Comparing nodes in two xml files

I need help with a flex app i am making. My skill level in flex is pretty much basic, so some of the questions may seem easy but they r not to me
I need an application that will load two external xml files and compare nodes. The xml files are pretty much identical except for the values ofcourse. After that i need to write this data to a new xml file which my flex app will generate. Can anyone plz give me an example code which i can later modify for my own application. You can give me any type of an example with the simplest xml files.
Thank you in advance

"for in" and "for each in" statements can be used to iterate through the nodes. If the two xml files are of same structure , you can easily compare the node attributes. Here is the link to the livedocs page for looping through xml nodes
http://livedocs.adobe.com/flex/3/html/help.html?content=13_Working_with_XML_08.html
Create xml from string
http://www.cflex.net/showFileDetails.cfm?ChannelID=1&ObjectID=784
Message was edited by: Subeesh Arakkan

Similar Messages

Compare two XML files: Analysis and Design

Hi, Java/XML/JDOM experts,
I realised that an open source of Java utility to compare two XML is still missing. So I would like to write one for my JDOM excises.
I plan to do it in three steps:
1.Define the problem domain.
2.Design the classes to be developed.
3.Coding
Below is the problem domain. Would you review it and tell me if it is fine?
Best regards,
AG
Compare two XML files
Schema assumption:
The xml files used for the comparison must have the same schema.
Definition:
1. Two elements of simple type are said equal if their name and value are identical.
2. Two elements of complex type are said comparable if their name, attributes are identical.
3. Two elements of complex type are said equal if they are comparable and their children elements are identical.

Hi,
Thanks for reviewing my idea.
The xml files used for the comparison must have the
same schema.Including not having a schema at all? And if they do
have a schema, must they be valid according to the
schema?I will only support schema based xml files. To include a schema is a good practice. So I will valid them agaisnt schema (is this possible with JDOM? I am testing ...)
>
2. Two elements of complex type are said comparableif
their name, attributes are identical.
3. Two elements of complex type are said equal ifthey
are comparable and their children elements are
identical.Do you plan to require child elements to appear in the
same order for the two documents to be equal? (Note
that XML specifically says that the order of
attributes is not significant.)No. The order is not significant as I use the attributes as the keys to find comparable element counterpart.
Here is the sample code already tested. Any comments are welcome!
The next step is to define the "delta xml schema" that will guide me to store the comparasion results. Do you have any suggestions?
Regards.
AG
public static boolean comparable(Element element1, Element element2)
     boolean returnValue=false;
     if (element1.getName()!=element2.getName()) {
          return returnValue;
} else {
          returnValue=true;
                    System.out.println ("place 2");
     List attributeList=element1.getAttributes();
     Iterator attributeIterator=attributeList.iterator();
     Attribute workingAttribute=null;
     while (attributeIterator.hasNext()) {
                         if (!workingAttribute.getValue().equals(
                         element2.getAttribute(workingAttribute.getName(), workingAttribute.getNamespace()).getValue()))
                              returnValue=false;
                              break;
     return returnValue;

How can compare two xml files.........

Hi developers..........
I have a problem in compare two xml files.My project description is I take two xml(file1,file2) files.Compare file1 with file2. Now I want what are the same words in to the file2.
file1:
<hello>
<html>
<jsp:plugin>
file2:
<hello>
<jsp:usebean>
<html>
result:
<hello>
any give the code for this logic.....

hi...can u pls send me the code which compares two
xml files and gives the output as difference between
two fileshttp://www.bmsi.com/java/#diff

Compare two xml files

hi all,
i am using Forms [32 Bit] Version 6.0.8.24.1 (Production)
can any body tell me, how two xml files can be compared.
for example
i have file 1(standard)
<Message-Header>
<Message-Id>1234</Message-Id>
<Sender-Company-ID>4569</Sender-Company-ID>
<Sender-Company-Name>abc company</Sender-Company-Name>
<Sender-User-ID>AA</Sender-User-ID>
<Recv-Company-ID>050</Recv-Company-ID>
<Recv-Company-Name>XYZ pvt.ltd</Recv-Company-Name>
<Creation-Time>20101019 15:59:39</Creation-Time>
<cons>
<con>
<con_number>xsu667</con_number>
</con>
</cons>
</Message-Header>
i have file 2(came from user)
<Message-Header>
<Message-Id>1234</Message-Id>
<Sender-Company-ID>4569</Sender-Company-ID>
<Sender-Company-Name>abc company</Sender-Company-Name>
<Sender-User-ID>AA</Sender-User-ID>
<Recv-Company-ID>050</Recv-Company-ID>
<Recv-Company-Name>XYZ pvt.ltd</Recv-Company-Name>
<Creation-Time>20101019 15:59:39</Creation-Time>
<cons>
<con>
<con_number>xsu667</con_number>
</con>
<con>
<con_number>xsu669</con_number>
</con>
</cons>
</Message-Header>how to map two files. do we have to compare line by line?
the file2 have to match with respect to structure and also data.
any suggestions are welcome.
Edited by: user13329002 on Oct 24, 2010 5:48 AM

user13329002 wrote:
hi,
i am not aware of these things(merge file).
can u tell me,what is the ultimate result of this merging.
and can u tell the stepts to acheive this..
Thanks..a) write files down to temporary directory by using text_io
b) call an external program you installed on the client like winmerge, windiff or about 100000 other programs out ther that can show you the differences of two files
this programs you pass the two files you wrote to disk at step a

How can i compare two XML files storeds in a LONG column

Hi,
I need to compare two xml files. My xmls are stored in two table like this:
Table 1
ID_COL number(5);
XML1 LONG()
Table 2
ID_COL number(5);
XML2 LONG()
I need compare the values of the tags of this xmls files e to list de differences.
Tks,
Fernando.

yes odie you are right...i think that my xml is wrong...
I would like to compare every element/attribute...
Bellow is another xml...this is ok....tks
<?xml version="1.0" encoding="UTF-8" ?>
- <nfeProc xmlns="http://www.portalfiscal.inf.br/nfe" versao="2.00">
- <NFe xmlns="http://www.portalfiscal.inf.br/nfe">
- <infNFe Id="NFe31121059106377000172550010003957681605366269" versao="2.00">
+ <ide>
<cUF>31</cUF>
<cNF>60536626</cNF>
<natOp>VDAS PROD ESTABELECIMENT</natOp>
<indPag>1</indPag>
<mod>55</mod>
<serie>1</serie>
<nNF>395768</nNF>
<dEmi>2012-10-03</dEmi>
<dSaiEnt>2012-10-03</dSaiEnt>
<hSaiEnt>18:30:00</hSaiEnt>
<tpNF>1</tpNF>
<cMunFG>3159605</cMunFG>
<tpImp>1</tpImp>
<tpEmis>1</tpEmis>
<cDV>9</cDV>
<tpAmb>1</tpAmb>
<finNFe>1</finNFe>
<procEmi>0</procEmi>
<verProc>1.0</verProc>
</ide>
+ <emit>
<CNPJ>59106377000172</CNPJ>
<xNome>METAGAL IND E COM LTDA</xNome>
<xFant>METAGAL INDUSTRIA E COMERCIO LTDA</xFant>
- <enderEmit>
<xLgr>ROD BR 459</xLgr>
<nro>333</nro>
<xCpl>KM 121</xCpl>
<xBairro>DISTRITO INDUSTRIAL</xBairro>
<cMun>3159605</cMun>
<xMun>SANTA RITA DO SAPUCAI</xMun>
<UF>MG</UF>
<CEP>37540000</CEP>
<cPais>1058</cPais>
<xPais>BRASIL</xPais>
<fone>3534719100</fone>
</enderEmit>
<IE>5969141300009</IE>
<IM>01183</IM>
<CNAE>2949299</CNAE>
<CRT>3</CRT>
</emit>
+ <dest>
<CNPJ>59275792000150</CNPJ>
<xNome>GENERAL MOTORS DO BRASIL LTDA</xNome>
- <enderDest>
<xLgr>AV GOIAS</xLgr>
<nro>1805</nro>
<xBairro>BARCELONA</xBairro>
<cMun>3548807</cMun>
<xMun>SAO CAETANO DO SUL</xMun>
<UF>SP</UF>
<CEP>09501970</CEP>
<cPais>1058</cPais>
<xPais>BRASIL</xPais>
</enderDest>
<IE>636003724112</IE>
<email>[email protected]</email>
</dest>
- <det nItem="1">
+ <prod>
<cProd>XM20C9500PPR</cProd>
<cEAN />
<xProd>ESPELHO RETROVISOR EXTERNO</xProd>
<NCM>70091000</NCM>
<CFOP>6501</CFOP>
<uCom>PC</uCom>
<qCom>80.0000</qCom>
<vUnCom>35.8700000000</vUnCom>
<vProd>2869.60</vProd>
<cEANTrib />
<uTrib>PC</uTrib>
<qTrib>80.0000</qTrib>
<vUnTrib>35.8700000000</vUnTrib>
<indTot>1</indTot>
<xPed>XRW001RV</xPed>
<nItemPed>000001</nItemPed>
</prod>
- <imposto>
- <ICMS>
- <ICMS00>
<orig>0</orig>
<CST>00</CST>
<modBC>3</modBC>
<vBC>2869.60</vBC>
<pICMS>12.00</pICMS>
<vICMS>344.35</vICMS>
</ICMS00>
</ICMS>
- <IPI>
<CNPJProd>00000000000000</CNPJProd>
<cEnq>0</cEnq>
- <IPINT>
<CST>54</CST>
</IPINT>
</IPI>
- <II>
<vBC>0.00</vBC>
<vDespAdu>0.00</vDespAdu>
<vII>0.00</vII>
<vIOF>0.00</vIOF>
</II>
- <PIS>
- <PISNT>
<CST>08</CST>
</PISNT>
</PIS>
- <COFINS>
- <COFINSNT>
<CST>08</CST>
</COFINSNT>
</COFINS>
</imposto>
<infAdProd>PC.93378954-COMPL.PED.XRW001RV</infAdProd>
</det>
+ <total>
- <ICMSTot>
<vBC>2869.60</vBC>
<vICMS>344.35</vICMS>
<vBCST>0.00</vBCST>
<vST>0.00</vST>
<vProd>2869.60</vProd>
<vFrete>0.00</vFrete>
<vSeg>0.00</vSeg>
<vDesc>0.00</vDesc>
<vII>0.00</vII>
<vIPI>0.00</vIPI>
<vPIS>0.00</vPIS>
<vCOFINS>0.00</vCOFINS>
<vOutro>0.00</vOutro>
<vNF>2869.60</vNF>
</ICMSTot>
<retTrib />
</total>
+ <transp>
<modFrete>0</modFrete>
- <transporta>
<CNPJ>00980331000488</CNPJ>
<xNome>THALE TRANSPORTES E LOG. LTDA</xNome>
<IE>5963866160070</IE>
<xEnder>ROD BR 459-KM 121 - DIST INDL, S/N</xEnder>
<xMun>SANTA RITA DO SAPUCAI</xMun>
<UF>MG</UF>
</transporta>
- <veicTransp>
<placa>DPF8048</placa>
<UF>SP</UF>
</veicTransp>
- <vol>
<qVol>20</qVol>
<esp>OUTROS</esp>
<pesoL>64.000</pesoL>
<pesoB>104.000</pesoB>
</vol>
</transp>
+ <cobr>
- <fat>
<nFat>000000395768</nFat>
<vOrig>2869.60</vOrig>
</fat>
- <dup>
<nDup>1</nDup>
<dVenc>2012-11-20</dVenc>
<vDup>2869.60</vDup>
</dup>
</cobr>
- <infAdic>
<infCpl>VIA DE TRANSPORTE RODOVIARIA CODIGO : 108061 PEDIDO NRO : ACIMA FABRICA :72480 REDESPACHO ATRAVES DE VELOCE LOGISTICA S/A ESTRADA DOS ALVARENGAS SAO BERNARDO CAMPO ASSUNCAO SP CNPJ : 10.299.567/0003-26 IE : 635.600.028.11 IPI - IMUNE CFE.ART.18, INCISO II, DO RIPI - DECRETO No.7.212/2010. REMESSA COM FIM ESPECIFICO DE EXPORTACAOMERC.A SER EXPORT.P/GENERAL MOTORS DO BRASIL LTDA.DECEX=3-0322/10-0007 ESTOCA-GEM TEMPORARIA NA VELOCE LOGISTICA S.A. ESTR.ALVARENGAS,4018 B.ASSUNCAO S.B.C. CNPJ10.299.567/0003-26IE.635.600.028.110 FT NR.431.183 ROMANEIO :131.588</infCpl>
</infAdic>
</infNFe>
+ <Signature xmlns="http://www.w3.org/2000/09/xmldsig#">
- <SignedInfo>
<CanonicalizationMethod Algorithm="http://www.w3.org/TR/2001/REC-xml-c14n-20010315" />
<SignatureMethod Algorithm="http://www.w3.org/2000/09/xmldsig#rsa-sha1" />
- <Reference URI="#NFe31121059106377000172550010003957681605366269">
- <Transforms>
<Transform Algorithm="http://www.w3.org/2000/09/xmldsig#enveloped-signature" />
<Transform Algorithm="http://www.w3.org/TR/2001/REC-xml-c14n-20010315" />
</Transforms>
<DigestMethod Algorithm="http://www.w3.org/2000/09/xmldsig#sha1" />
<DigestValue>jN2ozPH3/GvAS8Q5lh/t9bzuXCw=</DigestValue>
</Reference>
</SignedInfo>
<SignatureValue>GAXPLvMCtIYdwMxXDcyL0kr5hCDPCFw8/uNYHFcdTMqBhLgIcEtzHRf8qioWlUVSHNf5jnCLKGjhDV4bEJqkcBhWsKouMzojQ+Z6hkFQAWNuJfPIzutmtRy3AePc5tHK0lI3tF3ws9memboJ8sW21IOWHB6eB0jK2gmhcOlDejc=</SignatureValue>
- <KeyInfo>
- <X509Data>
<X509Certificate>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</X509Certificate>
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</NFe>
- <protNFe versao="2.00">
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<tpAmb>1</tpAmb>
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<chNFe>31121059106377000172550010003957681605366269</chNFe>
<dhRecbto>2012-10-03T17:35:55</dhRecbto>
<nProt>131120853536488</nProt>
<digVal>jN2ozPH3/GvAS8Q5lh/t9bzuXCw=</digVal>
<cStat>100</cStat>
<xMotivo>Autorizado o uso da NF-e</xMotivo>
</infProt>
</protNFe>
</nfeProc>

Comparision of two xml files

Hi all,
Could anybody tell me how to compare two xml files and find the details that differ?
If possible, can you get me the code?

You can simply compare the entire contents of the strings if you like, although simple whitespace differences (spaces, tabs, carriage returns, etc.) would result in an evaluation that the two are different (probably not what you want). You can parse them in DOM or SAX, and the minute an element fails, return false. Look up a tutorial on either DOM or SAX for ideas. Or you could iterate through the string and simply discard whitespace on your own.
It could potentially be more complicated then that. Does the ordering of elements matter? Meaning if I have elements a, b, c in document one but b, c, a in the other one (but a, b, c are identical otherwise) does that mean a different document? You really do not have enough requirements to go on. The above will likely work for you, and no, I will not write your code for you.
- Saish

Why we need to conver Context Node data into XML file----Export to Excel

Hi All,
Let me clarify my dought........today i have gone through the concept of "Exporting Context Data Using the Webdynpro Binary cache" in SAP Online Help.
From the SAP Online Help pdf document, i have found that, the context node data has been converted first in to XML file,after that file had been stored in the web dynpor binary cache...bla....bla.........
Here my qtn is why they had converted context node data into XML file. With out doing that can not we export context node data to excel file..?
Regards
Seshu
Edited by: Sesshanna D on Dec 19, 2007 7:25 AM

Hi Sesshanna,
it is not neccessary to do that but xml has the advantage, that it can be easily transformed into every output format that might occur in later project stages.
If it's simply about blowing out some Excel, I suggest using an OSS library such as jexcelAPI or Jakarta POI and building the Excel how you need it.
regards,
Christian

Unmarshalling a DOM node to an XML file with JAXB

I'm trying to unmarshall a DOM node to an XML file using JAXB. However I keep receiving a NullPointerException. This only seems to occur when I create the DOM Node from scratch. The stack trace looks like the following:
java.lang.NullPointerException
        at com.sun.xml.bind.unmarshaller.SAXUnmarshallerHandlerImpl.startElement
(SAXUnmarshallerHandlerImpl.java:87)
        at com.sun.xml.bind.unmarshaller.DOMScanner.visit(DOMScanner.java:109)
        at com.sun.xml.bind.unmarshaller.DOMScanner.parse(DOMScanner.java:64)
        at com.sun.xml.bind.unmarshaller.UnmarshallerImpl.unmarshal(Unmarshaller
Impl.java:149)
        at Main.main(Main.java:103)(If I unmarshal an XML file into a DOM node, I can successfully marshall the DOM node out to a new XML file using JAXB without error.)
Any insight into what I am doing wrong would be greatly appreciated!
Sample code and XSD follow...
Sample Code:
import itemlistsample.*;
import java.io.FileInputStream;
import java.io.FileOutputStream;
import java.io.IOException;
import java.util.Iterator;
import java.util.List;
import javax.xml.bind.JAXBContext;
import javax.xml.bind.JAXBException;
import javax.xml.bind.Marshaller;
import javax.xml.bind.Unmarshaller;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.DocumentBuilder;
import org.w3c.dom.Document;
import org.w3c.dom.Element;
import org.w3c.dom.NodeList;
import org.w3c.dom.Node;
import org.w3c.dom.Text;
public class Main
public static void main(String[] args)
      try
          JAXBContext jc = JAXBContext.newInstance( "itemlistsample" );
          Unmarshaller u = jc.createUnmarshaller();
          * Set up DOM Node Document Object.
          DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
          dbf.setNamespaceAware(true);
          DocumentBuilder db = dbf.newDocumentBuilder();
          Document doc = db.newDocument();
          System.out.println();
          System.out.println();
          System.out.println("Create a DOM Node and unmarshall to an XML file");
          * Generate elements within DOM document
          Element itemListElt = (Element)doc.createElement("item_list");
          Element itemInfo = (Element)doc.createElement("item_info");
          Element name = (Element)doc.createElement("name");
          Element price = (Element)doc.createElement("price");
          * 3-Ring Binder @ 4.99
          name.appendChild(doc.createTextNode("3-Ring Binder"));
          itemInfo.appendChild(name);
          price.appendChild(doc.createTextNode("4.99"));
          itemInfo.appendChild(price);
          itemListElt.appendChild(itemInfo);
          * Large Paper Clips @ 1.23
          itemInfo = (Element)doc.createElement("item_info");
          name = (Element)doc.createElement("name");
          price = (Element)doc.createElement("price");
          name.appendChild(doc.createTextNode("Large Paper Clips"));
          itemInfo.appendChild(name);
          price.appendChild(doc.createTextNode("1.23"));
          itemInfo.appendChild(price);
          itemListElt.appendChild(itemInfo);
          doc.appendChild(itemListElt);
          * Display DOM document as a sanity check
          itemListElt = doc.getDocumentElement();
          System.out.println(itemListElt.getTagName());
          NodeList nl = itemListElt.getElementsByTagName("item_info");
          traverse(" ", nl.item(0));
          * Use JAXB to unmarshal the DOM document into
          * an instance of the generated JAXB class for
          * the root element. Stack trace occurs here!
          ItemListType il = (ItemListType)u.unmarshal(doc);
          * Marshal to an XML file
          Marshaller m = jc.createMarshaller();
          m.setProperty( Marshaller.JAXB_FORMATTED_OUTPUT, Boolean.TRUE );
          m.marshal( il, new FileOutputStream("item_new.xml") );
      catch (Exception e)
     e.printStackTrace();
public static void traverse(String indent, Node n)
    if (n != null)
      if (n.getNodeName() != null)
        System.out.println(indent + n.getNodeName());
        traverse(indent + " ", n.getFirstChild());
      if (n.getNodeValue() != null)
        System.out.println(indent + n.getNodeValue());
      traverse(indent, n.getNextSibling());
}Sample XSD:
<?xml version="1.0" encoding="ISO-8859-1"?>
<xsd:schema xmlns:xsd="http://www.w3.org/2001/XMLSchema">
     <xsd:element name="item_list" type="ItemListType"/>
     <xsd:complexType name="ItemListType">
          <xsd:sequence>
               <xsd:element name="item_info" type="ItemInfoType" maxOccurs="unbounded"/>
          </xsd:sequence>
     </xsd:complexType>
     <xsd:complexType name="ItemInfoType">
          <xsd:sequence>
               <xsd:element name="name" type="xsd:string"/>
               <xsd:element name="price" type="xsd:double"/>
          </xsd:sequence>
     </xsd:complexType>
</xsd:schema>

Modified schema
<?xml version="1.0" encoding="ISO-8859-1"?>
<xsd:schema xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<xsd:element name="item_list">
<xsd:complexType>
<xsd:sequence>
<xsd:element ref="item_info" maxOccurs="unbounded"/>
</xsd:sequence>
</xsd:complexType>
</xsd:element>
<xsd:element name="item_info">
     <xsd:complexType>
<xsd:sequence>
<xsd:element name="name" type="xsd:string"/>
     <xsd:element name="price" type="xsd:double"/>
     </xsd:sequence>
</xsd:complexType>
</xsd:element>
</xsd:schema>

Merge Two Xml files ????

I have two xml files, which I want to merge.
Both are having same structure�
Eg. *INPUT-FILE-1*
<library>
     <book isbn="1">
          <name>Book-11</name>
          <author>steve</author>
          <price>2.99</price>
     </book>
          <book isbn="2">
          <name>Book-22</name>
          <author>john</author>
          <price>12.99</price>
     </book>
</library>
*INPUT-FILE-2*
<library>
     <book isbn="1">
          <name>Book-11</name>
          <author>steve</author>
          <price>2.99</price>
     </book>
          <book isbn="3">
          <name>Book-33</name>
          <author>johnthan</author>
          <price>12.99</price>
     </book>
</library>
*OUTPUT-file*
<library>
     <book isbn="1">
          <name>Book-11</name>
          <author>steve</author>
          <price>2.99</price>
     </book>
          <book isbn="2">
          <name>Book-22</name>
          <author>john</author>
          <price>12.99</price>
     </book>
</book>
          <book isbn="3">
          <name>Book-33</name>
          <author>johnthan</author>
          <price>12.99</price>
     </book>
</library>Merge should provide third file without any repetition of any record.
Which parser to use and how to use ???
Any help on this ???????????
Thanks !!

Merge should provide third file without any repetition of any record.
Which parser to use and how to use ???Look at JDOM
Any help on this ???????????One question mark is all that is necessary.

Merge two XML files From java

hi,
i'm in need to merge two XML files from my java code please help me as soon......

Rajesh42 wrote:
hi,
i'm in need to merge two XML files from my java code please help me as soon......Hello Rajesh42,
While it is wonderful that you have discovered the magically code tags, please consider if it is the right time to use them. Code tags should only go round code. Note used to make your posts "stand out", or used to quote other people. Just code.
As to your question, what have you tried, what are you stuck on?
Mike

Can we Concatinate two XML files to a single output?

I was stuck up with one scenario where I am getting a XML file output from a File Adapter say x1.
And another XML file output say x2 from other adapter. Now I want to club this two XML files into a single output where it should contain the contents of x1 and x2
When I am doing the Transformation I am getting the two files in the output folder but I want single file as output. Is it possible with ESB? If so Please suggest.
--Chandra

Hi Chandra,
Maybe the enrichment interaction scenario would work in your case.
My colleague Lucas Jellema wrote a blog post on it: http://technology.amis.nl/blog/?p=1464.
Or putting the same in a larger perspective: http://www.oracle.com/technology/pub/articles/jellema-esb.html.
Hth,
Sjoerd

Comparing two xml files in pl/sql

What is the best way to compare two 'complex' xml structures and return the difference using a plsql procedure/function. Example:
FUNCTION f_equals(XMLTYPE actualxml, XMLTYPE expectedxml) RETURN VARCHAR2
this should return 'EQUAL' if they are equal and the actual node with value if different..
Can somebody throw some ideas please?

The solution would depend on what you are trying to achieve, is it node to node comparison? overall file comparison? If there is any difference in either of the aforementioned approach, do what with the result?

Import two XML file in MDM

Hallo MDM Expert,
I would like to import two files XML in MDM, because I carry out By Manuel import. besides, are both XML file from two different System needs to remove de-duplication of the both file and compared them. afterwards as a file to the export manager be exported.
Please could give a Input? which step I can done to Import the both file and alimented de-duplication.
Thank in advance

Hi Dominique,
   To Import Second file please follow these steps:
In Import Manager after you import your first file then go to File --> Connect to Source in import manager, a new window comes then specify your second file name and perform Import normally.
   After both the files are imported you can follow these steps to remove duplicates:
Matching Mode is used to find and merge duplicates.This can be done in following steps:
      You have to use key mapping if incoming files are from different system.
Step1. In Data Manager go to Matching Mode and Select Transformation tab.Right click in Transformations pane and select Add Transformation then go to Properties pane and select the field you want to transform.Do the proper substitution in substitution pane example: Suppose that there are two values Marta. and Marta due to the "." MDM will interpret them as different values but they are duplicates so to eliminate this problem you can use substitution. So specify ".' in From and Blank space in To .Create similar transformation for other fields as well.
Step2. Go to Rules tab and Right click in Rules pane and select Add Rules then go to Properties pane and select the transformed field i.e.[XFM] .
Specify the scores for success failure and undefined properties as per your requirement.Create similar rules for other fields as well.
Step3. Go to Strategies tab. and Right click in Strategies pane and select Add strategies In the Rules Pane select the rules you want to include in the Strategy.Min Score and Max Score are calculated automatically. It is the sum of all individual matching rules in this strategy. Low Threshold and High Threshold classify the matching results and must be set manually. They decide the Match Class for a record upon executing the strategy.
Step4. Go to the Records Pane and to execute the matching, select one or more records from the record set and right-click. Select Match Records from the context menu and select the relevant matching type:
Selected vs. Selected matches the selected records with each other
Selected vs. Results matches the selected records with the record set derived from the search criteria
Selected vs. All matches the selected records with all records in the repository
Results vs. Results matches all records that result from the search criteria
Results vs. All matches all records that result from the search criteria with the records in the repository
Step5. On the basis of the Score select the record and See the corresponding matched records in the Matches tab and include the records you want to merge.
Step6. Go to Merge tab and for the selected matched records select the appropriate values and then right click in the bottom pane and select merge records. So the selected records are now existing as a new single merged record.
In order to syndicate data out of MDM follow these steps in Syndicator:
Step1. Go to Destination Items tab in bottom pane. Right click in Destination Items window and select "Add Destination Item" from the Context menu.
Step2. Go to "Properties" window and fill the required details.
Similarly you can create other destination fields as per your requirement.
Step3. Go to "Item Mapping" tab in bottom pane and Map the source field to the required destination field.
Step4. After all the mapping is done you can "Execute Syndication" and a flat file will be syndicated.
Note: You can syndicate Client specific data as well using Map Properties tab and selecting Output client system property
Thanks and Regards,
<b>Sagar Sonje
</b>
<b>Mark Helpful Answers</b>

To Get the value of a node in a XML file which is outside the envelope

Hi Everyone,
I am uploading data in a XML file into Oracle tables. I am using oracle 9i release 2. How to get a value of a node outside the envelope.
Here is my xml file.
<Response>
<TaskNo>14</TaskNor>
<ZoneResponse>
<GetServiceStatusResponse xmlns="http://mws.zonemws.com/Shipment/2010-10-01/">
<GetServiceStatusResult>
<Status>GREEN</Status>
<Date>2011-06-03</Date>
</GetServiceStatusResult>
<Metadata>
<Id>c9488a06</Id>
</Metadata>
</GetServiceStatusResponse>
</ZoneResponse>
</Response>
This is the response xml we are getting from the supplier. I do want to store all the values in an oracle table, including TaskNo(14). TaskNo is the main value
here. I am using dbms_xmlparser and dbms_xmldom in PL/SQL. I am able to get the values inside the envelope, but not the outside(taskno). It is not showing any errors. It is processing all
other values. I Posted this in the XML DB section also. Please help me to solve this issue. Any help,tips and suggesstion will be highly appreciated. Thanks in advance
--Vimal

Hi,
I am providing some additional info like procedure, table structure and sample xml file so that you can get a clear idea about my problem and help me.
My Procedure
PROCEDURE xml_upload (
p_directory IN VARCHAR2,
p_server_directory IN VARCHAR2,
p_filename IN VARCHAR2
AS
l_bfile BFILE;
l_clob CLOB;
l_parser DBMS_XMLPARSER.parser;
l_doc DBMS_XMLDOM.domdocument;
l_noderowset DBMS_XMLDOM.domnode;
l_noderow DBMS_XMLDOM.domnode;
l_nodecount NUMBER;
l_Resultlist DBMS_XMLDOM.domnodelist;
l_request_id VARCHAR2 (300);
l_task_number NUMBER;
l_tasknum_list DBMS_XMLDOM.domnodelist;
l_service_list DBMS_XMLDOM.domnodelist;
l_time_list DBMS_XMLDOM.domnodelist;
l_tasknode DBMS_XMLDOM.domnode;
l_servicenode DBMS_XMLDOM.domnode;
l_temp VARCHAR2 (1000);
l_table_name VARCHAR2 (100);
l_cmd_execution VARCHAR2 (1000);
l_orig_file_with_path VARCHAR2 (1000);
l_dest_file_with_path VARCHAR2 (1000);
l_status custom.task_status.status%TYPE;
l_time custom.task_status.timestamps%TYPE;
l_rows NUMBER;
l_message SYS.XMLTYPE;
l_return_status NUMBER;
TYPE tab_type IS TABLE OF custom.task_status%ROWTYPE;
t_tab tab_type := tab_type ();
PROCEDURE write_exception (
p1_filename VARCHAR2,
p_comments VARCHAR2,
p_rows_created NUMBER
IS
BEGIN
read_xml_file (p_directory, p_filename, l_message, l_return_status);
-- Convert the xml to a clob
l_clob := l_message.getclobval();
-- Create a parser.
l_parser := DBMS_XMLPARSER.newparser;
-- Parse the document and create a new DOM document.
DBMS_XMLPARSER.parseclob (l_parser, l_clob);
l_doc := DBMS_XMLPARSER.getdocument (l_parser);
-- Free any resources associated with the CLOB and Parser
-- dbms_lob.freetemporary(v_clob);
DBMS_XMLPARSER.freeparser (l_parser);
l_noderowset :=
DBMS_XMLDOM.item
(DBMS_XMLDOM.getchildnodes (DBMS_XMLDOM.makenode (l_doc)),
0
l_nodecount :=
DBMS_XMLDOM.getlength (DBMS_XMLDOM.getchildnodes (l_noderowset))
- 1;
t_tab.EXTEND;
FOR i IN 0 .. l_nodecount
LOOP
l_noderow :=
DBMS_XMLDOM.item (DBMS_XMLDOM.getchildnodes (l_noderowset), i);
l_Resultlist :=
DBMS_XMLDOM.getelementsbytagname
(DBMS_XMLDOM.makeelement (l_noderow),
'RequestId'
l_request_id :=
DBMS_XMLDOM.getnodevalue
(DBMS_XMLDOM.getfirstchild
(DBMS_XMLDOM.item (l_Resultlist,
0
END LOOP;
FOR i IN 0 .. l_nodecount
LOOP
l_noderow :=
DBMS_XMLDOM.item (DBMS_XMLDOM.getchildnodes (l_noderowset), i);
l_service_list:=
DBMS_XMLDOM.getelementsbytagname
(DBMS_XMLDOM.makeelement (l_noderow),
'Status'
l_status:=
DBMS_XMLDOM.getnodevalue
(DBMS_XMLDOM.getfirstchild
(DBMS_XMLDOM.item (l_service_list,
0
l_time_list:=
DBMS_XMLDOM.getelementsbytagname
(DBMS_XMLDOM.makeelement (l_noderow),
'Timestamp'
l_time:=
DBMS_XMLDOM.getnodevalue
(DBMS_XMLDOM.getlastchild
(DBMS_XMLDOM.item (l_time_list,
0
END LOOP;
select
extractvalue(column_value,'/Response/TaskNumber') into l_task_number
from
table(xmlsequence(xmltype('<Response>
<TaskNumber>14</TaskNumber>
<ZoneResponse>
<GetServiceStatusResponse xmlns="http://mws.zoneaws.com/InboundShipment/2010-10-01/">
<GetServiceStatusResult>
<Status>GREEN</Status>
<Timestamp>2011-06-03T22:17:17.313Z</Timestamp>
</GetServiceStatusResult>
<Metadata>
<RequestId>c9488a06-73c6-474e-b356-51d5f8feec00</RequestId>
</Metadata>
</GetServiceStatusResponse>
</ZoneResponse>
</Response>
t_tab (t_tab.LAST).status:= l_status;
t_tab (t_tab.LAST).timestamps:= l_time;
t_tab (t_tab.LAST).amz_request_id:= l_request_id;
t_tab (t_tab.LAST).tasknumber:= l_task_number;
-- Insert data into the real Staging table from the table collection.
FORALL i IN t_tab.first .. t_tab.last
INSERT INTO custom.task_status VALUES t_tab(i);
COMMIT;
DBMS_XMLDOM.freedocument (l_doc);
DBMS_LOB.freetemporary (l_clob);
DBMS_XMLPARSER.freeparser (l_parser);
DBMS_XMLDOM.freedocument (l_doc);
DBMS_LOB.freetemporary (l_clob);
DBMS_XMLPARSER.freeparser (l_parser);
DBMS_XMLDOM.freedocument (l_doc);
END rrs_xml_upload;
Sample File:
<Response>
<TaskNumber>14</TaskNumber>
<ZoneResponse>
<GetServiceStatusResponse xmlns="http://mws.zoneaws.com/InboundShipment/2010-10-01/">
<GetServiceStatusResult>
<Status>GREEN</Status>
<Timestamp>2011-06-03T22:17:17.313Z</Timestamp>
</GetServiceStatusResult>
<Metadata>
<RequestId>c9488a06-73c6-474e-b356-51d5f8feec00</RequestId>
</Metadata>
</GetServiceStatusResponse>
</ZoneResponse>
</Response>
Table: task_status
tasknumber number,
status varchar2(100),
timestamps varchar2(100),
requestid varchar2(100)
all I want is to populate the data from xml file to the particulare table. I can do that with the above procedure.
But In this below mentioned part of my procedure , I want to pass the file name instead of giving the entire content.
select
extractvalue(column_value,'/Response/TaskNumber') into l_task_number
from
table(xmlsequence(xmltype('<Response>
<TaskNumber>14</TaskNumber>
<ZoneResponse>
<GetServiceStatusResponse xmlns="http://mws.zoneaws.com/InboundShipment/2010-10-01/">
<GetServiceStatusResult>
<Status>GREEN</Status>
<Timestamp>2011-06-03T22:17:17.313Z</Timestamp>
</GetServiceStatusResult>
<Metadata>
<RequestId>c9488a06-73c6-474e-b356-51d5f8feec00</RequestId>
</Metadata>
</GetServiceStatusResponse>
</ZoneResponse>
</Response>
Alex or any other oracle pl/sql experts please help me to solve this issue.
FYI : I am using Oracle 9.2.0.8.0
Thanks,
Vimal..
Edited by: Vimal on Jun 13, 2011 4:10 PM

Need help in creating header node at reciver XML file?

Hello All,
Iam creating proxy to file scenario.....at receiver side iam creating XML file like below.
<?xml version="1.0" encoding="UTF-8" ?>
<OrderTransaction>
<TransactionInformation Version="2.0.0">
<DocId>0180000186</DocId>
<Sender>........
</OrderTransaction>
bit now client require one header node like below
<!DOCTYPE OrderTransaction PUBLIC "Order" "Order.dtd">
now th recevier xml need to look like
<?xml version="1.0" encoding="UTF-8" ?>
<OrderTransaction>
<!DOCTYPE OrderTransaction PUBLIC "Order" "Order.dtd">
<TransactionInformation Version="2.0.0">
<DocId>0180000186</DocId>
<Sender>........
</OrderTransaction>
how to add that node........... i cant add it as node element............ Please help me out.
Thanks and Regards,
Chinna
Edited by: chinnasapxi on Mar 16, 2010 8:11 PM

Hi Chinna,
Probably writing a script and calling in receiver file adapter after message processing and in the script just add the line in the 3rd line and then put the rest.
Regards,
---Satish

Comparing nodes in two xml files

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