Calculating distance between polyons in a donut

Is there any easy way of measure the nearest distance between the outer ring of a donut and the inner ring?
I've split the polygons into two discrete objects and tried sdo_distance but always get 0.00.
Any help would be appreciated?

Hi David,
In Oracle10g there is a function sdo_util.polygontoline.
If you extract each of the elements of interest, you can convert them to lines, then the distance will work for you.
If you keep the geometries as polygons, then the distance is 0 because one polygon is inside the other polygon.
Hope this helps, and all is well with you.
Dan

Similar Messages

Calculating distance between Lat Long points

I'm wondering if anyone out there has done this before in LabVIEW. Does anyone have a model of the "Great Circle" calculation? I have a file of lat/long points that I need to calculate the distance between. Any help??
V/r,
Chris

I haven't done it in LV, but if you go to Wikipedia and search for Great Circle Distance you'll find the formual and an example.

Calculating distance between lat long coordinates best possible way?

Hi,
Am proposing to have a table A with latitude and longitude values along with some other info for that lat lon in it. The number of rows of data will be more and it will be growing day by day. i am having one application which will provide a latitude and longitude value and this i have to compare with all the lat lon of the table A and fetch the nearest (distance wise) information from other columns corresponding to that lat long in table A.
what is the best method available to implement this so as to reduce the time required to compare lat lon supplied with all rows of data in table A.
Thanks in advance.

Have a look at the spatial option from oracle. Also there is a forum dedicated to this type of questions.
http://www.oracle.com/technetwork/database/options/spatial/index.html
especially: http://download.oracle.com/otndocs/products/spatial/pdf/locator11g_feature_overview.pdf
Edited by: Sven W. on Nov 30, 2010 5:53 PM

Calculate distance between Latitude and Longitude

Hi All,
I have one Latitude and Longitude points. I need to calculate distance between them.
Right now we are using HAVERSINE formula but the query takes longer time to complete.
Reference: http://www.movable-type.co.uk/scripts/latlong.html
Please assist on this.
Thanks in advance.

Check this link...
http://www.mrexcel.com/forum/excel-questions/202255-calculating-distance-between-two-latitude-longitude-points.html
I never did this before, but gave it a try using the formula mentioned in that link..
Data:
                   Lat                      Long                               R = 6,371 (Radius of earth (approximated))
Origin:        44.844263(B2)      -92.914803(C2)
Destination: 44.822075(B3)     -92.912498(C3)
Formula used:
A: =SIN(ABS(B3-B2)*PI()/180/2)^2+COS(B2*PI()/180)*COS(B3*PI()/180)*SIN(ABS(C3-C2)*PI()/180/2)^2
B: =2*ATAN2(SQRT(1-A),SQRT(A))
C: =R*B                  ---> DISTANCE!!!!
WITH t AS
        (SELECT POWER (
                   SIN (ABS (44.822075 - 44.844263) * ( (22 / 7) / 180 / 2)),
                   2)
                + COS (44.844263 * ( (22 / 7) / 180))
                  * COS (44.822075 * ( (22 / 7) / 180))
                  * POWER (
                       SIN (
                          ABS (-92.912498 - (-92.914803))
                          * ( (22 / 7) / 180 / 2)),
                       2)
                   E2
           FROM DUAL)
SELECT (2 * ATAN2 (SQRT ( (1 - E2)), SQRT (E2))) * 6371
FROM t;
Check if this gives correct values... (I did not verify this properly.. ) And this is faster in my opinion..
Please post your code for better suggestions from volunteers...
Cheers,
Manik.

Calculating co-ordinate distances between specific atoms

Hi,
Below is some code to calculate distances between all pairs of atoms. However, i need to make it slightly more specific by only calculating the distance between certain pairs of atoms
input
ATOM 5 CA PHE 1 113.142 75.993 130.862
ATOM 119 CA LEU 7 113.101 72.808 140.110
ATOM 138 CA ASP 8 109.508 74.207 140.047
ATOM 150 CA LYS 9 108.132 70.857 141.312
ATOM 172 CA LEU 10 110.758 70.962 144.119
e.g distance between all pairs for atoms 5, 119, 150 and 172 (say), last three columns are x,y and z co-ordinates
code it self
import java.util.*;
import java.io.*;
public class Distance {
public static void main(String[] args) {
System.out.println("***Campbells PDB Distance Calculator***" + "\n");
new Distance();
System.out.println("\nResults printed to file DistanceCalculations" + "\n");
System.out.println("\nDue to nature of code, if rerun results will be appended to the end of previous run.");
public Distance() {
Vector atomArray = new Vector();
String line;
try{
System.out.println("Enter PDB file:" + "\n");
BufferedReader inputReader =new BufferedReader (new InputStreamReader(System.in));
String fileName = inputReader.readLine();
if ( fileName !=null) {
BufferedReader inputDistance = new BufferedReader (new FileReader (fileName));
while (( line = inputDistance.readLine()) !=null && !line.equals(""))
Atom atom = new Atom(line);
atomArray.addElement(atom);
for (int j=0; j<atomArray.size(); j++) {
for (int k=j+1; k<atomArray.size(); k++) {
Atom a = (Atom) atomArray.elementAt(j);
Atom b = (Atom) atomArray.elementAt(k);
Atom.printDistance (a,b);
} //if
} //try
catch (IOException e) {
System.out.println("Input file problem");
} catch (Exception ex) {
System.out.println (ex);
class Atom {
public double x, y, z;
public String name;
public Atom(String s) throws IllegalArgumentException {
try {
StringTokenizer t = new StringTokenizer (s, " ");
t.nextToken();
this.name = t.nextToken();
for (int j=0; j<3; j++) t.nextToken();
this.x = new Double(t.nextToken()).doubleValue();
this.y = new Double(t.nextToken()).doubleValue();
this.z = new Double(t.nextToken()).doubleValue();
catch (Exception ex) {
throw new IllegalArgumentException ("Problem!!!! :-(");
public String toString() {
return "atom : " + name + "(x=" + x + " y=" + y + " z=" + z + ")";
public double distanceFrom (Atom other) {
return calculateDistance (x, y, z, other.x, other.y, other.z);
public static double calculateDistance (double x1, double y1, double z1, double x2, double y2, double z2) {
return Math.sqrt(Math.sqrt(Math.pow(Math.abs(x1-x2),2)+Math.pow(Math.abs(y1-y2),2))+Math.pow(Math.abs(z1-z2),2));
public static void printDistance (Atom a, Atom b) {
try{
FileWriter fw = new FileWriter("DistanceCalculations", true);
PrintWriter pw = new PrintWriter (fw, true);
if
(a.distanceFrom(b) <9){
pw.println("Distance between " + a.toString() + " and " + b.toString() + " is " + a.distanceFrom(b));
pw.flush();
pw.close();
} // if??
} //try loop
catch(IOException e) {
System.out.println("System error");
}

ok, essentially
want to calculate distance between to ranges. Say
range 1 is the first three, range 2 the rest. THen
calculate distance between all possible pairs between
these two rangesYes - and no doubt that any number of people here could write it for you. But that's not what the forum is about. So what, exactly, is preventing you from doing it?
Sylvia.

Find driving distance between two points without using API by use of Lat & Long?

Using Google geocode API : http://maps.googleapis.com/maps/api/geocode/xml?address=thane&sensor=true
We performed get distance between search criteria entered by user and all related clubs by lat & long stored at db.
2. Two different points such as
(origin: Lat1 & Long1) and (destination: Lat2 & Long2)
We tried for to get distance between these two points,
(Lat2 & Long2) to (Lat1 & Long1)
But distance which we get by calculation is simple straight line distance
Origin Destination
(Lat1 & Long1) (Lat2 & Long2)
3. This is not driving distance as google shows in exact Km
4. For that Google provide another API (distancematrix API)
http://maps.googleapis.com/maps/api/distancematrix/xml?origins=Thane&sensor=true&destinations=khopat&mode=driving&language=en%20-%20EN
5. But there is limit for DistanceMatrix-Service without ClientID and client key
100 elements per query.
100 elements per 10 seconds.
2 500 elements per 24 hour period.
But as element request exceeds it shows : OVER_QUERY_LIMIT error
6. In case of Client ID and Client key
In Distance Matrix 100 000 elements per 24 hour period,a maximum of 625 elements per query and a maximum of 1 000 elements per 10 seconds.
As per this one there is option to get purchase these API but basic question is remain same for us if we are requesting single origin and multiple destination then how element calculation done by google?
But in document google says :
Elements
The information about each origin-destination pairing is returned in an element entry. An element contains the following fields:
Status: See Status Codes for a list of possible status codes.
Duration: The duration of this route, expressed in seconds (the value field) and as text. The textual representation is localized according to
the query's language parameter.
Distance: The total distance of this route, expressed in meters (value) and as text. The textual value uses the unit system specified with the
unit parameter of the original request, or the origin's region.

Any information that you see in a google map webpage can be retrieved using the API. The best way of finding the tags on the webpage is to manually perform the query using an IE webpage. Then capture the source and save to a file so you
can use a text editor to look at results. I often on a webpage use the menu : View - Source and then copy the source to a text file.
jdweng

Finding Distance between two zipcodes with longtitude and latitude

Want to find distance between two zipcodes that have their latitude and longitude stored in a table.
The table is as follows
CREATE TABLE distance (zipcode VARCHAR2, LNG NUMBER, LAT NUMBER)
I couldn't come up with a calculation or understand the mathematical calculation on line.. Can you help me with some stored procedure that will do..?
Thanks

There is no logical complexity in your query besides knowing the basics of
http://en.wikipedia.org/wiki/Spherical_coordinates
Also, the table name "Distance" cannot be more confusing; what you have is essentially "PointsOnSphere".
select R*sqrt(
(sin(pi-p1.lng)*cos(p1.lat)-sin(pi-p2.lng)*cos(p2.lat))* (sin(pi-p1.lng)*cos(p1.lat)-sin(pi-p2.lng)*cos(p2.lat))
+
(sin(pi-p1.lng)*sin(p1.lat)-sin(pi-p2.lng)*sin(p2.lat))*
(sin(pi-p1.lng)*sin(p1.lat)-sin(pi-p2.lng)*sin(p2.lat))
+
(cos(pi-p1.lng)-cos(pi-p2.lng))*(cos(pi-p1.lng)-cos(pi-p2.lng))
from distance p1, distance p2
where R is the radius of Earth, and pi=3. Don't forget to convert angular degrees into radiants before you plug in them into the query above
Correction: This was euclidean distance sqrt((x1-x2)^2+(y1-y2)^2+(z1-z2)^2) between the points (x1,y1,z1) and (x2,y2,z2). Spherical distance is
sqrt(
(R*(colatitude1-colatitude2))^2+
(R*sin(colatitude1-colatitude2)*(longtitude1-longtitude2))^2
Message was edited by:
Vadim Tropashko

Distance between zipcodes

Want to find distance between two zipcodes that have their latitude and longitude stored in a table.
The table is as follows
CREATE TABLE distance (zipcode VARCHAR2, LNG NUMBER, LAT NUMBER)
I couldn't come up with a calculation or understand the mathematical calculation on line.. Can you help me with some stored procedure or straight query that will do..?
Thanks

Hi
Your best bet here is to convert the long/lat values to the spatial 'sdo_geometry' and use the sdo_geom.sdo_distance function.
-- create table
CREATE TABLE distance (zipcode VARCHAR2(5), LNG NUMBER, LAT NUMBER);
-- Add sample rows
insert into distance values (90210,-118.4099,34.0925);
insert into distance values (90806,-118.1894,33.8039);
-- add geometry column
alter table distance add geom sdo_geometry;
-- convert coordinates to geometry
update distance set geom = sdo_geometry(2001,8265,sdo_point_type(lat,lng,null),null,null);
commit;
-- example usage
select from_zipcode,to_zipcode,sdo_geom.sdo_distance(from_geom,to_geom,0.005,'unit=mile') distance
from
(select zipcode from_zipcode,geom from_geom
from distance
where zipcode = '90210') f,
(select zipcode to_zipcode,geom to_geom
from distance
where zipcode = '90806') t;
FROM_ZIPCODE TO_ZIPCODE DISTANCE
90210 90806 17.9768483148904 This distance is of course 'straight line' and not driving / walking time!
The '8265' above is the spatial reference identifier and I think is the right value to use here, although I'm sure my American counterparts will be happy to correct me if I have this wrong (i'm based in the UK and don't use American data that much anymore....)
If you wish to do any other analysis (such as nearest neighgbour etc) you will need to add metadata and a spatial index to this example....
You could implement the Great Circle calculation yourself and completely avoid using locator/spatial altogether but this would involve more code (= time = money).
Steve

Widgets that calculate distance between locations?

         I am wondering if there are any widgets available that will let me calculate the distance (in miles) between two locations (within the USA)
(If need be I could also work with a widget or app that will provide the distance between only cities and as opposed to specific addresses)
One with a map would be nice, but I'd be totally fine and super happy with the simplest of widgets to calculate mileage.
If there are no widgets that do this, then could someone suggest a good app that does this?   I have used 'eMaps' for calculating the mileage, but eMaps is a pain when you are using the 'Directions' function. Just some weird glitches/behavior, essentially just being a pain in the ***. I will be using this for work, I am a salesman in a steel company. So preferably I would like a widget (or app if all else fails) that is relatively simple, works well and is quick.
The exact mileage is needed for me to calculate 'freight rates' when I am preparing a quote for a customer. Needless to say, I cannot afford to tag another 10-15 mins onto this simple process everytime i have to get a freight rate, which is what ends up happening when using 'eMaps'.
Thank-you to everyone for your time and help!
Sincerely,
Otto
Centennial Steel

         I am wondering if there are any widgets available that will let me calculate the distance (in miles) between two locations (within the USA)
(If need be I could also work with a widget or app that will provide the distance between only cities and as opposed to specific addresses)
One with a map would be nice, but I'd be totally fine and super happy with the simplest of widgets to calculate mileage.
If there are no widgets that do this, then could someone suggest a good app that does this?   I have used 'eMaps' for calculating the mileage, but eMaps is a pain when you are using the 'Directions' function. Just some weird glitches/behavior, essentially just being a pain in the ***. I will be using this for work, I am a salesman in a steel company. So preferably I would like a widget (or app if all else fails) that is relatively simple, works well and is quick.
The exact mileage is needed for me to calculate 'freight rates' when I am preparing a quote for a customer. Needless to say, I cannot afford to tag another 10-15 mins onto this simple process everytime i have to get a freight rate, which is what ends up happening when using 'eMaps'.
Thank-you to everyone for your time and help!
Sincerely,
Otto
Centennial Steel

Distance between V490 an SE3500 as DAS ?

hi there,
i've a question concerning the suggestive max distance between sun v490 (2 Gb HBA) and the StorEdge3500 FC-Array.
a customer wants to create physical separation of his servers. so there are two v490 servers cross-connected to two
3500er fc-arrays. he plans to divide them into two rooms but with given access to both storage-systems.
there are no san-switches in use, so they are direct attached to the storage.
the max. theoretical length of a multimode optical fibre cable is round about 500 m - but does anyone know
if this is really possible ? or is the latency to high then ?
all in one i need to know if there can be really problems when the given enviroment (attachted in one rack) is
divided into to rooms without changing any HBAs or implementing some sansw - only by changing the optical
fibre cables ?
are there any whitepapers concerning this issue and the maximal distance with the 3500er acting as direct-attatched-storage ?
best regards
Stefan
(sorry about my english :) )

Hello bmeecg,
Welcome to the NI forums! If I understand your question correctly, you wish to calculate the instantaneous heart rate from your ECG (the inverse of your R-R interval). I would recommend using the Peak Detection vi (Functions Palette»Signal Processing»Signal Operation) to determine the location of the R wave (since it is the largest magnitude, you could set a threshold above your P and T waves so that it only picks up the R wave). The calculation for time is in the detailed help for the Peak Detection vi (Ctrl+H»Hover over the VI»Detailed Help).
I also found this forum which has a VI that reads an ECG and then does a lot of analysis. Maybe this would help you out as well.
And just FYI, the Counter/Timer forum is oriented toward our counter/timer boards (e.g. the PCI-6602), the Multifunction DAQ forum probably would have more of the type of people that could help with this issue.
However, please post back here if you have more questions about this.
Neal M.Applications Engineering National Instruments www.ni.com/support

Diversity - Distance between Antennas

Considering both antennas are similar-type and gain the two imp criterias i read in achiveing Diversity is
1. Antennas should be placed close enough to each other so that the RF coverage area is nearly identical.
2. The receiving antennas are spaced sufficiently apart to achieve independence (no coupling) between the received signals.
So the distance between both the antenna would be important.
In a cisco doc,
http://www.cisco.com/en/US/tech/tk722/tk809/technologies_tech_note09186a008019f646.shtml
For 2.4GHz wavelength = 12.5cm and for 5GHz wavelength = 6cm.
Hence for 2.4GHz wavelength,
Dist bet diversity Ant = 12.5cms Or 25cms or 37.5cms or 50cms
now from below POST:
http://forums.cisco.com/eforum/servlet/NetProf?page=netprof&forum=Wireless%20-%20Mobility&topic=WLAN%20Radio%20Standards&topicID=.ee6e8c2&fromOutline=&CommCmd=MB%3Fcmd%3Ddisplay_location%26location%3D.2cc18267
The spacing can be in multiples but is best in multiples of odd numbers. 1x or 3x. This allows for the phase to be always 100% out for the opposing antennae. 2x could cause phase shift overlay and could result in both antennae receiving the same phase shift differentiation.
Is this true? then my choise would narrow down to "Dist bet diversity Ant=12.5cms or 37.5cms'
But from below POST iam confused regarding point 1 and 2 (I have put them pointwise just for reference)
http://forums.cisco.com/eforum/servlet/NetProf?page=netprof&forum=Wireless%20-%20Mobility&topic=WLAN%20Radio%20Standards&topicID=.ee6e8c2&fromOutline=&CommCmd=MB%3Fcmd%3Ddisplay_location%26location%3D.2cc0332d
1. Never should you have the antennas exactly one wavelength away from each other. For the frequency of 2400, one wavelength is 4.92"... so any distance that is not a multiple of 4.92 and no more than a multiple of 4 is recommended.
2. You should use 1/2 wavelength distances and to be safe no more than multiple of 3.
My Questions are
1. Should the distance between my Antennas for diversity be any len more than 12.5 cms and less than 25cms or more than 37.5cms and less than 50cms?
2. Is it that the distance between my Antennas for diversity should not be exactly equal to the multiple of wavelengths? (12.5cms, 25cms, 37.5cms, 50cms)
3. Is it that i have to use only odd wavelengths multiples? (12.5cms, 37.5cms) and should not use even multiples?
4. The use 1/2 wavelength distances between the antennas is diversity. Is it ok? or is the minimum 1 wavelength as specfied in the cisco doc.
Also from the below POST iam confused regarding the MAX distance:
http://forums.cisco.com/eforum/servlet/NetProf?page=netprof&forum=Wireless%20-%20Mobility&topic=WLAN%20Radio%20Standards&topicID=.ee6e8c2&fromOutline=&CommCmd=MB%3Fcmd%3Ddisplay_location%26location%3D.1dd7905b
"Distance beyond 1-2 wavelengths is not critical. Since the antennas are not transmitting and/or receiving at the same time,there is no real chance of overloading the other antenna or radio front-end. "
There's not really a "max distance" as far as diversity is concerned. By placing the antennas some distance apart (the minimum, I believe, is ~one wavelength), you optimize the chance that a signal that is null (or interfered with) on one side, isn't on the other.
my question is
5. Is there a max distance between the antennas in diversity (like we read 4xwavelength) or there is no max distance? then wont there evolve a different RF coverage area for both the Antennas?
Another important question
> If my wireless card supports 5GHZ and 2.4GHZ and hence my antennas would be dual band. Then to achive antenna Diversity, what would be the distance between the two antennas? The minimum distance should be 1 wavelength, so For 2.4GHz wavelength = 12.5cm and for 5GHz wavelength = 6cm.
For a dual band antenna? how much should it be? Whats the min and max.
someone please can help me solve the huge confusion in my mind :)

First, let me say that this is certainly a well-done post, good job of back-tracking the links and expressing your questions.
The next thing is that there are more than a few nuances when dealing with RF and signal transmission and propagation, so to cover a specific topic fully would frequently cover more space than provided.
With all that dancing out of the way ;-), I'll take a shot at answering your questions...
"Is there a max distance ... ?"
Well, no, not really ... but there is a max *effective* distance and a fairly specific point of diminishing returns (as mentioned in the linked posts).
The design and implementation goal is to create a sort of "binocular view" with the antennas, such that the chance of a "null" is reduced, such that the signal / pattern developed from the diverse pair of antennas will create at least one clean and clear (reduced multipath, reduced nulls, possibly better line of sight)signal to (ideally) every client in the coverage area.
Even though only one antenna is active at any given time, having any conductor within the radiated field will distort the transmission envelope, either positively (in the case of a Yagi) or negatively (in the case of a grounded conductor, like a sprinkler head).
The amount of the distortion, and the shape of the distortion are functions of the size and shape of the parasitic element. The effect is so variable that it is one of the foundations for the contention that a comprehensive site survey is not really an option, it's mandatory; it's truely the only way to see what adaptations are necessary to make the "rules of thumb" function in the specific location.
Regarding antennas handling multiple bands:
The antennas (in this case) are close to resonant multiples. The differences are such that the logical / electrical length can be adjusted by adding inductive or capacitive loads at the transmitter or feed point.
Even though the physical shape of the antennas may be different from model to model, the electrical load characteristics for a given band / antenna remain similar, so electronically compensating to make an antenna primarily designed for 2.4GHz function well for 5.6GHz is not especially difficult. Going from the longer wavelength to the shorter is more effective and easier to design than trying to go the other way.
For example, a quarter-wave 2.4GHz antenna is easily compensated to create a good half wave (or loaded 5/8) 5.6GHz antenna.
So, (finally) to provide the proper spacing for a diverse pair of multi-band antennas, figure for the longer wavelength (2.4GHz in this case) and the (roughly double) distance is likely to be acceptable for the higher wavelength. The spacing doesn't have to be exact; personally, I used to shoot for ~18" (variable with the mounting location and antenna type)and I always had pretty good luck, according to the follow-up survey.
Because of the jillions of possible variables, you can't just calculate and hang the antennas and be done ... a survey should be done to verify the installations and to make educated adjustments that will optimize the system for that specific location and environment.
The initial calculations are ideal guidelines, then you make adjustments to cover things like metal wall studs, sprinkler heads, the boss' favorite "wall o' vines" ... you will rarely get a perfect environment, adjustments are almost always required.
It's late and I'm starting to babble ... ponder the above and let us know if it helped any. There are a great bunch of experienced folks here, and I think this will be the start of a great discussion.
Good Luck
Scott

HP Envy 17t-j100 Distance between USB Slots suggestion

I intended this post as a recommandation for HP.
I have an HP Envy Touchsmart 17t-j100 and everything is excelent up until now.
The only thing that is very annoying is the distance between USB ports. PLEASE increase the distance between USB ports for the future models. I have a lot of problems tryng to connect everything I need.
Even if I try to open the DVD drive, it will stuck in my USB device. I mean how much difficult is to put a distance of 1 cm between them?
If the USB cables are the standard size, there are no problems but most of the USB devices nowadays are much more wider than a standard USB cable and I keep having problems.
I mean it's a 17" laptop, there is plenty of space on the sides. In the end, it's better to drop the DVD drive and put a VGA slot instead, but with bigger distance between USB ports.
I am planning to buy another ENVY in the future but I really want my new laptop to have USB ports with a wider distance bewtween them.
Thank you very much and I hope HP will take care of this little problem on the future models.
Have a nice day.
This question was solved.
View Solution.

Hi @catapara89 ,
Thank you for visiting the HP Support Forums and Welcome. Thanks so much for taking the time to let us know of your suggestions on the USB slots. It is important and has been viewed.
Have a great week.
Thanks.
Please click “Accept as Solution ” if you feel my post solved your issue, it will help others find the solution.
Click the “Kudos, Thumbs Up" on the bottom to say “Thanks” for helping!

What is the maximum distance between a time capsule and an airport express?

What is the maximum distance between a time capsule and an airport express?

You can only "extend" the signal one time, so you need to have the AirPort Express located approximately 1/2 to 2/3 of the distance from the Time Capsule to the area that needs more wireless coverage.
I doubt that this will help much since you have a very challenging setup. Wireless is really only for "same room" or "nearby rooms" around the corner.
To do this correctly you will need to use an Ethernet cable connection from the Time Capsule to the AirPort Express, which could then be located close to the xBox.
If it is not possible to run the Ethernet cable, you might look at a pair of Ethernet powerline adapters to send a "psuedo" Ethernet signal over the AC wiring in your home.
This will not be anywhere near the performance of a regular Ethernet cable, but it will likely be much better than wireless.
Since Ethernet over powerline (EOP) is somewhat unpredictable, you would want to have a very clear understanding of the store's return policy in case things don't work out as hoped. Any computer / electronics superstore will have a selection of powerline adapters to choose from.

How do I cancel the distance between the numbers? I'm having trouble copy phone numbers from the phone book and send it via SMS This problem I've found in the Arabic language, numbers appear in reverse Please help System 6.0.1

How do I cancel the distance between the numbers?
I'm having trouble copy phone numbers from the phone book and send it via SMS
This problem I've found in the Arabic language, numbers appear in reverse
Please help
System 6.0.1

MPEG-4 should not be used in FCP unless it is converted first or optimized in the application.
Trash your preferences. Trash your project render files. Switch off background rendering. Do not re-render. Export your projects.
Ignore the last frame and first frame indicators.

Calculating Distance given a 4 point 2D image

Hi All,
3d n00b so play nice :-)
I'm trying to use a Wii remote camera to calculate real world distance from an object in Java.
The Wiimote will supply me the x and y coordinates of the 4 point object, which is actually 4 lights on the floor in this configuration.
I know the exact measurements of the 4 objects and the distance between them in the real world.
I know the 2D co-ordinates as represented on a 1024x768 screen.
I know the Angle of the Wiimote.
The lights will only ever be on a flat horizontal plane.
Is there anyway to reverse transform the 2D image from the camera back into 3D, taking into account the fact that the image may be rotated, and thus calculate the distance in the real world?
I'm guessing its some clever trig and some wizzy transformations although its been 20 years since I was in school! :-)
If you need any more explenation I'd be happy to attach some drawings.
Thanks in advance.
Uzerfriendly

hi
did you ever find out anything regarding your query?
i was trying to solve maybe a similar problem
though i'm not sure
how can i calculate the distance of an object of a known size (say, a person) that appears in a picture
presupposing the picture was image is not magnified or is somehow "sstandardized" or somehow "like" human vision
does it make any sense?
be happy to hear
thanks
doron

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