A subquery in order by clause

I don't know what's the meaning of a subquery in order by clause.
for example
select * from table_name
order by (select column from table_name where rownum<=1),
I hope someone can tell me the answer

I don't think I can really come up with a situation where it would be any better than other approaches, but it can be used to derive a value which is then used to ORDER the results of the outer query, i.e.
SQL> SELECT a FROM t;
A
A1
B1
2 rows selected.
SQL> SELECT a, seq FROM o;
A SEQ
A1 10
B1 20
2 rows selected.
SQL> SELECT a FROM t
2 ORDER BY ( SELECT seq FROM o WHERE o.a = t.a );
A
A1
B1
2 rows selected.
But, I would still go with a simple join in this situation.
Note, that the subquery can only return one row :
SQL> SELECT * FROM T ORDER BY ( SELECT A FROM T );
SELECT * FROM T ORDER BY ( SELECT A FROM T )
ERROR at line 1:
ORA-01427: single-row subquery returns more than one row

Similar Messages

  • Order by clause in cursor problem

    Hello,
    I'm unable to compile package body when i'm using order by clause in cursor subquery in stored procedure.
    Sample code:
    CREATE PACKAGE Announces AS
    TYPE tRefCur IS REF CURSOR;
    PROCEDURE TopAnnounces(
    iiCount IN NUMBER,
    osAnnounces OUT tRefCur,
    oiRetVal OUT NUMBER
    END Announces;
    CREATE PACKAGE BODY Announces AS
    PROCEDURE TopAnnounces(
    iiCount IN NUMBER,
    osAnnounces OUT NUMBER,
    oiRetVal OUT NUMBER
    AS
    BEGIN
    OPEN osAnnounces FOR
    SELECT Id, Name, AnnCount FROM
    SELECT Id, Name, COUNT(CategoryId) AS AnnCount FROM tblAnnounces
    GROUP BY Id, Name
    -- bellow is the line, where the code crash
    ORDER BY AnnCount DESC
    WHERE ROWNUM < iiCount + 1;
    oiRetVal := 0;
    EXCEPTION
    WHEN OTHERS THEN
    oiRetVal := -255;
    END TopAnnounces;
    END Announces;
    If I compile the code above I will get this error:
    PLS-00103: Encoutered the symbol "ORDER" when expecting on of the following:
    After I remark the problematic line, the compilation is successful (but not the result :).
    Is there something I'm doing wrong?
    Thanks for advice
    Vojtech Novacek
    null

    Sorry you can not use order by clause into one temporal table created by subquery.
    Put the order by clause offside of subquery.
    Atte.
    CC.
    <BLOCKQUOTE><font size="1" face="Verdana, Arial">quote:</font><HR>Originally posted by Vojtech Novacek:
    Hello,
    I'm unable to compile package body when i'm using order by clause in cursor subquery in stored procedure.
    Sample code:
    CREATE PACKAGE Announces AS
    TYPE tRefCur IS REF CURSOR;
    PROCEDURE TopAnnounces(
    iiCount IN NUMBER,
    osAnnounces OUT tRefCur,
    oiRetVal OUT NUMBER
    END Announces;
    CREATE PACKAGE BODY Announces AS
    PROCEDURE TopAnnounces(
    iiCount IN NUMBER,
    osAnnounces OUT NUMBER,
    oiRetVal OUT NUMBER
    AS
    BEGIN
    OPEN osAnnounces FOR
    SELECT Id, Name, AnnCount FROM
    SELECT Id, Name, COUNT(CategoryId) AS AnnCount FROM tblAnnounces
    GROUP BY Id, Name
    -- bellow is the line, where the code crash
    ORDER BY AnnCount DESC
    WHERE ROWNUM < iiCount + 1;
    oiRetVal := 0;
    EXCEPTION
    WHEN OTHERS THEN
    oiRetVal := -255;
    END TopAnnounces;
    END Announces;
    If I compile the code above I will get this error:
    PLS-00103: Encoutered the symbol "ORDER" when expecting on of the following:
    After I remark the problematic line, the compilation is successful (but not the result :).
    Is there something I'm doing wrong?
    Thanks for advice
    Vojtech Novacek<HR></BLOCKQUOTE>
    null

  • Order by clause in Sub query

    Hi,
    Can we use order by clause in Sub query?
    While using the order by clause, I am getting the "missing expression error" . If I remove order by clause query executing fine.
    Here is my query:
    select *
    from emp_mstr
    where emp_no in(select
    emp_no
    from emp_mstr
    order by branch_no);
    Thanks & Regards,
    Mahi

    May be you miss some required spaces also, other than wrong use of ORDER BY
    select *
    from emp_mstr
    where emp_no in
         ( select e2.emp_no
           from emp_mstr e2
    --       order by e2.branch_no
         );Why do you want to ORDER BY in the subquery, which you use with IN clause? That will not make any difference in the result..Means the result you get with ORDER BY will be same as without that.. And in this case, ORDER by is a unncessary overhead.. And Ordering is very costly..
    And why do you want to have the IN clause at all in your query? You are referring the same tables in the main query and sub query..
    The below will give the same result
    select *
    from emp_mstr
    where emp_no is not nullIf you want to use another table in the subquery, always use aliasess...
    select *
    from emp_mstr
    where emp_no in
         ( select e2.emp_no
           from emp_mstr2 e2
    --       order by e2.branch_no
         );

  • Order By Clause in View

    Hi,
    I have a doubt regarding Order By Clause in Views.
    As per my knowledge, we can't put an order by clause in the subquery that defines view. But when i created a view in Oracle 9i with the order by clause, view got created.
    Please see the my view code below :
    create or replace view testview
    as select * from employees
    order by 1,2;
    Could anyone please confirm that we can have order by clause in Views in oracle 9i?
    Thanks,
    Tandra

    According to the SQL Reference doc, there is no such restriction for a non-updatable view:
    The view subquery cannot select the CURRVAL or NEXTVAL pseudocolumns.
    If the view subquery selects the ROWID, ROWNUM, or LEVEL pseudocolumns, those columns must have aliases in the view subquery.
    If the view subquery uses an asterisk (*) to select all columns of a table, and you later add new columns to the table, the view will not contain those columns until you re-create the view by issuing a CREATE OR REPLACE VIEW statement.
    For object views, the number of elements in the view subquery select list must be the same as the number of top-level attributes for the object type. The datatype of each of the selecting elements must be the same as the corresponding top-level attribute.
    You cannot specify the SAMPLE clause.
    This restriction exists only for updatable views:
    If you want the view to be inherently updatable, it must not contain any of the following constructs:
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    A DISTINCT operator
    An aggregate or analytic function
    A GROUP BY, ORDER BY, CONNECT BY, or START WITH clause
    A collection expression in a SELECT list
    A subquery in a SELECT list
    Joins (with some exceptions as described in the paragraphs that follow).

  • Read only view which has an ORDER BY clause

    Aim to create a read only view which has an ORDER BY clause
    Sample script
    CREATE TABLE tab1 (
    col1 VARCHAR2(3),
    col2 NUMBER
    INSERT INTO tab1(col1, col2) VALUES ('ccc', 30);
    INSERT INTO tab1(col1, col2) VALUES ('bbb', 20);
    INSERT INTO tab1(col1, col2) VALUES ('ddd', 40);
    INSERT INTO tab1(col1, col2) VALUES ('aaa', 10);
    COMMIT;
    -- To creat View
    CREATE OR REPLACE VIEW v_tab1
    AS
    SELECT
    col1,
    col2
    FROM
    tab1
    ORDER BY
    col1
    WITH READ ONLY;
    I get the following error
    WITH READ ONLY
    ERROR at line 10:
    ORA-00933: SQL command not properly ended
    When I comment out the ORDER BY clause, the view is created
    Pls let me know how I can create a read only view with ORDER BY clause

    Hi,
    take a look at the documentation for CREATE VIEW, there is a restriction:
    "You cannot specify the ORDER BY clause in the subquery if you also specify the subquery_restriction_clause."
    Wolfgang

  • Subquery in the Where clause

    Can I put a subquery in the where clause, on the left side on the operator?
    This is a multi-row query.
    Like this,
       select a.col1, a.col2, b.col1, b.col2,
                 my_function(a.date1, b.date2) AS GROSSDAYS
       from table1 a
       where ( select ( a.date1 - b.date2 ) as range
                   from     table1 a
                   join      table2 b
                   on       a.col3 = b.col3
                   where rownum =1
                   in ( 1,2,3)
    and  a.col1 = b.col2I need to use a subquery because the column I need does not exist in the table, and I cannot make any changed to the table structure.
    Is what I'm doing possible?
    The subquery is the same as the function I have in the Select clause.

    I tried a subquery in the where clause, but now I'm getting a missing expression error!
       SELECT
            r.complete_flag, r.order_num, r.referral_num, TRUNC(r.referral_datetime) AS referral_datetime,
            r.clinic_specialty, a.appointment_datetime, TRUNC(a.appointment_date_made) AS appt_datemade, a.appointment_status_id,
             scref.scr_rules.calcatcdays(r.referral_datetime,a.appointment_date_made) AS ATCDays  -- returns difference between two dates
    FROM
            referral r,
                                 ( SELECT referral_num,appointment_datetime, appointment_date_made, appointment_status_id
                                      FROM   ( SELECT referral_num, appointment_datetime, appointment_date_made, appointment_status_id,
                                                ROW_NUMBER() OVER (PARTITION BY referral_num
                                                ORDER BY appointment_datetime) rn
                                            FROM   appointment
                                     WHERE rn = 1
                             a
    WHERE r.order_num IS NOT NULL
    AND   ( SELECT adays                      -- THIS IS WHERE I'M GETTING A MISSING EXPRESSION ERROR!!!
           FROM ( SELECT scref.scr_rules.calcatcdays(r.referral_datetime,a.appointment_date_made) AS adays
                    FROM referral r
                     JOIN appointment a
                     ON   a.referral_num = r.referral_num
                     WHERE ROWNUM = 1
           WHERE  adays
          ) = 3
    AND   r.referral_num = a.referral_num(+)
    AND   TRUNC(r.referral_datetime) >= TO_DATE('01-JUL-05','DD-MON-YY')
    AND   TRUNC(r.referral_datetime) <= TO_DATE('31-JUL-05','DD-MON-YY')

  • Correlated Subquery in ORDER BY

    The following is a valid sql. But, what is meant by a correlated scalar subquery in the ORDER BY clause?
    SELECT employee_id, last_name
    FROM employees e
    ORDER BY (SELECT department_name
    FROM departments d
    WHERE e.department_id=d.department_id);

    It is exactly the same in the ORDER BY clause as in any other part of a query. As biswabijay says, the correlated query is run once for each row in the result set.
    In essence, the fileds selected from the correlated query are added to the result for each row, then evaluated in the appropriate context (e.g. compared in a WHERE clause, used for sorting in an ORDER BY).
    A small addition to your original query makes this more apparent.
    SQL> SELECT employee_id, last_name, department_name
      2  FROM employees e, departments d
      3  WHERE e.department_id=d.department_id
      4  ORDER BY (SELECT department_name
      5  FROM departments d
      6  WHERE e.department_id=d.department_id);
    EMPLOYEE_ID LAST_NAME                 DEPARTMENT_NAME
            205 Higgins                   Accounting
            206 Gietz                     Accounting
            200 Whalen                    Administration
            100 King                      Executive
            101 Kochhar                   Executive
            102 De Haan                   Executive
            185 Bull                      Shipping
            144 Vargas                    Shipping
            143 Matos                     Shipping
            184 Sarchand                  ShippingHTH
    John

  • RESTICTIONS ON ORDER BY CLAUSE

    Can someone clear my doubts.I find it in DOCS but didn't succeded.Where it is written ?Please Explain me.
    Can We use ORDER BY CLAUSE in SubQuery ?
    Thanks.
    KarTiK.

    No,
    Even though It wont work..
    Findout yourself..
    SQL> select ename,sal
      2  from (select a.*,rownum s
      3        from emp a
      4        order by sal desc)
      5  where s = &rnk
      6  /
    Enter value for rnk: 4
    old   5: where s = &rnk
    new   5: where s = 4
    ENAME             SAL
    JONES            2975
    SQL> /
    Enter value for rnk: 3
    old   5: where s = &rnk
    new   5: where s = 3
    ENAME             SAL
    WARD             1250
    SQL> /
    Enter value for rnk: 1
    old   5: where s = &rnk
    new   5: where s = 1
    ENAME             SAL
    SMITH             800                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                   

  • Subquery in GROUP BY CLAUSE

    Is it possible to place a subquery in the GROUP BY CLAUSE? If it is, can anyone show me an example? thanks

    Hi,
    Here's a GROUP BY clause that uses an IN-subquery:
    SELECT    COUNT (*)     AS cnt
    FROM       scott.emp
    GROUP BY  CASE
              WHEN deptno  IN (
                             SELECT     deptno
                             FROM     scott.dept
                             WHERE     loc     = 'NEW YORK'
              THEN  1
              ELSE  2
           END
    ;I've never seen a need for this (and I've been to a state fair, a rodeo and a picnic!)
    Interestingly, if I copy the expression from the GROUP BY clause to the SELECT clause:
    SELECT    COUNT (*)     AS cnt
    ,       CASE
              WHEN deptno  IN (
                             SELECT     deptno
                             FROM     scott.dept
                             WHERE     loc     = 'NEW YORK'
              THEN  1
              ELSE  2
           END          AS new_york
    FROM       scott.emp
    GROUP BY  CASE
              WHEN deptno  IN (
                             SELECT     deptno
                             FROM     scott.dept
                             WHERE     loc     = 'NEW YORK'
              THEN  1
              ELSE  2
           END
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    ERROR at line 3:
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    SELECT       deptno
    FROM       scott.emp
    ORDER BY  CASE
              WHEN deptno  IN (
                             SELECT     deptno
                             FROM     scott.dept
                             WHERE     loc     = 'DALLAS'
              THEN  1
              ELSE  2
           END
    ;(New York is department 10, the first department anyway, so it's not as clear to use the exact same example.)

  • Subquery with ORDER BY

    AFAIK, subquery can have ORDER BY clause in 9iR2. But why I got this error:
    SQL> SELECT student_id FROM student
    2 WHERE zip =any (SELECT zip
    3 FROM zipcode
    4 WHERE rownum<=5 ORDER BY zip)
    5
    SQL> /
    WHERE rownum<=5 ORDER BY zip)
    ERROR at line 4:
    ORA-00907: missing right parenthesis
    The error disappear if I remove the ORDER BY clause. My version is 9.2.0.1.0.

    I'm sorry. ORDER BY is valid only in inline view and not in sub-query.
    SQL>select empno from emp
      2   where empno in (select empno from emp order by sal)
      3  /
    where empno in (select empno from emp order by sal)
    ERROR at line 2:
    ORA-00907: missing right parenthesis
    SQL>select empno from (select empno from emp order by sal)
      2  /
        EMPNO
         7369
         7900
         7876
         7654
         7521
         7934
         7844
         7499
         7782
         7698
         7566
         7902
         7788
         7839
         8888
         9999
    16 rows selected.
    SQL>Cheers
    Sarma.

  • Order by clause not working

    Hi, everyone,
    I am trying to use the following insert statement to insert records in asc order. if i use the select statement alone the order by clause works fine, but when i use the same sql and add a insert into table statment the order by clause does not work. I am not getting the records in ascending order. could anybody help me in this regard?
    INSERT INTO cat_sales_stg
    select      b.SSC,                
         ltrim(rtrim(a.CAT_DESC)) cat_desc,                
         SUM(a.AMOUNT) AMOUNT               
    FROM Trans a, SSC b                     
    WHERE a.ACCOUNT_NUMBER = TO_CHAR(b.ACCOUNT_NUMBER)                    
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    user10636796 wrote:
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    I am trying to use the following insert statement to insert records in asc orderWhat Toon, William, and others have said is that you DON'T insert rows in a specific order. That is completely outside the way relational databases are designed. You insert rows as unordered and use an ORDER BY clause in a SELECT when reading them. ORDER BY is for SELECT statements, not INSERT.
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    There is a databas object called a varray that can store data in sorted order. I have never seen them used because selecting the data back out again is more work; using an ordinary table and an ORDER BY clause is much easier.

  • Suppress "Order By" clause in Answers Query

    Hello,
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    I do not want to use Sort Order column in the repository.
    Thanks,
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    You add a rownumber to your DB view and use that to 'sort' your report.
    regards
    John
    http://obiee101.blogspot.com/

  • How to make an ORDER BY clause dynamic

    is there anyway to make the ORDER BY clause in an SQL query within a DB control
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    "Mark" <[email protected]> wrote:
    >
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  • In Report,order by clause is not working

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    Regards,
    Leelakrishna.G

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  • Error : The ORDER BY clause is invalid in views, inline functions, derived

    Hi All,
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    When I create a calculations in 11g like abc/sum(abc) in the column formula for a column then i get this error.
    What does this error mean? Does OBIEE 11g doesn't support using these expressions in the report and the fact that it applies the order by clause to the reports, the report fail?
    Could anybody please explain the issue. There is very limited information on this over the web.
    Thanks in advance.
    Ronny

    Thanks svee for the quick response, actually i had resolved the issue by unchecking the EXPRESSION_IN_ORDERBY_SUPPORTED option in the database. I want to understand how does that makes the difference?
    What does EXPRESSION_IN_ORDERBY_SUPPORTED mean? Does it mean that if I give any expression in my answers report and since obiee uses a order by for all the queries, the expression won't be supported?
    Please explain.

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