Creating a new recorded instance

Hi,
I have managed to get my webcam to record to fms but only one
instance, it just replaces the file each time it records, does
anyone know the way to make new instances, there is a thread on
here somewhere about it but have managed to lose it!
thanks for your help
Gavin

Do you want to create a new instance of the application for
each recording, or do you just want to save multiple recordings
through the same app instance?
If you want to create a new application instance, change your
rtmp string to reflect the instance name you want to use:
rtmp://myserver.com/myApplication/InstanceName
If you just want to change the name of the recorded flv file,
change the name of the stream you publish to
ns = new NetStream(nc);
ns.publish("someUniqueStreamNameHere", "record")

Similar Messages

Commit_form creating issue with When-New-Record-Instance trigger

Hello friends,
I am using Oracle forms 6i . I have a multi-data block. I have written commit_form in when-new-record-instance of the data block. When I launch the form on my instance the form does not open.
But when I comment out this code, the form opens on the instance. What could be the exact problem?
Also is there any condition that I can specify if the whole data block is null when I open the form?

Hi...
In When-New-Record-Instance, check if the block status is NEW. If Not, then just apply COMMIT_FORM;
try this code in your trigger
IF :SYSTEM.BLOCK_STATUS = 'CHANGED'
THEN
COMMIT_FORM;
END IF;
Should work for you.
Thanks....

Filling datarows before creating a new record frm-40735 ora-01422

Hello
I want to create a user-control table where I Store in the Mastertable the user informations. in the 2 detail tables I store the programmnames of the first level, in the second table I store the name of the form and if the user is allowed to insert, amend or delete.
I use a Master/2 Detail-Form. When I create a new record in the master block, I want to fill in the first and second detail block, informations of another user of the 2 detail tables. therefore I created a when-new-block-instance trigger with the following code:
select programm
into :k_zugriff.Programm
from k_zugriff, K_benutzer
where r_benutzer_zaehler=k_benutzer.zaehler
and oracle_user='ROBERT';
because this sql serves more than one row I receive the error code frm-40735 ora-01422
so how could I solve the problem to insert 5-10 rows in :k_zugriff.Programm. I can not make an insert before I go to the block k_zugriff, because the user number is not commited known. Also I want to commit the form when all informations are filled in. in case of a mistake I want to exit the form with no commit;
has anyone a usefull Idea?
regards
robert

it works thank you. where can I get further information about this technik. are there any turtorials or something where I get information how to build this complex forms??
right statement
DECLARE
CURsOR cr IS
select programm
from k_zugriff, K_benutzer
where r_benutzer_zaehler=k_benutzer.zaehler
and oracle_user='ROBERT';
BEGIN
FOR rec IN cr LOOP
IF :SYSTEm.RECOrD_STATUS!='NEW' THEN
CREATE_RECORD;
END IF;
:k_zugriff.Programm:=rec.PROGRAMM;
END LOOP;
END;

How to populate automatically in a when-new-record-instance trigger?

I have a form which displays around ten rows with about 5 columns. Whenever i will create a new record, i would like to place an initial value on the first column of every record. How do I do this? If I place the value in the properties of the item, it would be replicated on all the rows. What I want is to put a different value for each row created. But the problem is there is only one item property that i can put a value on (displayed 10 times). How do i put different initial values for each record created without creating new items for each record. is this possible? Thanks a lot

Hi Navnit,
Yes you are right, but it can work even we not plase quotation mark in it. But Yes I forget to place semi colon so now it is
IF :System.Cursor_Record = 1 THEN
   :Block.Col1 := '02:00';
ElsIF :System.Cursor_Record = 2 THEN
   :Block.Col1 := '07:00';
   ------and so on
END IF;Danish

Need help to create a new record in mdm using java webdynpro

hi all,
I have to develop an application to create a new record in mdm by using java WebDynpro . Please help me what is the process that i have to follow to do this and provide me if you have any step by step guidance for this.
thanks & regards,
Mahi.

Hi,
The below link will help u to make the application in JAVA webdynpro
The article has code to for creating records.
https://www.sdn.sap.com/irj/sdn/go/portal/prtroot/docs/library/uuid/803e9e80-21f4-2a10-8cbf-bcf6a8060be3
Hope this may help u .
Rgds
Ankit

When creating a new record in a list, I want to create a new record in another list, too, together with the ID of the first record

OK, for anyone who has ever programmed a database, this one is easy. However, I am EXTREMELY limited. I work with SharePoint 365 (2013). I am pretty proficient in a number of programing languages, but I really don't know how to program SP. I wouldn't even
know where to put code.
Say, I have two lists: List A, with Items A1 (ID), A2, A3 and List B, with Items B1 (Lookup to A1), B2, B3. What I want this: When I create a new record in List A I want that also an empty record (except for the B:A1 item) is created. Is that possible without
any major programing?

you can create a workflow to achieve your requirement
http://sharepoint.stackexchange.com/questions/50059/create-a-list-item-when-item-is-created-in-another-list
My Blog- http://www.sharepoint-journey.com|
If a post answers your question, please click Mark As Answer on that post and Vote as Helpful

How can I create a new OC4J Instance in Application Server Control

Hi All,
Is there any way to create a new OC4J Instance in Application Server Control of installed SOA Suite, so that it gets listed in Cluster Topology page.
Thanks
Krrish

Hi Eric,
Thanks for the reply.
it is pretty simple..which I didnt try earlier..
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Krrish

Create a new record in transformation

Hi there,
I would like to create a new datarecord, in a start/end routine or in a characteristic transformation routine. I am loading data from one cube to another.
I have, say, a data structure looking like this:
GL_Account; Fiscyear; Version; Amount
111000;          2008;      01;         100.000
I want to, based on this record, create a new record where version gets a new value (ex: 10, instead of 01), so the new record would look like, eg,:
GL_Account; FiscYear; Version; Amount
111000;          2008;       10;        100.000
What would be the best way of doing this?
Thanks for your help.
Jon
I'm on BI 7.0

Hi,
Do this in End routine of Transformation,
data:
          itab type tys_tg_1,
          it_resultpackage type tyt_tg_1.
    append lines of RESULT_PACKAGE to it_resultpackage.
    loop at it_resultpackage assigning <RESULT_FIELDS>.
    if <RESULT_FIELDS>-version = '01'.
        <RESULT_FIELDS>-version = '10'.
            append itab to RESULT_PACKAGE.
      endif.
      clear <RESULT_FIELDS>.
    endloop.

JDeveloper 10g Creating a new record with trigger sequence primary key

Hi there, I'm sorry to post this incredibly simple question and I'm sure that someone must have answered this on this forum before but the searching of this site is incredible slow and painful and after 30 mins I can't find help.
I am using a struts Data Action to create a new record in the database and then being forwarded to an edit page where I can enter the new details. Then when the details are entered I am clicking an update button and returning to a browse screen where I can either commit the change to the database or rollback. Sounds pretty simple but I am really struggling with trying to get the trigger of the number sequence to work properly.
Ideally I would like to click the create new record button and then the primary key/triggered sequence number is already displayed on the empty form...
... but if this is too tricky or not possible then I would like the user to either not enter any value in the key field (which currently causes error - JBO-27014: Attribute PoNo in PO_SYS_MODULE.PoSystemView1 is required) OR the user enters a number and the trigger overwrites this number with the next in the sequence.
I can enter a new record if I look in the manager console and see the next number in the sequence and then create the record using this number and then click commit twice, as the first time I get the error: JBO-25019: Entity row of key oracle.jbo.Key[154 ] not found in PoSystem. Or if I enter a value 5 times greater than the next in the sequence I have to click the commit button 5 extra times to get the sequence to match the input.
I hope that this lengthy explanation fills you in on my problem, there must be a simple solution to this and I will be VERY grateful to anyone who can help me.
Many thanks
Ben Sayers (clearly a newbie)

Hi,
ADF Business Components handles this for you - unless yo prefer doing this manually. In the Entity Object, set the PK attribute's type to DBSequence. Then create a database sequence and use a database trigger to add the sequence value on insert
Frank

When new record instance not firing on Purchase Order form

I query a purchase order and click on the shipment lines button. There are 2 shipment lines in this example. I am using CUSTOM.pll to inject some specific code to restrict the cancel functionality. One line I want to restrict the cancel functionality and the other line I don't want to restrict. The problem arises when I click between the two rows on the Org or Ship to fields. No event or trigger gets fired that I can see; hence, the CUSTOM.pll code does not get injected and the user will be able to cancel both lines. Any ideas? Thank you for your time,
-Kevin

What does that mean? In the middle of creating a record?
But how come system allows me to go to the 2nd tab when it goes to the last record and doesnt allow me to go the 2nd tab when i create in middle of the record
Seems that there is some difference in the data of the two records, maybe one record passing validation and the other one not.Validations are same, both the scenario it just creates a new record.

When-new-record-instance

Hi All !
I have a form, where in
*Trigger:when new form instance*
enter_query;
*Block level Trigger :when-new-record-instance*
:empaply.employeeid:=:global.employeeid;
select employee_id,firstname into :empaply.employeeid,:empaply.employeename
from pim_emplpersonalinfo where employee_id =:global.employeeid;
if :empaply.leavetype='Casual Leave' then
:empaply.status1:='Not Applicable';
:empaply.status2:='Not Applicable';
:empaply.status:='Pending Approval';
elsif :empaply.leavetype='Earn Leave' then
:empaply.status1:='Pending Approval';
:empaply.status2:='Pending Approval';
:empaply.status:='Pending Approval';
elsif :empaply.leavetype='Earn Leave' and :empaply.status='Rejected' then
:empaply.status1:='Not Applicable';
:empaply.status2:='Not Applicable';
elsif :empaply.leavetype='Earn Leave' and :empaply.status1='Rejected' then
:empaply.status2:='Not Applicable';
end if;And for a push button
*Trigger: when button pressed*
execute_query;Now my issue is the initial value i have set in the new record instance is not working automatically, it works when i click any other text box in my form or when i scroll down..
What can i down to overcome this?
Pls help !
Thanks and Regards
user 10685325
Edited by: user10685325 on Jun 22, 2009 1:19 AM

Hai,
The NEW-RECORD-INSTANCE Trigger will work only when the cursor moves to that record.
write in the POST-QUERY Trigger of the block.
Regards,
Manu.
If this answer is helpful or correct, please mark it. Thanks.

How to undo update of checkbox after triggering when-new-record-instance

Hi,
I am using eBusiness Forms Personalization in 11.5.10 to alter the Receipts form in Purchasing. I want to prevent users checking the rcv_transaction checkbox if the destination is "Multiple" and, instead, click the "+" sign to explode the multiple record into it's many component records.
I can do this by invoking the when-new-record-instance trigger to make the "multiple" record fields unalterable and issue a warning message when the user selects such records. However, my problem is that - if the user clicks the checkbox as the first field in a "multiple" record, then this updates the checkbox to "Yes" BEFORE the trigger fires, which then locks the record for update.
What I need is a solution that either sets the checkbox to unalterable for "multiple" records BEFORE the user clicks into such records, OR a method of undoing the update of the checkbox after the record has been selected (I cannot do this by simply setting it to "No" by the trigger as this is still technically an update and locks the record).
Cheers
Graham

Hi Navnit,
Yes you are right, but it can work even we not plase quotation mark in it. But Yes I forget to place semi colon so now it is
IF :System.Cursor_Record = 1 THEN
   :Block.Col1 := '02:00';
ElsIF :System.Cursor_Record = 2 THEN
   :Block.Col1 := '07:00';
   ------and so on
END IF;Danish

How to discover which field was clicked in when-new-record-instance

Suppose: a multi-record block. The user is positioned on an existing record on field A
Action: user clicks on empty (new) record on field B
Question: how can I discoverer that the user clicked on field B in the when-new-record-instance? Already tried :system.current_item and :system.trigger_item. They both contain 'field A'.
Edited by: user473811 on 26-aug-2010 4:56

That should work. What version of forms are you running?
I tested it out on Forms 9.0.4 just to make sure and :system.current_field, :system.current_item, :system.cursor_field, and :system.cursor_item all bring back field B when I run the form in debug mode. Is there logic in your when-new-record-instance trigger that is taking you back to field A before you look at the :system variables?
I would run the form in debug mode if I was you and break on the first thing in the WNRI trigger and just step through it looking at those system variables so you can see what it happening, but it should work unless you have some bugged up version of forms or are doing a go_item in the trigger back to field A.

FRM-40735: WHEN-NEW-RECORD-INSTANCE trigger raised unhandled exception ORA-

Hi,
In R12 When trying to search existing users through Sysadmin or any other user ...we are getting the below errror...
ORA-01403: no data found
FRM-40735: WHEN-NEW-RECORD-INSTANCE trigger raised unhandled exception ORA-06510
This error is not happening when we search for the SYSADMIN user....
Any idea why this error happening...
Also another error which is faced by users other than SYSADMIN is the below one when changing the responsability...
APP-FND-01926---The custom event WHEN-RESPONSIBILITY-CHANGED raised unhandled exception:User Defined Exception
Thanks
Joseph
Edited by: 783717 on Sep 27, 2010 10:49 PM

Hi,
In R12 When trying to search existing users through Sysadmin or any other user ...we are getting the below errror...
ORA-01403: no data found
FRM-40735: WHEN-NEW-RECORD-INSTANCE trigger raised unhandled exception ORA-06510
This error is not happening when we search for the SYSADMIN user....
Any idea why this error happening...What changes have been done recently?
Please run AutoConfig and make sure it completes successfully.
Also another error which is faced by users other than SYSADMIN is the below one when changing the responsability...
APP-FND-01926---The custom event WHEN-RESPONSIBILITY-CHANGED raised unhandled exception:User Defined ExceptionCan you find any errors in the database log file?
Please compile CUSTOM.pll (and other files) as per these docs and try again (as you are on R12 use frmcmp_batch.sh instead of f60gen).
APP-FND-01926, ORA-06508 [ID 797242.1]
APP-FND-01926: The custom event WHEN-LOGON-CHANGED raised unhandled exception: ORA-06508: PL/SQL: [ID 831159.1]
APP-FND-01926 when logon changed ORA-06508 [ID 334295.1]
Thanks,
Hussein

FRM-40735: WHEN-NEW-RECORD-INSTANCE trigger

Hi Guys,
Can someone help me to find the root cause of my follwoing issue
Issue
My Sales Order was giving following error when trying to open the form
'FRM-40735: WHEN-NEW-RECORD-INSTANCE trigger '
Bounced the instance the issue was resolved.
Again today morning ,same issue started again after the daily bounce which is done bu a script.
This time I bounced Form server and issue was resolved.
Can someone help me in finding the root cause of this issue.
This is issue is happening only on one form (Sales Order ) !!!!!
Thanks

Hi
This is a Standard form using cusom.pll.
This was working perfect for last 1 year.
There where no changes made in the forms or in the environment.
Only activity carried out was a rebooting of server.
Surprising it is working fine after boucing!!!!
any idea
Thanks

Creating a new recorded instance

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