Class to upload and download images

is there any class which we can use to upload and download images
only 1 restrain while downloadin it should NOT ask where to download
it should directly go to desktop.
please help
Edited by: Amit Sawant on Dec 20, 2007 10:45 AM

You have to call the Static methods of the Class: Cl_GUI_FRONTEND_SERVICES.
for UPLOAD:
call Method Cl_GUI_FRONTEND_SERVICES=>GUI_UPLOAD
for DOWNLOAD:
call Method Cl_GUI_FRONTEND_SERVICES=>GUI_DOWNLOAD
You can open this Class Cl_GUI_FRONTEND_SERVICES in Class builder SE24 and find these methods
Also refer to these links:
cl_gui_frontend_services
CL_GUI_FRONTEND_SERVICES
CALL METHOD CL_GUI_FRONTEND_SERVICES=>GUI_DOWNLOAD
Reward points if found helpful...
Cheers,
Chandra Sekhar.

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can anyone send me links how to to upload and download image to and from sever
Here i am using amfphp,mysql,php
i have an button and textfield.when i clicked on the button the path will be stored into database and image will be
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hi,
you need to first bring the image into your sap system.
that you can achieve by right clicking you application and then clicking on create mime object.
check out this link too:
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then you have to insert an image ui element in your view.
check out the link:
http://help.sap.com/saphelp_nw04/helpdata/en/f3/1a61a9dc7f2e4199458e964e76b4ba/content.htm
according to you req i think you need to upload and download the image file in your system using a button. so for this you can follow the below link:
https://www.sdn.sap.com/irj/scn/go/portal/prtroot/docs/library/uuid/00062266-3aa9-2910-d485-f1088c3a4d71
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Upload and Download images using API

Hi
I have an image catalog database where the actual images are stored on the database server filesystem and reduced size images are uploaded into the database. The user can browse and search the image catalog and see the reduced size images.
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Hi
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Uploading and downloading blobs without wwv_flow_files

Hi,
I am currently working on oracle 10g database and application express.
i went throu the material to upload and download images, pdf from a htmldb book.
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it seemed like we can only d/l the pdf, images and display on htmldb report only throu flows_files.wwv_flow_files view, as in the case of the script below
select
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from
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where
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Philip.

Hi,
I tried the document link you gave and it looks like, i can directly download pdfs from my own tables without needding to upload to wwv_flow_files_objecst$ table.
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when i click on the link a popup window with the option to save or open comes up.
but the popup window shows the filename as my procedure name through which i pass the id for the pdf document instaed of the filename which is shown as download link on the page.
How can i change this popup window filename to the default file name shown in the download link.
so that everytime i select the parameters, the page shows the pdf filename as link and on clicking the link the popup window should be able to show the same name shown as link.
i think this can be set either at the procedure level or at the page level.
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--        SET UP HTTP HEADER
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Link Attributes: target="_blank"
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Here the link text is the filename that i wanted to show when saving the file.
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Thanks,
Philip.

How to upload and Download the file in a system through java programing

I am trying to upload a file as well as want to download the uploaded file in my system....I don't have any server an all.
I want to implement this in my system only .
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can any one help me on this code ....please
here some piece of code
File Upload and Download Code Example
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sb.append( ':' );
sb.append( password );
sb.append( '@' );
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sb.append( fileName );
* type ==> a=ASCII mode, i=image (binary) mode, d= file directory
* listing
sb.append( ";type=i" );
BufferedInputStream bis = null;
BufferedOutputStream bos = null;
try
URL url = new URL( sb.toString() );
URLConnection urlc = url.openConnection();
bos = new BufferedOutputStream( urlc.getOutputStream() );
bis = new BufferedInputStream( new FileInputStream( source ) );
int i;
// read byte by byte until end of stream
while ((i = bis.read()) != -1)
bos.write( i );
finally
if (bis != null)
try
bis.close();
catch (IOException ioe)
ioe.printStackTrace();
if (bos != null)
try
bos.close();
catch (IOException ioe)
ioe.printStackTrace();
else
System.out.println( "Input not available." );
}

At least that is what the code you posted suggests to me.It looks like that to me too.
I believe that
URLConnection urlc = url.openConnection(url);Will return you an FTP URLConnection implementation if you pass it a ftp:// url
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Actually, looking at your code, this is already what you are doing, so I really don't get this:
am not using FTP server..... i want to implement in my system only ....So How i will do.
Can you give me any idea based on this code Can you explain a bit more what you need?
patumaire

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If the reason is about memory, warning message should be happened when upload the image, because "show thumbnail" means resize at second time, how come you failed to resize the picture that system let it upload succeed at the first time by the same resize process?
upload procedure
a.jpg: 2722x1814, 1.2mb
upload condition: fixed width 330px, 1.5mb
"upload and resize" a.jpg -> file upload -> "resize engine" -> passed (but not work and no warning message)
"show thumbnail" a.jpg -> "resize engine" -> failed (not enough memory)
it doesn't make sense.
and you miss an important key point, I upload the same picture myself, and resize work, so I said it happened at random, and that's why I am so worried.

Apex application file -upload and download a file.

hi
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Any idea where the file is stored?
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Dear nivesh!
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Workspace: flo_demo
Username: dev_null
Password: password
Application: 61811
Yours sincerely
Florian W.

Reg :File upload and download from client machine

hi..
anyone help me the way that how to upload and download word
document file from client machine.. i am using j2eeserver1.4 in linux..
i want upload file from client machine(windows) to server(linux.) please
help me . tell me idea regarding..
i have tried this coding.. but i can transfer txt file. only. when i upload mirosoft word file.. it will open with some ascii values with actual content.

<%@ page import="java.io.*" %>
<%String contentType = request.getContentType();
String file = "";
String saveFile = "";
FileOutputStream fileOut = null;
if ((contentType != null) && (contentType.indexOf("multipart/form-data") >= 0))
DataInputStream in = new DataInputStream(request.getInputStream());
int formDataLength = request.getContentLength();
byte dataBytes[] = new byte[formDataLength];
int byteRead = 0;
int totalBytesRead = 0;
while (totalBytesRead < formDataLength)
byteRead = in.read(dataBytes, totalBytesRead, formDataLength);
totalBytesRead += byteRead;
try {
file = new String(dataBytes);
saveFile = file.substring(file.indexOf("filename=\"") + 10);
saveFile = saveFile.substring(0, saveFile.indexOf("\n"));
saveFile = saveFile.substring(saveFile.lastIndexOf("/") + 1,saveFile.indexOf("\""));
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String boundary = contentType.substring(lastIndex + 1,contentType.length());
int pos;
pos = file.indexOf("filename=/" + 1);
pos = file.indexOf("\n", pos) + 1;
pos = file.indexOf("\n", pos) + 1;
pos = file.indexOf("\n", pos) + 1;
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int startPos = ((file.substring(0, pos)).getBytes()).length;
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fileOut.write(dataBytes, startPos, (endPos - startPos));
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Regards..
New User M.Senthil..

Hi,
Well,i don't know whether if this helps people here are not.
It is always a good practise to do it via Servlet and then download content.
The adavantage of doing this is
1). You may not need to pack the downloadable with the .war which you ultimately genrate which ceratinly help us in terms of faster deployment.
3). You may update the new content just by moving a file to the backup folder.
2).One may definately download the content irrespective to the content/file.
Hope example below helps..
Configurations:
In the above example we are assuming that we placing all downlodable file in D:/webapp/downlodables/ and you have configured the same path as a init param with the name "filePath" in your web.xml.
something like the one below.
<servlet>
 <servlet-name>DownloadServlet</servlet-name>
 <servlet-class>com.DownloadServlet</servlet-class>
 <init-param>
 <param-name>filePath</param-name>
 <param-value>D:/webapp/downlodables/</param-name>
 
 </init-param>
</servlet>
<servlet-mapping>
 <servlet-name>DownloadServlet</servlet-name>
 <url-pattern>/downloadFile</url-pattern>
</servlet-mapping>DownloadServlet.java:
==================
package com;
import javax.servlet.ServletConfig;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import java.io.BufferedOutputStream;
import java.io.File;
import java.io.FileInputStream;
import java.io.IOException;
import javax.activation.MimetypesFileTypeMap;
*@Author RaHuL
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* which could be accessed downloadFile?fid=fileName
* or
* http://HOST_NAME:APPLN_PORT/ApplnContext/downloadFile?fid=fileName
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public void doPost(HttpServletRequest request,HttpServletResponse response) throws Exception{
 processAction(request,response);
public void doGet(HttpServletRequest request,HttpServletResponse response) throws Exception{
 processAction(request,response);
NOTE: Make sure You include activations.jar in your CLASSPATH b4 trying the code.
therefore,if you have something like above set as your application enviroment in the above disccussed
can be done by just giving a simple hyper link like
<a href="downloadFile?fid=fileName.qxd" target="_blank">Download File</a>REGARDS,
RaHuL

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# Details
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Attila -
I went back and re-read the JavaDoc for AbstractPageBroker and MultipartFormItem and put together the following sample PageBroker based on the description from the JavaDoc:
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import java.io.FileOutputStream;
import java.io.IOException;
import javax.servlet.ServletConfig;
import javax.servlet.ServletContext;
import oracle.cabo.servlet.BajaContext;
import oracle.cabo.servlet.Page;
import oracle.cabo.share.util.MultipartFormItem;
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* Override of AbstractPageBroker.doUploadFile() which saves
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Page page,
MultipartFormItem item) throws IOException
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if (name == null)
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</contents>
</pageLayout>
</content>
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How does cloud work out in the australian country where I have very slow upload and download speeds and have unreliable connections?

I really just cant get my head around how cloud works when I have such low access to internet downloads..

Under these conditions no service which relies on using a fair amount of bandwidth is going to work. In your situation you may be able to handle a moderate amount of email, calaendars and contacts, though it will be slow to load; but heavy uploading and downloading of for example images in Photo Stream is likely to take so long as to be impracticable.

How to Upload and Download Files

Dear Friends
I want to write code for Upload and Download file ( Group of Files). Please Guide me the right way I have a few java files and i have compiled that but i donot know how to run that file and i am stranger to java also.
Please send me reply and sugessest me.
my email id is [email protected]
Amogh

I have write a upload code, but the code can deal with txt onle, it can not deal with bmp or doc, what the matter?
import java.io.*;
import javax.servlet.*;
import javax.servlet.http.*;
public class Upload extends HttpServlet {
 String rootPath;
 static final int MAX_SIZE = 102400;
 public void init(ServletConfig config) throws ServletException
 super.init(config);
 public void doGet(HttpServletRequest request,HttpServletResponse response)
 throws ServletException,IOException
 response.setContentType("text/html");
 PrintWriter out = new PrintWriter (response.getOutputStream());
 out.println("<html>");
 out.println("<head><title>Servlet1</title></head>");
 out.println("<body><form ENCTYPE=\'multipart/form-data\' method=post action=''><input type=file enctype=\'multipart/form-data\' name=filedata>");
 out.println("<input type=submit></form>");
 out.println("</body></html>");
 out.close();
 public void doPost(HttpServletRequest request,HttpServletResponse response)
 ServletOutputStream out=null;
 DataInputStream in=null;
 FileOutputStream fileOut=null;
 rootPath = "C:\\upload\\tmp\\"; //The directory to save the target file.
 try
 response.setContentType("text/plain");
 out = response.getOutputStream();
 catch (IOException e)
 System.out.println("Error getting output stream.");
 System.out.println("Error description: " + e);
 return;
 try
 String contentType = request.getContentType();
 if(contentType != null && contentType.indexOf("multipart/form-data") != -1)
 in = new DataInputStream(request.getInputStream());
 int formDataLength = request.getContentLength();
 byte dataBytes[] = new byte[formDataLength];
 int bytesRead = 0;
 int totalBytesRead = 0;
 int sizeCheck = 0;
 String sourceFileName = "";
 String targetFileName = "";
 while (totalBytesRead < formDataLength)
 sizeCheck = totalBytesRead + in.available();
 if (sizeCheck > MAX_SIZE)
 out.println("Sorry, file is too large to upload.");
 return;
 bytesRead = in.read(dataBytes, totalBytesRead, formDataLength);
 totalBytesRead += bytesRead;
 String file = new String(dataBytes);
 dataBytes = null;
 int lastIndex = contentType.lastIndexOf("=");
 String boundary = contentType.substring(lastIndex+1, contentType.length());
 //File Content
 //out.println("File content: " + file);
 if (file.indexOf("name=") > 0)
 int fileNameStart = 0;
 int fileNameEnd = 0;
 fileNameStart = file.indexOf("filename=\"");
 fileNameEnd = file.indexOf("Content-Type:");
 sourceFileName = file.substring(fileNameStart + 10, fileNameEnd - 3);
 //Source File
 out.println("Source file: " + sourceFileName);
 String successPage="";
 if (file.indexOf("name=\"SuccessPage\"") > 0)
 successPage = file.substring(file.indexOf("name=\"SuccessPage\""));
 successPage = successPage.substring(successPage.indexOf("\n")+1);
 successPage = successPage.substring(successPage.indexOf("\n")+1);
 successPage = successPage.substring(0,successPage.indexOf("\n")-1);}
 String overWrite;
 if (file.indexOf("name=\"OverWrite\"") > 0)
 overWrite = file.substring(file.indexOf("name=\"OverWrite\""));
 overWrite = overWrite.substring(
 overWrite.indexOf("\n")+1);
 overWrite = overWrite.substring(overWrite.indexOf("\n")+1);
 overWrite = overWrite.substring(0,overWrite.indexOf("\n")-1);
 else
 overWrite = "false";
 String overWritePage="";
 if (file.indexOf("name=\"OverWritePage\"") > 0)
 overWritePage = file.substring(file.indexOf("name=\"OverWritePage\""));
 overWritePage = overWritePage.substring(overWritePage.indexOf("\n")+1);
 overWritePage = overWritePage.substring(overWritePage.indexOf("\n")+1);
 overWritePage = overWritePage.substring(0,overWritePage.indexOf("\n")-1);
 targetFileName = sourceFileName.substring(sourceFileName.lastIndexOf("\\") + 1);
 targetFileName = rootPath + targetFileName;
 //Target File:
 out.println("Target file: " + targetFileName);
 int pos; //position in upload file
 pos = file.indexOf("filename=");
 pos = file.indexOf("\n",pos)+1;
 pos = file.indexOf("\n",pos)+1;
 pos = file.indexOf("\n",pos)+1;
 int boundaryLocation = file.indexOf(boundary,pos)-4;
 file = file.substring(pos,boundaryLocation);
 File checkFile = new File(targetFileName);
 if (checkFile.exists())
 if (!overWrite.toLowerCase().equals("true"))
 if (overWritePage.equals(""))
 out.println("Sorry, file already exists.");
 else
 //redirect client to OverWrite HTML page
 response.sendRedirect(overWritePage);
 return;
 File fileDir = new File(rootPath);
 if (!fileDir.exists())
 fileDir.mkdirs();
 fileOut = new FileOutputStream(targetFileName);
 fileOut.write(file.getBytes(),0,file.length());
 if (successPage.equals(""))
 out.println("File written to: " + targetFileName);
 else
 response.sendRedirect(successPage);
 else //request is not multipart/form-data
 out.println("Request not multipart/form-data.");
 catch(Exception e)
 try
 System.out.println("Error in doPost: " + e);
 out.println("An unexpected error has occurred.");
 out.println("Error description: " + e);
 catch (Exception f) {}
 finally
 try
 fileOut.close(); //close file output stream
 catch (Exception f) {}
 try
 in.close(); //close input stream from client
 catch (Exception f) {}
 try
 out.close(); //close output stream to client
 catch (Exception f) {}
}

Uploading and downloading files from a web app (Urgent!!)

Hi everyone:
I'm developing an application in PL/SQL to upload and download files from an HTML webpage. I congured the document table and the parameters necessary in the DAD of my application.
when I upload the file using my webpage that file info is automatically uploaded to the doc table. This is as far as I have gotten.
I need to do the following:
- Place the uploaded file into a column in another table in my database as part of a text message (think of it as an email message), and delete the file from the doc table (as this is thought to be a temp table that holds the file when uploaded from my webpage)
- Retreive the file so that it can be downloaded from another web page.
The file can be a PDF, WORD DOC, etc...
I now that I can do this with InterMedia but I haven't figured out how :(
Can anyone please point me to an example or some documentation that can guide me through the process.
DB VERSION: 8.1.7
IAS VERSION: 1.0.2.2
Thanks,
Carlos Abarca

The idea was for you to look at the code and get an idea of how to access the BLOB in the document table. IF you look at the procedure
insert_new_photo( new_description IN VARCHAR2,
new_location IN VARCHAR,
new_photo IN VARCHAR2 )
It shows how to access the blob that is stored in the document table. You can then copy this blob to your own table using the DBMS_LOB package.
Hope this helps,
Larry

Class to upload and download images

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