Deleting array elements

Hi!
I have a problem with my program. i have an array and in this array a several numbers. With the "In Range and Coerce" function i want to prove if the the array element is inside or outside of my limitations. If my array element is in the outside of my limitation, the code in the case structure should delete this element.
I need this program, because the array is displayed on a graph and i want only display the date, which is in the limitations.
I hope somebody could help me!
Best regards,
Peter
Labview 7.1 on Windows 2000
Attachments:
array.jpg ‏54 KB

Hallo Peter
Das Problem tritt auf, weil du immer wieder das selbe Array liest.
Die Knoten am Loop sollten Shift-Register sein, damit das Array, bei dem das Element gelöscht wurde, bei der nächsten Iteration gelesen wird. Allerdings musst du dann auf einen While-Loop umstellen, da du ansonsten Elemente lesen willst, die es im Array nicht mehr gibt.
Anbei eine mögliche Lösung.
Hoffe es hilft weiter.
Thomas
Using LV8.0
Don't be afraid to rate a good answer...
Attachments:
RemoveElements.vi ‏32 KB

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Deleting array element

Hi,
I am getting an array of 100 elements and i need to delete the the element if it contains 255.And most importantly the next element should be placed in its place.So if i get 30 255s then my output array should get reduced to 70.I tried search 1d array but it is returning only the index of first element containing 255.Please help!!!
Solved!
Go to Solution.

Hi muks,
i think i understand what you mean, but i have to create a test array to work with. Attached you can see another way to delete the 255 without using a loop.
Mike
Attachments:
Unbenannt 3.vi ‏13 KB
Remove_Element_from_Array.vi ‏14 KB

How to delete an element in an array...(simple way)

hi,
Newbie here... please help how to delete an element in an array list?
there are alot of codes but they're complicated for a newbie like me..
(simple codes would be better ..:) thank you...

makk_88 wrote:
since u want the simple method.....
just overrite the position of the element that need to be deleted with the next element in the array..
by doing this, element need to be deleted will not be accessibe..
i think u got..what i'm saying.
thnx..Mak,
Say we wish to delete the second element of an array a[1]. Do you really believe that a[1] = a[2] somehow magically deletes a[1]? I really don't think so Tim.
Two eggs, minus 1, equals two eggs? Interesting theory, but I think you're probably wrong.
*@OP:* My advise is just use an ArrayList.
Cheers. Keith.

How can I display all results of a array element in a TS2.0 NumericArrayMeasurement in a single report line?

TestStand2.0 generates for each result property ( data, limits, status...) of each array element in a NumericArrayTest an extra line in the test report.
How can I change this to display all result properties of one array element in a single line?
How can I reduce the spaces between the property name and its value in the report?
How can I delete the message: "Measurement[x]" and display only the Measurement Alias (named in the Edit Limits menu)?
This means I like to change my report from:
Measurement[0] (ADC1):
Data: 5000
Status: Passed
Measurement[1] (AD
C2):
To:
ADC1: Data: 5000 Status: Passed
ADC2: ...

Hi,
What you can do, is use the Override Callbacks for Modify the Report that is Generated.
Also you can also change the report sequence 'reportgen_txt.seq' to achieve the desired affect. If you go for modifying the report sequence then copy this to the User folder and then make your changes.
In the Resources Library you can find simple examples were the report has been modified by either using the Override Callbacks or by modifying the actual sequence.
One other item in the Report Options you will have to set the 'Select a Report Generator for Producing the Report Body' control to use the Sequence instead of the DLL.
Hope this helps
Ray Farmer
Regards
Ray Farmer

HOW TO DELETE DUPLICATE ELEMENT IN A VECTOR

Hi everybody!
If I've a vector like this vectA={apple,orange,grape,apple,apple,banana}
and I want final result be vectB={apple,orange,grape,banana}.
How should I compare each element in vectA and delete duplicate element. Like here duplicated element is apple. Only one apple remain in the vectB.
Any help,
Thanks.

Hello all. Good question and good answers, but I would like to elaborate.
To begin with, you specifically asked to map the following:
{apple,orange,grape,apple,apple,banana} ==> {apple,orange,grape,banana}
Both of cotton.m's solutions do NOT do this, unfortunately. They are both useful in particular cases though, so think about what you're trying to do:
cotton.m's first solution is best if order does not matter. In fact, as flounder first stated, whenever order doesn't matter, your most efficient bet is to use a Set instead of a List (or Vector) anyways.
Set vectB = new HashSet(vectA);This code maps to {banana, orange, grape, apple}, because HashSets are "randomly" ordered.
cotton.m's second solution is good if you want to impose NEW ordering on the List.
Set vectB = new TreeSet(vectA);This code maps to {apple, banana, grape, orange}, because TreeSet uses alphabetical-order on Strings by default.
java_2006, your solution is the most correct, but it's a little verbose for my taste :)
more importantly, the runtime-efficiency is pretty bad (n-squared). calling Vector.contains performs (at worst) n comparisons; you're going to call it n times! Set.contains usually performs 2 comparisons (constant, much better), so I suggest you USE a Set to do the filtering, while still sticking with your good idea to use a List. When the ordering is "arbitrary" (so can't use TreeSet) but still relevant (so can't use HashSet), you're basically talking about a List.
I think saving A LOT of time is worth using A LITTLE extra space, so here, let's save ourself some runtime, and some carpal-tunnel.
import java.util.*;
class Foo {
     public static void main(String[] args) {
          String[] fruits = {"apple","orange","grape","apple","apple","banana"};
          List     l = Arrays.asList(fruits),
               m = filterDups(l);
          System.out.println(m);
     // remember, both of the following methods use O(n) space, but only O(n) time
     static List filterDups(List l) {
          List retVal = new ArrayList();
          Set s = new HashSet();
          for (Object o : l)
               if (s.add(o))
                    retVal.add(o);     // Set.add returns true iff the item was NOT already present
          return retVal;
     static void killDups(List l) {
          Set s = new HashSet();
          for (Iterator i = l.iterator(); i.hasNext(); )
               if (! s.add(i.next()))
                    i.remove();
     // honestly, please don't use Vectors ever again... thanks!
     // if you're going to be a jerk about it, and claim you NEED a Vector result
     // then here's your code, whiner
     public static void mainx(String[] args) {
          String[] fruits = {"apple","orange","grape","apple","apple","banana"};
          List l = Arrays.asList(fruits);
          Vector v = new Vector(l);
          killDups(v);
          System.out.println(v);
}

How to delete an element in arraylist??

here i have an array list which contain details of an address book
I want to delete one element in the list
but its not deleting
Could anyone please take a look and help me
tank u in advance!!
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      relations R=(relations)p;
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           ((relations) (o)).affiche();
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}

It's a good thing you use code tags for posting here. Could you now consider using code conventions?
- Why is the second loop nested in the first one? (this second loop looks weird anyway...)
- The Iterator has a remove method. You should use it in such case.
- Looks like you have a malpositioned/misused break statement (which is probably the reason why nothing happen, as it terminates the for loop after the first iteration.)

Change array element "initialized" property

I'm a newcomer here. And it is a simple question.
The aim of this part is to save the array data.
You can see that if the array element is uninitialized, it won't be saved to spreadsheet, which saves space in the disk. So can I change the "initialized" property of this array element back to unitialized?
Thanks
Solved!
Go to Solution.

You can "right-click the element...data operations...delete element".
(This has nothing to do with "uninitialized". The size of the array is indicated by the bright elements, the dull elements are outside the valid range, which has nothing to do with the size of the container. Your first array has two elements and your second array has three elements.)
LabVIEW Champion . Do more with less code and in less time .

How do I access array elements in one method from another method?

Hi all!
How do I access the array's elements from another method so that method 2 can have access to method 1's array elements? Thanks for any help!
I am trying to create a simply program that will use a method to create an array and a SEPARATE method that will sort the array's elements (without using java's built in array features). I can create the program by simply having one method and sorting the array within that same method, BUT I want to sort the array from another method.
Here's my code so far:
public class ArraySort {
 public static void createArray(int size){
 double myArray[] = new double[size]; //create my new array
 for(int j=0; j < myArray.length; j++)
 myArray[j] = (200.0 * Math.random() + 1.0); //fill the array with random numbers
 public static void sortArray(){
 // I WANT THIS METHOD TO ACCESS THE ARRAY ELEMENTS IN THE METHOD ABOVE, BUT DON'T KNOW
 // HOW???? Please help!
 public static void main(String[] args) {
 createArray(4); //call to create the array
}Thanks again!
- Johnny

Thanks for the help all! I ve managed to get the program working, using java's built in array sort, but when i try to call on the array sort method from WITHIN my main method, nothing happens!
Can somebody please tell me why I am not able to call on the sort method from within my main class???? Thanks!
public class ArraySort {
 public void createArray(double[] arrayName, int size){
 double myArray[] = new double[size]; //create new array
 for(int j=0; j < myArray.length; j++)
 myArray[j] = (200.0 * Math.random() + 1.0); //populate array with
 } //random Numbers
 sortArray(myArray);
 } //Sort array(if I delete this & try to use it in Main method --> doesn't work???
 public void sortArray(double[] arrayName){
 DecimalFormat time = new DecimalFormat("0.00");
 Arrays.sort(arrayName); //sort array using Java's built in array method
 for(int i = 0; i <arrayName.length; i++)
 System.out.println(time.format(arrayName)); //print arary elements
public static void main(String[] args) {
ArraySort newArray = new ArraySort(); //create a new instance
double myArray[] = new double[0]; //create a new double array
newArray.createArray(myArray,4); //build the array of indicated size
//newArray.sortArray(myArray); //This will not work???? WHY?????//

Why do I get an "Array element prototype" -17001 error when trying to "View Paths"?

I added some custom types to my sequence file and to MyTypes.ini, and then opened and updated all of the .seq files under "Components/User". I'm a TestStand Newbie, but I think I did this correctly.
Now, if I try to "View Paths" in the sequence file, I get the following error:
Array element prototype does not have a location string!
Error Code: -17001, Program Error.
Source 'TSAPI'
Any idea what's going on?
Jim Polstra

Jim,
Thanks for the explanation and instructions for reproducing the problem.
I was able to reproduce this here as well and this is definitely not the intended behavior. As far as when this specific problem will be fixed, you can be assured that is being addressed in future releases of TestStand. For now though, we will have to consider a workaround, and it goes as follows:
It appears that this is happening only with specific type definitions such as "Path" (we haven't identified any others but we can't rule out yet that others don't exist), and it doesn't really have to be placed inside of a custom container type such as you illustrated. If you simply create a custom type that is just an array of "Path"s it will behave the same way when you View >> Paths. What's really funny about this though is that "Path" is simply a custom type based on the "String" intrinsic type. If you create your own custom string type called "MyPath" and replace the "FilePath" field in the "DataFile" container type with a new "FilePath" field based on the "MyPath" datatype, the error won't occur. This is also exactly what we recommend as a workaround. So, simply do the following to implement this:
1) Open MyTypes.ini and create a new custom type of type "String" named "MyPath".
2) Delete the field named "FilePath" from the "DataFile" custom type.
3) Create a new field in the "DataFile" custom container type, again called "FilePath", but make it of type "MyPath".
4) Save MyTypes.ini
5) Now try doing a View >> Paths on the MyTypes.ini file as before.
As a final note, we don't really believe that much concern should be placed on this by end-users in relation to a run-time scenario, as the only thing that is really being affected by this is an edit-time tool. We acknowledge the importance of having all of the design time tools work flawlessly, but it should be made clear that this will most likely not affect anything at run-time.
I hope this helps, and thank you again for reporting this issue to us. Let me know if you need anything else.
Jason F.
Applications Engineer
National Instruments
www.ni.com/ask

Reference to Array of Clusters with an array element

Hi,
I have an array of clusters CONTROL (calling it as "top level cluster array") with one of the cluster elements being a cluster array (please see attached).
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In my code, how do I typecast the Array Element (cluster) to the inner cluster (as shown in the figure) ?
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Solved!
Go to Solution.

You cannot use references in the same way that you use pointers around in C. LabVIEW does not manage memory in the same way that C does. This is actually a good thing, though C programmers find it "cumbersome" or "restrictive". I have also programmed in C, and frankly I prefer LabVIEW's memory management any day of the week.
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Please Help me on recreating deleted arrays

Hi,
I'm trying to recreate a deleted array as follows:
array=null;
Array array[] = new Array[100];
addToArray("elem1","elem2","elem3");
but doesn't work. I'm unable to recreate/populate the array. Can someone please help me with this?
I declared the array null first because the array was previously existing.
What I need to do is to be able to add array elements dynamically and delete some at the same time.
Deleting some elements seemed to be a complicated process so I thought of deleting the entire array instead then just recreate it and populate with required elements. I should keep the same array name.
Thanks!
Anna

array=null;
Array array[] = new Array[100]; // on this line you declare the variable array once again : the compiler doesn't accept it.
addToArray("elem1","elem2","elem3");
What I need to do is to be able to add array elements
dynamically and delete some at the same time. You can also give a look at the Collection
http://java.sun.com/docs/books/tutorial/collections/implementations/general.html
and especially the class "ArrayList" http://java.sun.com/products/jdk/1.2/docs/api/java/util/ArrayList.html
This class provides methods to add, delete element and dynamically enlarge the array.
Good luck

Displaying array elements on browser

hi im new to jsf
i have an array i defined it in bean class.i wanna show my array elements on browser
how can i write this code in jsp??
Edited by: xytk on Feb 10, 2010 9:42 AM

thanks..
i did it with <h:datatable>
but my page has 3 data table and all of them are on the left side and one under the other.But i wanna display one of them the right side of the page.
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<f:view><html>
<head>
</head>
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<f:facet name="header">
<h:outputText value="Sistemde Bulunan Tum Kitaplar" />
</f:facet>
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</h:dataTable>
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Don't Delete My Elements when I change my cluster style

See the picture below for an example of (what I consider to be) a frustrating "feature".
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Arrays also do this, but since we tend to spend more time designing clusters, it's far more frustrating than arrays.

I know the thread was linked to already, put to draw more attention to this I made a VI that should "Modernize" front panel contols in a VI.
http://forums.ni.com/t5/LabVIEW/Replace-cluster-bug/m-p/3148093#M906580
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Still Kudo'd

Delete array icon won't expand

Hi,
Does anyone have problem with "delete array" icon that won't expand to accept more indexes? From the Context help, it shows the delete array icon as expandable, but it won't work.
thanks,
atd
Solved!
Go to Solution.

No, the node is not expandable. I guess the image in the context help indicates how the node adapts to higher dimension input arrays.
Having the node expandable would be very dangerous because the indices assigned to elements of course change with every deletion. If you need to delete many sections, htere are much better ways to do this. "Delete from array" should typically not be used repetitively (e.g. in a tight loop).
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LabVIEW Champion . Do more with less code and in less time .

XMLBeans - how to delete an element?

Guys,
How do you delete an element within an xml data element?
If there's more than one way what are they?
Currently, I've generated XML java objects. I see a setNil() method and a couple removeXXX methods but neither appear to delete the element I'm trying to give the axe to.
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makk_88 wrote:
since u want the simple method.....
just overrite the position of the element that need to be deleted with the next element in the array..
by doing this, element need to be deleted will not be accessibe..
i think u got..what i'm saying.
thnx..Mak,
Say we wish to delete the second element of an array a[1]. Do you really believe that a[1] = a[2] somehow magically deletes a[1]? I really don't think so Tim.
Two eggs, minus 1, equals two eggs? Interesting theory, but I think you're probably wrong.
*@OP:* My advise is just use an ArrayList.
Cheers. Keith.

Deleting array elements

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