Can I make a dynamic video player stop just by exiting the frame and entering a new one?

Question

Ok so I have a flash presentation with a video clip which I am playing dynamically using a URL netStream. The problem is not getting it to play but rather getting it to stop playing. If I click the stop button, it stops, But if I just navigate to  a new frame, the video disappears but I can still hear the audio. (the only reason it disappears is because i used "video.visible = false" on all other frames other than the one I need it to play on. Additionally, If I navigate to a new frame while the video is playing, I cannot stop it or restart if I return back to the frame that the video is located on. Its like all my video control buttons are rendered useless if I leave the frame while it is playing. Do I need some sort of eventlistener or custom function? I hope I explained that well enough.
Here is my code if anyone has any suggestions.
Thanks!
  //video code
  var video:Video = new Video(480,204);
  video.y = stage.stageHeight / 2 - 278 / 2;
  video.x = stage.stageWidth / 2 - 290 / 2;
  addChild(video);
    var nc:NetConnection = new NetConnection();
  nc.connect(null);
  var ns:NetStream = new NetStream(nc);
  ns.addEventListener(NetStatusEvent.NET_STATUS, onStatusEvent);
  function onStatusEvent(stat:Object):void
  trace(stat.info.code);
  var meta:Object = new Object();
  meta.onMetaData = function(meta:Object){
  trace(meta.duration);
  ns.client = meta;
  video.attachNetStream(ns);
  btn_playvid.addEventListener(MouseEvent.CLICK, playFunction);
  function playFunction(evt:MouseEvent):void
  ns.play("assets/movie.mp4");
  btn_stopvid.addEventListener(MouseEvent.CLICK, stopFunction);
  function stopFunction(evt:MouseEvent):void
  ns.pause();

Answer 1

You need to call your stopFunction if you leave the frame as the video will continue to play. When you come back to this frame, you're creating a new video instance and NetStream, etc... If you place your video at a random x,y you should see that you have multiple video instances. You need to separate your init code from your control code.