Automated script to load files

Question

Hi ,
i have a procudure (pl/Sql) that loads a dat files to oracle tables, taking a file name as input parameter.
i manually execute this pl/sql on daily basis which usually takes 30 min for one file.
but now due to some issue in data i will have to truncate all the tables this procudes load as reload the data,there are nearly 100 files which i have to run,
the files should be processed one after the other in a order.
can any one suggest how can i automate this process.
i just wanna load 10 files at a time.
Meaning, a script to supply files names to this pl/sql and return the log
thanks.

Answer 1

simply use a date instead of a number.
  SQL> begin
    2    for i in ( select dt from ( select sysdate+level dt from dual
    3                  connect by level <= 10 ) ) loop
    4      dbms_output.put_line(to_char(i.dt,'ddmmyyyy')||'_DSW');
    5    end loop;
    6  end;
    7  /
  13052008_DSW
  14052008_DSW
  15052008_DSW
  16052008_DSW
  17052008_DSW
  18052008_DSW
  19052008_DSW
  20052008_DSW
  21052008_DSW
  22052008_DSW
  PL/SQL procedure successfully completed.
  SQL>
in your case you need to identify what is the starting date. replace the sysdate with that starting date and the level identifier from 10 to 100. assuming that in your given example it starts at 05062007.
  begin
    for i in ( select dt from ( select to_date('05-JUN-2007','dd-mon-yyyy')+level dt from dual
                  connect by level <= 100 ) ) loop
      dbms_output.put_line(to_char(i.dt,'ddmmyyyy')||'_DSW');
      procedure_load_file(to_char(i.dt,'ddmmyyyy')||'_DSW');
    end loop;
  end;