Array index out of bounds

Question

I have in my code a method, proceed(), and in the method main, which i called.
however, the error msg:
java.lang.ArrayIndexOutOfBoundsException: Array index out of range: 0
could someone please tell me what is wrong with my code?
// in the code, 2 arrays (keeping the contents and the count are
//declared
public static boolean proceed(String[] data, int[] count, int count_c){
for(int i=0; i<21; i++){
if ((data[i] == null) || (count[i] != count[i+1])){
return false;
if (count_c != count[21] && data[21] == null)
return false;
else
return true;
public static void main(String[] args){
Vector v=new Vector();
//... do something...
if(proceed(array, count, count_c)){
cell.setParameters(0, "cellid", array[0])
cell.setParameters(1, "sac", array[1]);                
     cell.setParameters(21,"tmr_cspu", array[21]);
v.add(cell);
count_c++;
temp[0] = ((OneCell)v.get(0)).printParameters()[0];
error     -->     java.lang.ArrayIndexOutOfBoundsException: Array index out of range: 0

Answer 1

sorry, i hope that this is better now. thanks for your comment.
in the code, 2 arrays (keeping the contents and the count) are declared
temp is also an array of size 23
i believe that the problem lies with the method proceedsince the method setParameters is correct...
i hope that my question is now clearer. thx for the trouble taken to answer me...
public static boolean proceed(String[] data, int[] count, int count_c){
    for(int i=0; i<21; i++){
        if ((data == null) || (count != count[i+1])){
            return false;
    if (count_c != count[21] && data[21] == null)
        return false;
    else
        return true;
public static void main(String[] args){
    Vector v=new Vector();
    //... do something...
    if(proceed(array, count, count_c)){
        cell.setParameters(0, "cellid", array[0])
        cell.setParameters(1, "sac", array[1]);
        cell.setParameters(21,"tmr_cspu", array[21]);
        v.add(cell);
        count_c++;
    temp[0] = ((OneCell)v.get(0)).printParameters()[0];