Count all rows in all tables

Question

Is there any easy way to count all of the rows in all of the tables?
I am currently generating a list of tables by selecting from all_tables and then turning that into individual select count(*) statements using awk.
I'm guessing there is probably some other better method?

Answer 1

Jim,
I have a sql script which I call numrows that will dynamically create select count(*) statements from the dba_tables dictionary view... It does not display all of the tables in the entire database, but instead prompts you for a particular schema. Maybe you can adjust to do what you want it to..
Regards,
David
+++beginning of script
-- Script to count the number of rows in tables
set serveroutput on
declare
numrows integer;
cursor c1 is select table_name from user_tables order by table_name;
function rowcount(tablename in user_tables.table_name%type)
return integer is
cursornum integer;
numrows integer;
ignore integer;
begin
cursornum := dbms_sql.open_cursor;
dbms_sql.parse(cursornum,
'select count(*) from ' | | tablename,
dbms_sql.v7);
dbms_sql.define_column(cursornum, 1, numrows);
ignore := dbms_sql.execute(cursornum);
ignore := dbms_sql.fetch_rows(cursornum);
dbms_sql.column_value(cursornum, 1, numrows);
dbms_sql.close_cursor(cursornum);
return numrows;
end;
begin
dbms_output.enable(10000);
dbms_output.put_line('Table Rows ');
dbms_output.put_line('------------------------------ ----------');
for c1rec in c1 loop
numrows := rowcount(c1rec.table_name);
dbms_output.put_line(rpad(c1rec.table_name, 32) | | numrows);
end loop;
end;
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