XSLT transformation help

Hi ,
Source data :-
<root xmlns="http://TargetNamespace.com/">
<header>
        <C2> </C2>
         <C3></C3>
        <C4></C4>
        <C5></C5>
</header>
<body>
    <a></a>
    <b></b>
</body>
<body>
    <a></a>
    <b></b>
</body>
<body>
    <a></a>
    <b></b>
</body>
<header>
        <C2> </C2>
         <C3></C3>
        <C4></C4>
        <C5></C5>
</header>
<body>
    <a></a>
    <b></b>
</body>
<body>
    <a></a>
    <b></b>
</body>
the above input needs to be transformed to
<Root>
     <child>
            <header> ..... </header>
             <body>   .. </body>
             <body>   .. </body>
             <body>   .. </body>
     </child>
     <child>
         <header>.......</header>
          <body>........</body>
           <body>........</body>
      </child>
</Root>
(... ) here are the actual elements I jus represented them as ( .... )
can some one tell me how can we write xslt for the above transformation ..

You need to create a target schema with below heirarchy.
Root
Child(unbounded)
body.(unbounded)
In .xsl file from source to target,
use mapping this way:
<Root>
for each on <Child>
for each on < body>
thanks

Similar Messages

Need help on xslt transformation

Hi ,
I am working on a xslt transformation and I am finding it difficult to implement the transformation. The scenario is as below.
Input format :-
A
B
B
B
4
5
A
B
B
A
B
B
B
Output format :-
A
B
B
B (since after A there were 3 B’s before the next A)
A
B
B(since after A there were two B’s before the next A)
A
B
B
B
I don't need type 4,5 records in the output xml,output should have repetition of (A followed by B’s(till the next occurrences of A)).
if some one encountered a similar transformation kindly let me know.

Hi,
You can use "Call" and "Apply" template.
1st thing to do:
e.g.
<xsl:template name="Check_Decimal">
    <xsl:param name="Xpath"/>
    <xsl:choose>
      <xsl:when test="($Xpath) and ($Xpath)!='4'">
        <xsl:value-of select="$Xpath"/>
      </xsl:when>
      <xsl:otherwise>
        <xsl:value-of select="' ' '"/>
      </xsl:otherwise>
    </xsl:choose>
</xsl:template>
            <xml_Target_Element_1>
              <xsl:call-template name="Check_Decimal">
                <xsl:with-param name="Xpath"
                                select="/x/y/z/xml_Target_Element_1"/>
              </xsl:call-template>
            </xml_Target_Element_1>
This means, it will display the value in xpath if value is not equal to 4. And if it is equal to 4, it displays nothing.
2nd thing to do:
Apply for-each to xpath till the String element reaches to "A".
Regards,
Richa

Help on xslt transformation

Hi,
I am working on a xslt transformation and I am finding it difficult to implement the transformation. The scenario is as below.
Input format :-
A
B
B
B
4
5
A
B
B
A
B
B
B
Output format :-
A
B
B
B (since after A there were 3 B’s before the next A)
A
B
B(since after A there were two B’s before the next A)
A
B
B
B
So basically I am not interested in 4,5 type records the output should have repetition of (A followed by B’s(till the next occurance of A)).
if some has done any similar kind of transformation ,kindly let me know

the pusedo code I am thinking for the above transformation is as below
for-each of A
     do mappings using A's elements values
     Flag=Run
     For-each of B
          if flag!=stop
                do B's mapping using B's elements values
                if next node is A
                Flag=Stop
But I came to know that varaibles once initilaised cannot be changed or modified .Also in the above approach in the second iteration of A when I say for-each of B ,xslt will start again from the first occurrence of B in the whole file and not from the B which is following the second A's occurence
i am wondering if can this can be achieved in xslt or shoud we consider using only java?

XSLT mapping Help Required.

XSLT mapping Help Required.
Hi Experts,
I am New to XSLT Mapping. I am practising the below Example:
InputXML File:
<?xml version="1.0" encoding="UTF-8"?>
<?xml-stylesheet type="text/xsl" href="Persons111.xsl"?>
<ns0:MT_XSLT_Source xmlns:ns0="http://XYZ.com/gen">
<Person>
<FirstName>Anshul</FirstName>
<LastName>Chowdhary</LastName>
<Gender>Male</Gender>
<Address>
<Street>2nd Main</Street>
<Houseno>83/b</Houseno>
<City>Mysore</City>
</Address> </Person>
</ns0:MT_XSLT_Source>
XSL StyleSheet File:
<?xml version='1.0' encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:ns0="http://XYZ.com/Gen"
Xmlns:ns1=”http://XYZ.com/Test”>
<xsl:template match="/">
<ns1:MT_XSLT_Target>
<Title> <xsl:value-of select="ns0:MT_XSLT_Source/Person/Gender"/> </Title>
<Name> <xsl:value-of select="concat(concat(ns0:MT_XSLT_Source/Person/FirstName,' '), ns0:MT_XSLT_Source/Person/LastName)"/>
</Name>
<Street> <xsl:value-of select="concat(concat(ns0:Mt_XSLT_Source/Person/Address/Houseno,' '),
ns0:Mt_XSLT_Source/Person/Address/Street)"/> </Street>
<City> <xsl:value-of select="ns0:Mt_XSLT_Source/Person/Address/City"/> </City>
</ns1:MT_XSLT_Target>
</xsl:template>
</xsl:stylesheet>
The Desired Output shuold be:
<?xml version="1.0" encoding="UTF-8"?>
<ns1:MT_XSLT_Target xmlns:ns1="http://XYZ.com/Test">
<Title>Male</Title>
<Name>Anshul Chowdhary</Name>
<Street>83/b 2nd Main</Street>
<City>Mysore</City>
</ns1:MT_XSLT_Target>
I have refered the xsl in xml and i am getting the below Oupt in a Single line like this:
Anshul Chowdhary Male 2nd Main 83/b Mysore
I am Unable to display in Target XML Fomrat as shown above. Please check and do the needful.
Regards,
GIRIDHAR

Hi,
I have used below for testing.
Input xml:
<?xml version="1.0" encoding="UTF-8"?>
<?xml-stylesheet type="text/xsl" href="Persons111.xsl"?>
<ns0:MT_XSLT_Source xmlns:ns0="http://XYZ.com/gen">
<Person>
<FirstName>Anshul</FirstName>
<LastName>Chowdhary</LastName>
<Gender>Male</Gender>
<Address>
<Street>2nd Main</Street>
<Houseno>83/b</Houseno>
<City>Mysore</City>
</Address> </Person>
</ns0:MT_XSLT_Source>
xsl code:
<?xml version='1.0' encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:ns0="http://XYZ.com/gen"
    xmlns:ns1="http://XYZ.com/Test">
    <xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
    <xsl:template match="/">
        <ns1:MT_XSLT_Target>
            <Title> <xsl:value-of select="ns0:MT_XSLT_Source/Person/Gender"/> </Title>
            <Name> <xsl:value-of select="concat(concat(ns0:MT_XSLT_Source/Person/FirstName,' '), ns0:MT_XSLT_Source/Person/LastName)"/>
            </Name>
            <Street> <xsl:value-of select="concat(concat(/ns0:MT_XSLT_Source/Person/Address/Houseno,' '),
                /ns0:MT_XSLT_Source/Person/Address/Street)"/> </Street>
            <City> <xsl:value-of select="/ns0:MT_XSLT_Source/Person/Address/City"/> </City>
        </ns1:MT_XSLT_Target>
    </xsl:template>
</xsl:stylesheet>
For testing in PI ,change the extension from .txt to .xsl and zip it and upload into PI as an imported archive .
Regards
Venkat

Error in ABAP XSLT transformation

Hi,
Im trying to upload some data from XML to abap. But Im getting an error while transforming xml data to internal table.
Here are the details.
XML:
<?xml version="1.0" encoding="ISO-8859-1" ?>

<?xml-stylesheet type="text/xsl" href="ABAP1.xsl"?>
<conceptRevDecisionXml>
<projectInfo>
<projectId>P000755</projectId>
<stage>CON</stage>
<country>Ethiopia</country>
<region>AFRICA</region>
<teamleader>Priya Agarwal</teamleader>
<teamleaderfirstname>Priya</teamleaderfirstname>
<teamleaderlastname>Agarwal</teamleaderlastname>
<actionType>X</actionType>
</projectInfo>
</conceptRevDecisionXml>
XSLT: Transformation
<xsl:transform version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:sapxsl="http://www.sap.com/sapxsl"
>
<xsl:strip-space elements="*"></xsl:strip-space>
<xsl:template match="/">
    <asx:abap xmlns:asx="http://www.sap.com/abapxml" version="1.0">
      <asx:values>
        <PROJID>
          <xsl:apply-templates select="//conceptRevDecisionXml"></xsl:apply-templates>
        </PROJID>
      </asx:values>
    </asx:abap>
</xsl:template>
<xsl:template match="conceptRevDecisionXml">
      <xsl:for-each select="projectInfo">
       <xsl:value-of select="projectId"></xsl:value-of>
       <xsl:value-of select="stage"></xsl:value-of>
       <xsl:value-of select="country "></xsl:value-of>
       <xsl:value-of select="region"></xsl:value-of>
       <xsl:value-of select="teamleader"></xsl:value-of>
       <xsl:value-of select="teamleaderfirstname"></xsl:value-of>
       <xsl:value-of select="teamleaderlastname"></xsl:value-of>
        <xsl:value-of select="actionType"></xsl:value-of>
        </xsl:for-each>
    </xsl:template>
</xsl:transform>
Once I run the program...Im getting an error saying...ABAP XML Formatting error in XML node..
Im new to ABAP-XML parsing..Pls help me where Im going wrong..
Thanks in advance.
Regards,
Priya

Hi Priya,
you can try with the below,
1) Create a local ITAB with the structure of the XML,
TYPES: BEGIN OF t_data,
        projectid           TYPE char30,
        stage               TYPE char30,
        country             TYPE char30,
        region              TYPE char30,
        teamleader          TYPE char30,
        teamleaderfirstname TYPE char30,
        teamleaderlastname TYPE char30,
        actiontype          TYPE char30,
       END OF t_data.
2) Create an XSLT prog in "STRANS" with the below code,
<xsl:transform xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:sap="http://www.sap.com/sapxsl" version="1.0">
<xsl:strip-space elements="*"/>
<xsl:template match="/">
<asx:abap xmlns:asx="http://www.sap.com/abapxml" version="1.0">
<asx:values>
<L_DATA>
<xsl:apply-templates select="//projectInfo"/>
</L_DATA>
</asx:values>
</asx:abap>
</xsl:template>
<xsl:template match="projectInfo">
<conceptRevDecisionXml>
<PROJECTID>
<xsl:value-of select="projectId"/>
</PROJECTID>
<STAGE>
<xsl:value-of select="stage"/>
</STAGE>
<COUNTRY>
<xsl:value-of select="country"/>
</COUNTRY>
<REGION>
<xsl:value-of select="region"/>
</REGION>
<TEAMLEADER>
<xsl:value-of select="teamleader"/>
</TEAMLEADER>
<TEAMLEADERFIRSTNAME>
<xsl:value-of select="teamleaderfirstname"/>
</TEAMLEADERFIRSTNAME>
<TEAMLEADERLASTNAME>
<xsl:value-of select="teamleaderlastname"/>
</TEAMLEADERLASTNAME>
<ACTIONTYPE>
<xsl:value-of select="actionType"/>
</ACTIONTYPE>
</conceptRevDecisionXml>
</xsl:template>
</xsl:transform>
3) Call the transformation as shown below,
CALL TRANSFORMATION zxslt_project ---> "Name of the XSLT prog created above
SOURCE XML l_xml_str                           ---> Source XML string
RESULT l_data = l_data.                          ---> ITAB as in step 1 above
Regards,
Chen

Error when applying a XSLT transformation: No valid XSLT pro

Dear All,
I am getting following error when opening the "General Supplier Data" from Pre-Select Supplier.
Error Message: "Error message: Error when applying a XSLT transformation: No valid XSLT program supplied"
I have already read the related threads on SDN and checked the SAP Note 883896 and others. Even tried running the program UXS_DEL_NAVIGATION_NODE and UXS_ADD_MISSING_XSLT_NAME. But not able to solve the issue.
Kindly Help.
Regards,
Sagar

Hi Masa,
Thanks for reply. I have checked this note. As note suggests, S_DEVELOP auth object is assigned to the user. and it has value *.
Do I need to check anything else?
Regards,
Sagar

Error when applying a XSLT transformation

central instance
transaction SURVEY
Extras->Target Group Hierarchy-> Import from file
select file
Error when applying a XSLT transformation
dialog instance working

Hello Andrey Kuryanov,
Could make sure you describe the problem more clear as much as you can so that community can help you better.
Please provide more details with more detailed steps and actual error messge.
Thanks
Raja Pamireddy
Moderator

UTF-8 encoding in XSLT transformation

Hello,
I have a problem with a transformation of an ABAP structure into XML. I use the XSLT transformation for this.
My XSLT starts like this:
<xsl:transform xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:strip-space elements="*"/>
<asx:abap xmlns:asx="http://www.sap.com/abapxml" version="1.0">
    <asx:values>
I tried many settings I could find posted on the internet, but I did not find one that would allow encoding to UTF-8.
It always encodes to iso-8859-1 which my interface partner cannot read.
Does anyone know a way to force encoding to UTF-8?
Adding a command like <xsl:output encoding="utf-8"/> did not help.
Thanks a lot!
       J. Euler

Hello!
I think I just solved the problem taking a different approach.
In a note here on SDN, a guy from SAP wrote, that the SAP XSLT processor is not able to code anything but the system's default to a string, BUT that it is able to code it to an xstring.
All I did now is add the tag
<xsl:output encoding="utf-8" indent="yes" method="xml"/>
to my xslt program and change the coding in the program accordingly.
The program code is now:
DATA: tempxstring TYPE xstring,
        temp_length TYPE i,
        conv      TYPE REF TO cl_abap_conv_in_ce.
CLEAR tempxstring.
TRY.
      CALL TRANSFORMATION
          zxxje_tst_xslt
        SOURCE omsregdatawebservice = wa_data
        RESULT XML tempxstring.
    CATCH cx_sy_conversion_base64.
    CATCH cx_sy_conv_illegal_date_time.
ENDTRY.
IF tempxstring IS NOT INITIAL.
    CLEAR: conv, temp_length, string_xml_result.
    conv = cl_abap_conv_in_ce=>create( input = tempxstring ).
    conv->read( IMPORTING data = string_xml_result len = temp_length ).
ENDIF.
Thanks anyways for all your help!
regards,
      Johannes Euler

XSLT transformation in XML to ABAP: special characters issue

Hi,
I am parsing well-formed XML file that has the following data (:
<projects><project><name>Wallis & Futuna</name></project></projects>
I use XSLT transformation:
<xsl:transform xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:sap="http://www.sap.com/sapxsl" version="1.0">
<xsl:strip-space elements="*"/>
<xsl:template match="projects">
    <asx:abap xmlns:asx="http://www.sap.com/abapxml" version="1.0">
        <PROJECTS>
          <xsl:for-each select="project">
            <PROJECT>
              <NAME>
                <xsl:value-of select="name"/>
              </NAME>
            </PROJECT>
          </xsl:for-each>
        </PROJECTS>
      </asx:values>
    </asx:abap>
</xsl:template>
</xsl:transform>
If I use the above example without &amp; everything works fine, but the original XML fails with exception CX_XSLT_DESERIALIZATION_ERROR and message "Error during deserialization". Googling around did not give an answer.
Any words of wisdom?
Edited by: Alexei Isaev on Apr 26, 2011 5:04 AM
Edited by: Alexei Isaev on Apr 26, 2011 5:05 AM

Hi,
Please visit the following link for reference.
http://help.sap.com/abapdocu_70/en/ABAPCALL_TRANSFORMATION.htm
Thanks & Regards,
Harish

XSLT Transformation problem

Hi,
hope anybody can help.
I try to transform a object to another object via XSLT transformation.
Here is my coding :
DATA: wa_transformation TYPE y0dpl_structures.
DATA: obj_import TYPE abap_trans_srcbind_tab,
        wa_import TYPE abap_trans_srcbind.
DATA: obj_export TYPE abap_trans_resbind_tab,
        wa_export TYPE abap_trans_resbind.
DATA: obj_data TYPE REF TO data.
* Get transformation data
SELECT SINGLE *
INTO wa_transformation
FROM y0dpl_structures
WHERE filetype = i_file_type.
* Create table with internal structure
CREATE DATA e_data TYPE (wa_transformation-structure_name).
wa_import-name = 'IMPORT'.
GET REFERENCE OF i_data INTO wa_import-value.
APPEND wa_import TO obj_import.
* Call transformation
CALL TRANSFORMATION (wa_transformation-transformation)
SOURCE (obj_import)
RESULT (obj_export).
i_data is a import parameter from type "ref to data".
My problem is, that "Call transformation" makes a shortdump when calling them.
Regards,
Anton

Found a solution for my problem. Now it works!
DATA: wa_transformation TYPE y0dpl_structures.
DATA: obj_import TYPE abap_trans_srcbind_tab,
        wa_import TYPE abap_trans_srcbind.
DATA: obj_data TYPE REF TO data.
DATA: wa_return TYPE bapiret2.
FIELD-SYMBOLS: <data> TYPE ANY TABLE.
* Get transformation data
SELECT SINGLE *
INTO wa_transformation
FROM y0dpl_structures
WHERE filetype = i_file_type.
IF sy-subrc IS INITIAL.
* Create table with internal structure
    CREATE DATA e_data TYPE STANDARD TABLE OF (wa_transformation-structure_name).
    ASSIGN i_data->* TO <data>.
    wa_import-name = 'IMPORT'.
    GET REFERENCE OF <data> INTO wa_import-value.
    APPEND wa_import TO obj_import.
* Call transformation
    CALL TRANSFORMATION (wa_transformation-transformation)
    SOURCE (obj_import)
    RESULT export_data = e_data.
ELSE.
    MOVE: 'Y0_DPL' TO wa_return-id,
           'E'      TO wa_return-type,
           '108'    TO wa_return-number.
    APPEND wa_return TO e_return.
    CLEAR: wa_return.
ENDIF.

BI Admin Tool and XSLT transformation for XML data source - How it works ?

Hello,
There is a possibility to import data from XML data source using BI Admin Tool.
In the import window we can point XSLT file. What is the purpose of that XSLT field?
Why I am asking ?
I thought it is smth like XSLT processor, but simply it doesnt work.
What I did:
- I pointed XML data source file
- I pointed XSLT transformation file
- Click OK, and still get the message that the XML file structure is not supported
After that I transformed that XML file with some desktop XSLT processor using the same XSLT file, and I tried to connect that file directly using BI Admin tool.Then it works. So it means that the transformation is ok.
So basically one question comes to my mind in that situation:
What is the purpose of XSLT field in BI Admin Tool when it comes to XML data source ?
(it doesnt look like XSLT processor)
Greetings
/Michal

Hi Mariano
Why you need to use XSLT for transforming XML file into ABAP table
Code is a part of some ABAP report. Looks like it is reading a file from file system and updating table after transformation
If you have requirement like you need to read XML file and then insert the data into a SAP table
You can use
File to RFC
File to Proxy scenario using SAP PI.
Please provide more inputs on requirement to help
Thanks
Gaurav

XSLT transformation for XML to ABAP internal table

Hi, can anyone please tell me how it should be the xslt tranformation to conver this xml
<Embargos_ARBA_DOC>
     <ns:Embargos_ARBA_MT
          xmlns:ns="un:swissmedical:sap:proxy:embargos_arba:file">
          <Embargos_ARBA_MT>
               <FECHA>20081101</FECHA>
               <CUIT>50000002124</CUIT>
               <MONTO>0000013794090</MONTO>
               <RAZON_SOCIAL>RAUL ARMANDO CUNQUEIRO S.A.C.I.</RAZON_SOCIAL>
          </Embargos_ARBA_MT>
          <Embargos_ARBA_MT>
               <FECHA>20081101</FECHA>
               <CUIT>55000001456</CUIT>
               <MONTO>0000001144410</MONTO>
               <RAZON_SOCIAL>PARODI ESTEBAN ARMANDO</RAZON_SOCIAL>
          </Embargos_ARBA_MT>
     </ns:Embargos_ARBA_MT>
</Embargos_ARBA_DOC>
to this abap Table....
DATA: BEGIN OF i_embargos_arba_doc occurs 0,
          fecha TYPE d,
          cuit TYPE char11,
          monto TYPE char13,
          razon_social(120),
        END OF i_embargos_arba_mt.
so i can transform it with this sentence
      CALL TRANSFORMATION ('embargos_transformation')
        SOURCE XML source
        RESULT Embargos_ARBA_DOC = embargos.
pls i need help because i am unable to create this xslt transformation...
I will give the highest rewards points to the one who can help me.
thanks!
mariano

Hi Mariano
Why you need to use XSLT for transforming XML file into ABAP table
Code is a part of some ABAP report. Looks like it is reading a file from file system and updating table after transformation
If you have requirement like you need to read XML file and then insert the data into a SAP table
You can use
File to RFC
File to Proxy scenario using SAP PI.
Please provide more inputs on requirement to help
Thanks
Gaurav

XSLT Transformation

Hi,
I am trying to upload one xml file and filling an internal table with the content and a XSLT transformation. After uploading the file and make the first transformation i obtein one string with all the fields without tags and separated by #. so when i try to call transformation for filling the internal table i obtein the exception cx_xslt_exception with the message 'No valid source context supplied'.
I would like to know if i am having poroblems with unicode characters. Is there any example made in sap that i can test or does anybody have had any similar problem?.
My string
<?xml version="1.0" encoding="utf-16"?>#######S####L####08##2######
Thanks in advance
regards

Hi Verma,
You're not transforming anything from your input to the output shown. You're actually constructing a new Output. I don't see anything being transformed from input to output.
Anyway, if you need a XSLT to be used to get the above Output in map, following XSLT shall help you:
<?xml version="1.0" encoding="UTF-16"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:msxsl="urn:schemas-microsoft-com:xslt" xmlns:var="http://schemas.microsoft.com/BizTalk/2003/var" exclude-result-prefixes="msxsl var s0" version="1.0" xmlns:s0="http://xmlns.service/1" xmlns:ns1="http://xmlns.types/1.0" xmlns:ns0="http://xmlns.OutService/2">
<xsl:output omit-xml-declaration="yes" method="xml" version="1.0" />
<xsl:template match="/">
<xsl:apply-templates select="/s0:Request" />
</xsl:template>
<xsl:template match="/s0:Request">
<Output xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns="http://xmlns.OutService/2">
<outContext xmlns:ns0="http://xmlns.OutService/2" xsi:type="ns0:ReferenceContext" xmlns="http://xmlns.types/1.0" />
</Output>
</xsl:template>
</xsl:stylesheet>
If this answers your question please mark it accordingly. If this post is helpful, please vote as helpful by clicking the upward arrow mark next to my reply.

XSLT Transformation Question

Hi together!
Hope anybody can help.
I have the follow XML structure :
<asx:abap xmlns:asx="http://www.sap.com/abapxml" version="1.0">¶
<asx:values>¶
<IMPORT>¶
<Y0DPL_LATAM_INV_FILE_UPLOAD>¶
<DATA>222358   1NU    480350    29102007VENDA DE MERCADORIA        30</DATA>¶
</Y0DPL_LATAM_INV_FILE_UPLOAD>¶
<Y0DPL_LATAM_INV_FILE_UPLOAD>¶
<DATA>35403474</DATA>¶
</Y0DPL_LATAM_INV_FILE_UPLOAD>¶
<Y0DPL_LATAM_INV_FILE_UPLOAD>¶
<DATA>35403822</DATA>¶
</Y0DPL_LATAM_INV_FILE_UPLOAD>¶
<Y0DPL_LATAM_INV_FILE_UPLOAD>¶
<DATA>4480350</DATA>¶
</Y0DPL_LATAM_INV_FILE_UPLOAD>¶
<Y0DPL_LATAM_INV_FILE_UPLOAD>¶
<DATA>220089</DATA>¶
</Y0DPL_LATAM_INV_FILE_UPLOAD>¶
<Y0DPL_LATAM_INV_FILE_UPLOAD>¶
<DATA>3540347</DATA>¶
</Y0DPL_LATAM_INV_FILE_UPLOAD>¶
<Y0DPL_LATAM_INV_FILE_UPLOAD>¶
<DATA>4480351 </DATA>¶
</Y0DPL_LATAM_INV_FILE_UPLOAD>¶
</IMPORT>¶
</asx:values>¶
</asx:abap>
After the XSLT Transformation i need the data in this structure :
<data>
     <invoice>
           <id>222358</id>
           <item>35403474</item>
           <item>35403822</item>
           <code>4480350</code>
     </invoice>
     <invoice>
           <id>220089</id>
           <item>35403474</item>
           <code>4480351</code>
     </invoice>
</data>
I tried to group the data with the tag "xsl:for-each-group". But i get no result.
Regards,
Anton

Hi,
no one with a good hint?
Regards,
Anton

XSLT transformation for deep structure .....

Hello,
I am trying to do an XSLT transformation for a deep structure HAP_S_PDF_DOCUMENT (see it in SE11), I have managed to achieve this. but not with perfection. i still get some redundant data and data have been experiencing Data duplication. I was hoping if you people point out the what is wrong in the transfromation. The data repeats for every once under node DATA and then under node of the refered structure name. Besides it also create a blank row even if the record is 0. I am mostly facing problem with nodes T_ELEMENTS. T_COL_CELL and T_FIELD. These are the nested structures, Can anybody help / guide me to achieve these transforamtion?
<xsl:transform xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:sap="http://www.sap.com/sapxsl" version="1.0">
<xsl:strip-space elements="*"/>
<xsl:template match="HAP_DOCUMENT">
<xsl:element name="HAP_DOCUMENT" namespace="">
<xsl:apply-templates select="MAIN_HEADER"/>
<xsl:apply-templates select="T_ELEMENTS"/>
<xsl:apply-templates select="T_STAT_CHG_BUTTONS"/>
<xsl:apply-templates select="S_APPRAISAL_ID"/>
<xsl:apply-templates select="S_HEADER"/>
<xsl:apply-templates select="POSITIONS"/>
<xsl:element name="STAT_CHG_BUTTON">
<xsl:value-of select="../STAT_CHG_BUTTON"/>
</xsl:element>
<xsl:element name="OFFLINE_ID">
<xsl:value-of select="OFFLINE_ID"/>
</xsl:element>
<xsl:element name="BSP_FLAG">
<xsl:value-of select="BSP_FLAG"/>
</xsl:element>
<xsl:element name="ROLE">
<xsl:value-of select="ROLE"/>
</xsl:element>
<xsl:element name="APPRAISAL_YEAR">
<xsl:value-of select="APPRAISAL_YEAR"/>
</xsl:element>
</xsl:element>
</xsl:template>
<xsl:template match="MAIN_HEADER">
<xsl:element name="MAIN_HEADER">
<xsl:for-each select="ZBGAPR_FORM_HEADER">
<xsl:element name="DATA">
<xsl:copy-of select="child::node()"/>
</xsl:element>
</xsl:for-each>
</xsl:element>
</xsl:template>
<xsl:template match="T_ELEMENTS">
<xsl:element name="T_ELEMENTS">
<xsl:for-each select="ZHAP_S_PDF_ELEMENTS">
<xsl:element name="DATA">
<xsl:apply-templates select="T_COL_CELL"/>
<xsl:copy-of select="child::node()"/>
</xsl:element>
</xsl:for-each>
</xsl:element>
</xsl:template>
<xsl:template match="T_COL_CELL">
<xsl:element name="T_COL_CELL">
<xsl:for-each select="ZHAP_S_PDF_COL_CELL">
<xsl:element name="DATA">
<xsl:apply-templates select="T_FIELD"/>
<xsl:copy-of select="child::node()"/>
</xsl:element>
</xsl:for-each>
</xsl:element>
</xsl:template>
<xsl:template match="T_FIELD">
<xsl:element name="T_FIELD">
<xsl:for-each select="ZHAP_S_PDF_FIELD">
<xsl:element name="DATA">
<xsl:apply-templates select="T_VAL_VALUES"/>
<xsl:apply-templates select="T_VAL_RANGES"/>
<xsl:copy-of select="child::node()"/>
</xsl:element>
</xsl:for-each>
</xsl:element>
</xsl:template>
<xsl:template match="T_VAL_VALUES">
<xsl:element name="T_VAL_VALUES">
<xsl:for-each select="HAP_S_BODY_CELL_VAL_VALUES">
<xsl:element name="DATA">
<xsl:copy-of select="child::node()"/>
</xsl:element>
</xsl:for-each>
</xsl:element>
</xsl:template>
<xsl:template match="T_VAL_RANGES">
<xsl:element name="T_VAL_RANGES">
<xsl:for-each select="HAP_S_BODY_CELL_VAL_RANGES">
<xsl:element name="DATA">
<xsl:copy-of select="child::node()"/>
</xsl:element>
</xsl:for-each>
</xsl:element>
</xsl:template>
<xsl:template match="T_STAT_CHG_BUTTONS">
<xsl:element name="T_STAT_CHG_BUTTONS">
<xsl:for-each select="HAP_S_BODY_CELL_VAL_RANGES">
<xsl:element name="DATA">
<xsl:copy-of select="child::node()"/>
</xsl:element>
</xsl:for-each>
</xsl:element>
</xsl:template>
<xsl:template match="S_APPRAISAL_ID">
<xsl:element name="S_APPRAISAL_ID">
<xsl:copy-of select="node()"/>
</xsl:element>
</xsl:template>
<xsl:template match="S_HEADER">
<xsl:element name="S_HEADER">
<xsl:apply-templates select="S_TEXTS"/>
<xsl:apply-templates select="T_APPRAISER"/>
<xsl:apply-templates select="T_APPRAISEE"/>
<xsl:apply-templates select="T_PART_APPRAISER"/>
<xsl:apply-templates select="T_OTHERS"/>
<xsl:apply-templates select="S_STATUS"/>
<xsl:apply-templates select="S_DATES"/>
<xsl:apply-templates select="S_DISPLAY"/>
</xsl:element>
</xsl:template>
<xsl:template match="POSITIONS">
<xsl:element name="POSITION">
<xsl:for-each select="ZBGHR_APR_POSITION_DET">
<xsl:element name="DATA">
<xsl:copy-of select="child::node()"/>
</xsl:element>
</xsl:for-each>
</xsl:element>
</xsl:template>
<xsl:template match="S_TEXTS">
<xsl:element name="S_TEXTS">
<xsl:copy-of select="node()"/>
</xsl:element>
</xsl:template>
<xsl:template match="T_APPRAISER">
<xsl:element name="T_APPRAISER">
<xsl:for-each select="HAP_S_PDF_APPRAISER">
<xsl:element name="DATA">
<xsl:copy-of select="child::node()"/>
</xsl:element>
</xsl:for-each>
</xsl:element>
</xsl:template>
<xsl:template match="T_APPRAISEE">
<xsl:element name="T_APPRAISEE">
<xsl:for-each select="HAP_S_PDF_APPRAISEE">
<xsl:element name="DATA">
<xsl:copy-of select="child::node()"/>
</xsl:element>
</xsl:for-each>
</xsl:element>
</xsl:template>
<xsl:template match="T_OTHERS">
<xsl:element name="T_OTHERS">
<xsl:for-each select="HAP_S_PDF_OTHERS">
<xsl:element name="DATA">
<xsl:copy-of select="child::node()"/>
</xsl:element>
</xsl:for-each>
</xsl:element>
</xsl:template>
<xsl:template match="T_PART_APPRAISER">
<xsl:element name="T_PART_APPRAISER">
<xsl:for-each select="HAP_S_PDF_PART_APPRAISERS">
<xsl:element name="DATA">
<xsl:copy-of select="child::node()"/>
</xsl:element>
</xsl:for-each>
</xsl:element>
</xsl:template>
<xsl:template match="T_PART_APPRAISER">
<xsl:element name="T_PART_APPRAISER">
<xsl:for-each select="HAP_S_PDF_PART_APPRAISERS">
<xsl:element name="DATA">
<xsl:copy-of select="child::node()"/>
</xsl:element>
</xsl:for-each>
</xsl:element>
</xsl:template>
<xsl:template match="S_STATUS">
<xsl:element name="S_STATUS">
<xsl:copy-of select="node()"/>
</xsl:element>
</xsl:template>
<xsl:template match="S_DATES">
<xsl:element name="S_DATES">
<xsl:copy-of select="node()"/>
</xsl:element>
</xsl:template>
<xsl:template match="S_DISPLAY">
<xsl:element name="S_DISPLAY">
<xsl:copy-of select="node()"/>
</xsl:element>
</xsl:template>
<xsl:template match="STAT_CHG_BUTTON">
</xsl:template>
<xsl:template match="OFFLINE_ID">
</xsl:template>
<xsl:template match="BSP_FLAG">
</xsl:template>
<xsl:template match="ROLE">
</xsl:template>
<xsl:template match="APPRAISAL_YEAR">
</xsl:template>
</xsl:transform>
Regards,
Shishir.P

"XSLT transformation for a deep structure"
which way abap to xml or xml to abap?
you may want to check this thread
Re: Problem converting XML back to structure using XSLT

XSLT transformation help

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