Insert system date and time

Question

Hi,
I'm trying to insert into the table's row the default time in which the data is added. I'm trying to do something like
"INSERT INTO TEST (DATESS) VALUES (to_date(sysdate, 'yyyy/mm/dd:hh:mi:ssam'))"
But this don't work. is there other more efficient way to insert the current time in which I add the new row to the table?
regards

Answer 1

user10484841 wrote:
Ok, but is it possible to insert the sysdate into this format yyyy/mm/dd:hh:mi:ssam?Oracle always stores dates in its own internal format. to_date() is used to tell oracle how to parse a string of characters that we humans recognize as a date. If you just gave it a string of "05-04-09" how would it know what is what? That's what the to_date function is for. Conversly, when retrieving a DATE type you use to_char to tell oracle how you want the internal representation converted to a character string that you can use. Try the following:
select sysdate from dual;
select to_char(sysdate,'dd-mm-yy') from dual;
select to_char(sysdate,'mon-yyyy') from dual;
select to_char(sysdate,'dd-mon-yy') from dual;
select to_char(sysdate,'dd-Mon-yy hh:24:mi:ss') from dual;
alter session set nls_date_format='dd-mm-yy';
select sysdate from dual;
alter session set nls_date_format='mon-yyyy';
select sysdate from dual;
alter session set nls_date_format='dd-mon-yy';
select sysdate from dual;
alter session set nls_date_format='dd-Mon-yy hh24:mi:ss';
select sysdate from dual;