Drag & drop - multi targets that swop?

Question

Is it possible to have two draggables for two targets?
Where drag-A can be dropped on target-A or target-B, but if
it does, then drag-B can only be dropped onto the other target
(where drag-A is not).
The reason for this is a sequence of 15 draggables and
targets for a process that need to be completed in the correct
order. The code is fine for that, but the process has some steps
that can be done in two ways, hence the choice.
In other words, the user can get a correct answer for the
whole process if they decide to make some steps one way or the
other.
I'm intermediate level in flash scripting but don't know the
simplest way to do this. I've research the flash sites but nothing
comes close. Maybe the instance names have to be changed
dynamically via if/else? Maybe on drop of drag-A onto target-B
asomehow changes the logic.

Answer 1

"kglad" <[email protected]> wrote in message
news:fjibuu$jta$[email protected]..
> apply your startDrag() to the loader.
Thanks for your reply. I tried to isolate just the picture as
follows:
function dragPic(event:MouseEvent):void {
trace("drag, " + this.parent)
// event.target.startDrag();
// this.startDrag();
var test:Loader = Loader(event.target);
test:startDrag();
I got the same results. Its not only dragging the picture,
but it is also
dragging the background JPG file as well. I've tried making
the
background image a movieclip, and that did not change the
results.
I'm sure its something simple, but I haven't found the right
combination or
example.
Bob