Button to open a seperate page

Question

Hello All,
Oracle 11g, Apex 3.1.2
i have a button with label - "Search Dictionary" when i click this button , it opens the url link in the same page - but i want to open as a seperate page . How to do so.
Second thing is how to create a URL link on a page.
thanks/kumar

Answer 1

Here's a way I do it.
In the HTML header, put in a script section that defines the JavaScript. (I borrowed this from another thread a LONG time ago):
<script language="JavaScript" type="text/javascript">
  function callEmpPopup (formItem1) {
    var formVal1 = document.getElementById(formItem1).value;
    var url;
  url = 'f?p=&APP_ID.:1055:&APP_SESSION.::::P1055_OFFICE_ID:' + formVal1;
  w = open(url,"winLov","Scrollbars=1,resizable=1,width=800,height=600");
  if (w.opener == null)
  w.opener = self;
  w.focus();
</script>Next, in the report definition, go to the Link section and set the target to be URL, and use the following
javascript:callEmpPopup('P0_ORG_ID')You'll need to actually create the page to be used for the popup. Notice that I am passing in the Page Item whose value I need to work with on the popup page, and that the new item also must exist. Also keep in mind that you'll only be able to have one of these popup windows open at a time. There might be a way to get around this, but I haven't really wanted my users opening up every popup reference...
This could potentially answer both your questions.