How do I trim a column up to a certain tag?

Originally posted using Google Groups:
Hi there,
Its been a while since I was around these parts, I hope your
all doing
well.
I have a database column that contains the following:
KELOWNA, BC @ X.10.SION 207 & Cheetah's 1st:
Stickybuds
2nd: DJ Thistle
3rd: All Good
I only want to show all of the this on one particular page,
on another
I just want to show the text up to the tag. I know
about left and
right trims, but you need to know how many characters in the
 tag
is to be able to do that, and it will vary from recordset to
recordset.
Any ideas?
Cheers,
Steve

Hi there,
That was just about what I needed, but ended up displaying
< at the end,
so I changed it to this:
<%=Left((rsDates.Fields.Item("fldDetails").Value),(InStr((rsDates.Fields.Item("fldDetails" ).Value),"<")-1))%>
Which did the job nicely.
I tried to use in a repeated region, where some of the data
doesnt
contain any markup, and experienced this error:
Microsoft VBScript runtime error '800a0005'
Invalid procedure call or argument: 'Left'
/Default.asp, line 129
Any idea what I am doing wrong?
Cheers,
Steve
Lionstone wrote:
> It would be something like:
>
>
Left(yourTextVariable,InStr(yourTextVariable," "))
>
> That will take the leftmost n characters, where n marks
the first character
> of the first " " in your string. If you'd like
(and if you know there
> are no "<" characters outside of your tags), you can
just find the first
> "<", which would work for any tag.
>
> "Dooza" <[email protected]> wrote in message
> news:e27urv$11$[email protected]..
>
>>Originally posted using Google Groups:
>>
>>Hi there,
>>Its been a while since I was around these parts, I
hope your all doing
>>well.
>>
>>I have a database column that contains the following:
>>
>>KELOWNA, BC @ X.10.SION 207 &
Cheetah's 1st: Stickybuds
>>2nd: DJ Thistle
>>3rd: All Good
>>
>>I only want to show all of the this on one particular
page, on another
>>I just want to show the text up to the 
tag. I know about left and
>>right trims, but you need to know how many characters
in the tag
>>is to be able to do that, and it will vary from
recordset to recordset.
>>
>>Any ideas?
>>
>>Cheers,
>>
>>Steve
>
>
>

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Hi Tiano
LabVIEW General
Ask:
Please enter a one-line summary of your question
Resources
• Technical Support
• Development Library
• Measurement Encyclopedia
"data/time reading into chart"
"In the attached file, I am trying to read the first column of data, and the next column is the value on the x-axis I want it plotted at. How do I read two columns of different data? I have looked in the books I have access to and the help within Labview but am still having trouble.
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Ellie"
data_set (Plain Text, 3K)
-posted by Ellie on 9/11/2001
markwysong on 9/11/2001 answered:
"Ellie,
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Mark"
Graph data from file (Binary Executable, 20K)
data.txt (Plain Text, 3K)
This answer has not yet been rated.
Rate this answer:
Mikael Garcia on 9/11/2001 answered:
"Ellie,
Here is one way of doing it. Take a look at this example (compatible with LabVIEW 4.1 and up) and post comments if you need further help. Basically, I read your file as text; split it; and make use of the Spread sheet string to Array function before I plot your data. Hope this helps./ Mikael"
ExtractAndPlot.vi (Binary Executable, 36K)
This answer has not yet been rated.
Rate this answer:
Ellie on 9/12/2001 commented:
"Thank you. I am trying to get the data from the text file into a string and am having some trouble. I am reading the file from a spreadsheet, and sending the output array to "Array to Spreadsheet String", but I'm not sure this is what I want to do. Is there another way to make an array into a string? Do I need to reformat my data?
Can you offer me any advice?
Thank you."
data_1 (Plain Text, 3K)
Mikael Garcia on 9/12/2001 commented:
"I noticed that you changed your file format according to what was said here. Yes, this new file of yours is easier to use but your original file does not have to be changed. Take a look at this example. I now added the file-read part. It will give you a dialog to locate your data file (use this VI with your original file with the header since this VI includes a string split function). Hope this helps. /Mikael"
ReadExtractandPlot.vi (Binary Executable, 35K)
Niko on 9/12/2001 answered:
"If you read this file with the "read from spreadsheet file.vi" you get you
data in a 2-D-array. Now it is easy with array- and cluster-functions to
handle the data the way you want.
hope that helps, Niko"
This answer has not yet been rated.
Rate this answer:
I intend to read from a .txt file that contains a column of numbers. After reading I want to display it as a waveform. In fact the numbers represent points along a waveform/graph of Flow vs. time. Thus I want to have this info in the chart or graph with flow in the y0axis and time in the x-axis. Can someone give me some detailed help please? Thank you in advance.
Attachments:
The_file.txt ‏18 KB

All you have to do is use Read From Spreadsheet File.vi that's on the File I/O palette. For your example .txt, set the Transpose input to true and wire the First Row output to a waveform graph. The only problem I see is that since your file doesn't contain any sampling info, the time axis will be relative. If have that information elsewhere, then you can put a build waveform function between the read and the graph. Wire the First Row output to the Y input Build Waveform and add t0 and dt values. I've attached an example.
Attachments:
Graph_from_text.vi ‏29 KB

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 lr_column_header = lr_column->get_header( ).
 lr_column_header->set_text( lf_string ).
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