404 Error when running a servlet!

Question

hello everyone
I have written a simple servlet that prints hello world.
I have saved it in : c:\program fles\apache tomcat 4.0\webapps\myapps\ web-inf\classes\oz\TestServlet.java
I call it from the browser : http://zaf:8080/myapps/web-inf/classes/oz/TestServlet and i get the message :
" The requested resource (/myapps/web-inf/classes/oz/TestServlet) is not available "
I tried using WEB-INF instead of web-inf but the problem persists.
Does anyone have any idea how to run it?
Any help on this would be appreciated!
Thanks.

Answer 1

Hi maza3 ,
I would like to clarify few of your points:-
1. You have made a directory oz in classes directory and placed the servlet there.
Why did you place the servlet in oz directory
You should place the servlet in oz directory only if the servlet class is in oz package. For that you have to mention the statement package oz; as the first statement of the servlet class TestServlet. Make the changes and recompile the servlet. After you have compiled it you can access this servlet by entering the following URL :-
http://zaf:8080/myapps/servlet/oz.TestServlet
2. If you want to make the URL smaller, you can make the entry in web.xml file as:-
web.xml is :-
<?xml version="1.0" encoding="ISO-8859-1"?>
<!DOCTYPE web-app
PUBLIC "-//Sun Microsystems, Inc.//DTD Web Application 2.3//EN"
"http://java.sun.com/dtd/web-app_2_3.dtd">;
<web-app>
<servlet>
<servlet-name>test</servlet-name>
<servlet-class>zo.TestServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>test</servlet-name>
<url-pattern>/test</url-pattern>
</servlet-mapping>
</web-app>
Copy this web.xml in WEB-INF directory.
Now you can access the servlet by the following URL
http://zaf:8080/myapps/test
3. There is another approach. Place the TestServlet(if it is not having package io; statement) directory in classes directory. Then you can access it using the following URL
http://zaf:8080/myapps/servlet/TestServlet
Hope this helps