Array of numbers

Iam having array of 32 numbers,from these array of 32 numbers I want to select only the first number.how can I do this.

Hello hofer:
You can use "Index Array", and wire a number 0 to the index input.
I hope this helps.

Similar Messages

Need help with ouput of a list or array of numbers input from user

I'm only a few weeks into learning java, so this may seem simple to some, but...
I am trying to write a program that will receive numbers from a user,
and then list, add, average those numbers. I've got the program to
work except for listing the numbers that were input.
Can someone help guide me????
i've left the code I've tried in as comments.
Enter an integer value, the program exits if the input is 0:
20
Enter an integer value, the program exits if the input is 0:
40
Enter an integer value, the program exits if the input is 0:
60
Enter an integer value, the program exits if the input is 0:
80
Enter an integer value, the program exits if the input is 0:
0
Total numbers entered: 4
The array of numbers is: 0 0 0 0
The sum is 200
The average is 50
The maximum number is 0
The minimum is 0
Here is my code:
* Title:        Reads integers and finds the total, average, maximum of the input values
* Description:
* Copyright:    Copyright (c) 2002
* Company:      Duke Court.
* @author Mary Davenport
* @version 1.0
public class part3page6
public static void main(String[] args)
int data = 0;
int sum = 0;
int countnum = -1;
int maximum = 0;
int minimum = 0;
int average = (countnum - 1);
do
      System.out.println("Enter an integer value, " +
        " the program exits if the input is 0: ");
      data = MyInput.readInt();
      sum += data;
      countnum++;
    } while (data != 0);
      //in order to figure the max & the min it appears that the
    //program will need to utilize arrays to store the individual numbers
    //that are input from the user.
    //create an array of the input data
    int[] number = new int[countnum];
    //creat a list of the input data
    int []myList = {data};
    //lists how many numbers entered
    System.out.println("Total numbers entered: " + number.length);
    //list array of numbers -- this is giving me [I@3179c3,
    //instead of 20, 40, 60, 80 when I use "new int[countnum]"
//     System.out.print("The array of numbers is: "
//      + new int[countnum]);
    //list array of numbers: this is giving me " 0 0 0 0 "
       //instead of 20, 40, 60, 80 with the following for statement
       // (number[i] + " ")
    System.out.print("The array of numbers is: ");
      for(int i=0; i<number.length; i++)
        System.out.print(number[i] + " ");
//list mylist of numbers from input, 20, 40, 60, 80
//output is The list of numbers is: [I@3179c3
// System.out.print("The list of numbers is: " + myList);
    System.out.println();
    System.out.println("The sum is " + sum);
    average = sum/countnum;
    System.out.println("The average is " + average);
    System.out.println("The maximum number is " + maximum);
    System.out.println("The minimum is " + minimum);

When you input the data you need to save it to the array. Currently you are not saving the value you are just adding it
ArrayList nums = new ArrayList();
   do
       System.out.println("Enter an integer value, " +
         " the program exits if the input is 0: ");
       data = MyInput.readInt();
nums.add(new Integer(data));
       sum += data;
       countnum++;
     } while (data != 0);

How do I convert a 1-D array of cluster of 5 elements into a 2-D array of numbers? (history data from a chart)

Hello,
in my vi I have a chart with 5 Plots displaying measurement data.
The user should be able to save all the history data from the chart at anytime. (e.g. the user watches the chart and some event happens, then he presses a "save"-button)
I know, that I can read out the history data with a property node. That is not the problem. The problem is, how do I handle the data? The type of the history data is a 1-D array of cluster of 5 elements.
I have to convert that data somehow into a 2 D-array of numbers or strings, so that I can easily save it in a text-file.
How do I convert a 1-D array of cluster of 5 elements into a 2-D array of numbers?
I use LabVIEW 7.1
Johannes
Greetings Johannes
Using LabVIEW 7.1 and 2009 recently
Solved!
Go to Solution.

Gerd,
thank you for the quick response and the easy solution.
Look what I did in the meantime. I solved the problem too, but muuuch more complicate :-)
And I have converted the numbers to strings, so that I can easily write them into a spreasheet file.
Johannes
Message Edited by johanneshoer on 04-28-2009 10:39 AM
Greetings Johannes
Using LabVIEW 7.1 and 2009 recently
Attachments:
SaveChartHistory.JPG ‏57 KB
SaveChartHistory.JPG ‏57 KB

How to create a list/array off numbers with boolean attributes

Hi,
Maybe the title doesn't explain this too well but what I'm trying to do I'd imagine should be straight forward, I just don't know how!
I want an array of numbers to be entered by a user, and for each of these numbers I wish to have a boolean, (it will select later what action is performed on that number)
The array size can vary
e.g.
element Numeric Value Boolean
0 5 True
1 20 True
2 -5 False
3 10 True
n 100 False
I don't see any list with numeric and boolean, maybe I just haven't spotted it or do I have to make it somehow?
Any suggestions please?
Thanks!
p.s. if anyone else is using Opera Browser to post here, hitting enter work properly for ye when entering text? For me it causes the cursor to go up one line instead of down! Drives me nuts! It only happens with this NI forum
Solved!
Go to Solution.

Hi thanks for the reply,
It not really what I'm looking for though.
I require is a control that inputs both numeric and boolean, as in the example I mentioned. I guess I'm looking for a cluster really but I thought there may be something more straight forward.
From the example I gave
Element 0 of this array has been entered as a x, and the boolean True was entered (so I perform a "test" A on value x)
Element 1 of this array has been entered as a y, and the boolean True was entered (so I perform a "test" A on value y)
Element 2 of this array has been entered as a z, and the boolean False was entered (so I perform a "test" B on value z)
I could also use a 2d array were I enter another numeric value (0/1 for False/True) but I'm not sure I can limit this column only to accept 0 or zero and the first row any number.
I was hoping there would be some easier way to do this

Fastest way to format an array of numbers

I am collecting 2D array of DBLs to be later processed by other Vis.
The process worked fine when I saved the array to a file (standard %.3f, write to spreadsheet) formatting, then later have a separate VI to open the file and process it.
The same process did not work when I tried to process the 2D array on the fly, without saving/opening to file.
After debugging, I found out what was holding me back. Yep you guessed it, the formatting. Without save to spreadsheet, instead of “0.000”, the value is not 2.803E-42 (I need to to be 0.000). What is the most efficient way to format the numbers to “.3f”, on the fly (without saving to file)?
Best,
Santiago

.3f is the same as a precision of 3 input to the number to fractional string vi (which can handle arrays automatically)
To keep only a precision of 3 you can also do it numerically by multiplying by 1000, rounding then dividing by 1000.
Here is a screenshot of the code using the two different methods. The numeric method should be fastest.
Systems Test Engineer
Certified LabVIEW Architect (CLA)
Attachments:
format array of numbers.png ‏4 KB

Finding Mode of an array of numbers.

I'm having troubles with finding the mode of an array of numbers.
When the mode is in the middle of the set of numbers, it works, but when it is at the end, it doesnt.
For example..
if i had the numbers ...
2,3,3,4,5,6,6,6 in an array, it would tell me that the mode is 3.
if i had the numbers...
2,4,5,5,5,6 in an array, it would tell me that the mode is 5.
So the first set of numbers, the mode is incorrect, but the second set of numbers is correct.
The following is my code...
public static int getMode(int[] list)
int mode = 0;
int elements = 0;
int tempMode = list[0];
int temp = 1;
for(int x = 1; x < list.length; x++)
if(list[x-1] == list[x])
temp++;
}else{
if(temp > elements)
System.out.println("entered");
tempMode = list[x-1];
elements = temp;
temp = 1;
}else{
temp = 1;
mode = tempMode;
return mode;
}

You need to add another test at the end of the loop:
    public static int getMode(int[] list)
        int mode = 0;
        int elements = 0;
        int tempMode = list[0];
        int temp = 1;
        int x;
        for (x = 1; x < list.length; x++)
            if (list[x - 1] == list[x])
                temp++;
            else
                if (temp > elements)
                    tempMode = list[x - 1];
                    elements = temp;
                    temp = 1;
                else
                    temp = 1;
        if (temp > elements)
            tempMode = list[x - 1];
        mode = tempMode;
        return mode;

OCR - array of numbers

Hello
I am beginner in image processing and I need sugestion how to create array of numbers from image.
So far I ve processed this:
to that:
in vision builder.
Now I should divide this square into 9x9 smaller and then run OCR in each of them?
And what about size of the base numbers in OCR, should I create instances of the same number (depending on size?)
Thanks for help

I ve done that in 6 steps starting from:
1) color plane extraction HSL
2)Local Threashold Background Correction look for dark objects 11x11
3)Binary image conversion
4)Adv Morphology remove border objecst
5)Lookup table Equalize and 4x find straight edge
but sometimes after morphology i get that:
depending on foto quality
thanks for some suggestions

Sorting array of numbers

I have an multiple arrays of numbers 1-10 in different orders. I want to sort them in ascending order.
example
for(int pass=0; pass < sizeofarray; pass++){
    for(int t=0; t < sizeofarray; t++){
        if(array[t] > array[t+1]){
            hold=array[t];
            array[t] = array[t+1];
            array[t+1] = hold;
}This loops through 10 times no matter how the array is originally sorted. How do I decrease the number of times this cycles if the array is pre-sorted?
example arrays {10,9,8,7,6,5,4,3,2,1} need to go 10 times
{1,2,3,4,5,6,7,8,9,10} only needs to check it once.
Help, please only loops, no array.sort. This is a homework assignment.

Quicksort while effective, is not what I needed. A modified bubble sort is what I wanted. Thanks to all who posted. I found the logic I was able to modify for my needs at
http://www.autoobjects.com/Home/Teaching/CmpE_126/CmpE_126_Lectures/Sortings/sortings.html#Bubble_Sort
here's basically what it did (in C++):
    Improved Bubble Sort                                                                                                        */
void BubbleSort( UserData x[ ], int siz ){
        int i, j, switched;
        /* outer loop controls the number of pass */
        for( i = 0, switched = true; i < siz - 1 && switched == true; i++ ){
                /* initially no interchanges have been made on this pass */
                /* inner loop controls each individual pass */
                for( j = siz - 1, switched = false; j > i; j-- ){
                        if( getKey( x[ j ] ) > getKey( x[ j - 1 ] )){ /* an interchange becomes required */
                                switched = true;
                                Swap( x[ j ], x[ j - 1 ] );
                        }        /* inner loop */
                }       /* outer loop */
        return;
        }Thanks to jbish who had the most useful answer for my needs.

I have an array here numbers are coming continuously, I have to make a table of number and repeition (frequency) of the number

I have an array here numbers are coming continuously, I have to make a table of number and repeition (frequency) of the number

So? It is not clear what exactly you want to do. Nor is it clear what problems you are having (other than asking us to do your work for you). Why don't you try to solve this problem yourself, and if you get stuck, show us your code, tell us what questions you have, and someone will surely help you.
BS

What is the best way to get the minimum or maximum value from an Array of numbers?

Let's say I have an Array of numbers: [2,3,3,4,2,2,5,6,7,2]
What is the best way to find the minimum or maximum value in
that Array?
Right now, to get the maximum, I am looping through the
Array, and resetting a variable to the value if it is greater than
the existing value:

Here's other approaches, the cookbook is your friend:
http://digitalmedia.oreilly.com/pub/a/oreilly/digitalmedia/helpcenter/actionscript30cookbo ok/chapter5.html?page=7
enjoy.

Convert array of numbers in numbers

Hello I am trying to use the example of advanced peak detector, I have my own signal in an array of number that I send to a waveform chart.
Then I want to use this example to the the same with my signal , but I dont know how to convert one array of numbers judt in numbers
( thick orange line into thin orange line)
thank you very much

Hello,
If you wire your (thick orange line) into a loop (for or while) the auto-indexing of the loop will do th work for you and then you can put your Point by Point peak detection inside the loop.
But if you have your data in an array, you may want to try the Peak Detector.vi that is situated in the Analyse - Signal Processing - Time domain group. You can wire there your array directly and the results aout are the same as the other one.
Hope this helps,
Paulo

Sorting an array of numbers with loops

Hi, i'm looking for a way to sort an array or numbers with loops.
my array looks like this. int[] numbers = {5,2,7,9,1}
i know how to use the "sort" method and i want to do it without the sort method, but i am not very clear on the logic behind it.
by the end it should look like this, {1,2,5,7,9}
i know 2 loops are used, can you please give me a logic to work with.
i have started the loops but what to do inside???
int temp;
for (int i=0; i<numbers.length; i++){
for (int j=1; j<numbers; j++){
if (numbers<numbers[j])
temp = numbers[i];
Any suggestions i will be thankful for.
thank you.

fly wrote:
no not really a homework question.. i want to improve my logic because it is very poor at the moment.. but i'm sure someone knows how to sort an array with loops only.Yes, we do know how to do it, I once wrote a heapsort in assembly code, as a real work project. But you rarely get a project like that the good ones were all done years ago.
All the algorithms I suggested you look at use loops. the simplest and slowest is the bubble sort. This one runs by comparing values and swapping their locations, the wikipedia article http://en.wikipedia.org/wiki/Bubble_sort has the algorithm.

Array of string and array of numbers

Why am i not getting an array of numbers form this array of strings?
Attachments:
Untitled 5.vi ‏8 KB

Here's a quick attempt at a crude workaround. See if it works for you....
LabVIEW Champion . Do more with less code and in less time .
Attachments:
Untitled 5_MODCA.vi ‏13 KB
CrudeCleanup.png ‏7 KB

Using .sort() to sort an array of numbers NOT as strings

Hi,
is there a function or simple way to sort an array of numbers in order of their values and not as strings? E.g, have 100 come AFTER 9; (9, 100) not (100, 9).
Thanks.

use the ARRAY.numeric parameter.
(and you can always use a custom sort function parameter for more customized sorts.)

I am reading from an instrument a 1D string array of numbers in ascii. I want to be extract the actual data values from the string. How do I do that?

labview 6i. Using sr785 instrument.

Two ways. Use Fract/Exp to Number function on the Strin>Strin Number Conversion palette. It accepts both individual or strin array inputs. Wire your string array in an get an array of doubles out. You can also use Scan From String on the String palette inside of a for loop. The for loop will autoindex the string array in and autoindex an array of doubles out.
Attachments:
string_to_double.jpg ‏10 KB

Array of numbers

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