Where can I get some help with my Nokia Maps Licen...
My problem is I bought a license and a Nokia n97.
I originally bought the license on my n95 and was able to transfer my license to my new n97. But since I have upgraded to version 3.0 my license has dissapeared.
I tried doing the sim card transfer method and that works up to the point where it tries to associate it with my new sim card (I changed provides when I upgraded). When it gets to this point it simply states "No updates" and then keeps trying again and again. I have rolled it back to version 2 and now have the same problem.
Unfortunately I have lost the email I got when I registered and I can't find any information on how to get this email resent.
I have tried speaking with Nokia care here in Sydney, Australia and they said it is a known problem but there is no fix for it.
I would like to try entering my license code again manually to see if thats possible. But I am told and I can see that nokia doesn't allow its customers to get this information again.
Please do something about this Nokia. It's really a **bleep** situation.
Solved!
Go to Solution.
zgeek wrote:
My problem is I bought a license and a Nokia n97.
I originally bought the license on my n95 and was able to transfer my license to my new n97. But since I have upgraded to version 3.0 my license has dissapeared.
I tried doing the sim card transfer method and that works up to the point where it tries to associate it with my new sim card (I changed provides when I upgraded). When it gets to this point it simply states "No updates" and then keeps trying again and again. I have rolled it back to version 2 and now have the same problem.
Unfortunately I have lost the email I got when I registered and I can't find any information on how to get this email resent.
I have tried speaking with Nokia care here in Sydney, Australia and they said it is a known problem but there is no fix for it.
I would like to try entering my license code again manually to see if thats possible. But I am told and I can see that nokia doesn't allow its customers to get this information again.
Please do something about this Nokia. It's really a **bleep** situation.
Hi zgeek,
I had a similar issue when moving from my N95-1 (maps 3.0 installed and licence upgraded) to my N86-1 (maps 3.0 pre-loaded). Everything was fine with the old SIM but couldn't transfer the licence across to the new handset and SIM.
Nokia ended up giving me new licences as the old ones didn't want to work anymore.
Have you searched your e-mail for the word "openbit"? Not sure if they just do Europe or the worldwide licencing sales.
One of the Nokia staff that contributes to the support forums was able to assist me (see this thread), as long as you have your N95 IMEI and SIM and your N97 IMEI and SIM then they should be able to sort it - It took me 3 weeks to resolve and cbidlake was excellent and prodding the right people.
Hope that this helps.,
Alun.
N8-00 (Product Code: 059C5Q8 (UK Generic)) FW Belle (111.030.0609.377.01)
Orange 5.1, NK702, 7110, 8310, 7250, 6230, N70, N95-1, N86 8MP, N8-00
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Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 66
at Graph.ChainingHashTable.get(ChainingHashTable.java:76)
at Graph.Vertex.isNeighbor(Vertex.java:123)
at Graph.LinkedGraph.addEdge(LinkedGraph.java:42)
at Graph.Traversals.main(Traversals.java:311)
The following is my code
Traversal.java
package Graph;
public class Traversals implements Callback<Vertex>
public void visit( Vertex data )
System.out.println( data.getName() );
* Perform a breadth first traversal of the vertices in the given graph
* starting at the specified node. The call back object is used to process
* each node as it appears in the traversal.
* @param g the graph to traverse
* @param start the vertex where the traversal will start
* @param cb the object that processes vertices.
public void BFSTraverse( Graph g, Vertex start, Callback<Vertex> cb )
Queue<Vertex> waiting = new LinkedQueue<Vertex>(); // Queue of waiting
// vertices
// Ensure the graph has no marked vertices
List<Vertex> vertices = g.getVertices();
for( vertices.first(); vertices.isOnList(); vertices.next() )
vertices.get().setTag( false );
// Put the start vertex in the work queue
waiting.enqueue( start );
// While there are waiting vertices
while( !waiting.empty() )
// Get the next Vertex
Vertex curVertex = waiting.front();
waiting.dequeue();
// If this Vertex hasn't been processed yet
if( !curVertex.getTag() )
cb.visit( curVertex ); // Process the vertex
curVertex.setTag( true ); // Mark it as visited
// Put its unmarked neighbors into the work queue
List<Vertex> neighbors = curVertex.getNeighbors();
for( neighbors.first(); neighbors.isOnList(); neighbors.next() )
Vertex cur = neighbors.get();
if( !cur.getTag() )
waiting.enqueue( cur );
* Use Kruskal's algorithm to create a minimum spanning tree for the given
* graph. The MST is returned in the form of a graph.
* @param g the graph from which to generate the MST
* @return a graph containing the the vertices of g and the the edges
* nesseary to form a minimum spanning tree.
public Graph kruskalMST( Graph g )
// Where the MST will be stored
Graph mst = new LinkedGraph();
// All the vertices in the graph
List<Vertex> vertices = g.getVertices();
// List of Vertex Sets
List<Set<String>> vertexSets = new LinkedList();
// Add the vertices in the original graph to mst
// and create the vertex sets at the same time
for( vertices.first(); vertices.isOnList(); vertices.next() )
String curName = vertices.get().getName();
Set<String> curSet = null; // new ArrayBasedSet<Vertex>();
// Add the name of the current vertex to its set and then
// add the set to the list that contains the vertex sets
curSet.add( curName );
vertexSets.add( curSet );
// Add the current vertex to the MST graph
mst.addVertex( curName );
// Put the edges into a heap which effectively sorts them
Heap<Edge> edges = new ArrayBasedHeap<Edge>();
List<Edge> allEdges = g.getEdges();
for( allEdges.first(); allEdges.isOnList(); allEdges.next() )
edges.insertHeapNode( allEdges.get() );
// Setup is complete - run the algorithm
// There is more than one set left in the list vertex sets
while( vertexSets.size() > 1 )
// Get the smallest edge
Edge cur = edges.getSmallest();
// Find the sets where these vertices are located
int sourcePos = findSet( vertexSets, cur.getSource().getName() );
int destPos = findSet( vertexSets, cur.getDest().getName() );
// If the vertices are in different sets - add the edge to
// the MST
if( sourcePos != destPos )
Set<String> sourceSet = vertexSets.get( sourcePos );
Set<String> destSet = vertexSets.get( destPos );
// Add the edge to the MST
mst.addEdge( cur.getSource().getName(),
cur.getDest().getName(), cur.getCost() );
// Merge the sets
sourceSet.union( destSet );
vertexSets.remove( destPos );
// The MST can be read from this graph
return mst;
* Return the position of the first set in the list that contains the
* specified name.
* @param vertexSets a list of sets to search.
* @param name the name being searched for.
* @return the position of the first set in the list that contains the name
* or -1 if the name cannot be found.
private int findSet( List<Set<String>> vertexSets, String name )
int retVal = -1;
// Step through the list and examine each set. Stop when you
// find a set with the name or we fall off the list
for( int i = 0; retVal == -1 && i < vertexSets.size(); i = i + 1 )
Set curSet = vertexSets.get( i );
// Does the current set contain the name we are looking for?
if( curSet.contains( name ) )
retVal = i;
// Return the position of the set
return retVal;
* Perform Dijkstra's Shortest Path algorithm on the given graph, starting
* at the given vertex.
* @param g the Graph to traverse.
* @param name the name of the vertex where the traversal starts.
* @return an array containing vertex path costs.
public int[] dijkstraSP( Graph g, String name )
// The names of the vertices for which the shortest
// path is not known
Set<String> u = new ArrayBasedSet<String>();
// The names of the vertices for which the shortest
// path is known
Set<String> s = new ArrayBasedSet<String>();
// Put the vertices in an array to make things easier
List<Vertex> vertices = g.getVertices();
Vertex v[] = new Vertex[ vertices.size() ];
for( int i = 0; i < vertices.size(); i++ )
v[ i ] = vertices.get( i );
// The starting vertex
Vertex start = g.getVertex( name );
// The lowest costs seen so far
int c[] = new int[ v.length ];
// Temporary edge used by the program
Edge curEdge = null;
// Sort the vertices by name so that the costs will
// appear in order by name
Heap<String> names = new ArrayBasedHeap<String>();
// Build the heap
for( int i = 0; i < v.length; i = i + 1 )
names.insertHeapNode( v[ i ].getName() );
// Read out the values
for( int i = 0; !names.empty(); i = i + 1 )
v[ i ] = g.getVertex( names.getSmallest() );
// We "know" the shortest path to the source
s.add( name );
// For each vertex, compute the starting cost
for( int i = 0; i < v.length; i = i + 1 )
// If this isn't the start node
if( !v[ i ].getName().equals( name ) )
// Put it in the unknown set
u.add( v[ i ].getName() );
// Compute the initial cost to reach this Vertex
curEdge = start.getEdge( v[ i ].getName() );
if( curEdge != null )
c[ i ] = curEdge.getCost();
else
// This Vertex is currently unreachable
c[ i ] = Integer.MAX_VALUE;
else
// It costs 0 to get to the start vertex
c[ i ] = 0;
// Set is complete - run the algorithm until all of
// the paths are known
while( !u.isEmpty() )
// Find the position of the lowest-cost unknown node
int min = Integer.MAX_VALUE;
int minPos = -1;
for( int i = 0; minPos == -1 && i < c.length; i = i + 1 )
if( c[ i ] < min && u.contains( v[ i ].getName() ) )
min = c[ i ];
minPos = i;
// We know the shortest path to the vertex
s.add( v[ minPos ].getName() );
u.remove( v[ minPos ].getName() );
// Update the costs based
for( int i = 0; i < c.length; i = i + 1 )
// Get the edge between the new shortest and the
// current node in the array
curEdge = v[ minPos ].getEdge( v[ i ].getName() );
// If there is an edge
if( curEdge != null )
// If going through the new node is better than
// what has been seen update the cost
if( c[ i ] > c[ minPos ] + curEdge.getCost() )
c[ i ] = c[ minPos ] + curEdge.getCost();
return c;
public static void main( String args[] )
Traversals t = new Traversals();
Graph g = new LinkedGraph();
g.addVertex( "A" );
g.addVertex( "B" );
g.addVertex( "C" );
g.addVertex( "D" );
g.addVertex( "E" );
g.addVertex( "F" );
g.addEdge( "A", "B", 5 ); <--------------------------------------------------------------------------------------------Line 311
g.addEdge( "A", "D", 9 );
g.addEdge( "A", "C", 10 );
g.addEdge( "B", "A", 5 );
g.addEdge( "B", "D", 4 );
g.addEdge( "C", "A", 10 );
g.addEdge( "C", "D", 13 );
g.addEdge( "C", "E", 14 );
g.addEdge( "D", "B", 4 );
g.addEdge( "D", "A", 9 );
g.addEdge( "D", "C", 13 );
g.addEdge( "D", "E", 7 );
g.addEdge( "D", "F", 8 );
g.addEdge( "E", "C", 14 );
g.addEdge( "E", "D", 7 );
g.addEdge( "E", "F", 2 );
g.addEdge( "F", "D", 8 );
g.addEdge( "F", "E", 2 );
int costs[] = t.dijkstraSP( g, "A" );
for( int i = 0; i < costs.length; i = i + 1 )
System.out.println( costs[ i ] );
}ChainingHashTable.java
package Graph;
* An implementation of a HashTable using chaining for collision resolution.
* Javadoc comments for methods specified in the Table interface have been
* omitted.
* This code assumes that the preconditions stated in the comments are true when
* a method is invoked and therefore does not check the preconditions.
public class ChainingHashTable<K, V> implements Table<K, V>
private List<Tuple<K, V>> hashTable[]; // The hashtable
int size; // The size of the hash table
* Create a new hash table.
* @param cardinality the number of elements in the domain.
public ChainingHashTable( int cardinality )
// Note that the cast is necessary because you cannot
// create generic arrays in Java. This statement will
// generate a compiler warning.
hashTable = (LinkedList<Tuple<K, V>>[]) new LinkedList[ cardinality ];
size = 0;
public void put( K key, V value )
int bucket = key.hashCode();
// Do we need to create a new list for this bucket?
if( hashTable[ bucket ] == null )
hashTable[ bucket ] = new LinkedList<Tuple<K, V>>();
hashTable[ bucket ].add( new Tuple<K, V>( key, value ) );
size = size + 1;
public void remove( K key )
int bucket = key.hashCode();
List<Tuple<K, V>> chain = hashTable[ bucket ];
boolean found = false;
// Is there a chain to search?
if( chain != null )
// Step through the chain until we fall off the end or
// find the tuple to delete
chain.first();
while( !found && chain.isOnList() )
// If this tuple has the key we are looking for
// delete it and stop the loop
if( chain.get().getKey().equals( key ) )
chain.remove();
found = true;
else
chain.next();
public V get( K key )
int bucket = key.hashCode();
List<Tuple<K, V>> chain = hashTable[ bucket ]; <----------------------------------------------------------------Line 76
V retVal = null;
// Is there a chain to search?
if( chain != null )
// Step through the chain until we find the element or
// run out of list.
for( chain.first(); retVal == null && chain.isOnList(); chain
.next() )
// If this tuple has the key we are looking for,
// extract the value
if( chain.get().getKey().equals( key ) )
retVal = chain.get().getValue();
return retVal;
public boolean isEmpty()
return size == 0;
public int size()
return size;
public int cardinality()
return hashTable.length;
public List<K> getKeys()
List<Tuple<K, V>> chain;
List<K> keys = new LinkedList<K>();
// Go through each chain and create a list that contains all
// of the keys in the table
for( int i = 0; i < hashTable.length; i++ )
if( hashTable[ i ] != null )
chain = hashTable[ i ];
for( chain.first(); chain.isOnList(); chain.next() )
keys.add( chain.get().getKey() );
return keys;
public List<V> getValues()
List<Tuple<K, V>> chain;
List<V> values = new LinkedList<V>();
// Go through each chain and create a list that contains all
// of the keys in the table
for( int i = 0; i < hashTable.length; i++ )
if( hashTable[ i ] != null )
chain = hashTable[ i ];
for( chain.first(); chain.isOnList(); chain.next() )
values.add( chain.get().getValue() );
return values;
* Return a string representation of this hash table.
* @return a string representation of this hash table.
public String toString()
StringBuffer hashAsString = new StringBuffer( "" );
List chain = null;
for( int i = 0; i < hashTable.length; i = i + 1 )
hashAsString.append( "h[" + i + "]==" );
if( hashTable[ i ] != null )
chain = hashTable[ i ];
for( chain.first(); chain.isOnList(); chain.next() )
hashAsString.append( " " + chain.get() );
hashAsString.append( "\n" );
return hashAsString.toString();
} // ChainingHashTable -
Can I get some help with CF8 and Unix from this forum?
I did my dev in my local machine running windowsXP and CF8
In prod. environment, my CF8 runs in Unix and I'm not familiar with Unix at all.
My manager is out for awhile and I want to do this if I could without waiting for him because in windows it is very simple.
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How can I do these things in Unix?
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C:/ColdFusion8/www/WEB-INF/cfclasses
All my CF files for the application are on C:/Inetpub/www/myfolder/
So my questions are:
1. How can I access point 1 using my FTP to move my exe file to the right folders
2. Since I don't have CF administrator interface with Unix, how can I do point 2 and 3 above????
I have searched on this forum if someone had this problem in the past and also googled it but I got no result.1) If the account you use to FTP to the site does not give you permissions to the ColdFusion instlation directories, you will need to ask permission from whomever in your organization provides those permissions.
2) You would run the same ColdFusion administrator tool. It is usually located at yourwebsite-domain/cfide/administrator/
If it is not located at this location, you need to ask whomever controls your ColdFusion server where it is located and how you should access it.
In otherwords, these are not general problems that we can help you with much. These are specific problems dealing with your organizaiton and how it has configured its systems and network. -
Can I get some help with keyboard shortcuts?
This is my first Mac and I'm totally converted. Excellent! But the transition from a Windows O/S has not been without its difficulties. One problem that eludes me is how do I (in either Pages or Word for Mac) go directly to the end of a line of text? In Windows, there's the 'end' key. Is there an equivalent in Mac? Can't seem to find it. Help would be appreciated.
a full mac keyboard does have the same home and end keys and they work the same way you are used to. on a laptop keyboard they are combined with left and right arrow keys. I'm not at my laptop right now but as i recall to get the home or end functionality you need to hold one of the modifier keys. try control+left arrow and control+right arrow for starters. or fn+left arrow and fn+right arrow.
Message was edited by: V.K. -
Can I get some help with embedded attachments, please?
Hi guys,
I am having the reverse problem with attachments, I actually *want* a file to remain embedded in an email. When my clients on PC or webmail open my e-mails, the attachment comes through no longer inline, but as an attachment that they have to click and download. It happens whether the file is a .jpg or .pdf. I have "Windows friendly Attachments" checked.
Is there a work-around to this? I know in Outlook you can manually embed an image, but I don't want to have to buy it just to be able to work with PC clients.
Thanks in advance!Hi,
The mail servers and other factors that have been mentioned are actually rarely an issue in this case. The problem lies in Mail, which will send an HTML message with correctly embedded images only if all of the following conditions are met:
The message format is set to "rich text" (this is how Mail calls HTML).
The message contains actual text formatting (different styles, colors, fonts or font sizes, etc.).
The message does not contain any attachments other than images.
If you don't need to send embedded images very often and stick to the three above rules, it will work OK.
If you need to send embedded images reliably without having to worry about formatting and other attachments you can try Attachment Tamer: It's a Mail plug-in that among other things allows you to send embedded images reliably. It always sends attachments as they are displayed (images displayed in place are sent as embedded images, any files displayed as icons as regular attachments). You set up how you prefer files to be displayed and attached and default, and then adjust individual attachments as needed. Unlike Thunderbird, Attachment Tamer isn't free, but it costs just a few bucks and integrates with Apple Mail seamlessly (and there is of course a free trial version).
(The forum conditions require me to say that I may receive some form of compensation, financial or otherwise, from my recommendation or link. Indeed, I'm the developer of Attachment Tamer.) -
Can i get some help with the bing app please?
ironically i searched all over the bing website and couldn't find the answer to this:
on the bing commercial they show the ability to hold up your phone with the app open and on the screen you see the scene in front of you but with little popups telling you what each place is. i cannot figure out how to get the app to do that, can anyone provide instructions? thanks.Bing Mobile email support is here:
https://support.discoverbing.com/default.aspx?%7b!%7dsource=app_iPhone&ct=eformt s&mkt=en-US&productkey=bingmobile&scrx=1&st=1&wfxredirect=1 -
Can I get some help with some scenes
I've started a new project and I've ran into a bit of trouble.
My question
Is it possible to write some code where when a scene reaches a certain frame it move onto the next scene.yes, you can either use a goto on the frame where you want to jump to the next scene or, you can create an enterframe loop that repeatedly checks the currentFrame/currentScene.name and use a goto (and stop the loop) when your certain frame is reached.
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Can I get some help with a recursive function in Java?
I'm trying to make a FrozenBubble clone in Java. I'm having trouble with the method that checks for rows with the same color. Here's what I have now:
public int checkColors (BubbleNode node, BubbleNode prevNode, int counter) {
counter--;
if (node != null && prevNode != null && node.imageX != prevNode.imageX)
return 0;
if (counter == 0) {
fallingList.add (node);
return 1;
if (node.left != null && node.left != prevNode) {
if (checkColors (node.left, node, counter) == 1) {
fallingList.add (node);
return 1;
else
return 0;
if (node.right != null && node.right != prevNode) {
if (checkColors (node.right, node, counter) == 1) {
fallingList.add (node);
return 1;
else
return 0;
if (node.topLeft != null && node.topLeft != prevNode) {
if (checkColors (node.topLeft, node, counter) == 1) {
fallingList.add (node);
return 1;
else
return 0;
if (node.topRight != null && node.topRight != prevNode) {
if (checkColors (node.topRight, node, counter) == 1) {
fallingList.add (node);
return 1;
else
return 0;
if (node.bottomLeft != null && node.bottomLeft != prevNode) {
if (checkColors (node.bottomLeft, node, counter) == 1) {
fallingList.add (node);
return 1;
else
return 0;
if (node.bottomRight != null && node.bottomRight != prevNode) {
if (checkColors (node.bottomRight, node, counter) == 1) {
fallingList.add (node);
return 1;
else
return 0;
if (fallingList.size () > 2) {
deleteNodes ();
return 0;
The bubbles are six sided nodes, and imageX is the x coordinate for the start of the bubble in the bubble image, you can think of it as the color of the bubble. I also posted this on the UbuntuForums here, but since it seems like the only person willing to help me has gone to bed and the program is already late, I'm thought I would also post it here.
Thanks!"Green" usually indicates a problem with graphic card drivers; see http://forums.adobe.com/thread/945765
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Can I get some help with ibooks?
ok I have several questions.
1: do I have to own/use a Mac or any other kind of computer from apple to be able to sell books on ibooks?
2 What kind of files do ibooks support? can I sell odt files on it?
3 how much money do apple get from the sales?1. If you do not have a mac, you will probably have to use an Aggregator to sell your books instead of doing it directly.
2. .epub and .ibooks only. Not pdf and not odt and not word or anything else.
3. 30% I think.
Read the FAQs for more info:
http://www.apple.com/itunes/working-itunes/sell-content/books/book-faq.html -
...I cannot download tracks from iMatch. What is the fix?
You can only add music to iTunes Match from your iTunes library on your computer, not from your iOS device. If you have music on your iPad that is not on your computer, you'll have to import it to your iTunes library on your computer to add it to iTunes Match.
Music purchased from the iTunes store can be imported directly to your iTunes library by authorizing your computer for the Apple ID(s) used to purchase the music (in Store>Authorize This Computer), then connecting the iPad to your computer, opening iTunes and going to File>Devices>Transfer Purchases. Music from other sources will require using 3rd party software to transfer to your computer, such as Touch Copy.
Maybe you are looking for
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Return to Warehouse from other plant - Related to STO return
Hi Gurus, We have a scenario at our client: We had a stock transfer order from plant 1 to plant 2. In plant 2 we did the created the delivery - created transfer order - performed good issue - confirmed transfer order and the material is issue to stoc
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Disable a custom object in dialog ??
hi, i created a custom container and associated a text object to it. i want it to be disabled intially. how to set that ?? i create the object as fol CREATE OBJECT g_editor EXPORTING parent = g_editor_container
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I can't open apps on my macbook pro
I can't open some of apps like iphoto, keynote, ilol(this is most important one). If I trying to open, computer just shut down and restart. Some people suggest me to format mac os x and reinstall so I did it but still doesn't work. what should I do?
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My mic is not working after Lion install.
I just installed Lion on my macbook and now when I try to load rosetta stone language software it can't locate my mic. Any ideas? TL
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I own an iBook (clamshell) with Firewire. It has a 366 MHz G3 processor, 320 MB RAM, and 10 GB HD. Currently I am using OS 10.1.5 and occasionally reboot into OS 9. Can I run OS 10.4 on this system and will it run decently? Some have told me to only