XML Parser returning XML content

Question

This probably seems like overkill..
Im building a JSP that reads in XML and parses it. I then need to filter for specific values in the XML, and return a chunk of the XML to the output stream.
So far I've got..
      //set-up in and content-type
        FileInputStream file = new FileInputStream (getServletContext().getRealPath("/games_arcade/xml/game_marketing_content.xml"));
        //response.setContentType("text/xml");
        //parse the request
        Document doc = null ;
        try {
               DocumentBuilderFactory docBuilderFact = DocumentBuilderFactory.newInstance();
               DocumentBuilder docBuilder = docBuilderFact.newDocumentBuilder();
               doc = docBuilder.parse(file);
               out.println("Go on ya good thing!!!");
        } catch (ParserConfigurationException pcEx) {
            throw new ServletException("jaxp not configured!", pcEx);
        //get needed data from the xml
        NodeList games = doc.getElementsByTagName("game");
          out.println(output.toString());
          Now Im lost. All the requisites are there, imports etc, Im just stuck with filtering the NodeList.
Or am I completely wrong with this approach?
Any help greatly appreciated.
thanks!
Stephen

Answer 1

Hi,
thanks for the replyand suggestions. Have a bit of an issue with this method, this method (due to technical limitations) is completely JSP, using a standard iPlanet 6.1 classpath. I cant deploy WAR's (and cant use taglibs). Xpath/XSL would be ideal, but how do I write the output as XML?
So are you suggesting
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
  <xsl:output method="html"/>
    <xsl:template match="/">
        <xsl:for-each select="games/game">
          <xsl:if test="@id = $GAMEID">
               ... output the xml node using value-of's etc...
          </xsl:if>
        </xsl:for-each>
      </xsl:template>
    </xsl:stylesheet>Cheers Dr Clap!
Stephen