd in the drive. it might read some data discs. what is wrong with it and how do i fix it?

    My optical drive will not read any music cds or recognize a blank cd. it might read some data cds. what is wrong with it and how can i fix it?

    The optics might be dirty. Try running a cleaning CD through it and see if that makes a difference.
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    Allan

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  • What's wrong with my browsers?

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    # connection loss (even when AExtreme is very close)
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  • What's wrong with my iPod's Cover Flow??

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  • What's wrong with my Final Cut Pro 7.03?

    What's wrong with my Final Cut Pro 7.03?
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  • My macbook pro freezes and then displays a blue screen with black stripes... do you know what's wrong with it?

    My macbook pro freezes and then displays a blue screen with black stripes... do you know what's wrong with it?
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  • C# - What's wrong with a table called JOBS? :(

    Post Author: Gee
    CA Forum: .NET
    Hi
    I've just moved up to .NET 2005. and am having a big problem right now with one report in particular.
    The report uses an Oracle table called "JOBS". It worked just fine in .NET 2003. Now though, it comes up with the dreaded field name not known error.
    So, I tried to just do a completely new report with just ONE field from the JOBS table on it. It doesn't want to know!
    I then copied (so it was IDENTICAL) the table structure and data to a new one called "JOBSTEST". The simple report worked (once I'd changed it to use the JOBSTEST fields of course)
    I deleted the original JOBS table, copied a new JOBS table from the JOBSTEST table and... it didn't work again!
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    Thank you so much for your time in helping me

    Post Author: Gee
    CA Forum: .NET
    Hi
    I've just moved up to .NET 2005. and am having a big problem right now with one report in particular.
    The report uses an Oracle table called "JOBS". It worked just fine in .NET 2003. Now though, it comes up with the dreaded field name not known error.
    So, I tried to just do a completely new report with just ONE field from the JOBS table on it. It doesn't want to know!
    I then copied (so it was IDENTICAL) the table structure and data to a new one called "JOBSTEST". The simple report worked (once I'd changed it to use the JOBSTEST fields of course)
    I deleted the original JOBS table, copied a new JOBS table from the JOBSTEST table and... it didn't work again!
    So, what's wrong with having a table called "JOBS"? Because that seems to be the problem!
    Oh... it works ok on the development machine. Just not any other. ALL other reports work fine!
    Thank you so much for your time in helping me

  • I can't figure out what's wrong with this code

    First i want this program to allow me to enter a number with the EasyReader class and depending on the number entered it will show that specific line of this peom:
    One two buckle your shoe
    Three four shut the door
    Five six pick up sticks
    Seven eight lay them straight
    Nine ten this is the end.
    The error message i got was an illegal start of expression. I can't figure out why it is giving me this error because i have if (n = 1) || (n = 2) statements. My code is:
    public class PoemSeventeen
    public static void main(String[] args)
    EasyReader console = new EasyReader();
    System.out.println("Enter a number for the poem (0 to quit): ");
    int n = console.readInt();
    if (n = 1) || (n = 2)
    System.out.println("One, two, buckle your shoe");
    else if (n = 3) || (n = 4)
    System.out.println("Three, four, shut the door");
    else if (n = 5) || (n = 6)
    System.out.println("Five, six, pick up sticks");
    else if (n = 7) || (n = 8)
    System.out.println("Seven, eight, lay them straight");
    else if (n = 9) || (n = 10)
    System.out.println("Nine, ten, this is the end");
    else if (n = 0)
    System.out.println("You may exit now");
    else
    System.out.println("Put in a number between 0 and 10");
    I messed around with a few other thing because i had some weird errors before but now i have narrowed it down to just this 1 error.
    The EasyReader class code:
    // package com.skylit.io;
    import java.io.*;
    * @author Gary Litvin
    * @version 1.2, 5/30/02
    * Written as part of
    * <i>Java Methods: An Introduction to Object-Oriented Programming</i>
    * (Skylight Publishing 2001, ISBN 0-9654853-7-4)
    * and
    * <i>Java Methods AB: Data Structures</i>
    * (Skylight Publishing 2003, ISBN 0-9654853-1-5)
    * EasyReader provides simple methods for reading the console and
    * for opening and reading text files. All exceptions are handled
    * inside the class and are hidden from the user.
    * <xmp>
    * Example:
    * =======
    * EasyReader console = new EasyReader();
    * System.out.print("Enter input file name: ");
    * String fileName = console.readLine();
    * EasyReader inFile = new EasyReader(fileName);
    * if (inFile.bad())
    * System.err.println("Can't open " + fileName);
    * System.exit(1);
    * String firstLine = inFile.readLine();
    * if (!inFile.eof()) // or: if (firstLine != null)
    * System.out.println("The first line is : " + firstLine);
    * System.out.print("Enter the maximum number of integers to read: ");
    * int maxCount = console.readInt();
    * int k, count = 0;
    * while (count < maxCount && !inFile.eof())
    * k = inFile.readInt();
    * if (!inFile.eof())
    * // process or store this number
    * count++;
    * inFile.close(); // optional
    * System.out.println(count + " numbers read");
    * </xmp>
    public class EasyReader
    protected String myFileName;
    protected BufferedReader myInFile;
    protected int myErrorFlags = 0;
    protected static final int OPENERROR = 0x0001;
    protected static final int CLOSEERROR = 0x0002;
    protected static final int READERROR = 0x0004;
    protected static final int EOF = 0x0100;
    * Constructor. Prepares console (System.in) for reading
    public EasyReader()
    myFileName = null;
    myErrorFlags = 0;
    myInFile = new BufferedReader(
    new InputStreamReader(System.in), 128);
    * Constructor. opens a file for reading
    * @param fileName the name or pathname of the file
    public EasyReader(String fileName)
    myFileName = fileName;
    myErrorFlags = 0;
    try
    myInFile = new BufferedReader(new FileReader(fileName), 1024);
    catch (FileNotFoundException e)
    myErrorFlags |= OPENERROR;
    myFileName = null;
    * Closes the file
    public void close()
    if (myFileName == null)
    return;
    try
    myInFile.close();
    catch (IOException e)
    System.err.println("Error closing " + myFileName + "\n");
    myErrorFlags |= CLOSEERROR;
    * Checks the status of the file
    * @return true if en error occurred opening or reading the file,
    * false otherwise
    public boolean bad()
    return myErrorFlags != 0;
    * Checks the EOF status of the file
    * @return true if EOF was encountered in the previous read
    * operation, false otherwise
    public boolean eof()
    return (myErrorFlags & EOF) != 0;
    private boolean ready() throws IOException
    return myFileName == null || myInFile.ready();
    * Reads the next character from a file (any character including
    * a space or a newline character).
    * @return character read or <code>null</code> character
    * (Unicode 0) if trying to read beyond the EOF
    public char readChar()
    char ch = '\u0000';
    try
    if (ready())
    ch = (char)myInFile.read();
    catch (IOException e)
    if (myFileName != null)
    System.err.println("Error reading " + myFileName + "\n");
    myErrorFlags |= READERROR;
    if (ch == '\u0000')
    myErrorFlags |= EOF;
    return ch;
    * Reads from the current position in the file up to and including
    * the next newline character. The newline character is thrown away
    * @return the read string (excluding the newline character) or
    * null if trying to read beyond the EOF
    public String readLine()
    String s = null;
    try
    s = myInFile.readLine();
    catch (IOException e)
    if (myFileName != null)
    System.err.println("Error reading " + myFileName + "\n");
    myErrorFlags |= READERROR;
    if (s == null)
    myErrorFlags |= EOF;
    return s;
    * Skips whitespace and reads the next word (a string of consecutive
    * non-whitespace characters (up to but excluding the next space,
    * newline, etc.)
    * @return the read string or null if trying to read beyond the EOF
    public String readWord()
    StringBuffer buffer = new StringBuffer(128);
    char ch = ' ';
    int count = 0;
    String s = null;
    try
    while (ready() && Character.isWhitespace(ch))
    ch = (char)myInFile.read();
    while (ready() && !Character.isWhitespace(ch))
    count++;
    buffer.append(ch);
    myInFile.mark(1);
    ch = (char)myInFile.read();
    if (count > 0)
    myInFile.reset();
    s = buffer.toString();
    else
    myErrorFlags |= EOF;
    catch (IOException e)
    if (myFileName != null)
    System.err.println("Error reading " + myFileName + "\n");
    myErrorFlags |= READERROR;
    return s;
    * Reads the next integer (without validating its format)
    * @return the integer read or 0 if trying to read beyond the EOF
    public int readInt()
    String s = readWord();
    if (s != null)
    return Integer.parseInt(s);
    else
    return 0;
    * Reads the next double (without validating its format)
    * @return the number read or 0 if trying to read beyond the EOF
    public double readDouble()
    String s = readWord();
    if (s != null)
    return Double.parseDouble(s);
    // in Java 1, use: return Double.valueOf(s).doubleValue();
    else
    return 0.0;
    Can anybody please tell me what's wrong with this code? Thanks

    String[] message = {
        "One, two, buckle your shoe",
        "One, two, buckle your shoe",
        "Three, four, shut the door",
        "Three, four, shut the door",
        "Five, six, pick up sticks",
        "Five, six, pick up sticks",
        "Seven, eight, lay them straight",
        "Seven, eight, lay them straight",
        "Nine, ten, this is the end",
        "Nine, ten, this is the end"
    if(n>0)
        System.out.println(message[n]);
    else
        System.exit(0);

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