What to do with a messed up Power Book???

Hello fellow Mac Heads!
I recently damaged my PowerBook G4 (last edition made b/f it was discontinued). I was told my an Apple Genius that it can't be covered by Apple Care and that I would need to send it to a 3rd party to get a new HD.
What are my options at this point?
I've tried looking for a buyer of slighty damaged PowerBooks but couldn't find anything legit. Do you know of a reputable business out that you could recommend to me? If so, I would appreciate it!!
Thank you,
Chepe
PowerBook Mac OS X (10.4.9)

As far as "OPTIONS" what are you looking for?
1) Repair Centers?
http://techrestore.com/xcart/home.php?cat=252
http://www.macservice.com/powerbookg412.html
http://www.iresq.com/portables/aluminum12.php
http://www.powerbookmedic.com/Apple-Powerbook-Repair-iBook-Repair-Parts-Hinges-G 3-G4-p-3.html
2) Places that buy used and even damaged Macs?
http://www.medicmacs.com/sales.html
(did you try eBay, of course?)

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The Frolick wrote:
…the computer will sometimes grey over (as if someone put a fairly thick grey film over the entire screen), and tell me I have to restart the computer. So what's wrong with it?…
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Read here.
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I can't figure out what's wrong with this code

First i want this program to allow me to enter a number with the EasyReader class and depending on the number entered it will show that specific line of this peom:
One two buckle your shoe
Three four shut the door
Five six pick up sticks
Seven eight lay them straight
Nine ten this is the end.
The error message i got was an illegal start of expression. I can't figure out why it is giving me this error because i have if (n = 1) || (n = 2) statements. My code is:
public class PoemSeventeen
public static void main(String[] args)
EasyReader console = new EasyReader();
System.out.println("Enter a number for the poem (0 to quit): ");
int n = console.readInt();
if (n = 1) || (n = 2)
System.out.println("One, two, buckle your shoe");
else if (n = 3) || (n = 4)
System.out.println("Three, four, shut the door");
else if (n = 5) || (n = 6)
System.out.println("Five, six, pick up sticks");
else if (n = 7) || (n = 8)
System.out.println("Seven, eight, lay them straight");
else if (n = 9) || (n = 10)
System.out.println("Nine, ten, this is the end");
else if (n = 0)
System.out.println("You may exit now");
else
System.out.println("Put in a number between 0 and 10");
I messed around with a few other thing because i had some weird errors before but now i have narrowed it down to just this 1 error.
The EasyReader class code:
// package com.skylit.io;
import java.io.*;
* @author Gary Litvin
* @version 1.2, 5/30/02
* Written as part of
* <i>Java Methods: An Introduction to Object-Oriented Programming</i>
* (Skylight Publishing 2001, ISBN 0-9654853-7-4)
* and
* <i>Java Methods AB: Data Structures</i>
* (Skylight Publishing 2003, ISBN 0-9654853-1-5)
* EasyReader provides simple methods for reading the console and
* for opening and reading text files. All exceptions are handled
* inside the class and are hidden from the user.
* <xmp>
* Example:
* =======
* EasyReader console = new EasyReader();
* System.out.print("Enter input file name: ");
* String fileName = console.readLine();
* EasyReader inFile = new EasyReader(fileName);
* if (inFile.bad())
* System.err.println("Can't open " + fileName);
* System.exit(1);
* String firstLine = inFile.readLine();
* if (!inFile.eof()) // or: if (firstLine != null)
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* System.out.print("Enter the maximum number of integers to read: ");
* int maxCount = console.readInt();
* int k, count = 0;
* while (count < maxCount && !inFile.eof())
* k = inFile.readInt();
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* // process or store this number
* count++;
* inFile.close(); // optional
* System.out.println(count + " numbers read");
* </xmp>
public class EasyReader
protected String myFileName;
protected BufferedReader myInFile;
protected int myErrorFlags = 0;
protected static final int OPENERROR = 0x0001;
protected static final int CLOSEERROR = 0x0002;
protected static final int READERROR = 0x0004;
protected static final int EOF = 0x0100;
* Constructor. Prepares console (System.in) for reading
public EasyReader()
myFileName = null;
myErrorFlags = 0;
myInFile = new BufferedReader(
new InputStreamReader(System.in), 128);
* Constructor. opens a file for reading
* @param fileName the name or pathname of the file
public EasyReader(String fileName)
myFileName = fileName;
myErrorFlags = 0;
try
myInFile = new BufferedReader(new FileReader(fileName), 1024);
catch (FileNotFoundException e)
myErrorFlags |= OPENERROR;
myFileName = null;
* Closes the file
public void close()
if (myFileName == null)
return;
try
myInFile.close();
catch (IOException e)
System.err.println("Error closing " + myFileName + "\n");
myErrorFlags |= CLOSEERROR;
* Checks the status of the file
* @return true if en error occurred opening or reading the file,
* false otherwise
public boolean bad()
return myErrorFlags != 0;
* Checks the EOF status of the file
* @return true if EOF was encountered in the previous read
* operation, false otherwise
public boolean eof()
return (myErrorFlags & EOF) != 0;
private boolean ready() throws IOException
return myFileName == null || myInFile.ready();
* Reads the next character from a file (any character including
* a space or a newline character).
* @return character read or <code>null</code> character
* (Unicode 0) if trying to read beyond the EOF
public char readChar()
char ch = '\u0000';
try
if (ready())
ch = (char)myInFile.read();
catch (IOException e)
if (myFileName != null)
System.err.println("Error reading " + myFileName + "\n");
myErrorFlags |= READERROR;
if (ch == '\u0000')
myErrorFlags |= EOF;
return ch;
* Reads from the current position in the file up to and including
* the next newline character. The newline character is thrown away
* @return the read string (excluding the newline character) or
* null if trying to read beyond the EOF
public String readLine()
String s = null;
try
s = myInFile.readLine();
catch (IOException e)
if (myFileName != null)
System.err.println("Error reading " + myFileName + "\n");
myErrorFlags |= READERROR;
if (s == null)
myErrorFlags |= EOF;
return s;
* Skips whitespace and reads the next word (a string of consecutive
* non-whitespace characters (up to but excluding the next space,
* newline, etc.)
* @return the read string or null if trying to read beyond the EOF
public String readWord()
StringBuffer buffer = new StringBuffer(128);
char ch = ' ';
int count = 0;
String s = null;
try
while (ready() && Character.isWhitespace(ch))
ch = (char)myInFile.read();
while (ready() && !Character.isWhitespace(ch))
count++;
buffer.append(ch);
myInFile.mark(1);
ch = (char)myInFile.read();
if (count > 0)
myInFile.reset();
s = buffer.toString();
else
myErrorFlags |= EOF;
catch (IOException e)
if (myFileName != null)
System.err.println("Error reading " + myFileName + "\n");
myErrorFlags |= READERROR;
return s;
* Reads the next integer (without validating its format)
* @return the integer read or 0 if trying to read beyond the EOF
public int readInt()
String s = readWord();
if (s != null)
return Integer.parseInt(s);
else
return 0;
* Reads the next double (without validating its format)
* @return the number read or 0 if trying to read beyond the EOF
public double readDouble()
String s = readWord();
if (s != null)
return Double.parseDouble(s);
// in Java 1, use: return Double.valueOf(s).doubleValue();
else
return 0.0;
Can anybody please tell me what's wrong with this code? Thanks

String[] message = {
    "One, two, buckle your shoe",
    "One, two, buckle your shoe",
    "Three, four, shut the door",
    "Three, four, shut the door",
    "Five, six, pick up sticks",
    "Five, six, pick up sticks",
    "Seven, eight, lay them straight",
    "Seven, eight, lay them straight",
    "Nine, ten, this is the end",
    "Nine, ten, this is the end"
if(n>0)
    System.out.println(message[n]);
else
    System.exit(0);

What to do with a messed up Power Book???

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