X6 Won't Copy Songs or Read from Mass Memory

Hi. My Nokia X6-00 16GB was working fine the other day. It's only 3days old and it will not let me copy music to my phone. I've tried everything. Wiped the mass memory. Hard Reset. Reinstalled the Ovi Suite.
When the phone is in mass memory mode i cannot access The Mass Memory / Phone Memory Folder in Windows Explorer. It Says I cannot view the folder because their isnt a program associatied with it.
Songs won't copy. only a certain few do. Even tho i tried putting on songs i had orginaly before the problems started and they wont go back on. "The phone doesn't support them" even though it did a few days ago. Any help?
Thanks

Mine is exactly the same downloaded 3 songs all fine then next day all downloads fail phone is only a week old

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import com.br.kernel.Kernel32;
import com.sun.jna.Memory;
import com.sun.jna.Native;
import com.sun.jna.Pointer;
import com.sun.jna.ptr.IntByReference;
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    int VK_RSHIFT = 0xA1;
    int VK_CONTROL = 17;
    int VK_LCONTROL = 0xA2;
    int VK_RCONTROL = 0xA3;
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import com.sun.jna.*;
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import com.sun.jna.ptr.IntByReference;
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http://pastebin.com/Vq8wfy39

Hello there,
this tutorial was exactly what I needed, so thank you.
Your problem seems to be in this line:
int writeMemory = writeMemory(writeprocess, address, new short[0x22222222]);
The problem is, you're creating a new short array with the length of 0x22222222. Which not only results in an java.lang.OutOfMemoryError: Java heap space
but also, if it would work, would create an empty array with the length of 0x22222222.
I think you want to write 0x22222222 as value in your address.
Correctly stored the code you'd need to write would be:
short[] sarray = new short[]{(short) 0x22222222};
But because the value is too long for the short, the value stored in your array would be the number 8738.
I think, what you want to do is to store the number 572662306, which would be the hex value, stored in an int variable.
So first of all you need to strip down your hex-value to shorts:
Short in Java uses 16 Bit = 2 Byte. 0x22222222 -> 0x2222 for your high byte and 0x2222 for your low byte
So your array would be
short[] sarray = new short[]{0x2222,0x2222};//notice, that sarray[0] is the lowbyte and sarray[1] the high byte, if you want to store 20 it would be new short[]{20,0} or if you use hex new short[]{0x14,0x00}
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public static int writeMemory(Pointer process, int address, short[] data) {
IntByReference written = new IntByReference(0);
int size = data.length*Short.SIZE/8;
Memory toWrite = new Memory(size);
for (int i = 0; i < data.length; i++) {
toWrite.setShort(i*Short.SIZE/8,
data[i]);
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size, written);
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You need to calculate your offset right. And the size of your memory. Maybe you could write this method not with shorts, but with integers. But this should work.
If you pass your new array to this function, it should write 0x22222222 to your adress. If you read out your toWrite value with toWrite.getInt(0) you get the right value.
And there is one more thing. In order to write data to a process, you need to grant two access rights:
A handle to the process memory to be modified. The handle must have PROCESS_VM_WRITE and PROCESS_VM_OPERATION access to the process.
You have to grant the right to write data: PROCESS_VM_WRITE: 0x0020 and PROCESS_VM_OPERATION: 0x0008
So your writeProcess needs to get initialized this way:
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I hope this works for you. Let me know.
Greetings
Edit:
Because every data you write will be 1 byte to whatever count of byte I think the best way is to use the following method to write data to the memory:
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X6 Won't Copy Songs or Read from Mass Memory

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