How to find out if I navigate out of the page

Question

Dear gurus,
I need to replicate ‘Warn about changes’ functionality in a certain case.
In my case page A displays view object VO1 in a tabular form, each record having a link in column ‘type’ that takes navigation to page B.
On page B the user changes the type to a new value using a pick list and submits a page B, then clicks Apply button that takes him back to page A with the new value for type brought from page B.
Now page A has a new value for type. Not committed yet. I need to show a warning popup message (similar to seeded ‘Warn about changes’ message) if a user navigates out of page A now.
I am thinking about using javascript to show the popup message. I will use the condition whether VO1 is dirty or not. But I don’t know how to track the fact that I navigated out of page A. Does anybody know how to find out is navigation out of the current page did occur?
Thank you
Anatoliy

Answer 1

Hi,
as there are links on the table from where you are navigating...set the fireaction property to fire an event say
"click". grab that event in contoller.
Controller code:
String name = (String)pageContext.getParameter("event");
if("click".equals(event))
this means you are navigating out of page A.
now invoke a method in AM to check if VO is dirty or not and if it dirty then throw an exception on page rather than pop_up.
String check = (String)am.invokeMethod("checkvodirty");
if("dirty".equals(check))
throw new OAException("The Transaction is dirty",OAException.ERROR);
else
navigate to page B using pageContext.setForwardurl().
In AM you can write :
public String checkvodirty()
sapeEAAddressesVOImpl addr = getsapeEAAddressesVO1();
String test = "";
if(addr.isDirty())//this checks that VO is dirty
test = "dirty";
else
test = "notdirty";
return test;
Thanks,
Gaurav