ALV: count of unique entries

Hi Team,
A conventional report has Plant, Delivery Doc. No., Customer ID and Material # in its line, sorted by Plant.
On change of the Plant, the count of unique Delivery documents,Customers and Materials is displayed as shown below,
Plnt  Delivery#  Ord/PO#    SaTy   Cust
3100 81546208   800865     KB     11316
3100 81546205   800864     OR     730
3100 81546206   800864     OR     730
3100 81546209   800865     KB     11316
3100 81546206   800864     OR     730
3100 81546207   800864     OR     730
3100      5            2                           2
I require to display this report using ALV, how to display this unique entries count in ALV.
Thanks & Regards,
Lakshmanan

Hi,
Fill these details in the final internal table which was used to display output on change of plant number.
Then these details will be displayed in the alv output. If you want you can fill these cells in a different color.
Example Code:
  it_head-code = 'MKT'.
  it_head-dept = 'Marketing'.
  APPEND it_head.
  CLEAR it_head.
  it_head-code = 'QA'.
  it_head-dept = 'Quality'.
  APPEND it_head.
  CLEAR it_head.
  it_head-code = 'TES'.
  it_head-dept = 'Testing'.
  APPEND it_head.
  CLEAR it_head.
  it_item-code = 'MKT'.
  it_item-emp  = 'Srinivasu'.
  it_item-city = 'Thane'.
  APPEND it_item.
  CLEAR it_item.
  it_item-code = 'MKT'.
  it_item-emp  = 'Sekhar'.
  it_item-city = 'Thane'.
  APPEND it_item.
  CLEAR it_item.
  it_item-code = 'MKT'.
  it_item-emp  = 'Radha Krishna'.
  it_item-city = 'Thane'.
  APPEND it_item.
  CLEAR it_item.
  it_item-code = 'MKT'.
  it_item-emp  = 'Sudheer'.
  it_item-city = 'Thane'.
  APPEND it_item.
  CLEAR it_item.
  it_item-code = 'QA'.
  it_item-emp  = 'Srinu'.
  it_item-city = 'Thane'.
  APPEND it_item.
  CLEAR it_item.
  it_item-code = 'QA'.
  it_item-emp  = 'Sanjay'.
  it_item-city = 'Delhi'.
  APPEND it_item.
  CLEAR it_item.
  it_item-code = 'QA'.
  it_item-emp  = 'Nilkesh'.
  it_item-city = 'Hyderabad'.
  APPEND it_item.
  CLEAR it_item.
  it_item-code = 'QA'.
  it_item-emp  = 'Boxer'.
  it_item-city = 'KAKINADA'.
  APPEND it_item.
  CLEAR it_item.
  it_item-code = 'TES'.
  it_item-emp  = 'Federer'.
  it_item-city = 'Swiss'.
  APPEND it_item.
  CLEAR it_item.
  it_item-code = 'TES'.
  it_item-emp  = 'Sachin'.
  it_item-city = 'India'.
  APPEND it_item.
  CLEAR it_item.
  it_item-code = 'TES'.
  it_item-emp  = 'Dravid'.
  it_item-city = 'India'.
  APPEND it_item.
  CLEAR it_item.
  LOOP AT it_item.
    AT NEW code.
      wa_item-code  = it_item-code.
      wa_item-emp   = 'EMPLOYEE NAME'.
      wa_item-city  = 'CITY'.
      wa_item-cbox  = 'X'.
      wa_item-color = color[].
      APPEND wa_item TO it_item1.
      CLEAR wa_item.
    ENDAT.
    wa_item-code = it_item-code.
    wa_item-emp  = it_item-emp.
    wa_item-city = it_item-city.
    APPEND wa_item TO it_item1.
    CLEAR wa_item.
    aux_cnt = aux_cnt + 1.
    AT END OF code.
      wa_item-code  = it_item-code.
      wa_item-emp   = 'No Of Employees'.
      wa_item-city  = aux_cnt.
      wa_item-color = color1[].
      APPEND wa_item TO it_item1.
      CLEAR wa_item.
      CLEAR aux_cnt.
    ENDAT.
  ENDLOOP.

Similar Messages

  • Is there a formula to count unique entries in a range of cells, and possible ignore certain predefined entries

    I would like to create a formula to accomplish a task, I am not sure how to do it.
    Basically, I will have cells A1-A31, with 1 corresponding with a day of the month.
    Each cell A1-A31 will contain HEX data, in the form of a name (ie: John Smith) I would like another cell such as A5 to count the unique entries within the range of A1-A31.
    If I can be pointed in the right direction, I can figure out for corresponding cells.
    Basically it will look like this (plus other calculations, I already achieved)
    DATE     NAME                     TOTAL_CASES
    1            John Smith                          1
    2           John Smith                            1
    3           Roxy Jones                          2
    4           Huang Nguyen                    3
    5           Huang Nguyen                   3
    6           Bradly Katz                         4
    7           Linda Schutlz                       5
    8            off                                       5          <--- possible addition step of ignoring "off"
    9          Julie Dawgie                         6
    Additionally, if there is a way to count the "unique entries" in the given range, it it possible to IGNORE an item, such as the word "off" and/or "vacation?

    The formula only appears to count the total number of "Y", but should be ignoring a second "Y" for that name.
    Date
    Claimant Name
    hidden counter
    sucessful?
    days sucessful
    days worked
    days sucessful
    days worked
    Case%
    Overall%
    0
    0
    0
    1
    0
    1
    Brian
    1
    Y
    1
    1
    2
    1
    200.000%
    150.000%
    2
    Brian
    0
    Y
    2
    2
    2
    1
    200.000%
    150.000%
    3
    Octavio
    1
    N
    2
    3
    2
    2
    100.000%
    83.333%
    4
    Vicki
    1
    N
    2
    4
    2
    3
    66.667%
    58.333%
    5
    Octavio
    0
    N
    2
    5
    2
    3
    66.667%
    53.333%
    6
    Sara
    1
    N
    2
    6
    2
    4
    50.000%
    41.667%
    7
    Sara
    0
    N
    2
    7
    3
    4
    75.000%
    51.786%
    8
    Delfino
    1
    Y
    3
    8
    4
    5
    80.000%
    58.750%
    9
    Delia
    1
    Y
    4
    9
    5
    6
    83.333%
    63.889%
    10
    Vicki
    0
    Y
    5
    10
    6
    6
    100.000%
    75.000%
    11
    Cesar
    1
    Y
    6
    11
    7
    7
    100.000%
    77.273%
    12
    Larry
    1
    Y
    7
    12
    8
    8
    100.000%
    79.167%
    13
    Larry
    0
    Y
    8
    13
    8
    8
    100.000%
    80.769%
    when counted correctly, it would look like:
    Date
    Claimant Name
    hidden counter
    Was Video Obtained?
    Days Video Obtained
    Days Worked
    Cases Video Obtained
    Cases Worked
    Case%
    Overall%
    0
    0
    0
    0
    0
    1
    Brian
    1
    Y
    1
    1
    1
    1
    100.000%
    100.000%
    2
    Brian
    0
    Y
    2
    2
    1
    1
    100.000%
    100.000%
    3
    Octavio
    1
    N
    2
    3

  • How do I count the unique value pairs in two columns of a table?

    I have a table (Table 2) that is populated with data from an imported .csv file. On table 1 I need to count the unique value pairs in two columns of Table 2.
    Here's what I have:
    Date                                        Person
    7/10/2011                         A
    7/12/2011                         W
    7/12/2011                         X
    7/12/2011                         X
    7/12/2011                         X
    7/12/2011                         Z
    7/14/2011                         Z
    7/15/2011                 X
    7/16/2011                         Z
    I'm focusing on person "X" and can easily count how many days that person shows up but what I want is to see on how many unique days that person shows up.
    Here's the result I'm looking for (Person "X" shows up on 2 different days - 3 times on 7/12/2011 and once on 7/15/2011):
    X                    2
    I can't seem to find a function that allows me to do that. I also am not allowed to modify Table 2 so that leaves me to come up with a solution on Table 1.
    Any ideas would be greatly appreciated.

    Hi John,
    Not being allowed to modify Table 2 is a minor inconvenience. Just copy (using a formula) the necessary two columns onto Table 1.
    Yellow columns may be hidden. The procedure progresses from left to right. All formulas are entered into row 2 then filled down that column to the end of the table. The table must be as long as the list in column A of Table 2.
    A2: =Table 2::A
    Fill right to column B.
    Fill both columns down as far as needed.
    I've used actual Date and Time values in column A, formatted to show only the Date part, but the technique will work with text in these cells, provided all cells representing the same 'date' have exactly the same content.
    C2: =A&B
    This concatenates the contents of each row of columns A and B into a single text string.
    D2: =COUNTIF($C$2:C2,C)
    This counts the number of occurrences of the Date&Name string on the current row from the first regular cell in column C (C2) to the current cell.
    E2: =IF(COUNTIF($B$2:B2,B)=1,MAX($E$1:E1)+1,"")
    This constructs the index of first occurrences of each name, in the order they first occur. The index is used by LOOKUP in column F.
    F2: =IF(ROW()-1>MAX(E),"",LOOKUP(ROW()-1,$E,$B))
    This uses the index value created in E as a search-for value to extract a single copy of the names in column B. The result is a list of all distinct names in the list. Note that spelling differences will be counted as distinct names.The IF statement stops the listing when the last distinct name is extracted.
    G2: =IF(LEN(F)>0,COUNTIFS($B,"="&F,$D,"=1"),"")
    This counts the number of 'first occurrences of distinct Date & Name strings for each name on the list (ie. the number of distinct dates on which each name appears in the original list).
    All of the functions used are described, with at least one example for each, in the iWork formulas and Functions User Guide. You can download the guide, and the Numbers '09 User Guide, via the Help menu in numbers.
    Regards,
    Barry

  • VSR check on the counter reading in entry unit

    Hi Gurus,
    Where can I find the field for Counter Reading in Entry Unit at the Meas.Data/Notific Tab when we create the new warranty claim? I need to get this field for VSR check, this field cannot left blank. The structure and field name that I find from the screen itself is WTY_VERS_RIFLTCOUN, RECNT. But I cannot find this field in the VSR check's tables.
    Thanks for your help.
    Best Regards,
    Hedy

    Hi gurus,
    I had solved my problen on this issue.
    Thanks for your time.

  • Counting the duplicate entries without looping itab.

    Hi ,
    I want to count the duplicate entries in  itab without looping
    the itab.
    can any one help me....

    If you just want to know the number of duplicate entries:
    DATA:
      zlt_itab1 TYPE ....
      zlt_itab2 LIKE itab1,
      zlv_lines TYPE i,
    *-Copy table
    zlt_itab2 = zlt_itab1
    *-Sort on field to count duplicates:
    SORT zlt_itab2 BY <field for counting duplicates>
    *-Total number of lines:
    zlv_lines = LINES( zlt_itab2).
    *-Remove duplicates:
    DELETE ADJACENT DUPLICATES FROM zlt_itab2.
    *-Calculate number of duplicates:
    zlv_lines = zlv_lines - LINES(zlt_itab1).
    Regards,
    John.

  • How to get a count of unique records

    How do you get a count of unique records? Looking only for one number, not a list..so if the data is:
    ID
    ===
    1234
    1234
    1234
    1236
    1236
    1237
    Then, the count total will be one field called 'ID' with the value '3' in it..
    All I know how to do is get a count that will count all records, or do it in two queries. Looking to do this in one query statment..
    Thanks..

    Just a small clarification...
    Concatenation could potentially give wrong result, depending on the data.
    For example...
    sudhakar@ORCL>ed
    Wrote file afiedt.buf
      1  with t1 as
      2  (select 'AA' c1, '101' c2 from dual union
      3  select 'AA1' c1, '01' c2 from dual union
      4  select 'AA101' c1, null c2 from dual union
      5  select 'BB2' c1, '345' c2 from dual union
      6  select 'AA101' c1, null c2 from dual union
      7  select 'BB2' c1, '345' c2 from dual union
      8  select 'BB234' c1, '5' c2 from dual
      9  )
    10* select count(distinct c1 || c2) from t1
    sudhakar@ORCL>/
                        2IMHO, the required answer will be...
    sudhakar@ORCL>ed
    Wrote file afiedt.buf
      1  with t1 as
      2  (select 'AA' c1, '101' c2 from dual union
      3  select 'AA1' c1, '01' c2 from dual union
      4  select 'AA101' c1, null c2 from dual union
      5  select 'BB2' c1, '345' c2 from dual union
      6  select 'AA101' c1, null c2 from dual union
      7  select 'BB2' c1, '345' c2 from dual union
      8  select 'BB234' c1, '5' c2 from dual
      9  )
    10* select count(distinct c1 ||'.'|| c2) from t1
    sudhakar@ORCL>/
                             5
    sudhakar@ORCL>vr,
    Sudhakar B.

  • Counter of unique products

    Hi,
                Actually i have to calculate the Counter of unique products., and print this value in the Smartform. Can you please help me out (the logic for this) please.
    I need to print a text called "**TOTALS** ". Also print the counter. Actually this is a modification to the existing layout. The line items are printed in the ITEM linetype. Do i need to print these TOTALS and Counter fields in the footer Line type, as I also need to print the literal **DATA CONTINUED ON NEXT PAGE** if data rolls onto next page in the footer. Please help me out.
    Example:
    QTY    PRODUCT          field1        field2         field3
    1              270
    2              270
    3              270
    4              271
    5              272
    6              272
                                  **TOTALS**
                     3
                                                                     **DATA CONTINUED ON NEXT PAGE**
    Thanks....

    Determine the internal table in which the data is stored. Now add coding (right mouse click on node) to loop over this internal table and determine the totals. Define a global parameter for the totals and use this in the footer.
    In stead of adding some coding in the smartform itself, you can also do this in the initialization (form / subroutines).
    The data is either part of the import parameters, or is retrieved somewhere in the initialization (form / subroutines).

  • How do I count the unique text entries in a column

    I want to count thenumber of unique text entries in a column how do I do that?

    Or, if you will need to do this on different documents, you can copy this script into AppleScript Editor, select the cells in whichever document you are working on, and run. No need to set up the formulas and extra column again.
    SG
    --select range of cells, run; provides count of distinct values
    tell application "Numbers" to tell the front document to tell active sheet
              set selectedTable to (the first table whose class of selection range is range)
              tell selectedTable to tell the selection range
                        set distinctValues to {}
                        repeat with aCell in its cells
                                  tell aCell
                                            if its value is not in distinctValues then ¬
                                                      copy its value to the end of distinctValues
                                  end tell
                        end repeat
                        return count of distinctValues
              end tell
    end tell
    --end of script

  • How to count unique entries accross the data grid?

    So I have managed to put a bunch of data into a partitioned cache 3 nodes.
    And now I would like to perform the following query/calculation.
    Say I have the following model...
    Person
    firstName
    lastName
    phoneNumber
    creditCard
    email
    ipAddress
    Given a person's email, count unique phoneNumbers, ipaddresses and creditCards.
    Or
    Given a person' s credit card count how many unique phonenumber, emails and ipAddresses.
    That said if we have the follwoing data...
    John Smith - [email protected] - 555-555-5555 - 1234567890000000 - xxx.xxx.xxx.xxx
    John Smith - [email protected] - 999-555-5555 - 1234567890000000 - xxx.xxx.xxx.yyy
    John Smith - [email protected] - 777-555-5555 - 1234567890000000 - xxx.xxx.xxx.yyy
    For query 1 given [email protected] I should get back
    1 unique phoneNumber
    1 unique creditCard
    2 unique ips
    For query 2 given 1234567890000000
    3 unique phoneNumbers
    2 unique emails
    2 unique ips
    Is possible through a regular query?
    Basically it's a cross reference algorithm.
    Edited by: 884647 on Sep 27, 2011 8:33 AM
    Edited by: 884647 on Sep 27, 2011 8:37 AM

    Just found this in a thread...
    Filter filter = ....
    ValueExtractor email = new ReflectionExtractor("email");
    ValueExtractor phone = new ReflectionExtractor("phonenumber");
    ValueExtractor ip = new ReflectionExtractor("phonenumber");
    Map mapResult = cache.aggregate(filter, new CompositeAggregator(new EntryAggregator[] {new ReducerAggregator(email), new ReducerAggregator(phone), new ReducerAggregator(ip)});
    Seems like the right solution and this works across a partitioned cache?

  • ALV Count the records in group

    I have a report which list the billing documents which sort and group by sales office. The layout is something like this
    Sales Office      Billing Document    Amount
    A                      0001                     1000
    A                      0002                     1000
    Doc. count = 2
    B                      0003                     1500 
    Doc. count = 1
    I know that I can add a column with the value 1 in each cell and sum them up.
    Is that any other alternatives?

    Hi,
    Where do you want to show this count. Do you want to show it as the column in output or in the header of the ALV. You can just see the entries in the output table and print that count.
    Reward points if useful.
    Regards,
    Atish

  • Regarding -ALV count in subgroup.

    Hi Experts,
    I am using ALV grid in my Report.
    I have 10 groups like 0-10 ,10-20,20-30,30-40.............
    and i have some records in each group.
    my problem is I have to count number of records per age group .
    i can subtotal it easily for salary field.
    but how should i count number of records per age group?

    Hi,
    Before displaying datta try this..
    1. consider 2 fields r there :  group, count.
    2. declare two new itabs itab_groups, itab_new_disp as ur old itab - "itab_display".
    itab_groups[] = itab_display[].
    sort itab_groups by groups.
    delete adjacent duplicates from itab_groups comparing groups.
    loop at itab_groups.
       loop at itab_display where group eq itab_groups-group.
         count = count +  itab_display-count.
          itab_new_disp = itab_display.
          append   itab_new_disp.
       endloop.
       itab_new_disp-group = 'subtotal'.
       itab_new_disp-COUNT =   count.
       append   itab_new_disp.
       clear : count.
    endloop.
    3. Now pass the itab - 'itab_new_disp' , to the fun module for display.
    reply back..... with ur code..
    With Rgds,
    S.Barani

  • How to get the count of the entries in the table view

    Hello experts,
             I have got a requirement where i need to display the total number of entries present in the table view, since the result comprises of several pages. This requirement is even applicable for the filter options in the table view i.e., if i use a filter it should count the total number of entries that satisfy the filter criteria.
    Thanks in advance,
    Vijayalakshmi

    hi,
    its simple,just place an input field in the layout and display the cpunt in that field.
    for that do as below,
    first in the layout of the page where you are giving tableview tab,in the next line give
    <b><htmlb:inputField id="Count"
                      value="<%=ln%>"
                      disabled = 'X'/></b>
    to display the count in that input field which is disabled.
    and if i am mot wrong in the Initialization event, you are writing select query right to populate internal table.
    after that write,
    <b>describe table it_mara lines ln.</b>
    and define this ln in page attributes as type i.
    do award points f it helps u,
    regards,
    Message was edited by:
            sowjanya s

  • To count the repeated entries in a XML document.

    HOW TO COUNT THE REPEATED  NUMBER OF ENTRIES IN A XML DOCUMENT USING THE SAP REPORT PROGRAM?
      <?xml version="1.0" encoding="utf-16" ?>
    - <ROOT>
    - <SYSTEMDETAILS>
    - <item>
      <SYSDETAILSNAME>CODE</SYSDETAILSNAME>
      <SYSDETAILS>00</SYSDETAILS>
      </item>
    - <item>
      <SYSDETAILSNAME>LICENSE</SYSDETAILSNAME>
      <SYSDETAILS>INITIAL</SYSDETAILS>
      </item>
    - <item>
      <SYSDETAILSNAME>BASIS RELEASE</SYSDETAILSNAME>
      <SYSDETAILS>700</SYSDETAILS>
      </item>
    - <item>
      <SYSDETAILSNAME>SYSTEM NAME</SYSDETAILSNAME>
      <SYSDETAILS>IS3</SYSDETAILS>
      </item>
    - <item>
      <SYSDETAILSNAME>CLIENT</SYSDETAILSNAME>
      <SYSDETAILS>800</SYSDETAILS>
      </item>
    - <item>
      <SYSDETAILSNAME>LOCLANG</SYSDETAILSNAME>
      <SYSDETAILS>English</SYSDETAILS>
      </item>
      </SYSTEMDETAILS>
    - <ACH>
    - <item>
      <NAME>HLA0009999</NAME>
      <TLEVEL>01</TLEVEL>
      <TEXT>SAP</TEXT>
      <TEXT4>Application Components</TEXT4>
      <TEXTLOC>Application Components</TEXTLOC>
      </item>
    <item>
      <NAME>ABA0000311</NAME>
      <TLEVEL>02</TLEVEL>
      <TEXT>AP</TEXT>
      <TEXT4>Application Platform</TEXT4>
      <TEXTLOC>Application Platform</TEXTLOC>
      </item>
    - <item>
      <NAME>KPE0000001</NAME>
      <TLEVEL>03</TLEVEL>
      <TEXT>AP-PPE</TEXT>
      <TEXT4>Integrated Product and Process Engineering</TEXT4>
      <TEXTLOC>Integrated Product and Process Engineering</TEXTLOC>
      </item>
    SAY THE  BOLD PART SHOWS 1 USER ,SO HOW MANY TIMES THE SAME USER APPEARS IN THE DOCUMENT.
    HOW CAN I FIND THAT?

    If the same content of file already thr in the Internal table as 1 STRING/LINE then you can loop the internal table count the entries which one you want like
    Kanagaraja L

  • Getting a COUNT of unique document numbers loaded

    What do i need to use in the Mapping in order to get the following results :-
    I am loading from a Purchase Order Item table (with Purch.Ord. number as the key). As this is an item detail table, there will be multiple records for 1 purchase order no. the result i need is a COUNT of the unique list of PO numbers loaded from this table. how can i achieve this ?
    even if i load from the PO header table (which will give me unique PO numbers for each record), how do i get the COUNT of records loaded from the table and use that result to put into my data warehouse target ?
    thanks for any replies in advance !

    thanks for the answer Igor. you have partially answered my question (as i am a newbie to OWB, i have to test out your suggestion to see if i can achieve the results you mentioned).
    maybe an example will make my question clearer.
    Assume 1 have records for 2 POs in table PURCHORD:-
    PONUM POITEMNO PRDCODE QTY
    10000 001 PRD_A 10
    10000 002 PRD_B 2
    10001 001 PRD_A 5
    10001 002 PRD_B 1
    10001 003 PRD_C 10
    the result i expect if i extract records from this table i => 2 unique Purchase Orders (my measure in the Cube is count of POs)! it is basically a COUNT on the "DISTINCT (GROUP by PONUM)". i just can't figure out how to implement this in OWB.
    thanks again

  • Loop or count for unique in dropdown?

    I'm trying to build my first dynamic dropdown populated from an XML file.
    The XSD and XML files are output from Access. The nodes of the XML are pretty simple, example as follows:
    <AllStudentsAllSchools>
    <LastName>Doe<LastName>
    <FirstName>Jane<FirstName>
    <SchoolName>Main street Middle<SchoolName>
    </AllStudentsAllSchools>
    The dyanamics on the PDF are running - I'm getting fields filled from the XML.
    (As in the above sample XML) For a dropdown to just list the unique school names and not repeat every row that contains a school name... Do I loop through the XML with a javascript loop or count, etc? Or can this be set up automatically in Livecycle, maybe with the Dynamic Properties dialog under the binding tab?
    Currently, what I have is the dropdown only reads the first row, pulling only one school name.
    Each of the subforms within the main flowed form are set up as Fragments (Including this school name dropdown). Some fragments are dynamic and some not. The dropdown within the fragment is the dynamic one, reading the XML file. The same XML file is the data connection for the PDF (that contains the Fragments).
    Example PDF, XSD and XML attached, although the dropdown isn't set up as a Fragment here.
    Thanks for any responses...
    - e

    Thanks so much for the advice, Ben.
    I'm not sure where to put the code you sent.
    I have an on "exit" switch case javascript on this dropdown that calls the next dropdowns that appear when a user selects a school name.
    I tried putting your code above this switch case as well as below it but neither pulled dynamically from the dom.
    The PDF default connection is the XSD and XML (on the PDF that contains this school names dropdown fragment). There are many other nodes in the XML - with the school names dropdown and a couple of other dropdowns being dynamic - a 'swith-case' on both static and dynamic dropdowns.
    Is the three step code you sent to be set up on the fragment containing this dropdown or on the PDF itself that contains this subform-fragment? Do I need to set up the default data connection on the fragment file as well or does the '3 step' javascript not need this?
    I'm not sure how to mix the switch-case with what you sent since I wouldn't know before hand how many schools the dropdown may display at any given time. I know I could'nt use the following since there would be more than just a "case 0". Maybe just an "on select anything" type javascript?
    switch (this.selectedIndex){
    case 0 : ewcDataManageSubform.presence = "visible";
                 ewcPermissionsSubform.presence = "hidden";
                 ewcOrderBySubform.presence = "hidden";
                 SubmitButton1Subform.presence = "hidden";
                 break;
    default : ewcDataManageSubform.presence = "hidden";
                 ewcPermissionsSubform.presence = "hidden";
                 ewcAnthropoSubform.presence = "hidden";
                 ewcFitTestSubform.presence = "hidden";
                 ewcOrderBySubform.presence = "hidden";
                 SubmitButton1Subform.presence = "hidden";
                 break;
    Thanks again for your input and sending the javascript solution... Just not sure where to put it and if I need to bind the fragment form to a default connection pointing to the XML (as well as the PDF that displays the fragment subform). A learning curve for me here but, what an awesome program this is!
    - e

Maybe you are looking for

  • Font There but Not

    I have a particular font, visible in the Fonts folder (in Library). That font will not show up in FontBook or even Spotlight! AND, it won't appear in my font lists (such as in InDesign or Word, or anything)! I've tried "validating file" within FontBo

  • No cursor in address bar by default

    i looked at the other threads saying that it was an add on that caused this, i just installed mozilla in my windows 8 new computer and NO CURSOR in new windows, it is costing me ALOT of productivity and time. How do i Fix this? I have NO ADDONS

  • Iphoto Too much memory being taken up?

    I don't know if this has already been brought up but: When I go into my Iphoto, it says that there's 11 gigs taken up. But when I click on "Iphoto Library" it says that 26 gigs are being used. What's the deal? Garbage is empty. Is it thumbnails? And

  • Handling address related information for different countries

    Hi, We are trying to understand the best way to display / query address related information (while designing internationalization for our application) - from users based on their locale - for example we would need to ask zip code - if the user is in

  • 9i vs RedHat 7.1 - problem with /lib/libm.so.6

    I'm install 9i db on my RedHat 7.1 (downgraded binutils & sun jdk1.3.1) - all work fine. I try to install iFS 1.1.10.1.0 (downloaded from OTN) - all work, but after iFS start oracle DB write .trc file with error: --- Cut --- ORA-00600: internal error