Every two charater of a column into a row

Question

Hello everyone,
I am trying to convert every two characters of a column into a row.
Something like...
with t as
SELECT
          '00112233445566778899' TN
             FROM dual
--union all
--select 'xxyyzzaabbccddeeffgg' from
--dual
SELECT SUBSTR 
         ( tn 
         , decode(n,0,0,(((n*2)+1)-2))
         , 2
         ) AS token  ,n
    FROM ( select * from t
       , ( SELECT LEVEL n
             FROM (SELECT length(tn)/2 max_elements FROM t)
          CONNECT BY LEVEL <= max_elements +30
   WHERE n <= LENGTH(tn) /2
TO          N
00          1
11          2
22          3
33          4
44          5
55          6
66          7
77          8
88          9
99         10The above query fails when I try to do it for multiple rows(It goes in an infinite loop).
Is there a way to convert ever two characters of a column into a row.
I am using Oracle 9i.
Thanks in Advance,
Jaggyam

Answer 1

jaggyam wrote:
Note : I am using 9i.It's usually a good idea to mention that at the beginning otherwise we have to assume you are using the latest/supported versions of oracle.
Does this work in 9i.... (I don't have an old version to try it on)
SQL> ed
Wrote file afiedt.buf
  1  with t as (select '00112233445566778899' as txt from dual union all
  2             select 'aabbccddeeff' from dual)
  3      ,m as (select max(length(txt)/2) mx from t)
  4  --
  5  select txt
  6  from (
  7    select substr(txt, ((rn-1)*2)+1, 2) as txt
  8    from t, (select rownum rn from m connect by rownum <= mx)
  9    )
10* where txt is not null
SQL> /
TX
00
aa
11
bb
22
cc
33
dd
44
ee
55
ff
66
77
88
99
16 rows selected.
SQL>