Regex - Pattern for positive numbers

Hi,
I wanna check for positive numbers.
My code so far:
Pattern p = Pattern.compile("\\d+");
Matcher m = p.matcher(str);
boolean b = m.matches(); But I don't know how to check for positive numbers (including 0).
Thanks
Jonny

Just to make your life easier:
package samples;
import java.util.regex.Matcher;
import java.util.regex.Pattern;
* @author notivago
public class Positive {
 public static void main(String[] args) {
 String input = "- 12 +10 10 -12 15 -12,000 10,000 5,000.42";
 Pattern p = Pattern.compile( "\\b(?<!-\\s?|\\.|,)([0-9]+(?:,?[0-9]{3})*(?:\\.[0-9]*)?)" );
 Matcher matcher = p.matcher( input );
 while( matcher.find() ) {
 System.out.println( "Match: " + matcher.group(1) );
}

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Regex Pattern For this String ":=)"

Hello All
True, this isn't the place to ask this but here it is anyway, if you can help please do.
Can anybody tell me the regex pattern for this String:
":=)"
Thanks
John

Yep, cheers it's ":=\\)"
public class Test {
 public static void main( String args[] ) {
 String s = "one:=)two:=)three:=)four";
 String ss[] = s.split( ":=\\)" );
 for( int i=0; i<ss.length; i++ )
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}resulting in:
ss[0] = {one}
ss[1] = {two}
ss[2] = {three}
ss[3] = {four}

What's the regex pattern for regular English chars and numbers ...

In Java String there is a matches(String regex) method, how can I specify the regex for regular English chars, I want it to tell me if the string contains non-English chars. The string is from an email, my application wants to know if the email contains any foreign characters, such as French, Spanish, Chinese ...
So if the string looks like this : "Hi Frank, today is (5-7-2007), my address is : '[email protected]', email me ~ ! ^_^, do you know 1+2=3 ? AT&T, 200%, *[$300] | {#123}, / _ \;"
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since french, english, and spanish use thesame
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Creating a regex.Pattern for bulletin board tags

I'm making a BB code system and have a problem making my patterns do as I like. At least when they are nested.
For example, I'm using the this pattern:
\\[b\\](.*?)\\[/b\\]And I'm replacing it with this:
{0}If I apply this to the text:
This is my text with bold words. Sometimes the tags [b]are nested[/b].It will turn into this (with a little cleaning.):
This is my text with bold words. Sometimes they are nested.But what I really wanted, was this (with a little cleaning.):
This is my text with bold words. Sometimes they are nested.I've tried a lot of different things, but always seems to run into a dead end. I'm hoping it's simply because I do not know enough about patterns, but I could really need some inspiration or guidance. Seems I'm running out of new things to try.
Edited by: bsindu on Dec 5, 2007 1:44 AM

It could be done using some replaceAll(...) operations:
public class Foo {
 public static void main(String[] args) throws Exception {
 String text = "This is my text with bold words. Sometimes the tags [b]are nested[/b].";
 String s = text.
 replaceAll("(\\[.\\][^\\[]+)\\[.\\]", "$1"). // replace the last tag of two successive 's
replaceAll("\\[.\\]([^\\[]+\\[.\\])", "$1"). // replace the first tag of two successive 's
 replaceAll("\\[(/?.)\\]", "<$1>"); // replace all and with and 
 System.out.println(text);
 System.out.println(s);
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Need help verifying positive numbers

I have a payroll program I've been working on for class the last few weeks. The most recent modification is that I need to confirm the hours and pay scale are entered in positive numbers. I've tried a while and an if...else statement and am getting an error telling me that I have an "illegal start" to the expression, and that the way I've written the statement is incompatible with boolean. Here is the code - I've colored the if...else statements red. The else statements don't give me an error, but the if statements do. (BTW, I've had the same problem trying to use a while statement.)
I'm pretty sure it has something to do with how I've written the if statement, but I can't put my finger on it. Can someone help?
Thanks,
import java.util.Scanner; // program uses Scanner
public class WeeklyPayrollTest
 public static void main(String args[])
 // create scanner to obtain input from command window
 Scanner input = new Scanner( System.in );
 // declare variables
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 exitPayroll = "N";
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 double payRate = 0;
 // create a WeeklyPayroll object and assign it to currentPayroll
 WeeklyPayroll currentPayroll = new WeeklyPayroll();
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 System.out.println( "Please enter employee name: " );
 String nameOfEmployee = input.next(); // read user input
 // prompt for and input hours worked
 System.out.println( "Enter hours worked: ");
{color:#ff0000} if( input.nextDouble( <= 0 ) ) // compare input for positive numbers
 System.out.println( "Only positive numbers are allowed. " +
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{color}
 System.out.println( "Would you like to exit this program? " +
 "Enter Y for yes and N for no." );
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 } // end while loop
 System.out.println( "Thank you for using this payroll program." );
 } // end main
} // end class WeeklyPayrollTest

if( input.nextDouble( ) <= 0) // compare input for positive numbers
 System.out.println( "Only positive numbers are allowed. " +
 "Please enter a correct number." ); // alert user positive numbers needed
 numberHours = input.nextDouble(); // prompt for hours
}This will through away the result. Try this
numberHours = input.nextDouble;
while ( input.nextDouble( ) <= 0) // compare input for positive numbers
 System.out.println( "Only positive numbers are allowed. " +
 "Please enter a correct number." ); // alert user positive numbers needed
 numberHours = input.nextDouble(); // prompt for hours
}

Parentheses for negative numbers in Excel 2011

I couldn't find an appropriate section for this question. Please forgive me if I posted it in the wrong place.
I've been using Excel for Mac 2011 since it came out. Up until I updated to Yosemite, formatting negative numbers with parentheses appeared in the drop down menu, i.e., right click to get format cells, click "number" tab on top, click "number" on left. There is a dialog as to how you want negative numbers formatted. Parentheses used to be an option but no more. I attached a screen shot. Help!

Same issue here with Excel 2011, problem started with the Yosemite installation and was not fixed with 10.10.1 nor the latest Microsoft update.
It's a big problem for accountants!
On the Microsoft forum this gentleman replied with a workaround but it's a hassle to have to do this for each new spreadsheet.
JonathanBuhacoff replied on November 9, 2014
If you go to the dialog shown in Phillip's post and select "Custom" on the left side, you can enter this to get the parenthesis back:
$#,##0;[Red](-$#,##0)
Or this to use square brackets:
$#,##0;[Red]"["-$#,##0"]"
The format means use $#,##0 for positive numbers and use [-$#,##0] in red for negative numbers.
You could remove the hyphen too and just do this:
$#,##0;[Red]"["$#,##0"]"
I hope Apple takes note and pushes a fix for us.

Searching Site Content Using REGEX Patterns

Intent: Detect content in SharePoint 2013 lists and libraries that matches a REGEX pattern, like social security numbers.
SharePoint 2013 only exposes KQL and FQL languages.
http://msdn.microsoft.com/en-us/library/office/jj163973.aspx
I am comfortable writing this as an App. I do not know how to pass the search index through a REGEX match. Perhaps there is a way to access the data on more of a server model instead of through the client APIs?

Hi Eric,
For achieving your demand, you can write a Content Enrichment Web Service to extract regex patterns from a managed property.
Here is a blog you can refer to:
SharePoint 2013 Content Enrichment: Regular Expression Data Extraction:
http://blogs.technet.com/b/peter_dempsey/archive/2013/12/04/sharepoint-2013-content-enrichment-regular-expression-data-extraction.aspx
Reference:
http://msdn.microsoft.com/en-us/library/office/jj163982.aspx
http://blogs.msdn.com/b/richard_dizeregas_blog/archive/2013/06/19/advanced-content-enrichment-in-sharepoint-2013-search.aspx
Thanks,
Eric
Forum Support
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How to use multiple patterns for masking/format the input text

Hi All,
I am using Jdeveloper 11.1.1.5 and i have a requirement where i need to format my input Text value in these below patterns:-
Format
Example
AA9A 9AA
EC1A 1BB
A9A 9AA
W1A 1HQ
A9 9AA
M1 1AA
B33 8TH
A99 9AA
AA9 9AA
CR2 6XH
DN55 1PT
AA99 9AA
For Example :- If user puts value as EC1A1BB, it should automatically changed to EC1A 1BB
if user puts value as W1A1HQ, it should be automatically changed to W1A 1HQ and so on..
If it could have been one format , i might have followed this :- https://blogs.oracle.com/jdevotnharvest/entry/get_social_security_numbers_right
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Regards,
Shah

For the validation you should be able to use one regular expression where you add the logical or (|) (check the doc http://docs.oracle.com/javase/6/docs/api/java/util/regex/Pattern.html) between the groups. If none of the patterns matches you have an error.
For the for formatting I'm not sure you can use only one expression.
I suggest to write one method which does the checking on and the formatting may be using an array of patterns to check and iterate the patterns in a loop. Once you found a match you can read the needed format from another array (or an other dimension if you prefer to use a multidimensional array).
Timo

Keep Original Position Numbers in Purchase Order Creation

Hi community, i'm trying to solve the following problem in purchase order creation using BAPI_PO_CREATE1:
I'm loading a file with several order numbers and positions to be created in R/3. This file has a structure similar to:
OrderNumber;PositionNumber;Material;Quantity;Unit;.......
The purchase order is created successfully, but i need to keep original position numbers in the order. i.e:
Supposing this input file:
1900;08;993322;10.00;KG.....
1900;13;994455;12.00;KG.....
the positions in purchase order are created as
00010
00020
But i need positions to be created as:
00008
00013
Any ideas?????
Thanks you for your cooperation
Leonardo

Hi Leonardo,
I doubt if that is possible.
You can have the configuration set up to set the Item Number Interval to step size like 5,10,15 etc,
based on this value, your line item number will be
5,10,15,20...
10,20,30,40..
15,30,45,60
etc.
to set this value, you should go to SPRO.
Material Management->Purchase Order->Define Document Types
Regards,
Ravi Kanth Talagana

Patterns for charts

I need to print a chart out in black & white and would like to use different patterns for the bars instead of colors. Does anyone know how to make the bars appear as different patterns instead of color?

Numbers doesn't come with hashed patterns for black & white charts. You can make your own. Below are two patterns. You can flip the diagonal one to create a third. The difficult part in making one of these patterns is designing it to make a continuous pattern when attached side by side.
Use the Graphic Inspector to change the bar color to a tiled image fill and put a solid line around the bars.
/___sbsstatic___/migration-images/migration-img-not-avail.png
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Regex pattern, filter delimiter in sql code

Hi,
The problem I'm having is that the regex pattern below is not catching the beginning "go" and ending "go" of a string.
"(?iu)[(?<=\\s)]\\bgo\\b(?=\\s)"
The idea is catching the "whole word", in this case the word is "go" so if the word is at the beginning of the string or at the end, i still want to include it.
So, for example:
"go select * from table1 go" -> should catch 2 "go"s but catches 0
"go go# select * from table1 --go go" -> should also catch 2 "go"s but catches 0
"go go select * from table1 go go" -> should catch 4 "go"s but catches 2
I have the "[(?<=\\s)]" and the "(?=\\s)" so that the word "go" when next to a special character is not included, for example "--go".
The problem is that this also negates the beginning and ending of the string.
Code to test example: It should split at 1st, 2nd and last "go", but only splits at the 2nd "go".
String s = "go go select * from table1 --go go";
String delimiter = "go";
String[] queries = s.split("(?iu)[(?<=\\s)]\\b" + delimiter + "\\b(?=\\s)");
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System.out.println(queries[i]);
I really need to fix this but I'm not having much success.
Any help will be appreciated, thanks in advance.

Yes,
I prefer this one: Regex Powertoy (interactive regular expressions)
It's not 100% perfect, but you can see with my example and this online tester that the 1st "go" is not matched. And this is a problem for me.
I want to eliminate the special characters like "#go" or "-go" but i don't want to eliminate the end and start of string.

Java Regex Pattern

Hello,
I have parsed a text file and want to use a java regex pattern to get the status like "warning" and "ok" ("ok" should follow the "warning" then need to parser it ), does anyone have idea? How to find ok that follows the warning status? thanks in advance!
text example
121; test test; test0; ok; test test
121; test test; test0; ok; test test
123; test test; test1; warning; test test
124; test test; test1; ok; test test
125; test test; test2; warning; test test
126; test test; test3; warning; test test
127; test test; test4; warning; test test
128; test test; test2; ok; test test
129; test test; test3; ok; test testjava code:
String flag= "warning";
 while ((line= bs.readLine()) != null) {
 String[] tokens = line.split(";");
 for(int i=1; i<tokens.length; i++){
 Pattern pattern = Pattern.compile(flag);
 Matcher matcher = pattern.matcher(tokens);
 if(matcher.matches()){
// save into a list

sorry, I try to expain it in more details. I want to parse this text file and save the status like "warning" and "ok" into a list. The question is I only need the "ok" that follow the "warning", that means if "test1 warning" then looking for "test1 ok".
121; content; test0; ok; 12444 <-- that i don't want to have
123; content; test1; warning; 126767
124; content; test1; ok; 1265 <-- that i need to have
121; content; test9; ok; 12444 <-- that i don't want to have
125; content; test2; warning; 2376
126; content; test3; warning; 78787
128; content; test2; ok; 877666 <-- that i need to have
129; content; test3; ok; 877666 <-- that i need to have
// here maybe a regex pattern could be deal with my problem
// if "warning|ok" then list all element with the status "warning and ok"
String flag= "warning";
 while ((line= bs.readLine()) != null) {
 String[] tokens = line.split(";");
 for(int i=1; i<tokens.length; i++){
 Pattern pattern = Pattern.compile(flag);
 Matcher matcher = pattern.matcher(tokens);
 if(matcher.matches()){
// save into a list

Util.regex.Pattern documentation

The 1.5 documentation for util.regex.Pattern defines quantifiers that are greedy, reluctant, or possessive. The definitions of these quantifiers seem to be the same. For example, X?, X??, and X?+ are each defined as "X, once or not at all." Is this a mistake? If not, what's that difference among greedy, reluctant, and possessive?

It's not a mistake, it's just incomplete. A normal (greedy) quantifier matches as many times as it can, but will back off if necessary to achieve an overall match. A reluctant quantifier matches the minimum number of times that it has to, and only tries to match more if that's the only way to achieve an overall match. A greedy quantifier matches as many times as it can and never backs off, even if that makes an overall match impossible. Here's a demonstration:import java.util.regex.*;
public class Test
public static void main(String[] args)
    String input = "XXXXX";
    Pattern p1 = Pattern.compile("(X+)(X+)");
    Pattern p2 = Pattern.compile("(X+?)(X+)");
    Pattern p3 = Pattern.compile("(X++)(X+)");
    Matcher m = p1.matcher(input);
    if (m.matches())
       System.out.println("p1:\t" + m.group(1) + "\t" + m.group(2));
    m = p2.matcher(input);
    if (m.matches())
       System.out.println("p2:\t" + m.group(1) + "\t" + m.group(2));
    m = p3.matcher(input);
    if (m.matches())
       System.out.println("p3:\t" + m.group(1) + "\t" + m.group(2));
p1:     XXXX    X
p2:     X       XXXXIn p1, the X+ in the first group initially matches all five X's, then hands off to the second group. The X+ there has to match at least one X, but there are none left. So the first group gives up one of its X's, the second group matches it, and Bob's your uncle.
In p2, the X+? has to match at least one X, so it does, then hands off to the second group, which happily gobbles up the rest of the input.
In p3, the X++ matches all the X's, but refuses to back off and give the X+ in the second group the one X it needs, so the match fails.

Applying REGEX-pattern into XML File

I have the following problem:
I have an xml-file. let's say...
<NODE><NODE1 attr1="a1" attr2="a2">
 <NAME> abc</NAME>
 <VERSION> 1.0</VERSION>
</NODE1>
<NODE2 attr1="a3" attr2="a4">
 <NAME> xyz</NAME>
 <VERSION> 3.1</VERSION>
</NODE2></NODE>I need to know "HOW can I get the values of <NAME></NAME> and <VERSION></VERSION> without using DOM.
Since my xml-file is pretty big and DOM will take much Memory, i want to avoid it.
Can anybody suggest some "Regex pattern" so that i can apply it on the xml-file (after converting into String)
Thanks in Advance

That worked perfectly. I assumed ( insert comment here ) that the members of the Properties objects were Strings, and therefore followed the same rules where "\" characters are concerned.
Thank you for pointing out the difference between the two objects, I am not sure how long it would have taken me to figure that out.
Regards,
John Gooch

RegEx Error for Huge File .. Please help , Its Urgent

Hi all,
I am getting following exception,
does anyone know about it
java.lang.IndexOutOfBoundsException: No group 1
at java.util.regex.Matcher.group(Matcher.java:355)
at java.util.regex.Matcher.appendReplacement(Matcher.java:585)
at java.util.regex.Matcher.replaceFirst(Matcher.java:701)
at XSLT_OnlyJava.<init>(XSLT_OnlyJava.java:84)
at XSLT_OnlyJava.main(XSLT_OnlyJava.java:93)
Exception in thread "main"
I am parsing huge file with regex and replacing some part
Thanks,
Vinayak

sorry for late
This is my code
text = contents.toString();
 String regex = "<tu.*?/tu>";
 Matcher matcher = Pattern.compile(regex,Pattern.CASE_INSENSITIVE|Pattern.DOTALL).matcher(text);
 while(matcher.find()){
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 String segRegex = "<seg>.*?</seg>";
 Matcher segMatcher = Pattern.compile(segRegex,Pattern.CASE_INSENSITIVE|Pattern.DOTALL).matcher(tuvSegment);
 if(segMatcher.find()){
 SegVal = segMatcher.group();
 String ReplsegRegex = "<seg />";
 Matcher ReplsegMatcher = Pattern.compile(ReplsegRegex,Pattern.CASE_INSENSITIVE|Pattern.DOTALL).matcher(tuvSegment);
 text = ReplsegMatcher.replaceFirst(SegVal);
The text string contains teh .tmx file
Thanks,
Vinayak

Regex - Pattern for positive numbers

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