About overloading and overriding

Question

I hava a Java code like this:
class Homer {
float doh(float f) {
System.out.println("doh(float)");
return 1.0f;
char doh(char c) {
System.out.println("doh(string)");
return 'd';
class Bart extends Homer { 
float doh(float f) {
System.out.println("doh(float)");
return 1.0f;
class Hide {
public static void main(String[] args) {
Bart b = new Bart();
b.doh('x');//compiler error in this line
b.doh(1);
b.doh(1.0f);
An error was ocurred:reference to doh is ambigous
Who can told me why?

Answer 1

andy.g
you are wrong!
you cannot undertand what is the different between
overlaoding and overiding!sorry for the wrong answer.
the point is the super-class's method with most specific signiture has the same priority as the sub-class's method that could match(not exactly the same, but can be promoted, like char to float) the signiture during method binding/finding. java always put the current class's method at the first place, but when a method in super-class is more specicif in signiture, the compiler can't determin which one to use.
actually, there is nothing related to overriding in this case, e.g.:
class A{
  char method(char c){.....}
class B extends A{
  //nothing's been overrided
  float method(float f){......}
  public static void main(String[] args){
     B b = new B();
     b.method('c');  //compiler error.
}so it is definetely a priority's problem, the super class's methods do not have the same prority as the sub-class's.