Add a row after every n records

Question

Hi
I have a query that returns only one column
Column1
a
b
c
d
g
e
f
g
h
I want to add 01 as the first row and then after 5 records i want to add 02 then 03 after another 5 records and so on i.e
Column1
01
a
b
c
d
e
02
f
g
h
How can this be done?

Answer 1

Hi,
Nice post.
Regards salim.
other solution.
SELECT res
  FROM t
model
dimension by( row_number()over(partition by 1 order by rownum) rn)
measures(col1,cast ( col1 as varchar2(20)) as res, count(1)over(partition by 1) cpt,trunc(rownum/5) diff)ignore nav
(diff[for rn from 1 to cpt[1]+trunc((cpt[1]+cpt[1]/5)/5) increment 1]=
case when diff[cv(rn)] is present then  diff[cv(rn)]
else   case when mod(cv(rn),5)=0 then
       diff[cv(rn)-1]+1
       else diff[cv(rn)-1]end 
end,
res[for rn from 1 to cpt[1]+trunc((cpt[1]+cpt[1]/5)/5) increment 1]=
  case when mod(cv(rn),5)=0 then 
       to_char((cv(rn)/5),'fm00')
  else  col1[cv(rn)-diff[cv(rn)]]end )
SQL> WITH t AS
  2       (SELECT 'a' col1
  3          FROM DUAL
  4        UNION ALL
  5        SELECT 'b'
  6          FROM DUAL
  7        UNION ALL
  8        SELECT 'c'
  9          FROM DUAL
10        UNION ALL
11        SELECT 'd'
12          FROM DUAL
13        UNION ALL
14        SELECT 'g'
15          FROM DUAL
16        UNION ALL
17        SELECT 'e'
18          FROM DUAL
19        UNION ALL
20        SELECT 'f'
21          FROM DUAL
22        UNION ALL
23        SELECT 'g'
24          FROM DUAL
25        UNION ALL
26        SELECT 'h'
27          FROM DUAL
28        UNION ALL
29        SELECT 'i'
30          FROM DUAL
31        UNION ALL
32        SELECT 'j'
33          FROM DUAL
34        UNION ALL
35        SELECT 'k'
36          FROM DUAL
37          UNION ALL
38        SELECT 'l'
39          FROM DUAL
40          UNION ALL
41        SELECT 'm'
42          FROM DUAL
43          UNION ALL
44        SELECT 'o'
45          FROM DUAL
46          UNION ALL
47        SELECT 'p'
48          FROM DUAL
49          UNION ALL
50        SELECT 'q'
51          FROM DUAL
52          UNION ALL
53        SELECT 'z'
54          FROM DUAL
55          UNION ALL
56        SELECT 'z'
57          FROM DUAL
58          UNION ALL
59        SELECT 'z'
60          FROM DUAL
61          UNION ALL
62        SELECT 'y'
63          FROM DUAL)
64  SELECT res
65    FROM t
66  model
67  dimension by( row_number()over(partition by 1 order by rownum) rn)
68  measures(col1,cast ( col1 as varchar2(20)) as res, count(1)over(partition by 1) cpt,trunc(rownu
m/5) diff)ignore nav
69  (diff[for rn from 1 to cpt[1]+trunc((cpt[1]+cpt[1]/5)/5) increment 1]=
70  case when diff[cv(rn)] is present then  diff[cv(rn)]
71  else   case when mod(cv(rn),5)=0 then
72         diff[cv(rn)-1]+1
73         else diff[cv(rn)-1]end 
74  end,
75   res[for rn from 1 to cpt[1]+trunc((cpt[1]+cpt[1]/5)/5) increment 1]=
76    case when mod(cv(rn),5)=0 then 
77         to_char((cv(rn)/5),'fm00')
78    else  col1[cv(rn)-diff[cv(rn)]]end )
79 
SQL> /
RES
a
b
c
d
01
g
e
f
g
02
h
i
j
k
03
l
m
o
p
04
q
z
z
z
05
y
26 ligne(s) sélectionnée(s).
SQL> Edited by: Salim Chelabi on 2009-04-15 13:35