Why throw exception in main thread

Question

A very simple example
public class ExceptionTest {
  public static void main(String[] args) throws StupidException {
   int i = 0;
   if (i == 0)
      throw new StupidException():
public class StupidException {
  public StupidException() {}
}

Answer 1

Umm, one of us is missing something here. My only question is "What are you surprised about?" You have the line
throw new StupidException();and you don't catch that exception anywhere, so of course the program is going to exit that way. You explicitly told main to throw an exception and it did it.
Sorry, not trying to sound snotty or anything. I guess I still just don't know what you're asking.
>
class ExceptionTest {
public static void main(String[] args) throws
StupidException {
int i = 0;
if (i == 0)
throw new StupidException();
class StupidException extends Exception {
public StupidException() {
System.out.println("Da. This is a stupid
d exception!");
}The error that occurs during runtime, along with
expected output, is the following:
Da. This is a stupid exception!
StupidException
at ExceptionTest.main(ExceptionTest.java:7)
Exception in thread "main"
Process completed.
Okay. Now the question again will be "Why is this
runtime error thrown?" It is possible for the main
method to throw an IOException. This is a common
throwable.It's possible for main to throw any throwable you tell it to.
>
It is true that a try/catch can handle this. But then
again creating an exception package for a full
application makes could use of the write once/use
anywhere dictum.I have no idea what you're talking about here. What do you mean "an exception package for a full application"? and what does that have to do with write one, run anywhere?
>
Anyone able to naildown the conflict with the runtime
system?What conflict would that be.