Eliminate duplicates in merged lists

is there an esay way to eliminate duplicates in a merge?

Hi herbio,
More information will help to find a solution. How/what did you merge?
Hint 1: if you sort by that column, you will see duplicates come together.
Hint 2: Filter by other Columns may help.
The more you tell, the better we can help .
Regards,
Ian.

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OK, time to move over to the Aperture Discussions Group.
It's at this link - https://discussions.apple.com/community/professional_applications/aperture
This group you are in now is for Lion discussions, and over in the Aperture group, you'll meet skilled people who will help. Especially if you state your questions clearly and provide sufficient context such that the reader can figure out what is needed.
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And i'm surprised iTunes didn't alert me that this might happen. Like when I'm downloading photos I'm always alerted that I already have that and do i wish to replace the current one, or not make duplicates.
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Your specification can be interpreted more than one way.
In the examples you give, "duplicate records" not only have the same EMPNO, but all the data is the same. If this is what you are trying to avoid, use DISTINCT. Instead ofFROM EMP_TEST Ewrite FROM (select distinct * from EMP_TEST) EThis will eliminate duplicates if and only if every column has the same value.
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Variable name is HP_G1
HP_dmg1 = (DefaultListModel) HP_G1.getModel();
int a = HP_G1.getModel().getSize();
System.out.println("HP list no--------> "+a);
if(a!=0)
for (int j=0; j<a; j++)
String item1 = String.valueOf(HP_List.getModel().getElementAt(j));
System.out.println("HP list added--------> "+item1);
if(HP_dmg1.equals(item1)){
HP_dmg1.remove(j);
else
HP_dmg1.addElement(GPL);
}

Your code is unreadable, so I'll ignore it. In the future please press the message editor's CODE button to format code.
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Eliminate duplicate while fetching data from source

Hi All,
CUSTOMER TRANSACTION
CUST_LOC     CUT_ID          TRANSACTION_DATE     TRANSACTION_TYPE
100          12345          01-jan-2009          CREDIT
100          23456          15-jan-2000          CREDIT
100          12345          01-jan-2010          DEBIT
100          12345          01-jan-2000          DEBITNow as per my requirement, i need to fetch data from CISTOMER_TRANSACTION table for those customer which has transaction in last 10 years. In my above data, customer 12345 has transaction in last 10 years, whereas for customer 23456, does not have transaction in last 10 years so will eliminate it.
Now, CUSTOMER_TRANSACTION table has approximately 100 million records. So, we are fectching data in batches. Batching is divided into months. Total 120 months. Below is my query.
select *
FROM CUSTOMER_TRANSACTION CT left outer join
(select distinct CUST_LOC, CUT_ID FROM CUSTOMER_TRANSACTION WHERE TRANSACTION_DATE >= ADD_MONTHS(SYSDATE, -120) and TRANSACTION_DATE < ADD_MONTHS(SYSDATE, -119) CUST
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Now the problem is duplication of records.
while fetching data for jan-2009, it will get cust_id 12345 and will fetch all 3 records and load it into target.
while fetching data for jan-2010, it will get cust_id 12345 and will fetch all 3 records and load in into target.
So instead of having only 3 records, for customer 12345 it will be having 6 records. Can someone help me on how can i eliminate duplicate records from getting in.
As of now i have 2 ways in mind.
1. Fetch all records at once. Which is impossible as it will give space issue.
2. After each batch, run a procedure which will delete duplicate records based on cust_loc, cut_id and transaction_date. But again it will have performance problem.
I want to eliminate it while fetching data from source.
Edited by: ace_friends22 on Apr 6, 2011 10:16 AM

You can do it this way....
SELECT DISTINCT cust_doc,
                cut_id
FROM customer_transaction
WHERE transaction_date >= ADD_MONTHS(SYSDATE, -120)
   AND transaction_date < ADD_MONTHS(SYSDATE, -119)However please note that - if want to get the transaction in a month like what you said earlier jan-2009 and jan-2010 and so on... you might need to use TRUNC...
Your date comparison could be like this... In this example I am checking if the transaction date is in the month of jan-2009
AND transaction_date BETWEEN ADD_MONTHS(TRUNC(SYSDATE,'MONTH'), -27) AND LAST_DAY(ADD_MONTHS(TRUNC(SYSDATE,'MONTH'), -27)) Your modified SQL...
SELECT *
FROM customer_transaction
WHERE transaction_date BETWEEN ADD_MONTHS(TRUNC(SYSDATE,'MONTH'), -27) AND LAST_DAY(ADD_MONTHS(TRUNC(SYSDATE,'MONTH'), -27))Testing..
--Sample Data
CREATE TABLE customer_transaction (
cust_loc number,
cut_id number,
transaction_date date,
transaction_type varchar2(20)
INSERT INTO customer_transaction VALUES (100,12345,TO_DATE('01-JAN-2009','dd-MON-yyyy'),'CREDIT');
INSERT INTO customer_transaction VALUES (100,23456,TO_DATE('15-JAN-2000','dd-MON-yyyy'),'CREDIT');
INSERT INTO customer_transaction VALUES (100,12345,TO_DATE('01-JAN-2010','dd-MON-yyyy'),'DEBIT');
INSERT INTO customer_transaction VALUES (100,12345,TO_DATE('01-JAN-2000','dd-MON-yyyy'),'DEBIT');
--To have three records in the month of jan-2009
UPDATE customer_transaction
   SET transaction_date = TO_DATE('02-JAN-2009','dd-MON-yyyy')
WHERE cut_id = 12345
   AND transaction_date = TO_DATE('01-JAN-2010','dd-MON-yyyy');
UPDATE customer_transaction
   SET transaction_date = TO_DATE('03-JAN-2009','dd-MON-yyyy')
WHERE cut_id = 12345
   AND transaction_date = TO_DATE('01-JAN-2000','dd-MON-yyyy');
commit;
--End of sample data
SELECT *
FROM customer_transaction
WHERE transaction_date BETWEEN ADD_MONTHS(TRUNC(SYSDATE,'MONTH'), -27) AND LAST_DAY(ADD_MONTHS(TRUNC(SYSDATE,'MONTH'), -27));Results....
CUST_LOC     CUT_ID TRANSACTI TRANSACTION_TYPE
      100      12345 01-JAN-09 CREDIT
      100      12345 02-JAN-09 DEBIT
      100      12345 03-JAN-09 DEBITAs you can see, there are only 3 records for 12345
Regards,
Rakesh
Edited by: Rakesh on Apr 6, 2011 11:48 AM

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Ethan Hua
TechNet Community Support
It's recommended to download and install
Configuration Analyzer Tool (OffCAT), which is developed by Microsoft Support teams. Once the tool is installed, you can run it at any time to scan for hundreds of known issues in Office
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tt2

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