Append a text file

How do i append (at the end) a txt file?

Should I post a link to a Javadoc for the language
API�s?Does that actually append, or does it overwrite the
original file?Apparently I should:
http://java.sun.com/j2se/1.3/docs/api/java/io/FileOutputStream.html#FileOutputStream(java.lang.String, boolean)

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Using get -childitem to scan different drives but append one text file.

Folks,
I need some help, I wrote the below to scan for certain files types on client machines but I cant get the script to scan anything other than the C$. Apologies I am kind of new to scripting and PS. The script is kicked off using a batch file that makes the
CR directory on the clients. I think the problem stems from the $disk variable or the way I have used foreach or the loop - any help would be appreciated
Set-Location c:\
$s = new-object -comObject SAPI.SPVoice
$s.speak("Scan in progress")
write-host "Scanning for files"
$Extension = @("*.zip","*.rar","*.ppt","*.pdf")
$Path = "$env:userprofile\Desktop"
$disks = "c$","D$"
foreach ($disks in $disks)
{get-childitem -force -include $Extension -recurs -EA SilentlyContinue >$path\files.txt}
$s.speak("Scan completed")
Write-Host "Scan complete, files.txt created on your desktop - press any key to exit..."
$x = $Host.UI.RawUI.ReadKey("NoEcho,IncludeKeyUp")
Remove-Item c:\cr -recurse -EA SilentlyContinue
exit

Then there is "$x = $Host.UI.RawUI.ReadKey("NoEcho,IncludeKeyUp")" , What are you trying to do?
It looks like that is a pause after the code has completed to give the user time to read the message prior to exiting.
@V Sharma - As gaff-jakobs has mentioned, there are some parts of your code that need looked at. Please take a look at what he has advised and make the necessary changes. If you want to append data (doing a > does not append), I would look at using Out-File
-Append -FilePath <filename> to accomplish this.
Usually, outputting to a text file limits what you can do with the output once it goes to a text file. I would look at using something such as Export-Csv -Append -Path instead (assuming you are running PowerShell V3). But if saving to a text file is part
of your requirement, then just be sure to use the first method I mentioned.
Boe Prox
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Appending one text file to another

Hi,
I have a huge text file which is basically a load of Spam email. I've now got more text files of spam that I want to append onto the old one. I can't for the life of me remember how to do it at the command line. Can anyone help?
Cheers,
Stu

cat file1 file2 > file3
concatenates file1 and file2 and writes the result to file3.

Appending to text file

Hello everyone
I am working on a galil motor controller for a stepper motor. I have a fully functioning code for the stepper motor but I am now trying to create a data file to log the motors activity. I have created two attempts at appending to a file everytime the motor changes position. One of my attempts was a shift register using a while loop, it works the only problem with it is that it is constantly running. This makes the motor run constantly so if I set an angle itll try to keep setting it as long as the while loop is running.
Attached is my VI I have worked very hard at this. Please let me know how i could fix it
Thanks
Attachments:
galil mc USER rotationTESTING 5-13.vi ‏251 KB
galil mc USER rotation 5-12-14.vi ‏237 KB

You write to the file before setting the pointer to the end. Here, I made a very simple edit that should get you going.
There are only two ways to tell somebody thanks: Kudos and Marked Solutions
Unofficial Forum Rules and Guidelines
Attachments:
Append to File.PNG ‏50 KB

Append to text file

i'm trying to append some string to a file but it gives me error while compiling.
here's my code:
import java.io.FileOutputStream;
import java.io.File;
import java.io.IOException;
import java.util.Calendar;
import java.util.Date;
import java.awt.*;
import java.text.SimpleDateFormat;
public class testWrite
     public static void main(String args[])
          File outputFile=new File("file.txt");
          try
               Calendar myCalendar = Calendar.getInstance();
     FileWriter oStream=new FileWriter(outputFile,true);
               FileOutputStream oStream=new FileOutputStream(outputFile,true);
               SimpleDateFormat datfmt = new SimpleDateFormat( "dd.MM.yyyy HH:mm:ss" );
               Date date=new Date();
               String strDate=datfmt.format(date);
               oStream.write(strDate.getBytes());
               oStream.close();
          catch(IOException e)
can someone tell me what's wrong with it.

here is the corrected programme
import java.io.*;
import java.io.FileOutputStream;
import java.io.File;
import java.io.IOException;
import java.util.Calendar;
import java.util.Date;
import java.awt.*;
import java.text.SimpleDateFormat;
public class testWrite
public static void main(String args[])
          //File outputFile=new File("file.txt");
          try
          Calendar myCalendar = Calendar.getInstance();
          //FileWriter oFileWriter=new FileWriter("file.txt",true);
          FileOutputStream oStream=new FileOutputStream("file.txt",true);
          SimpleDateFormat datfmt = new SimpleDateFormat( "dd.MM.yyyy HH:mm:ss" );
          Date date=new Date();
          String strDate=datfmt.format(date);
          oStream.write(strDate.getBytes());
          oStream.close();
          catch(IOException e)
U had used file object in the constructor of the fileOutputStream object which is not the argument the constructor expects,the constructor expects a String with the fileName in it.

Problem on appending the text file using FileConnection!!!

it's in here...
http://forum.java.sun.com/thread.jspa?threadID=718613&tstart=0
my apology for double-cross posting..
thanks much

attachments
Attachments:
julian user not appended.JPG ‏260 KB
julian user appended.JPG ‏257 KB
galil mc USER rotation w File writing 5-16-14.vi ‏251 KB

Appending a text file

Each time I run the following code snipit:
PrintWriter pw = new PrintWriter(new FileWriter("highscores.dat"),true);
pw.println(player[winner[0]].getName() + ":" + player[winner[0]].getScore());It opens the file and overwrites the stuff in it. I thought it would append the file. Why is this?
-William

it should be either PrintWriter(new
FileWriter("highscores.dat",true)) or
PrintWriter(new FileWriter("highscores.dat",
true),true)you were nearly there ...
PrintWriter pw = new PrintWriter(new FileWriter("highscores.dat"),true);
By specifying true as second parameter of PrintWriter constructor you indicated that you want PrintWriter to automatically flush what is printed direct to the file with which its connected to. And this is not what you wanted, you expected appending.
If you want to append you have to place the "true" argument as second parameter of FileWriter constructor ... so creating a PrintWriter for appending would look like this:
PrintWriter pw = new PrintWriter(new FileWriter("highscores.dat",true));

Append to Zip file

Hi everyone,
I have created a zip file (test.zip), but i cant figure out how to append a text file to it.
Can anybody help?

http://java.sun.com/j2se/1.5.0/docs/api/java/util/zip/ZipInputStream.html#createZipEntry(java.lang.String)

Java write/append to each line of a text file

I have spent numerous hours trying to figure out what I am doing wrong. If anyone more experienced could tell me what is wrong with my code.
I have a very simple text file with 5 lines:
line1
line2
line3
line4
line5
All I am trying to do is append some string to the end of each of those lines. Everytime I run my code, it erases all content but does not write/append anything to the file. Any help is greatly appreciated.
Thanks! I am about to throw this monitor out the window!!
package Chapter6;
import java.io.*;
public class fileNavigation2 {
     public static void main(String[] args) {
          File dir = new File("C:\\testing");
          System.out.println(dir.isDirectory());
          try {
               File file = new File(dir, "Test.txt");
               FileReader fr = new FileReader(file);
               BufferedReader br = new BufferedReader(fr);
               FileWriter fw = new FileWriter(file);
               BufferedWriter bw = new BufferedWriter(fw);
               String s = "Add1,";
               String s2 = "Add2\n";
               String str;
               while((str = br.readLine()) != null) {
               StringBuffer sb = new StringBuffer(str);
               sb.append(s + s2);
               String y = sb.toString();
               System.out.println(sb);
               System.out.println("Appending");
               bw.write(y);
               bw.close();
               System.out.println("Done");
          }catch(IOException e) {}
}

First, thanks a lot for your feedback. The code makes a lot of sense but it does not update the content of my Test.txt file.
I only edited the line of code that creates the new file so that it could find the location of the file.
Scanner file = new Scanner(new File("C:\\testing",fileName));==============================
The code now looks like:
import java.io.*;
import java.util.*;
public class Main {
    static void appendTo(String fileName, String[] newLines) throws IOException {
        List<String> allLines = getLinesFrom(fileName);
        for(String line : newLines) {
            allLines.add(line);
        writeLinesTo(fileName, allLines);
    static List<String> getLinesFrom(String fileName) throws IOException {
        List<String> lines = new ArrayList<String>();
        Scanner file = new Scanner(new File("C:\\testing",fileName));
        while(file.hasNextLine()) {
            lines.add(file.nextLine());
        file.close();
        System.out.println(lines);
        return lines;
    static void writeLinesTo(String fileName, List<String> lines) throws IOException {
        BufferedWriter out = new BufferedWriter(new FileWriter(fileName));
        for(String line : lines) {
            out.write(line);
            out.write(System.getProperty("line.separator"));
        out.close();
    public static void main(String[] args) {
        String fileName = "Test.txt";
        String[] extraLines = {
                "a new line",
                "and yet another new line"
        try {
            appendTo(fileName, extraLines);
            System.out.println("Done.");
        } catch (IOException e) {
            e.printStackTrace();
}Again, thanks for the help.

Append a line to a text file

hi,
I'm using Oracle 11g.
I'm storing text files in XML DB and accessing them using FTP, pl/sql and Java.
Sometimes this files are huge, and all I need is to append a line.
Is there any way to do this, without reading the full content of the file, using PL/SQL? Or Java?
Thanks for all the help you can give me.

procedure writeDebug(P_LOG_MESSAGE VARCHAR2)
as
pragma autonomous_transaction;
V_LOG_CONTENT CLOB;
V_LOG_BUFFER blob;
V_SOURCE_OFFSET integer := 1;
V_TARGET_OFFSET integer := 1;
V_WARNING integer;
V_LANG_CONTEXT integer := 0;
V_DEBUG_CONTENT blob;
begin
createDebugOutputFile;
update RESOURCE_VIEW
set RES = updateXML(RES,'/Resource/DisplayName/text()',extractValue(RES,'/Resource/DisplayName/text()'))
where equals_path(RES,G_DEBUG_OUTPUT_FILE) = 1;
select extractValue(RES,'/Resource/XMLLob')
into V_DEBUG_CONTENT
from RESOURCE_VIEW
where equals_path(RES,G_DEBUG_OUTPUT_FILE) = 1;
V_LOG_CONTENT := chr(13) || chr(10) || to_char(systimestamp,'YYYY-MM-DD"T"HH24:MI:SS.FF') || ' : ' || P_LOG_MESSAGE;
dbms_lob.createTemporary(V_LOG_BUFFER,true);
dbms_lob.convertToBlob(V_LOG_BUFFER,V_LOG_CONTENT,dbms_lob.getLength(V_LOG_CONTENT),V_SOURCE_OFFSET,V_TARGET_OFFSET,nls_charset_id('AL32UTF8'),V_LANG_CONTEXT,V_WARNING);
dbms_lob.freeTemporary(V_LOG_CONTENT);
dbms_lob.open(V_DEBUG_CONTENT,dbms_lob.lob_readwrite);
dbms_lob.append(V_DEBUG_CONTENT,V_LOG_BUFFER);
dbms_lob.close(V_DEBUG_CONTENT);
dbms_lob.freeTemporary(V_LOG_BUFFER);
commit;
end;

Appending objects in text file and searching.......

I have been trieng to implement simple search operation on the class objects stored in the text file. but when i try to append new objects in the same file and search for the same; java.io.StreamCorruptedException is thrown. wat the problem is, that wen i append to the text file; it stores some header information before the actual object is stored and on the deserialization, this header information is causing the exception. the same header information is stored every time, i append to the file. anybody knws hw to get past it??? my code is as given below:
package coding;
import java.io.BufferedReader;
import java.io.EOFException;
import java.io.File;
import java.io.FileInputStream;
import java.io.FileOutputStream;
import java.io.FileReader;
import java.io.FileWriter;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.ObjectInputStream;
import java.io.ObjectOutputStream;
import java.io.PrintWriter;
import java.io.Serializable;
     class Employee implements Serializable{
          private static final long serialVersionUID = 1L;
          String name;
          int id;
          public int getId() {
               return id;
          public void setId(int id) {
               this.id = id;
          public String getName() {
               return name;
          public void setName(String name) {
               this.name = name;
          public Employee(String name, int id) {
               this.name = name;
               this.id = id;
     public class FileSearch{
     public static void main(String[] args) throws IOException
          /*Entering the records into the file*/
          Employee ob = null;
          File file=new File("c:\\abc.txt");
          InputStreamReader isr=new InputStreamReader(System.in);
          BufferedReader stdin=new BufferedReader(isr);
          char fileExist='y';
          if(file.exists())
               System.out.println("File already exists!!!");
               System.out.println("Append New Records(press y) Or Search Existing File(press any other button)?:");
               String strTemp=stdin.readLine();
               fileExist=strTemp.charAt(0);
          else
               System.out.println("File doesnt exist; creating new file......");
          if(fileExist=='y')
               FileOutputStream fos=new FileOutputStream(file,true);
               ObjectOutputStream oos=new ObjectOutputStream(fos);
               char choice='y';
               System.out.println("Enter records:");
               while(choice=='y')
                    System.out.println("enter id:");
                    String id_s=stdin.readLine();
                    int id=Integer.parseInt(id_s);
                    System.out.println("enter name:");
                    String name=stdin.readLine();
                    ob=new Employee(name,id);
                    try
                         oos.writeObject(ob);
                         //count++;
                         oos.flush();
                    catch(Exception e)
                         e.printStackTrace();
                    System.out.println("Enter more records?(y/n)");
                    String str1=stdin.readLine();
                    choice=str1.charAt(0);
               oos.close();
          /*Searching for the record*/
          System.out.println("Enter Record id to be searched:");
          String idSearchStr=stdin.readLine();
          int idSearch=Integer.parseInt(idSearchStr);
          try
               FileInputStream fis=new FileInputStream(
                         file);
               ObjectInputStream ois=new ObjectInputStream(fis);
               int flag=1;
               FileReader fr=new FileReader(file);
               int c=fr.read();
               for(int i=0;i<c;i++)
                    Object ff=ois.readObject();
                    Employee filesearch=(Employee)ff;
                    if(filesearch.id==idSearch)
                         flag=0;
                         break;
               ois.close();
               if(flag==1)
                    System.out.println("Search Unsuccessful");
               else
                    System.out.println("Search Successful");
          catch(Exception e)
               e.printStackTrace();
}

966676 wrote:
All what I need to elect by who this word repeated. But I don't know really how to make It, maybe LinkedListYou should choose the simplest type fullfilling your needs. In this case I'd go for <tt>HashSet</tt> or <tt>ArrayList</tt>.
or I dont know, someone could help me?You need to introduce a variable to store the actual name which must be resetted if an empty line is found and then gets assigned the verry next word in the file.
bye
TPD

Why ehen appending text file to text area, all the text in 1 line..

please hlp
      public void actionPerformed(ActionEvent e)
          TArea.setText("");
          try
          String StrNeeded;
          BufferedReader BR;
          BR=new BufferedReader(new InputStreamReader(new FileInputStream("Data.txt")));
          StrNeeded=BR.readLine();
               while(StrNeeded!=null)
               TArea.append(StrNeeded);
               StrNeeded=BR.readLine();
          catch(Exception excep)
}this is my code m problem is that,
i read a text file that has many lines, when i read it, i append it into the textarea, but what happend was all the text in my text area is in 1 line only(the other line is also appended but it is appended in the sama line.. help me

readLine removed the line feed from the end of the line.
You should append a \n to the end of the line like this:TArea.append(StrNeeded + "\n");Also it's a bad idea to catch an exception and do nothing.
Add printStackTrace in the catch block.

Write to text file. Append to existing file. Create file if file doesn't exist.

Hi folks,
up to LabVIEW 7 there was a wonderful "Write to Text File" vi which allowed the option "Append to File". Now, in LabVIEW 8, this old vi is not longer supported anymore. Instead, I am suggested to use a new "Write to Text File" vi. This vi does not offer the option "Append to File" anymore. Rather it is proposed in the online help that one should use the "Set File Position" in order to append text to the file. This much less straightforward than the old solution. Furthermore, I miss an option which would create the complete path if it doesn't exist yet.
To summarize: Isn't there really any smart "Write to Text File" vi available which offers both the options "Append" and "Create path if file does not yet exist". Of course, I could write such a file on my own but I am sure that it is of such general interest that it already exist. In any situation, when a log file shall be written, the wanted vi would be ideal.
Thanks a lot,
Peter

Ray,
I know that the old vi is still available. See the screenshot which I attach to this message. What I am missing is an option "Create file or even complete path if file or path do not yet exist.". Is there any reason why NI doesn't provide neither this option nor a simple "Append to file" functionality in the new "Write to Text File" vi?
Regards,
Peter
Attachments:
Clipboard01.png ‏7 KB

Appended text file in loop adds unwanted delimiter value at end of each iteration.

I am using 'Export To Spreadsheet.vi' in a loop which saves a text file and appends data from a 1D array waveform for each iteration. My problem is that at the end of every iteration an extra delimiter value is appended to the file. When I then attempt to graph my data, I get gaps, as seen below (circled in black).
When I start to analyze the data, I'm sure this will be a nuisance. I can not seem to find a solution to this problem. Any advise would be greatly appreciated.
Thanks.
Solved!
Go to Solution.

Export Waveforms... does indeed place an end of line at the end of the last line, resulting in a gap when the next batch of data is appended. I just had the same problem with a VI that a co-worker had written.
The fix is non-trivial. First, make a copy of the Vi to a new location and with a modified name. (If you change a VI in vi.lib, it causes all kinds of problems.)
Then go in and place string indicators various places until you find where the extra EOL characters are. The output of Array to Spreadsheet String ends with EOL. I do not have all the other changes readily accessible. I think we also changed the time format because the default setting lost resolution.
That VI opens, writes, and closes the file on every call so this is not very efficient for frequent calls.
It would almost be easier to write a Waveform to String formatting VI which does what you want and then use the standard OpenCreate/Replace File, Write to Text File, and Close File functions.
Lynn

How to append paragraph in text file of TextEdit application using applescript

how to append paragraph in text file of TextEdit application using applescript and how do i save as different location.

christian erlinger wrote:
When you want to print out an escape character in java (java is doing the work in client_text_io ), you'd need to escape it.
client_text_io.put_line(out_file, replace('your_path', '\','\\'));cheersI tried replacing \ with double slash but it just printed double slash in the bat file. again the path was broken into two lines.
file output
chdir C:\\DOCUME~1\
195969\\LOCALS~1\\Temp\
Edited by: rivas on Mar 21, 2011 6:03 AM

Append a text file

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