WRT54G Access Restriction Time /Day Problems. Need Help!
Hi,
I have a WRT54G wireless router. When I set the access restriction time to DENY everyday from 11:00pm to 6:00am, it displayed that "The end time must be bigger than start time!". It is from 11 at night to 6 in the morning. How else do I set it? I even upgrade the firmware to v4.21.1 but it still does not work with that time setting. I tried to set to ALLOW everyday from 6:00am to 11:30pm and it accepted the settting but it just applied the restriction right away without waiting for the right time (after I enable it, none of the laptops can access internet even its only 9:10pm).. The time in the linksys setup page is correct as well as all my pcs. Please help! Thanks.
The Access Restrictions feature of a Linksys router allows you to limit Internet access on your network. You can deny certain computers’ Internet access or block certain applications and services.
Here is the link for setting up the Access Restrictions on a Linksys router: http://www6.nohold.net/Cisco2/ukp.aspx?vw=1&docid=20b29e54474a4a17aff594cb659747ea_4041.xml&pid=80&r...
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ABOUT wrt54g 'Access Restriction'
Dear all:
once the duration of rule expired. It won't apply another rule by the time serial.
For example, I set up one of PCs was allowed to access internet between 7:00am~11:55am. This PC could access to internet after 11:55am, even I set another rule for this PC with duration 12:00pm~18:00pm.
Is any solution for my needs.
Beswt Regards
tom
Solved!
Go to Solution.The Access Restrictions feature allows you to limit Internet access on your network. You can deny access to certain computers, block certain applications and services, and block certain websites by the use of keywords or by the URL at a given time. This feature allows you to customize up to 10 different Internet Access Policies for particular computers, which are identified by their IP or MAC addresses.
Here is the link Implementing Access Restrictions for computers: http://www6.nohold.net/Cisco2/ukp.aspx?vw=1&docid=20b29e54474a4a17aff594cb659747ea_4041.xml&pid=80&r... -
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Hello All,
This is the problem I am stuck with right now.
I have two array lists one producer array list and one consumer array list denoted by a and b
P1 P2 P3 P4 P5
5 6 7 8 9
C1 C2 C3 C4 C5
2 3 4 5 6
Now we find all those producer consumer pairs which satisfy the criteria Pi>=Ci
We have the following sets
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(5,3)(6,3)(7,3),(8,3),(9,3)
(5,4)(6,4)(7,4),(8,4),(9,4)
(5,5)(6,5)(7,5),(8,5),(9,5)
(6,6)(7,6)(8,6),(9,6)
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Thanks.
Regards.
NP
What I have tried till now.
I have one more question could you help me with this.
I have an array list of this form.
package mypackage1;
import java.util.*;
public class DD
private int P;
private int C;
private int weight;
public void set_p(int P1)
P=P1;
public void set_c(int C1)
C=C1;
public void set_weight(int W1)
weight=W1;
public int get_p()
return P;
public int get_c()
return C;
public int get_x()
return weight;
public static void main(String args[])
ArrayList a=new ArrayList();
ArrayList min_weights_int=new ArrayList();
ArrayList rows=new ArrayList();
ArrayList temp=new ArrayList();
Hashtable h=new Hashtable();
String v;
int o=0;
DD[] d=new DD[5];
for(int i=0;i<4;i++)
d=new DD();
for(int i=0;i<4;i++)
d[i].set_p(((int)(StrictMath.random()*10 + 1)));
d[i].set_c((int)(StrictMath.random()*10 + 1));
d[i].set_weight(0);
System.out.println("Producers");
for(int i=0;i<4;i++)
System.out.println(d[i].get_p());
System.out.println("Consumers");
for(int i=0;i<4;i++)
System.out.println(d[i].get_c());
System.out.println("Weights");
for(int i=0;i<4;i++)
System.out.println(d[i].get_x());
for(int i=0;i<4;i++ )
int bi =d[i].get_c();
ArrayList row=new ArrayList();
for(int j=0;j<4;j++)
if( d[j].get_p() >=bi)
d[j].set_weight((int)(StrictMath.random()*10 + 1));
row.add("(" + bi + "," + d[j].get_p() + "," +d[j].get_x() + ")");
else
d[j].set_weight(0);
row.add("null");
rows.add(row);
System.out.println(rows);
int f=0;
for(Iterator p=rows.iterator();p.hasNext();)
temp=(ArrayList)p.next();
String S="S" +f;
h.put(S,temp);
String tt=new String();
for(int j=0;j<4;j++)
if(temp.get(j).toString() !="null")
// System.out.println("In if loop");
//System.out.println(temp.get(j).toString());
String l=temp.get(j).toString();
System.out.println(l);
//System.out.println("Comma matches" + l.lastIndexOf(","));
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f++;
for(Enumeration e=h.keys();e.hasMoreElements();)
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int ii=0;
int smallest=0;
String key=(String)e.nextElement();
System.out.println("key=" + key);
temp=(ArrayList)h.get(key);
System.out.println("Array List" + temp);
for( int j=0;j<4;j++)
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if(l!="null")
System.out.println("l=" +l);
[\code]In your example you selected the pair with the greatest
distance from the first set, and the pair with the least
distance from the second. I don't see how the distance
function was used.
Also it's not clear to me that there is always a solution,
and, if there is, whether consistently choosing the
furthest or the closest pairs will always work.
The most obvious approach is to systematically try
all possibilities until the answer is reached, or there
are no possibilities left. This means backtracking whenever
a point is reached where you cannot continue. In this case
backtrack one step and try another possibility at this
step. After all possible choices of the previous step,
backtrack one more step and so on.
This seems rather involved, and it probably is.
Interestingly, if you know Prolog, it is ridiculously
easy because Prolog does all the backtracking for you.
In Java, you can implement the algorithm in much the same
way as Prolog implementations do it--keep a list of all the
choice points and work through them until success or there
are none left.
If you do know Prolog, you could generate lots of random
problems and see if there is always a solution. -
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Repairing the Hard Drive and Permissions
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3. Boot from your OS X Installer disc. After the installer loads select your language and click on the Continue button. When you reach the screen to select a destination drive click once on the destination drive then click on the Option button. Select the Archive and Install option. You have an option to preserve users and network preferences. Only select this option if you are sure you have no corrupted files in your user accounts. Otherwise leave this option unchecked. Click on the OK button and continue with the OS X Installation.
4. Upon completion of the Archive and Install you will have a Previous System Folder in the root directory. You should retain the PSF until you are sure you do not need to manually transfer any items from the PSF to your newly installed system.
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