Can I use regular expression in JCR QueryBuilder?

I want to find all the pages with cq:tag which end with "/testingtag"
is it possible to do so using ?
Are there any online tutorial on JCR QueryBuilder?
I tried something like that but unfortunately it is not showing what I expected to see
fulltext=testingtag$
type=cq:tags

Note that the querybuilder is a CQ (AEM) specific feature. A google search should give you what you want in the first search results: http://lmgtfy.com/?q=cq+querybuilder
Now regarding your specific question: you want to use the property predicate with the like operation:
property=cq:tags
property.value=%/testingtag
property.operation=like
However, I don't see why you would want to search for all tags ending with a certain name. Tags must always be present under /etc/tags to be valid and so the logic would always be "let the user search/select some tags, and then search for that list specifically". Use the cq tagging API (javadocs) and also the querybuilder tag predicates (which are unfortunately not so well documented):
tagid=some:tag/id
tagid.property=jcr:content/cq:tags # to set a different property path; the default is cq:tags
See also http://forums.adobe.com/message/4691188, http://forums.adobe.com/message/5223518 or https://www.sfu.ca/itservices/cms/howto/advanced/organize-and-optimize/advanced-queries.ht ml for some tagid predicate samples.

Similar Messages

Can I use regular expressions in Java 1.3

Hi,
Dose Java 1.3 suport regular expressions?
How can I use it?
Thanks.
bevin ye

The 1.3 core API doesn't support regular expressions. Hint: There's an item "Since:" in the JavaDoc of most classes that indicates the version it was initially available. If you look it up in the JavaDoc of java.util.regex.Pattern you'll notice that it's value is 1.4.
But there are several third party libraries that implement regular expressions, 'though I've not used them extensivly, so I can't tell you which one's the most usefull.

How can I use regular expression to open files of certain types in java?

Ok this is the problem I am facing:
I have a command line input of something like "/usr/foo/bar/*.html"
and there are multiple files in that folder that end with .html.
How can I use the input to go through/open all the .html files in Java?
Help would be greatly appreciated thanks!

Or if you have to do it in java, check out the interfaces java.io.FileFilter and java.io.FileNameFilter
http://home.tiscali.nl/~bmc88/java/sbook/0128.html
class HTMLFilter implements FilenameFilter {
public boolean accept(File dir, String name) {
return (name.endsWith(".html"));
}Cheers,
evnafets

How can I use regular expression to match this rule

I have a String ,value is "<a>1</a><a>2</a><a>3</a>",and want to match other String like "<a>1</a><a>8</a>",if the one of the first string(like "<a>1</a>") will occur in the second string,then will return true.but I don't know how to write the regular expresstion.
Thx

Fine fine. :P
I was a little bored, so here's some code that uses Strings and a StringBuffer (though you could use a String in place of the StringBuffer). Is this perhaps better? :)
          String testMain = "<a>1</a><ab>2</ab><ab>3</ab>";
          String test = "<ab>1</ab><ab>3</ab>";
          String open = "<ab>";
          String close = "</ab>";
          StringBuffer search = new StringBuffer();
          String checkString = null;
          int lastCheck = 0;
          int start = 0;
          int finish = 0;
          boolean done = false;
          while (!done) {
               start = test.indexOf(open);
               finish = test.indexOf(close);
               if ((start == -1) || (finish == -1)) {
                    System.out.println("No more tags to search for.");
                    done = true;
               else {
                    checkString = test.substring((start + open.length()), finish);
                    search = new StringBuffer();
                    search.append(open);
                    search.append(checkString);
                    search.append(close);
                    if (testMain.indexOf(search.toString()) != -1) {
                         System.out.println("Found value: " + checkString);
                    test = test.substring(finish + close.length());
Resulting output:
Found value: 3
No more tags to search for.
-G

Using regular expressions for validation in i18n

Can we use regular expressions for validation of inputs in a java application taking care of i18N aspects too. Zip code for different locales are different. Can we use regular expressions to validate zipcode inputs from different locales

hi,
For that shall i have to create individual patterns for matching the inputs from different locales or a single pattern will do in the case of validating phone nos. around the world, zip codes etc. In case different patterns are required, programmer should have a konwledge of difference in patters for different locales.
regards
sdas

How to use regular expression to delete a character?

Hello,
I have a query,
select partition_name from dba_tab_partitions where table_owner='xxx'and num_rows <>0 and table_name = 'xxx';
P5
P6
P7
P12
P13
P14
P17
P18
P19
P20
P24
How can I use regular expression in above SQL query to get result without letter 'P', like..
5
6
7
12
13
14
17
18
19
20
24
thank you

I find answer...
select regexp_replace(partition_name,'P','')
thanks anyway

Trying to use regular expressions to convert names to Title Case

I'm trying to change names to their proper case for most common names in North America (esp. the U.S.).
Some examples are in the comments of the included code below.
My problem is that *retName = retName.replaceAll("( [^ ])([^ ]+)", "$1".toUpperCase() + "$2");* does not work as I expect. It seems that the toUpperCase method call does not actually do anything to the identified group.
Everything else works as I expect.
I'm hoping that I do not have to iterate through each character of the string, upshifting the characters that follow spaces.
Any help from you RegEx experts will be appreciated.
{code}
* Converts names in some random case into proper Name Case. This method does not have the
* extra processing that would be necessary to convert street addresses.
* This method does not add or remove punctuation.
* Examples:
* DAN MARINO --> Dan Marino
* old macdonald --> Old Macdonald <-- Can't capitalize the 'D" because of Ernst Mach
* ROY BLOUNT, JR. --> Roy Blount, Jr.
* CAROL mosely-BrAuN --> Carol Mosely-Braun
* Tom Jones --> Tom Jones
* ST.LOUIS --> St. Louis
* ST.LOUIS, MO --> St. Louis, Mo <-- Avoid City Names plus State Codes
* This is a work in progress that will need to be updated as new exceptions are found.
public static String toNameCase(String name) {
* Basic plan:
* 1. Strategically create double spaces in front of characters to be capitalized
* 2. Capitalize characters with preceding spaces
* 3. Remove double spaces.
// Make the string all lower case
String retName = name.trim().toLowerCase();
// Collapse strings of spaces to single spaces
retName = retName.replaceAll("[ ]+", " ");
// "mc" names
retName = retName.replaceAll("( mc)", " $1");
// Ensure there is one space after periods and commas
retName = retName.replaceAll("(\\.|,)([^ ])", "$1 $2");
// Add 2 spaces after periods, commas, hyphens and apostrophes
retName = retName.replaceAll("(\\.|,|-|')", "$1 ");
// Add a double space to the front of the string
retName = " " + retName;
// Upshift each character that is preceded by a space
// For some reason this doesn't work
retName = retName.replaceAll("( [^ ])([^ ]+)", "$1".toUpperCase() + "$2");
// Remove double spaces
retName = retName.replaceAll(" ", "");
return retName;
Edited by: FuzzyBunnyFeet on Jan 17, 2011 10:56 AM
Edited by: FuzzyBunnyFeet on Jan 17, 2011 10:57 AM

Hopefully someone will still be able to provide a RegEx solution, but until that time here is a working method.
Also, if people have suggestions of other rules for letter capitalization in names, I am interested in those too.
* Converts names in some random case into proper Name Case. This method does not have the
* extra processing that would be necessary to convert street addresses.
* This method does not add or remove punctuation.
* Examples:
* CAROL mosely-BrAuN --> Carol Mosely-Braun
* carol o'connor --> Carol O'Connor
* DAN MARINO --> Dan Marino
* eD mCmAHON --> Ed McMahon
* joe amcode --> Joe Amcode         <-- Embedded "mc"
* mr.t --> Mr. T                    <-- Inserted space
* OLD MACDONALD --> Old Macdonald   <-- Can't capitalize the 'D" because of Ernst Mach
* old mac donald --> Old Mac Donald
* ROY BLOUNT,JR. --> Roy Blount, Jr.
* ST.LOUIS --> St. Louis
* ST.LOUIS,MO --> St. Louis, Mo     <-- Avoid City Names plus State Codes
* Tom Jones --> Tom Jones
* This is a work in progress that will need to be updated as new exceptions are found.
public static String toNameCase(String name) {
     * Basic plan:
     * 1. Strategically create double spaces in front of characters to be capitalized
     * 2. Capitalize characters with preceding spaces
     * 3. Remove double spaces.
    // Make the string all lower case
    String workStr = name.trim().toLowerCase();
    // Collapse strings of spaces to single spaces
    workStr = workStr.replaceAll("[ ]+", " ");
    // "mc" names
    workStr = workStr.replaceAll("( mc)", " $1 ");
    // Ensure there is one space after periods and commas
    workStr = workStr.replaceAll("(\\.|,)([^ ])", "$1 $2");
    // Add 2 spaces after periods, commas, hyphens and apostrophes
    workStr = workStr.replaceAll("(\\.|,|-|')", "$1 ");
    // Add a double space to the front of the string
    workStr = " " + workStr;
    // Upshift each character that is preceded by a space and remove double spaces
    // Can't upshift using regular expressions and String methods
    // workStr = workStr.replaceAll("( [^ ])([^ ]+)", "$1"toUpperCase() + "$2");
    StringBuilder titleCase = new StringBuilder();
    for (int i = 0; i < workStr.length(); i++) {
        if (workStr.charAt(i) == ' ') {
            if (workStr.charAt(i+1) == ' ') {
                i += 2;
            while (i < workStr.length() && workStr.charAt(i) == ' ') {
                titleCase.append(workStr.charAt(i++));
            if (i < workStr.length()) {
                titleCase.append(workStr.substring(i, i+1).toUpperCase());
        } else {
            titleCase.append(workStr.charAt(i));
    return titleCase.toString();
{code}

Using regular expressions in java

Does anyone of you know a good source or a tutorial for using regular expressions in java.
I just want to look at some examples....
Thanks

thanks a lot... i have one more query
Boundary matchers
^      The beginning of a line
$      The end of a line
\b      A word boundary
\B      A non-word boundary
\A      The beginning of the input
\G      The end of the previous match
\Z      The end of the input but for the final terminator, if any
\z      The end of the input
if i want to use the $ for comparing with string(text) then how can i use it.
Eg if it is $120 i got a hit
but if its other than that if should not hit.

Changeparticular characters in a string by using regular expressions ...

Hello Everyone,
I am trying to write a function by using oracles regular expression function REGEXP_REPLACE but I could not succed till now.
My problem as follows, I have a text in a column for example let say 'sdfsdf Sdfdfs Sdfd' I want replace all s and S characters with X and make the text look like 'XdfXdf XdfdfX Xdfd'.
Is it possible by using regular expressions in oracle ?
Can you give me some clues ?
Thank you

SSU wrote:
Hello Everyone,
I am trying to write a function by using oracles regular expression function REGEXP_REPLACE but I could not succed till now.
My problem as follows, I have a text in a column for example let say 'sdfsdf Sdfdfs Sdfd' I want replace all s and S characters with X and make the text look like 'XdfXdf XdfdfX Xdfd'.
Is it possible by using regular expressions in oracle ?
Can you give me some clues ?
Thank you
SQL> SELECT
2 regexp_replace('sdfsdf Sdfdfs Sdfd','s|S','X') from dual;
REGEXP_REPLACE('SD
XdfXdf XdfdfX XdfdRegards,
Achyut

Using regular expressions for validating time fields

Similar to my problem with converting a big chunk of validation into smaller chunks of functions I am trying to use Regular Expressions to handle the validation of many, many time fields in a flexible working time sheet.
I have a set of FormCalc scripts to calculate the various values for days, hours and the gain/loss of hours over a four week period. For these scripts to work the time format must be in HH:MM.
Accessibility guidelines nix any use of message box pop ups so I wanted to get around this by having a hidden/visible field with warning text but can't get it to work.
So far I have:
var r = new RegExp(); // Create a new Regular Expression Object
r.compile ("^[00-99]:\\] + [00-59]");
var result = r.test(this.rawValue);
if (result == true){
true;
form1.flow.page.parent.part2.part2body.errorMessage.presence = "visible";
else (result == false){
false;
form1.flow.page.parent.part2.part2body.errorMessage.presence = "hidden";
Any help would be appreciated!

Date and time fields are tricky because you have to consider the formattedValue versus the rawValue. If I am going to use regular expressions to do validation I find it easier to make them text fields and ignore the time patterns (formattedValue). Something like this works (as far as my very brief testing goes) for 24 hour time where time format is HH:MM.
// form1.page1.subform1.time_::exit - (JavaScript, client)
var error = false;
form1.page1.subform1.errorMsg.rawValue = "";
if (!(this.isNull)) {
var time_ = this.rawValue;
if (time_.length != 5) {
    error = true;
else {
    var regExp = /^([01]?[0-9]|2[0-3]):[0-5][0-9]$/;
    if (!(regExp.test(time_))) {
      error = true;
if (error == true) {
form1.page1.subform1.errorMsg.rawValue = "The time must be in the format HH:MM where HH is 00-23 and MM is 00-59.";
form1.page1.subform1.errorMsg.presence = "visible";
Steve

Matching substrings between square brackets using regular expressions

Hello,
I am new at Java and have a problem with regular expressions. Let me describe the issue in 3 steps:
1.- I have an english sentence. Some words of the sentence stand between square brackets, for example "I [eat] and [sleep]"
2- I would like to match strings that are in square brackets using regular expressions (java.util.regex.*;) and here is the code I have written for the task
+Pattern findStringinSquareBrackets = Pattern.compile("\\[.*\\]");+
+     Matcher matcherOfWordInSquareBrackets = findStringinSquareBrackets.matcher("I [eat] and [sleep]");+
+//Iteration in the string+
+          while ( matcherOfWordInSquareBrackets.find() )+
+{+
+          System.out.println("Patter found! :"+ outputField.getText().substring(matcherOfWordInSquareBrackets.start(), matcherOfWordInSquareBrackets.end())+"");     +
+          }+
3- the result I have after running the code described in 2 is the following: *Patter found!: [eat] and [sleep]*
That is to say that not only words between square brackets are found but also the substring "and". And this is not what I want.
What I would like to have as a result is:
*Patter found!: [eat]*
*Patter found!: [sleep]*
That is to say I want to match only the words between the square brackets and nothing else.
Does somebody know how to do this? Any help would be great.
Best regards,
Abou

You can find the words by looping through the sentence and then return the substring within the indexes.
int start=0;
int end=0;
for(int i=0; i<string.length(); i++)
   if(string.substring(i,i+1).equals("[");
start=i;
if(start!=0)
if(string.substring(i,i+1).equlas("]");
end=i;
return string.substring(start,end+1);
}something like that. This code will only find the firt word however. I do not know much about regex so I cannot help anymore.
Edited by: elasolova on Jun 16, 2009 6:45 AM
Edited by: elasolova on Jun 16, 2009 6:46 AM

Checking valid e-mail's using Regular expressions

Hey buddies ,
I desperately need some help here. I need to develop a generic method that wiull use regular expressions and patterns to validate an e-mail.
Does anyonw have any idea on how to do this. And if possible please share some code with me.
Thanks a lot

You can do regular expresions in java using java.util.regex.*:
import java.util.regex.*;
   Pattern p = Pattern.compile("\\S++\\s++");
   Matcher m = p.matcher(sInputLine);
   if(m.find()){
      sUser = m.group().trim();
   }For more info on regular expressions in java, check out the javadocs:
http://java.sun.com/j2se/1.4.2/docs/api/java/util/regex/Pattern.html

Requirement to update a column by using Regular Expression

Hi All,
    I have a requirement to update a column which is having values like below code.
based on the conditinos I need to update from ‘E’ to ‘Z’. Few positions I need to update and remaining positions I need leave as it is.
How I can achive this requirement by using regular expression regexp_replace.
Actual value --> 'AEAAAEAA    EE    AA    EE    AA    EE    EEEAA    AA    AA       '
After update --> 'AZAAAZAA    EE    AA    EE    AA    EE    EEEAA    AA    AA       '

below is my requirement. I am adding the conditions dynamically as per the conditions. I dont know the position of the E. If 'E' is in any position I need to update with 'Z' if that 'E' satisfy the condition.
I dont want to update all the E's to Z's.
I want to update specific E's which satisfy the condition.
    IF l_kwhhilow >= 1 THEN
        l_where := l_where||' SUBSTR(OVERRIDEFIELD,1,1) = ''E'' OR ';
        l_exp := l_exp||'Z';
    ELSE
        l_exp := l_exp||'\1';
    END IF;
    IF l_kwhilow >= 1 THEN
        l_where := l_where||' SUBSTR(OVERRIDEFIELD,2,1) = ''E'' OR ';
         l_exp := l_exp||'Z';
    ELSE
        l_exp := l_exp||'\2';
    END IF;
    IF l_kvahilow >= 1 THEN
        l_where := l_where||' SUBSTR(OVERRIDEFIELD,3,1) = ''E'' OR ';
         l_exp := l_exp||'Z';
    ELSE
        l_exp := l_exp||'\3';
    END IF;
    IF l_kvarhilow >= 1 THEN
        l_where := l_where||' SUBSTR(OVERRIDEFIELD,4,1) = ''E'' OR ';
         l_exp := l_exp||'Z';
    ELSE
        l_exp := l_exp||'\4';
    END IF;
    IF l_todkwh1hilow >= 1 THEN
        l_where := l_where||' SUBSTR(OVERRIDEFIELD,5,1) = ''E'' OR ';
         l_exp := l_exp||'Z';
    ELSE
        l_exp := l_exp||'\5';
    END IF;
    IF l_todkwh2hilow >= 1 THEN
        l_where := l_where||' SUBSTR(OVERRIDEFIELD,6,1) = ''E'' OR ';
         l_exp := l_exp||'Z';
    ELSE
        l_exp := l_exp||'\6';
    END IF;
    l_exp := ''''||l_exp||'''';
    l_exp1 := '\1\2\3\4'||l_exp1;
    IF l_todkw1hilow >= 1 THEN
        l_where := l_where||' SUBSTR(OVERRIDEFIELD,11,1) = ''E'' OR ';
         l_exp1 := l_exp1||'Z';
    ELSE
        l_exp1 := l_exp1||'\5';
    END IF;
    IF l_todkw2hilow = 1 THEN
        l_where := l_where||' SUBSTR(OVERRIDEFIELD,12,1) = ''E'' OR ';
         l_exp1 := l_exp1||'Z';
    ELSE
        l_exp1 := l_exp1||'\6';
    END IF;
    l_exp1 := ''''||l_exp1||'''';
IF i give 10 in the regexp_replace it is not working.
SET OVERRIDEFIELD =     REGEXP_REPLACE(SUBSTR(overridefield,1,6), ''(.)(.)(.)(.)(.)(.)'','||l_exp||')'||
                                          ' ||REGEXP_REPLACE(SUBSTR(overridefield,7,6), ''(.)(.)(.)(.)(.)(.)'','||l_exp1||')'||
                                          ' ||SUBSTR(overridefield,13)'||

Using Regular Expression

I do have a table with one varchar2 column with the following values:
COL_NAME
1.1.3.TECH.SG.1.Action.2
1.1.3.TECH.SG.1.Action.3
1.1.3.TECH.SG.1.Action.4
1.1.3.TECH.SG.1.Action.5
1.1.3.TECH.SG.1.Action.6
I need the last digit to be reduced by 1 like below:
COL_NAME NEW_VALUE
1.1.3.TECH.SG.1.Action.2 1.1.3.TECH.SG.1.Action.1
1.1.3.TECH.SG.1.Action.3 1.1.3.TECH.SG.1.Action.2
1.1.3.TECH.SG.1.Action.4 1.1.3.TECH.SG.1.Action.3
1.1.3.TECH.SG.1.Action.5 1.1.3.TECH.SG.1.Action.4
1.1.3.TECH.SG.1.Action.6 1.1.3.TECH.SG.1.Action.5
How can this be achieved by a SQL statement using Regular Expression ?
Pls suggest.
Regards
MS

You don't really need regexps, you can just use normal instr() and substr():
1 with v as (
2     select '1.1.3.TECH.SG.1.Action.2' as val from dual union all
3     select '1.1.3.TECH.SG.1.Action.3' as val from dual union all
4     select '1.1.3.TECH.SG.1.Action.4' as val from dual union all
5     select '1.1.3.TECH.SG.1.Action.5' as val from dual union all
6     select '1.1.3.TECH.SG.1.Action.6' as val from dual
7 )
8 select val
9 , substr(val, 1, instr(val, '.', -1))
10 || to_char(to_number(substr(val, instr(val, '.', -1) + 1)) + 1) new_val
11* from v
SQL> /
VAL                      NEW_VAL
1.1.3.TECH.SG.1.Action.2 1.1.3.TECH.SG.1.Action.3
1.1.3.TECH.SG.1.Action.3 1.1.3.TECH.SG.1.Action.4
1.1.3.TECH.SG.1.Action.4 1.1.3.TECH.SG.1.Action.5
1.1.3.TECH.SG.1.Action.5 1.1.3.TECH.SG.1.Action.6
1.1.3.TECH.SG.1.Action.6 1.1.3.TECH.SG.1.Action.7
5 rows selected.cheers,
Anthony

Searching for a substring using Regular Expression

I have a lengthy String similar to repetetion of the one below
String str="<option value='116813070'>Something1</option><option value='ABCDEF' selected>Something 2</option>"I need to search for the Sub string "<option value='ABCDEF' selected>" (need to get the starting index of sub string) and but the value ABCDEF can be anything numberic with varying length.
Is there any way i can do it using regular expressions(I have no other options than regular expression)?
thanks in advance.

If you go through the tutorial then you will find this on the second page:
import java.io.Console;
import java.util.regex.Pattern;
import java.util.regex.Matcher;
public class RegexTestHarness {
    public static void main(String[] args){
        Console console = System.console();
        if (console == null) {
            System.err.println("No console.");
            System.exit(1);
        while (true) {
            Pattern pattern =
            Pattern.compile(console.readLine("%nEnter your regex: "));
            Matcher matcher =
            pattern.matcher(console.readLine("Enter input string to search: "));
            boolean found = false;
            while (matcher.find()) {
                console.format("I found the text \"%s\" starting at " +
                   "index %d and ending at index %d.%n",
                    matcher.group(), matcher.start(), matcher.end());
                found = true;
            if(!found){
                console.format("No match found.%n");
}It's does everything you need and a bit more. Adapt it to your needs then write a regular expression. Then if you have problems by all means come back and post them up here, but first at least attempt to solve it yourself.

Can I use regular expression in JCR QueryBuilder?

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