XML in String

I am using SAXParser. I see API to parse a file or URI. If content in XML document is in string form(Read into string) , what API is to be used. I see InputSource also.. It is not being used for String XML data.
Thanks

InputSource input=new InputSource(new StringReader("xmlString"));

Similar Messages

How to Parse XML into String in BPEL?

Hi,
Can anyone tell me, how can I parse XML into String?
I am taking input from File Adapter, File adapter is reading that XML.
Then in assign activity i am using XPath expression(built functions) using XMLParser(),doTranslateToNative() etc.. many functions I have tried but XML is not getting parsed into String Variable.
Please help me asap.
Thanks
Shikha

Thanks a lot Eric.
I am trying this, oraext:get-content-as-string('receiveInput_Read_InputVariable','body','/ns3:orders')
but getting this error
<bpelFault><faultType>0</faultType><subLanguageExecutionFault xmlns="http://schemas.oracle.com/bpel/extension"><part name="summary"><summary>XPath expression failed to execute. An error occurs while processing the XPath expression; the expression is oraext:get-content-as-string('receiveInput_Read_InputVariable','body','/ns3:orders'). The XPath expression failed to execute; the reason was: internal xpath error. Check the detailed root cause described in the exception message text and verify that the XPath query is correct. </summary></part><part name="code"><code>XPathExecutionError</code></part></subLanguageExecutionFault></bpelFault>

XML to string using xslt or java mapping

Hi Experts,
I want to put xml into string and i need to change lessthan symbol to "&lt" and greaterthan symbol to "&gt" , can anyone please help me how to do this??? can you provide code for java mapping or XSLT mapping to achive this.
SOURCE
<?xml version="1.0" encoding="UTF-8"?>
<ns0:source_mt xmlns:ns0="urn:ppp:prototype">
 <row>
 <name1>IT</name1>
 <name2>SOLUTIONS</name2>
 </row>
</ns0:source_mt>
TARGET
<?xml version="1.0" encoding="UTF-8"?>
<ns0:target_mt xmlns:ns0="urn:ppp:prototype">
 <row>
 <Body>"&lt"name1"&gt" IT"&lt"/name1"&gt" "&lt"name2"&gt" SOLUTIONS"&lt";/name2"&gt" </Body>
 </row>
</ns0:target_mt>

Hi ,
 here is the XSLT code to obtain the desired output
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml"/>
<xsl:template match="/">
<ns0:target_mt xmlns:ns0="urn:ppp:prototype">
 <xsl:for-each select="//row">
 <row>
 <Body>
 <xsl:for-each select="name1">
 <xsl:value-of select="concat('*"<"name1">"*',normalize-space(.),'*"<"/name1">"*')"></xsl:value-of>
 </xsl:for-each>
 <xsl:for-each select="name2">
 <xsl:value-of select="concat('*"<"name2">"*',normalize-space(.),'*"<"/name2">"*')"></xsl:value-of>
 </xsl:for-each>
 </Body>
 </row>
 </xsl:for-each>
</ns0:target_mt>
</xsl:template>
</xsl:stylesheet>
output produced as viewed in browser is
http://postimage.org/image/1lqbgw8kk/
Now to obtain exactly the output you posted earlier here is the code
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml"/>
<xsl:template match="/">
<ns0:target_mt xmlns:ns0="urn:ppp:prototype">
 <xsl:for-each select="//row">
 <row>
 <Body>
 <xsl:for-each select="name1">
 <xsl:value-of select="concat('*"&lt"name1"&gt"*',normalize-space(.),'*"&lt"/name1"&gt"*')"></xsl:value-of>
 </xsl:for-each>
 <xsl:for-each select="name2">
 <xsl:value-of select="concat('*"&lt"name2"&gt"*',normalize-space(.),'*"&lt"/name2"&gt"*')"></xsl:value-of>
 </xsl:for-each>
 </Body>
 </row>
 </xsl:for-each>
</ns0:target_mt>
</xsl:template>
</xsl:stylesheet>
output you can see from link below
http://postimage.org/image/2c7bzo478
Hope this helps.
Hi,
 Could you please kindly let us know if the solution is working properly as per your requirement?
regards
Anupam
Edited by: anupamsap on Jul 26, 2011 6:29 AM
Edited by: anupamsap on Jul 26, 2011 4:10 PM

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data xmlString type string.
data xmlXString type xstring.
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Here' s my answer for others that may need it:
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If I use
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parse
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MapViewer API: addMapCacheTheme creates unexpected XML request string

Hi,
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 viewer.setImageFormat(MapViewer.FORMAT_PNG_URL);
 viewer.setMapRequestSRID(8307);
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 viewer.setMapTitle(null);
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 viewer.setDeviceSize(new Dimension(480, 480));
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<?xml version="1.0" standalone="yes"?>
<map_request
datasource="ADATASOURCE"
srid="8307"
width="480"
height="480"
bgcolor="#a6caf0"
antialiase="false"
format="PNG_URL"
>
<center size="1.0">
<geoFeature>
<geometricProperty typeName="center">
<Point>
<coordinates>29.0,41.0</coordinates>
</Point>
</geometricProperty>
</geoFeature>
</center>
<themes>
<theme name="AMAPCACHE" datasource="ADATASOURCE">
<map_cache_theme map_cache_name="AMAPCACHE" snap_to_cache_scale="true"/> </theme> <theme name="AMAPCACHE" >
<wfs_feature_request
datasource="ADATASOURCE"
/>
</theme>
</themes>
</map_request>
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Ver10131_B06102 to Ver11_B07100.
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<?xml version="1.0" standalone="yes"?>
<map_request
datasource="ADATASOURCE"
srid="8307"
width="480"
height="480"
bgcolor="#a6caf0"
antialiase="false"
format="PNG_URL"
>
<center size="1.0">
<geoFeature>
<geometricProperty typeName="center">
<Point>
<coordinates>29.0,41.0</coordinates>
</Point>
</geometricProperty>
</geoFeature>
</center>
<themes>
<theme name="AMAPCACHE" datasource="ADATASOURCE">
<map_cache_theme map_cache_name="AMAPCACHE" snap_to_cache_scale="true"/> </theme> </themes>
</map_request>
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OS: Windows XP Pro SP2
IDE: JDeveloper 10.1.3.1.0
Thanks in advance,
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Hi Cihan,
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We have Java tool that does a string replacement inside another string (that is actually an XML request). It works fine when searching for a simple substring (that exists within 1 line of the XML string).
But when I'm trying to find and replace a substring that covers more then 1 line of XML request - it does not work. And I'm not sure what is wrong or (more importantly) how to make it work.
There is no return or new-line chars seen in the XML request.
To make it more clear - here is what I have and trying to do:
<a>
<a>

<c>
<d> </d>
<c>
<c>
</c>
</c>
</c>

</a>
</a>
If I'll seach for either <c> OR </c> OR <d> </d> it all works fine ... BUT if Itry to find
</c>

which will be copied directly from the XML request and past into field - thus it will look like this (horisontal line instead of vertical) </c> - it does not work

qavlad wrote:
But when I'm trying to find and replace a substring that covers more then 1 line of XML request - it does not work. First statement - "more than 1 line"
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There is no way that I can understand what you meant in your first statement in terms of your second.
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Urgent Help required! - Storing the XML as String instead as a file

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I need urgent help on this.
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<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE Test SYSTEM "Test.dtd">
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Gayathri.

hi,
i think this is what u want
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 StringWriter strResponse = null;
 try {
 OutputFormat format = new OutputFormat(d);
 strResponse = new StringWriter();
 XMLSerializer serial = new XMLSerializer( strResponse, format );
 serial.asDOMSerializer();
 serial.serialize(d.getDocumentElement());
 catch (Exception e) {
 System.out.println(e.toString());
 return strResponse.toString();
}HTH
vasanth-ct

How convert an xml to string for a textflow

Hi
usually I use fields type String to feed the textFlows.
now for visual convenience, I would like to store them in file formatted XML, and the thing succeeds well, but when I want use them I have problems, because the formatting XML creates line spacings that I don't want,
for example:
<TextFlow columnCount="inherit" columnGap="inherit" columnWidth="inherit" lineBreak="toFit" paddingBottom="4" paddingLeft="4" paddingRight="4" paddingTop="4" paragraphSpaceAfter="15" paragraphSpaceBefore="0" verticalAlign="top" id="flow" whiteSpaceCollapse="preserve" xmlns="http://ns.adobe.com/textLayout/2008">
<linkActiveFormat>
 <TextLayoutFormat color="#cc00cc" fontWeight="bold" textDecoration="underline"/>
</linkActiveFormat>
<linkHoverFormat>
 <TextLayoutFormat color="#cc0000" fontWeight="bold" textDecoration="underline"/>
</linkHoverFormat>
<linkNormalFormat>
 <TextLayoutFormat color="#000099" fontWeight="bold" textDecoration="none"/>
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 Gestione dei testi con TLF e Testo classico


 Le novità introdotte con l'ultima release di Flash CS5 sono molteplici, una di queste novità riguarda i campi di testo.


 Cosa c'è da sapere sul Text Layout Framework (TLF)?
 <img id="1|emot|0" height="18" width="18" source="[object Bitmap]"/>
 


 Che rispetto al Testo Classico,

</TextFlow>
produce me:
init--------------------------------------------------------------
 Gestione dei testi con TLF e Testo classico
 Le novità introdotte con l'ultima release di Flash CS5 sono molteplici, una di queste novità riguarda i campi di testo.
 Cosa c'è da sapere sul Text Layout Framework (TLF)?
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--------------------------------------------------------------------- end
instead of:
init--------------------------------------------------------------
Gestione dei testi con TLF e Testo classico
Le novità introdotte con l'ultima release di Flash CS5 sono molteplici, una di queste novità riguarda i campi di testo.
Cosa c'è da sapere sul Text Layout Framework (TLF)?
Che rispetto al Testo Classico,
--------------------------------------------------------------------- end
as I will want.
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can you help me?
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jeanPaul

hi
I tested with this code:
package
import flash.net.URLRequest;
import flash.net.URLLoader;
import flash.display.Sprite;
import flash.events.*;
import flashx.textLayout.elements.*;
import flashx.textLayout.conversion.*;
import flashx.textLayout.formats.TextLayoutFormat;
public class importer extends Sprite
 private var urlRequest:URLRequest;
 private var urlLoader:URLLoader;
 public function importer()
 urlRequest = new URLRequest('newPRV_scritto.xml');
 urlLoader = new URLLoader();
 urlLoader.addEventListener(Event.COMPLETE, caricato);
 urlLoader.addEventListener(IOErrorEvent.IO_ERROR, erroreCaric);
 urlLoader.load(urlRequest);
 private function erroreCaric(e:IOErrorEvent):void
{ trace("error: file not found"); }
private function caricato(e:Event):void
 var markup:String = e.target.data;
 var config:Configuration = new Configuration();
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what you say of it?

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I am trying to parse an xml string using Xerces.
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<segment id="seg1" pointIndex="2" meters="239" seconds="22" distance="0.1 mi" time="21 secs">Turn left at 19th St NE</segment>
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<segment id="seg5" pointIndex="102" meters="1859" seconds="93" distance="1.2 mi" time="1 min">Turn right at 16th Ave SW</segment>;
XMLReader reader = new SAXParser();
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org.xml.sax.SAXParseException: File "<segments meters="8643" seconds="538" distance="5.4 mi" time="8 mins"><segment id="seg0" pointIndex="0" meters="122" seconds="11" distance="0.1 mi" time="11 secs">Head southwest from B Ave NE</segment><segment id="seg1" pointIndex="2" meters="239" seconds="22" distance="0.1 mi" time="21 secs">Turn left at 19th St NE</segment><segment id="seg2" pointIndex="5" meters="2985" seconds="192" distance="1.9 mi" time="3 mins">Turn right at 1st Ave NE</segment><segment id="seg3" pointIndex="43" meters="3280" seconds="211" distance="2.0 mi" time="3 mins">Continue on 1st Ave SW/1st Ave NW</segment><segment id="seg4" pointIndex="96" meters="158" seconds="10" distance="0.1 mi" time="10 secs">Bear right at US-151-BR S</segment><segment id="seg5" pointIndex="102" meters="1859" seconds="93" distance="1.2 mi" time="1 min">Turn right at 16th Ave SW</segment></segments>" not found.
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 at org.apache.xerces.framework.XMLParser.parse(XMLParser.java:1097)
 at org.apache.xerces.framework.XMLParser.parse(XMLParser.java:1139)
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reader.parse(new InputSource(new StringReader(xml)));

SaxParser error parsing xml encoded string

I'm trying to parse an XML string with Java's SaxParser. The program
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Is my XML string okay?
<?xml version="1.0" encoding="utf-8"
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org.xml.sax.SAXParseException: Inadmissible sign at the document end<
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at org.apache.crimson.parser.Parser2.fatal(Parser2.java:3370)
at org.apache.crimson.parser.Parser2.parseInternal(Parser2.java:673)
at org.apache.crimson.parser.Parser2.parse(Parser2.java:337)
at
org.apache.crimson.parser.XMLReaderImpl.parse(XMLReaderImpl.java:448)
at javax.xml.parsers.SAXParser.parse(SAXParser.java:345)
at javax.xml.parsers.SAXParser.parse(SAXParser.java:143)
at EchoSaxParser.parse(EchoSaxParser.java:51)
at StringParser.parse(StringParser.java:23)
at Servant.stringparse(Servant.java:30)
at TEST._TestImplBase._invoke(_TestImplBase.java:43)
at
com.sun.corba.se.internal.corba.ServerDelegate.dispatch(ServerDelegate.java�:353)
at com.sun.corba.se.internal.iiop.ORB.process(ORB.java:280)
at
com.sun.corba.se.internal.iiop.RequestProcessor.process(RequestProcessor.ja�va:81)
at
com.sun.corba.se.internal.orbutil.ThreadPool$PooledThread.run(ThreadPool.ja�va:106)
Any help would be greatly appreciated!
Thank you!

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It's all one line.
I also tried adding System.getProperty("line.separator") add the
end of each tag so I get :
<?xml version="1.0" encoding="utf-8" ?>
<DTYPE>IMG</DTYPE>
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Problem in transforming XML to string using XSLT

Hi there,
I have a R/3 -> XI -> WebService scenario where the message from XI to webservice needs to be sent in document/wrapped mode (the message xml must be embedded in a string element) and this message needs to be digitally signed.
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XI sends string to signer as "<"
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For Java Mapping, you can refer this-
/people/prasad.ulagappan2/blog/2005/06/29/java-mapping-part-i
/people/prasad.ulagappan2/blog/2005/06/29/java-mapping-part-ii
/people/prasad.ulagappan2/blog/2005/06/29/java-mapping-part-iii
In Java Mapping, in the startdocument event , you need to check for the specialchars, and just repalce the value required.
But, what i am thinking is , just try with Java functions inside the XSLT mapping instead of going for Java Mapping. You can call java functions from the XSLT. So before the document starts pasring, you need to replace the special characters. I did not try in XSLT like this.
For this , you can think with this e.g
/people/pooja.pandey/blog/2005/06/27/xslt-mapping-with-java-enhancement-for-beginners
Regards,
Moorthy

XML in String

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