Data with two rows in a single column

I have been working on a report with the customer due amounts shown in bucketed columns eg 1-30 , 31-60 etc for each Customer,
so for each column I want to show an additional row with the % of the due amounts for each bucketed column.
. The format of report should look like below in pivot/table view
|Customer| |Due1-30 | Due31-60 | Due60+ |     Total |
|XYZ | |     3000 |     2000 |     5000 |     10000 |
|      |%Due |     30% |     20% | 50% |     100% |
ABC….
I have to get the percentages on the measure values in a separate row(not as a seperate column). Could you please help me how to get result like the format what I have shown
Thanks,
BP
Edited by: user8116383 on May 6, 2011 8:55 AM

Hi
This can be achievable by using Pivot view.
1.In Columns field place the customer and place the measure lables in the rows field and the measure column in measure field.
2.Duplicate the measure column and name it as %Due and click more options on this duplicated column and click shown data as -> percent of -> Row
Thanks
Diney

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        <property name="EPCFLevel" value="0"/>
        <property name="ComponentType" value="com.sapportals.portal.layout"/>
        <property name="com.sap.portal.pcm.Title" value="Light 2 Columns (Equal Widths)"/>
        <property name="com.sap.portal.pcm.Description" value="Layout displaying two equal-width columns"/>
        <property name="com.sap.portal.reserved.layout.TagLibLayout" value="/SERVICE/com.sap.portal.pagebuilder/taglib/layout.tld"/>
        <property name="com.sap.portal.reserved.layout.TemplateFile" value="light_equalWidths.jsp"/>
        <property name="AuthScheme" value="anonymous"/>
        <property name="com.sap.portal.reserved.layout.Cont1" value="column1">
          <property name="plainDescription" value="Column 1"/>
          <property name="orientation" value="vertical"/>
          <property name="designClass" value="prtlPageConL"/>
        </property>
        <property name="com.sap.portal.reserved.layout.Cont2" value="column2">
          <property name="plainDescription" value="Column 2"/>
          <property name="orientation" value="vertical"/>
          <property name="designClass" value="prtlPageConR"/>
        </property>
      </component-profile>
    </component>
    <component name="narrowWideNarrow">
      <component-config>
        <property name="ClassName" value="com.sapportals.portal.pb.layout.PageLayout"/>
        <property name="ResourceBundleName" value="pagebuilder_nls"/>
        <property name="SafetyLevel" value="no_safety"/>
      </component-config>
      <component-profile>
        <property name="ComponentType" value="com.sapportals.portal.layout"/>
        <property name="com.sap.portal.pcm.Title" value="3 Columns (Narrow:Wide:Narrow)"/>
        <property name="com.sap.portal.pcm.Description" value="Three columns displayed in a narrow:wide:narrow layout"/>
        <property name="com.sap.portal.reserved.layout.TagLibLayout" value="/SERVICE/com.sap.portal.pagebuilder/taglib/layout.tld"/>
        <property name="com.sap.portal.reserved.layout.TagLibHtmlb" value="/SERVICE/com.sap.portal.htmlb/taglib/htmlb.tld "/>
        <property name="com.sap.portal.reserved.layout.TemplateFile" value="narrowWideNarrow.jsp"/>
        <property name="AuthScheme" value="anonymous"/>
        <property name="com.sap.portal.reserved.layout.Cont1" value="column1">
          <property name="plainDescription" value="Column 1"/>
          <property name="orientation" value="vertical"/>
          <property name="designClass" value="prtlPageConL"/>
        </property>
        <property name="com.sap.portal.reserved.layout.Cont2" value="column2">
          <property name="plainDescription" value="Column 2"/>
          <property name="orientation" value="vertical"/>
          <property name="designClass" value="prtlPageConM"/>
        </property>
        <property name="com.sap.portal.reserved.layout.Cont3" value="column3">
          <property name="plainDescription" value="Column 3"/>
          <property name="orientation" value="vertical"/>
          <property name="designClass" value="prtlPageConR"/>
        </property>
      </component-profile>
    </component>
    <component name="light_narrowWideNarrow">
      <component-config>
        <property name="ClassName" value="com.sapportals.portal.pb.layout.PageLayout"/>
        <property name="ResourceBundleName" value="pagebuilder_nls"/>
        <property name="SafetyLevel" value="no_safety"/>
      </component-config>
      <component-profile>
        <property name="EPCFLevel" value="0"/>
        <property name="ComponentType" value="com.sapportals.portal.layout"/>
        <property name="com.sap.portal.pcm.Title" value="Light 3 Columns (Narrow:Wide:Narrow)"/>
        <property name="com.sap.portal.pcm.Description" value="Three columns displayed in a narrow:wide:narrow layout"/>
        <property name="com.sap.portal.reserved.layout.TagLibLayout" value="/SERVICE/com.sap.portal.pagebuilder/taglib/layout.tld"/>
        <property name="com.sap.portal.reserved.layout.TemplateFile" value="light_narrowWideNarrow.jsp"/>
        <property name="AuthScheme" value="anonymous"/>
        <property name="com.sap.portal.reserved.layout.Cont1" value="column1">
          <property name="plainDescription" value="Column 1"/>
          <property name="orientation" value="vertical"/>
          <property name="designClass" value="prtlPageConL"/>
        </property>
        <property name="com.sap.portal.reserved.layout.Cont2" value="column2">
          <property name="plainDescription" value="Column 2"/>
          <property name="orientation" value="vertical"/>
          <property name="designClass" value="prtlPageConM"/>
        </property>
        <property name="com.sap.portal.reserved.layout.Cont3" value="column3">
          <property name="plainDescription" value="Column 3"/>
          <property name="orientation" value="vertical"/>
          <property name="designClass" value="prtlPageConR"/>
        </property>
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    </component>
</components>
<services/>
</application>
Greetings,
Praveen Gudapati

How do you find the average value of all the data between two points on a single channel

I am tring to calculate the average value of all the data points on a single plot between two seperate points
I have attahced an illustration.
Tim
Solved!
Go to Solution.
Attachments:
plot.jpg ‏173 KB

Hey smoothdurban,
I've seen Brad's code, and trust me, it's worth the effort to let him help you get it up and running - it's definitely the most ideal way to solve this problem. However, as Brad said, there are multiple ways to tackle this - both interactive and programmatic - so in the meantime, I'll take a second to detail one of the interactive and sure-fire ways to find the average of data between two points on a single channel.
We'll use"Flags." Set up your VIEW graph exactly as you did on your original screenshot, using Band Cursors to approximate the beginning and ending X-values representing the range you want to examine. Next:
1. Click the "Set Flags" button () that is a part of your 2D Axis System. Note that you can hold down the Shift button if you ever decide you want to do this on more than a single curve at one time.
2. Select the "Flags: Copy Data Points" button that enables after Flags are set.
3. This creates new channel(s) in the default (bold) group in the Data Portal that contains only the Flagged data.
4. Select DIAdem ANALYSIS.
5. Select Statistics » Descriptive Statistics.
6. In the Channels input, select the newly created channel containing your Flagged Y-Data.
7. Ensure that the Arithmetic Mean parameter is set. You can preview the data and the result in the dialog before pressing OK to execute the calculation.
You may have noticed that in the Descriptive Statistics calculation, one of the parameters that you can set is the range of channel rows to operate on - so, if you know the row numbers of your beginning and ending X-values, you could just simply run the Descriptive Statistics calculation and use this parameter to operate on a row subset of your original channel instead of the entire channel.
Derrick S.
Product Manager
NI DIAdem
National Instruments

Concat rows values into single column

Hi All,
How can I concat values of a multiple rows into a single column by separating them by comma.
Eg:
SELECT empno FROM emp;
empno
1
2
3
4
I want output should be:
Empnos
1,2,3,4
Thanks & Regards,
Danish

MichaelS wrote:
Or
SQL> select rtrim(xmlagg(xmlelement(e, empno || ',')).extract('//text()').extract('//text()') ,',') empnos from emp
EMPNOS
7369,7499,7521,7566,7654,7698,7782,7788,7839,7844,7876,7900,7902,7934
Hi Michael,
is it an error or is it correct to put extract 2 times? This is giving to me the same result:
select rtrim(xmlagg(xmlelement(e, empno || ',')).extract('//text()'),',') empnos from emp;
EMPNOS
7369,7499,7521,7566,7654,7698,7782,7788,7839,7844,7876,7900,7902,7934           Regards.
Al

JTabbedPane with two rows of tabs

Hi,
I need to create a JTabbedPane with layout policy as SCROLL_TAB_LAYOUT with two rows of tabs. The first level will have say 10 tabs and the all the remaining tabs (say 20) will be added in the next level. Please help me out on this, to how to proceed with it?
Edited by: Soundarapandian on Nov 25, 2009 3:10 PM

Soundarapandian wrote:
I need to create a JTabbedPane with layout policy as SCROLL_TAB_LAYOUT with two rows of tabs. The first level will have say 10 tabs and the all the remaining tabs (say 20) will be added in the next level. Please help me out on this, to how to proceed with it?Try this (imho better) approach:
create a new tabbedpane for each level and add each of these tabbedpanes to an upperlevel tabbedpane, thus allowing you to pre-select the desired level.

Compare column data of two rows

Hi there,
I a have a table
COMP_ID      PROD      COLOR       COMPAREFLAG ORDER_NUMBER
1           sun      red            -                          2
2              sun      blue          Y                         2
3           horse      black         -                          1
4              horse   white            Y                         1
5           chair      black          -                         3
6          chair    black          Y                         3I would like to compare for example the columns PROD and COLOR of two rows with ORDER_NUMBER = 2
The row with COMP_ID = 1 is the first entry and with COMP_ID = 2 the second one therefore the COMPAREFLAG is set to 'Y'.
If the entries are diffrent both rows should be return to output.
I would like to compare also the rows with COMP_ID 5 and 6. In this case nothing should be return to output.
I don't know how to manage this. Can anyone please help me?
Thanks,
ben
Message was edited by:
ben512

I hope that I well understand.
Do you want to get rows only if PROD/COLOR of one row is different of the PROD/COLOR from other row (with the same order_number) ?
What you can try :
SQL> with tbl as
2 (select 1 comp_id, 'sun'   prod, 'red'   color, null compareflag, 2 order_number from dual union all
3   select 2 comp_id, 'sun'   prod, 'blue' color, 'Y' compareflag, 2 order_number from dual union all
4   select 3 comp_id, 'horse' prod, 'black' color, null compareflag, 1 order_number from dual union all
5   select 4 comp_id, 'horse' prod, 'white' color, 'Y' compareflag, 1 order_number from dual union all
6   select 5 comp_id, 'chair' prod, 'black' color, null compareflag, 3 order_number from dual union all
7   select 6 comp_id, 'chair' prod, 'black' color, 'Y' compareflag, 3 order_number from dual )
8 select comp_id, prod, color, compareflag, order_number
9 from (select comp_id,
10                prod,
11                decode(first_value(prod) over (partition by order_number order by comp_id range between unbounded preceding and unbounded following),
12                       last_value(prod) over (partition by order_number order by comp_id range between unbounded preceding and unbounded following),null,prod) prod_d,
13                color,
14                decode(first_value(color) over (partition by order_number order by comp_id range between unbounded preceding and unbounded following),
15                       last_value(color) over (partition by order_number order by comp_id range between unbounded preceding and unbounded following),null,color) color_d,
16                 compareflag,
17                 order_number
18         from   tbl
19         where order_number=&order_number)
20 where (prod_d is not null or color_d is not null)
21 order by 1;
Enter value for order_number: 1
old 19:        where order_number=&order_number)
new 19:        where order_number=1)
   COMP_ID PROD COLOR C ORDER_NUMBER
         3 horse black              1
         4 horse white Y            1
SQL> /
Enter value for order_number: 2
old 19:        where order_number=&order_number)
new 19:        where order_number=2)
   COMP_ID PROD COLOR C ORDER_NUMBER
         1 sun   red                2
         2 sun   blue Y            2
SQL> /
Enter value for order_number: 3
old 19:        where order_number=&order_number)
new 19:        where order_number=3)
no rows selected
SQL> Nicolas.

Copy data of two rows together into a new row

Hello everyone.
I have a question about copying data of two existing rows together into a new third row.
See this short example:
This is the current situation. The rows STATE_1 and STATE_2 contain different separated information.
In the past data were saved randomly in one of those rows.
This is the table State:
ID
Cust_ID
STATE_1
STATE_2
STATE_3
1
88
Customer is waiting.
Call from yesterday.
2
11
Mr. Smith, no answer.
Waiting until December
3
11
Pls create PO.
Old PO was cancelled
4
5
No access to system.
From now on everything has to be saved to the empty STATE_3 but I also need the old entries from the past which also have to be copied together into STATE_3
like this:
ID
Cust_ID
STATE_1
STATE_2
STATE_3
1
88
Customer is waiting.
Call from yesterday.
Customer is waiting. Call from yesterday
2
11
Mr. Smith, no answer.
Waiting until December.
Mr. Smith, no answer. Waiting until December.
3
11
Pls create PO.
Old PO was cancelled.
Pls create PO. Old PO was cancelled.
4
5
No access to system.
No access to system.
Is there an easy SQL-command?
Thanks for any help.

Hi,
DB2000 wrote:
Hello everyone.
I have a question about copying data of two existing rows together into a new third row.
See this short example:
This is the current situation. The rows STATE_1 and STATE_2 contain different separated information.
In the past data were saved randomly in one of those rows.
This is the table State:
ID
Cust_ID
STATE_1
STATE_2
STATE_3
1
88
Customer is waiting.
Call from yesterday.
2
11
Mr. Smith, no answer.
Waiting until December
3
11
Pls create PO.
Old PO was cancelled
4
5
No access to system.
When you say "row", do you mean "column"?
DB2000 wrote:
Because in this case STATE_1 and STATE_2 are only text of a log file/history.
So I think 1NF isn't really violated and because of performance of the database in this case it's better to put obsolete rows together.
Why do you think that?
The definition of First Normal Form is that every column of every row contains 1 piece of information, not a variable number of pieces. Whether or not that data is only text of a log file/history has nothing to do with it.
You might claim you have good reasons (such as performance) for violating First Normal form, but you can't say that you're not violating it.

Fetch Multiple row in repor to insert data with multiple rows .

Hi Friends
i want to Insert emp attendance .
There are 10 emp in company .they enter there arival time in attendance register .
i have two item
1--p1_att_date
2--p1_status
ATTEN_STATUS are PRESENT by default in selectlist .
i want, when i enter date in p1_att_date item and Press submit then generate a report with 10 employee and insert in_time in report and when press enter then data with 10 emp should insert in to table ABC .
i don't want to use tabularform for this .actully i don't want to use ADD_ROW option to ADD attendance for second emp.so please give me some solution.
Emp_ID     ATTEN_DATE     ATTEN_STATUS      IN_TIME     OUT_TIME
101     22-JAN-2009     PRESENT
102     22-JAN-2009     PRESENT
103     22-JAN-2009     PRESENT
104     22-JAN-2009     PRESENT
105     22-JAN-2009     PRESENT
106     22-JAN-2009     PRESENT
107     22-JAN-2009     PRESENT
108     22-JAN-2009     PRESENT
109     22-JAN-2009     PRESENT
110     22-JAN-2009     PRESENT
My table is :-
table Name --ABC
emp_id number;
atten_date date;
atten_status varchar2(12);
in_time timestemp;
out_time timestemp;
How can i do this.
Thanks
Manoj

Hi Manoj,
You can create multiple records easily using a single, simple, form. However, you would surely have to enter in the times individually using a tabular form (otherwise, you would have to use the same form 10 times). You do not have to keep the Add Row option on the page - this functionality can be removed.
Andy

Creating two rows from a single row information

Hi,
I have data that will always be returned as a single row from a join of tables t1, t2.
However I want the single row to be split into two rows. i.e First row containing some fields and second row containing th remaining fields.
I think there might be a thread already existing. Can you please point me in the right direction if it is.
select t1.c1, t1.c2, t2.c1, t2.c2
from t1, t2
where t1.c3 = t2.c3
I expect the output 2 rows like the following
t1.c1 t2.c1
t1.c2 t2.c2
Thanks

SQL>WITH t1 AS (SELECT     't1c1_' || ROWNUM AS c1, 't1c2_' || ROWNUM AS c2, ROWNUM AS c3
2                    FROM DUAL
3              CONNECT BY LEVEL <= 3),
4       t2 AS (SELECT     't2c1_' || ROWNUM AS c1, 't2c2_' || ROWNUM AS c2, ROWNUM AS c3
5                    FROM DUAL
6              CONNECT BY LEVEL <= 3),
7       t3 AS (SELECT t1.c1 AS c11, t1.c2 AS c12, t2.c1 AS c21, t2.c2 AS c22, ROWNUM AS r
8                FROM t1, t2
9               WHERE t1.c3 = t2.c3)
10 SELECT   a, b
11      FROM (SELECT c11 AS a, c21 AS b, r, 1 AS s
12              FROM t3
13            UNION ALL
14            SELECT c12, c22, r, 2 AS s
15              FROM t3)
16 ORDER BY r, s;
A                                             B
t1c1_1                                        t2c1_1
t1c2_1                                        t2c2_1
t1c1_2                                        t2c1_2
t1c2_2                                        t2c2_2
t1c1_3                                        t2c1_3
t1c2_3                                        t2c2_3Urs

Subtracting two rows from the same column

Hi,
I have the following table with about 6000 rows of different year_month but I am compare and subtract v
Organization     Year_month     Contribution
Kano     JAN-2011     200000
KADUNA     JAN-2011     300000
ABUJA     JAN-2011     400000
Kano     FEB-2011     300000
KADUNA     FEB-2011     200000
ABUJA     FEB-2012     600000
I want to select a year_month at run time to subtract the contribution of the first year_month from the contribution of the second year_month and give me the result as shown in the following table
Organization     JAN-2011     FEB-2011     diffrence
Kano     200000     300000     -100000
KADUNA     300000     200000     100000
ABUJA     400000     600000     -200000
Here is my code returning too many va
create or replace function "GET_MONTHLY_VALUE"
(q_name in VARCHAR2,
hmoCode in VARCHAR2)
return VARCHAR2
is
c1 number;
begin
select NHIS_CONTRIBUTION into c1 from CONTRIBUTION_MGT where upper(YEAR_MONTH)=upper(q_name) and upper(ORGANIZATION)=upper(hmoCode);
return c1;
exception when NO_DATA_FOUND THEN
return null;
end;
------a call to the above function:
create or replace function process_cont_monthly return varchar
is
Cursor cont_cursor is select ORGANIZATION from CONTRIBUTION_MGT;
begin
for
cont_rec in cont_cursor loop
select GET_MONTHLY_VALUE(:p26_month,cont_rec.ORGANIZATION) first, GET_MONTHLY_VALUE(:p26_month2,cont_rec.ORGANIZATION) second,
abs(GET_MONTHLY_VALUE(:p26_month,cont_rec.ORGANIZATION)-GET_MONTHLY_VALUE(:p26_month2,cont_rec.ORGANIZATION)) Diffrence
from CONTRIBUTION_MGT;
end loop;
commit;
end;
I became totally confused and don’t know what to do next
Any help and better guide is appreciated

Hi,
Here's one way:
WITH    months_wanted     AS
     SELECT     1 AS col, TO_DATE ('JAN-2011', 'MON-YYYY') AS month     FROM dual
    UNION ALL
     SELECT     2 AS col, TO_DATE ('FEB-2011', 'MON-YYYY') AS month     FROM dual
,     pivoted_data     AS
     SELECT       c.organization
     ,       NVL (SUM (CASE WHEN m.col = 1 THEN c.contribution END), 0)     AS total_1
     ,       NVL (SUM (CASE WHEN m.col = 2 THEN c.contribution END), 0)     AS total_2
     FROM       months_wanted     m
     JOIN       contribution_mgt c ON c.year_month >=            m.month
                                 AND c.year_month < ADD_MONTHS (m.month, 1)
SELECT    organization
,       total_1
,       total_2
,       total_1 - total_2     AS difference
FROM       pivoted_data
ORDER BY organization
;I assume that the year_month column is a DATE. Date information always belongs in DATE columns.
As written, the two months do not need to be consecutive. If you always want consectuive months, this can be re-written so that you only have to enter the first month, not both of them.
I hope this answers your question.
If not, post a little sample data (CREATE TABLE and INSERT statements, relevant columns only) for all tables involved, and also post the results you want from that data.
Point out a few places where the query above is giving the wrong results, and explain, using specific examples, how you get those results from that data in those places. If you changed the query at all, post your code.
Always say which version of Oracle you're using.
See the forum FAQ {message:id=9360002}

Data with two rows in a single column

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