Calculate row size of table with clob

Hi
I have a table which has clob data type, how can I calculate size of each row ?

Mark D Powell wrote:
What version of Oracle?
Are you interested in the combined row size of the base table row and the Lob segment or just the row size of the base table row? Or just the lob segment size?
Are you asking about a specific row or just the average for the entire table?
Depending on your version of Oracle dbms_stats which calculates the avg_row_len for the base table when lob columns are present incorrectly.
HTH -- Mark D Powell --I need row size for every record in the table, the table itself is only 1GB, can be combined size or lob size relevant to each record in a table it doesnt matter.
v11.2
thanks

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Understanding logminer results -- inserting row into table with CLOB field

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2619178     0C00070028000000     UPDATE     TESTTABLE     AAAFEXAABAAALEJAAB     update "DEVUSER"."TESTTABLE" set "DESCRIPTION" = NULL ...
2619178     0C00070028000000     COMMIT                  AAAAAAAAAAAAAAAAAA     commitEdited by: 958701 on Sep 12, 2012 9:05 AM
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Hi,
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Sorry I have posted the wrong link, it should be:
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http://download.oracle.com/docs/cd/B19306_01/server.102/b14237/statviews_1092.htm#i1581211
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DISABLE STORAGE IN ROW
CHUNK 16384
RETENTION
CACHE READS
NOLOGGING)
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nvl(vsize(CASE_NUMBER ),0)+1 +
nvl(vsize(CASE_DATA_NAME),0)+1 +
nvl(vsize(LASTMOD_TIME_T),0)+1
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m I right?
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Michael,
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:-) Srini.
==========================
My Results:
==========================
SQL> create table sample (
2 id integer primary key,
3 the_data CLOB default empty_clob() )
4 lob (the_data) store as ool_sample;
Table created.
SQL> select segment_name, round(sum(bytes)/1024, 2) || 'K' as sotrage_consumed
2 from user_segments
3 where segment_name in ('SAMPLE', 'OOL_SAMPLE')
4 group by segment_name;
SEGMENT_NAME
SOTRAGE_CONSUMED
OOL_SAMPLE
20K
SAMPLE
10K
SQL> select count(*) from sample;
COUNT(*)
0
SQL> begin
2 for i in 1..1000
3 loop
4 insert into sample values (i, RPAD('some data', 4000) );
5 end loop;
6 end;
7 /
PL/SQL procedure successfully completed.
SQL> select segment_name, round(sum(bytes)/1024, 2) || 'K' as sotrage_consumed
2 from user_segments
3 where segment_name in ('SAMPLE', 'OOL_SAMPLE')
4 group by segment_name;
SEGMENT_NAME
SOTRAGE_CONSUMED
OOL_SAMPLE
6420K
SAMPLE
70K
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1000 rows deleted.
SQL> select segment_name, round(sum(bytes)/1024, 2) || 'K' as sotrage_consumed
2 from user_segments
3 where segment_name in ('SAMPLE', 'OOL_SAMPLE')
4 group by segment_name;
SEGMENT_NAME
SOTRAGE_CONSUMED
OOL_SAMPLE
6420K
SAMPLE
70K
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Commit complete.
SQL> select segment_name, round(sum(bytes)/1024, 2) || 'K' as sotrage_consumed
2 from user_segments
3 where segment_name in ('SAMPLE', 'OOL_SAMPLE')
4 group by segment_name;
SEGMENT_NAME
SOTRAGE_CONSUMED
OOL_SAMPLE
6420K
SAMPLE
70K
SQL> begin
2 for i in 1..1000
3 loop
4 insert into sample values (i, rpad('some data', 4000));
5 end loop;
6 end;
7 /
PL/SQL procedure successfully completed.
SQL> select segment_name, round(sum(bytes)/1024, 2) || 'K' as sotrage_consumed
2 from user_segments
3 where segment_name in ('SAMPLE', 'OOL_SAMPLE')
4 group by segment_name;
SEGMENT_NAME
SOTRAGE_CONSUMED
OOL_SAMPLE
9616K
SAMPLE
70K
SQL> truncate table sample;
Table truncated.
SQL> select segment_name, round(sum(bytes)/1024, 2) || 'K' as sotrage_consumed
2 from user_segments
3 where segment_name in ('SAMPLE', 'OOL_SAMPLE')
4 group by segment_name;
SEGMENT_NAME
SOTRAGE_CONSUMED
OOL_SAMPLE
20K
SAMPLE
10K

Oracle 11g imp erroneously tries to recreate existing tables with CLOBs?

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3. I then manually created my xmltype table in the SCHEMA2 and did a select into to load it (make sure you have the select privileges to do so):
INSERT INTO SCHEMA2.XMLTABLE2 SELECT * FROM SCHEMA1.XMLTABLE1;
4. I am still taking an export with exp of the xmltable as well even though I'm not sure I can do anything with it.
Thanks!
Edited by: stacyz on Jul 28, 2009 9:49 AM

Row chaining in table with more than 255 columns

Hi,
I have a table with 1000 columns.
I saw the following citation: "Any table with more then 255 columns will have chained
rows (we break really wide tables up)."
If I insert a row populated with only the first 3 columns (the others are null), is a row chaining occurred?
I tried to insert a row described above and no row chaining occurred.
As I understand, a row chaining occurs in a table with 1000 columns only when the populated data increases
the block size OR when more than 255 columns are populated. Am I right?
Thanks
dyahav

user10952094 wrote:
Hi,
I have a table with 1000 columns.
I saw the following citation: "Any table with more then 255 columns will have chained
rows (we break really wide tables up)."
If I insert a row populated with only the first 3 columns (the others are null), is a row chaining occurred?
I tried to insert a row described above and no row chaining occurred.
As I understand, a row chaining occurs in a table with 1000 columns only when the populated data increases
the block size OR when more than 255 columns are populated. Am I right?
Thanks
dyahavYesterday, I stated this on the forum "Tables with more than 255 columns will always have chained rows." My statement needs clarification. It was based on the following:
http://download.oracle.com/docs/cd/B28359_01/server.111/b28318/schema.htm#i4383
"Oracle Database can only store 255 columns in a row piece. Thus, if you insert a row into a table that has 1000 columns, then the database creates 4 row pieces, typically chained over multiple blocks."
And this paraphrase from "Practical Oracle 8i":
V$SYSSTAT will show increasing values for CONTINUED ROW FETCH as table rows are read for tables containing more than 255 columns.
Related information may also be found here:
http://download.oracle.com/docs/cd/B10501_01/server.920/a96524/c11schem.htm
"When a table has more than 255 columns, rows that have data after the 255th column are likely to be chained within the same block. This is called intra-block chaining. A chained row's pieces are chained together using the rowids of the pieces. With intra-block chaining, users receive all the data in the same block. If the row fits in the block, users do not see an effect in I/O performance, because no extra I/O operation is required to retrieve the rest of the row."
http://download.oracle.com/docs/html/B14340_01/data.htm
"For a table with several columns, the key question to consider is the (average) row length, not the number of columns. Having more than 255 columns in a table built with a smaller block size typically results in intrablock chaining.
Oracle stores multiple row pieces in the same block, but the overhead to maintain the column information is minimal as long as all row pieces fit in a single data block. If the rows don't fit in a single data block, you may consider using a larger database block size (or use multiple block sizes in the same database). "
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Create a test table named T4 with 1000 columns.
With the table created, insert 1,000 rows into the table, populating the first 257 columns each with a random 3 byte string which should result in an average row length of about 771 bytes.
SPOOL C:\TESTME.TXT
SELECT
SN.NAME,
MS.VALUE
FROM
V$MYSTAT MS,
V$STATNAME SN
WHERE
SN.NAME = 'table fetch continued row'
AND SN.STATISTIC#=MS.STATISTIC#;
INSERT INTO T4 (
COL1,
COL2,
COL3,
COL255,
COL256,
COL257)
SELECT
DBMS_RANDOM.STRING('A',3),
DBMS_RANDOM.STRING('A',3),
DBMS_RANDOM.STRING('A',3),
DBMS_RANDOM.STRING('A',3)
FROM
DUAL
CONNECT BY
LEVEL<=1000;
SELECT
SN.NAME,
MS.VALUE
FROM
V$MYSTAT MS,
V$STATNAME SN
WHERE
SN.NAME = 'table fetch continued row'
AND SN.STATISTIC#=MS.STATISTIC#;
SET AUTOTRACE TRACEONLY STATISTICS
SELECT
FROM
T4;
SET AUTOTRACE OFF
SELECT
SN.NAME,
SN.STATISTIC#,
MS.VALUE
FROM
V$MYSTAT MS,
V$STATNAME SN
WHERE
SN.NAME = 'table fetch continued row'
AND SN.STATISTIC#=MS.STATISTIC#;
SPOOL OFFWhat are the results of the above?
Before the insert:
NAME                      VALUE
table fetch continue        166
After the insert:
NAME                      VALUE
table fetch continue        166
After the select:
NAME                 STATISTIC#      VALUE
table fetch continue        252        332 Another test, this time with an average row length of about 12 bytes:
DELETE FROM T4;
COMMIT;
SPOOL C:\TESTME2.TXT
SELECT
SN.NAME,
MS.VALUE
FROM
V$MYSTAT MS,
V$STATNAME SN
WHERE
SN.NAME = 'table fetch continued row'
AND SN.STATISTIC#=MS.STATISTIC#;
INSERT INTO T4 (
COL1,
COL256,
COL257,
COL999)
SELECT
DBMS_RANDOM.STRING('A',3),
DBMS_RANDOM.STRING('A',3),
DBMS_RANDOM.STRING('A',3),
DBMS_RANDOM.STRING('A',3)
FROM
DUAL
CONNECT BY
LEVEL<=100000;
SELECT
SN.NAME,
MS.VALUE
FROM
V$MYSTAT MS,
V$STATNAME SN
WHERE
SN.NAME = 'table fetch continued row'
AND SN.STATISTIC#=MS.STATISTIC#;
SET AUTOTRACE TRACEONLY STATISTICS
SELECT
FROM
T4;
SET AUTOTRACE OFF
SELECT
SN.NAME,
SN.STATISTIC#,
MS.VALUE
FROM
V$MYSTAT MS,
V$STATNAME SN
WHERE
SN.NAME = 'table fetch continued row'
AND SN.STATISTIC#=MS.STATISTIC#;
SPOOL OFFWith 100,000 rows each containing about 12 bytes, what should the 'table fetch continued row' statistic show?
Before the insert:
NAME                      VALUE
table fetch continue        332
After the insert:
NAME                      VALUE
table fetch continue        332
After the select:
NAME                 STATISTIC#      VALUE
table fetch continue        252      33695The final test only inserts data into the first 4 columns:
DELETE FROM T4;
COMMIT;
SPOOL C:\TESTME3.TXT
SELECT
SN.NAME,
MS.VALUE
FROM
V$MYSTAT MS,
V$STATNAME SN
WHERE
SN.NAME = 'table fetch continued row'
AND SN.STATISTIC#=MS.STATISTIC#;
INSERT INTO T4 (
COL1,
COL2,
COL3,
COL4)
SELECT
DBMS_RANDOM.STRING('A',3),
DBMS_RANDOM.STRING('A',3),
DBMS_RANDOM.STRING('A',3),
DBMS_RANDOM.STRING('A',3)
FROM
DUAL
CONNECT BY
LEVEL<=100000;
SELECT
SN.NAME,
MS.VALUE
FROM
V$MYSTAT MS,
V$STATNAME SN
WHERE
SN.NAME = 'table fetch continued row'
AND SN.STATISTIC#=MS.STATISTIC#;
SET AUTOTRACE TRACEONLY STATISTICS
SELECT
FROM
T4;
SET AUTOTRACE OFF
SELECT
SN.NAME,
SN.STATISTIC#,
MS.VALUE
FROM
V$MYSTAT MS,
V$STATNAME SN
WHERE
SN.NAME = 'table fetch continued row'
AND SN.STATISTIC#=MS.STATISTIC#;
SPOOL OFFWhat should the 'table fetch continued row' show?
Before the insert:
NAME                      VALUE
table fetch continue      33695
After the insert:
NAME                      VALUE
table fetch continue      33695
After the select:
NAME                 STATISTIC#      VALUE
table fetch continue        252      33695 My statement "Tables with more than 255 columns will always have chained rows." needs to be clarified:
"Tables with more than 255 columns will always have chained rows +(row pieces)+ if a column beyond column 255 is used, but the 'table fetch continued row' statistic +may+ only increase in value if the remaining row pieces are found in a different block."
Charles Hooper
IT Manager/Oracle DBA
K&M Machine-Fabricating, Inc.
Edited by: Charles Hooper on Aug 5, 2009 9:52 AM
Paraphrase misspelled the view name "V$SYSSTAT", corrected a couple minor typos, and changed "will" to "may" in the closing paragraph as this appears to be the behavior based on the test case.

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