6/7 is 0?

Question

hi.
Am doing a calculation in java.if do 6/7 means the result is 0.since i store the result in double.
After that i perform some calculation using Number Format ,then also same result.
here is my code.
NumberFormat f = NumberFormat.getInstance();
f. setMaximumFractionDigits(2);
String cal2=f.format(6/7);
float cal22=Float.parseFloat(cal2);
System.out.println(cal22);
double db=6/7;
System.out.println(db);Both the above logic giving 0.
Suggest me a thing to do this.
Thanks in advance
regards,
satheeshkannan

Answer 1

duffymo wrote:
Brynjar wrote:
duffymo wrote:
Brynjar wrote:
Unless you cast the numbers to float/double, or add .0, as in 6.0/7.0, the numbers are treated as integers, including the result. Easy to get around, but clumsy nonetheless.Clumsy? Why? Not if you know the difference between integer and floating point numbers.
This is true in any number of languages. It's hardly clumsy, just the nature of integer numbers in computers.
%Maybe just a matter of taste. I'd want automatic float conversion in the OP's case, as he declares the result of the division as a float.Not me. I would be worried about those times when things were going on behind the scenes without me knowing it.
Making one of the arguments a floating point number is an easy thing to do without forcing the compiler to infer anything. Reading minds is asking for trouble.
%That's a good point. While it may feel 'clumsy' to some because it can be inconvenient in the usual case, there's a very good reason why it's this way. I suppose something like this would get picked up as an Xlint warning