Why socket doesn't throw an exception

Question

Hello,
I am using following code
client:
      InetAddress addr = InetAddress.getByName("localhost");
      sock = new Socket(addr, 5551);
      in = new BufferedReader(
        new InputStreamReader(
          sock.getInputStream()));
      out = new PrintWriter(
        new BufferedWriter(
          new OutputStreamWriter(
            sock.getOutputStream())), true);server
try{
  ServerSocket server = new ServerSocket(port);
  Socket socket = server.accept();
  BufferedReader in = new BufferedReader(
     new InputStreamReader(
       socket.getInputStream()));
  PrintWriter out = new PrintWriter(
    new BufferedWriter(
      new OutputStreamWriter(
       socket.getOutputStream())), true);
  while (true){
     String msg = in.readLine();
     System.out.println(msg);
catch (SocketException  se){
  System.out.print(se.toString());
catch (IOException e){
  System.out.print(e.toString());
catch (Exception ex) {
  System.out.print(ex.toString());
}When I close client, server is constantly writing null (msg is null). Why doesn't it throw an exception?
Thank you.

Answer 1

The moral of the story is avoid using Readers and Writers with Sockets. They swallow exceptionsThat's not so. It is PrintWriters and PrintStreams that swallow exceptions.
@OP: there is no reason for your code to throw an exception. It keeps reading the socket and encountering EOF, signalled by the null return, at which point any sensible code should exit the loop and close the socket. However as you don't do that, you just read the socket and get the EOF again ...
You would only get an exception, specifically an EOFException, if you were calling one of the readXXX methods that is specified to throw it. readLine() isn't one of those.