XSL and getNodeValue() problem

Question

I'm having a problem get an output that I expect. If I start with xml like this:
<?xml version="1.0" encoding="UTF-8"?>
<ROWSET>
<ROW num="1">
<PUBLISH_DOCUMENT_ID>3</PUBLISH_DOCUMENT_ID>
<TOPIC_ID>2</TOPIC_ID>
<SECTION_ID>1</SECTION_ID>
</ROWSET>
And apply XSL like this:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes"/>
<xsl:template match="/">
<CONTENT>
<xsl:apply-templates select="/ROWSET/ROW"/>
</CONTENT>
</xsl:template>
<xsl:template match="ROW">
<URL>http://healthecare140:7601/medical/medicalDocument.jsp?page=medical&;topic=<xsl:value-of
select="TOPIC_ID"/>&;item=<xsl:value-of select="SECTION_ID"/>
</URL>
</xsl:template>
</xsl:stylesheet>
I get this (as expected):
<CONTENT>
<URL>
http://localhost:7601/medical/medicalDocument.jsp?page=medical&;topic=3&;item=1
</URL>
</CONTENT>
BUT, then when I run this code:
NodeList nodes = doc.getElementsByTagName("URL");
if(nodes.getLength() > 0) {
url = nodes.item(0).getFirstChild().getNodeValue();
System.out.println("URL ===== " + url);
I get this result??????:
URL ===== http://healthecare140:7601/medical/medicalDocument.jsp?page=medical <<<--------what happend to the "&;topic=3&;item=1" part of the nodeValue?
Any ideas on what I'm doing wrong?
thanks,
chad.
null

Answer 1

I have discovered some things that I would like to share.
There are actually multiple child nodes, the first being what was displayed. So you need to either roll through all of the children nodes and build the text or do this (normalize the node):
Node n = nodes.item(0);
n.normalize();
url = normalize(n.getFirstChild()
.getNodeValue());
.normalize() is the key!
later,
chad.