Execute a servlet in tomcat

hai friends,
I am trying to execute a simple servlet in tomcat but I couldn't..
please help me

Can you execute the default Servlets in Tomcat which are found in the "Examples" folder ? http://localhost:<PORT NO>/examples/
If yes then try deploying your servlet in the examples folder and find out a file called "servlet.jar " in your server and set its classpath.
I hope that will work.
Shashi

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Problem in executing servlets under tomcat 4.1

Dear Group,
I am using Tomcat 4.1 and have the following directory structure:
1.     C:\Tomcat 4.1\webapps\testapp
----It is my root directory and I have my html file called
sample.html
2.     C:\Tomcat 4.1\webapps\testapp\WEB-INF------web.xml is here
3.     C:\Tomcat 4.1\webapps\testapp\classes\TestServlet.class
-------here I have the servlet, no package---only one servlet
My[b] web.xml has entry for:
<?xml version="1.0" encoding="ISO-8859-1"?>
<!DOCTYPE web-app
    PUBLIC "-//Sun Microsystems, Inc.//DTD Web Application 2.3//EN"
    "http://java.sun.com/dtd/web-app_2_3.dtd">
<web-app>
    <servlet>
        <servlet-name>TestServlet</servlet-name>
        <servlet-class>TestServlet</servlet-class>
    </servlet>
    <servlet-mapping>
        <servlet-name>TestServlet</servlet-name>
        <url-pattern>/TestServlet</url-pattern>
    </servlet-mapping>
</web-app>My[b] sample.html contains:
<HTML>
<BODY>
<form method="post" action="http://localhost:8080/testapp/TestServlet">
<input type=submit value="showServlet">
<h2>
<font color="green">First try on Serlvet</font>
</h2>
</form>
</BODY>
</HTML>Here is what I have done:
1.     Started the Tomcat server
2.     In the IE browser, I typed http://localhost:8080/testapp/sample.html
-------- - the file shown correctly and I clicked the showServlet button.
3.     I got the follow error �HTTP Status 404 - /testapp/TestServlet" the
requested resource not availble
4.     when I clicked the showServelt button the control goes to another page
(as it should go to execute the servlet) .
The URL is �http://localhost:8080/testapp/TestServlet�
Please enlighten me where I went wrong?

Hello all,
Thank you for answering the question now the servlet gets executed.
I here posts the steps i carried out to execute the
servlet. If anyone have different idea pls post. Im
pasting here the steps also attaching one.
Steps to create your directory and work in Tomcat 4.1
1.     Create your directory in Tomcat�s webapps Directory.
-----If your tomcat is in d:\ the your directory may look
----- D:\tomcat\webapps\<your directory>
     ------E.g. �d:\tomcat\webapps\test�
2.     In the test directory you can your html files directly or you can create a
directory to hold html files.
     --------E.g. �d:\tomcat\webapps\test\first.html (OR)
-------E.g. �d:\tomcat\webapps\test\html-files\first.html�
3.     Create a folder called WEB-INF inside test
-------E.g. �d:\tomcat\webapps\test\WEB-INF
------ Under the WEB-INF folder put your web.xml file
4.     Create another folder named classes under the same test
----- E.g. �d:\tomcat\webapps\test\classes
----- Here you need to place your servlet classes
----- E.g. �d:\tomcat\webapps\test\classes\testServlet.class
5.     Start any browser that are java enabled
6.     Type �http://<machine name (or) IP add.>:8080/<your folder
name>/<html file>�
----     E.g. http://localhost:8080/test/ html-files/first.html
-----E.g.http://127.0.0.1:8080/test/html-files/first.html
7.     Click the component (button, label�) to enable servlet
8.     That�s all! Now you should get your servlet executed.
Files:
1.     web.xml
<!DOCTYPE web-app PUBLIC "-//Sun Microsystems,
Inc.//DTD Web Application 2.3//EN"
"http://java.sun.com/dtd/web-app_2_3.dtd">
<web-app>
<servlet>
    <servlet-name>testServlet</servlet-name>
    <servlet-class>testServlet</servlet-class>
</servlet>
<servlet-mapping>
    <servlet-name>testServlet</servlet-name>
    <url-pattern>/testServlet/*</url-pattern>
</servlet-mapping>
</web-app>
2. first.html
<html>
<body>
<form method="POST"
action="http://localhost:8080/test/testServlet">
<input type=submit value=click></input>
</form>
</body>
</html>
3. testServlet.java
import javax.servlet.*;
import javax.servlet.http.*;
import java.io.*;
public class testServlet extends HttpServlet
     public void doPost(HttpServletRequest req,
HttpServletResponse res)throws      ServletException,
IOException
          PrintWriter out = res.getWriter();
          out.println("<html>");
          out.println("<body>");
          out.println("<h1>Hello! </h1>");
          out.println("</body>"+"</html>");
}I have put my first.html inside the folder
�d:\tomcat\webapps\test\html-files\� and testServlet
is under �d:\tomcat\webapps\test\WEB-INF\classes\� folder.

How to execute servlets in tomcat?

Hi,
I have compiled servlet file and tried to execute that file from root i.e. (http://localhost/'filename'....)as class file is in web-inf/classes.But it is executing from "http://localhost/servlet/" where is that servlet directory?
why all servlets executes from "servlet/" directory?
Please reply....
Thanx in advance.

I has the same problem, and my solution was to include a line in the tomcat-auto file foreach servlet i had.
Under
JkMount /MyApp/servlet/* ajp13
I set a line
JkMount /MyApp/MyServlet ajp13
and in the web.xml of my webapp i included a servlet mapping for the servlet:
<servlet>
<servlet-name>MyServlet</servlet-name>
<servlet-class>MyPackage.MyServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>MyServlet</servlet-name>
<url-pattern>/MyServlet</url-pattern>
</servlet-mapping>
Then restarting tomcat and apache it worked.
One question i have is that tomcat-auto file it is supposed to be auto-generated by tomcat, but in my case it is not, each time i add an app in the webapps dir i have to add all the stuff in tomcat-auto file. Does anyone know how to autogenerate this file?

How to execute a servlet on jakarta-tomcat-4.0.3

Please let me know how to execute a servlet on jakarta-tomcat-4.0.3 .I am able to compile it .
Regards,
Saurabh Singhal

Hi
You must provide a mapping in your web.xml configuration file. This mapping will allow you to access servlet via url in form: "http://[domain]:[port]/[context]/servlet/[servlet full qualified name]"
This file should be located at $TOMCAT_HOME/conf.
Sample web.xml contains:
<web-app>
    <display-name>Sample Database App</display-name>
    <description>
     This is a simple application.
    </description>
    <servlet>
        <servlet-name>MyServlet</servlet-name>
        <servlet-class>MyServletImpl</servlet-class>
    </servlet>
    <servlet-mapping>
        <servlet-name>MyServlet</servlet-name>
     <url-pattern>/myservletaddr</url-pattern>
    </servlet-mapping>
</web-app>
You can find more info at:
http://scitec.uwichill.edu.bb/cmp/online/CS36L/tutorials/TomcatIntroduction/TomcatIntroSampleApp.html
or
http://www.moreservlets.com/Using-Tomcat-4.html

How to execute CGI Programs in Tomcat Server

Hi,
I am working on executing Perl Scrtipts(or CGI programs) in Tomcat Server.
I have downloaded ActivePerl 5.8.0 6.0.3 build.I have modified some .jar files in tomcat\server\lib.
I have changed conf\web.xml to access the CGIServlet.class that is in servlets-cgi.jar.
My example.cgi is
#!c:\Perl\bin\perl.exe
print
"Content-type: text/plain\n\n";
foreach $var (
sort keys %ENV) {
print
"$var=\"$ENV{$var}\"\n";
@values = split(
/&/,$ENV{'QUERY_STRING'});
foreach $i (@values) {
($varname, $mydata) = split(
/=/,$i);
print "$varname = $mydata\n";
and my test.html is
<HTML>
     <HEAD>
          <TITLE>Environment Variables using GET</TITLE>
     </HEAD>
     <BODY>
          <FORM ACTION="cgi-bin/example.cgi" METHOD="POST">
               Press submit for a list of environment variables. <BR>
               First Name: <input type="text" name="fname" size=30><p>
               Last Name: <input type="text" name="lname" size=30><p>
               <input type="submit">
          </FORM>
     </BODY>
</HTML>
here I have changed url mapping in web.xml to cgi-bin.
The test.html produces two text fields first and last name on submit:
it accesses:http://localhost:8080/smalltownpapers/cgi-bin/example.cgi?fname=Tim&lname=Eden
this should print some environmental variables but it is producing an empty page.
Tomcat is not showing any errors or Tomcat is not at all listening.
Can any one help me to solve this and how to execute Perl scripts in Tomcat server
Thanks,
Regards
Murthy

Sorry, I've never done this. I went to the Tomcat site and pulled down the CGI docs, which you might have seen:
http://jakarta.apache.org/tomcat/tomcat-5.0-doc/cgi-howto.html
No other help available from me. Sorry.

How to run a servlet in Tomcat 5.0 server

HI Everybody,
I want to know how to run the servlet file on my tomcat 5.0 server. that is where to place a class file and deployment details.
Thanks In ADVANCE

Sourav_cs wrote:
I am a biginner to start servlet i get confusion to configure servlet in tomcat 5 where it should be saved in tomcat directory and how to execute that as first timeHi,
goto
tomcat 5.0\webappsnow create a folder here. this is your webapplication project name. Let's suppose it as "TestApp"
inside this create directories as follows :
TestApp
        |
        |-----JSP/htmls( if you have any )
        |
        |-----WEB-INF(File Folder)
                   |
                   |-----web.xml
                   |-----lib ( Directory. place all the .jar files which are required for this project(if any) )
                   |-----classes ( .class files. )[all of your java code should be placed here.](servlets / beans/ pojo )this is the general Directory structure of a web application. now you've to place the compiled .class file of your servlet in the "TestApp\WEB-INF\classes" directory. make sure that you've configured the servlet in Deploment Desctiptor, i.e, web.xml.
now start the server and type the url like : "http://localhost:8080/TestApp/TestServlet"
the port no. 8080 is the default port no. of tomcat. you have to give your port no. if u've modified it. and TestServlet is the <url-pattern> of your servlet.
go through some tutorials .. then you can easily know that
Diablo

How to run servlets in tomcat

Hi ,
How to run servlets in tomcat server. I created two files html and servlet file.
Html file
callservlet.html
<html>
<body>
<form method=post action="servletcalled.class">
<input type=submit value="submit">
</form>
<body>
</html>
servlet file
servletcalled.java contains
public void doPost(HttpServletRequest req,HttpServletResponse res ){
java.io.PrintWriter out = req.getWriter();
out.println("Hi, executed");
i put the callservlet.html in webapps/examples/ and servletcalled.class was in webapps/examples/Web-inf/classes/
After starting the tomcat and running the program html file is getting exceuted but when i click on the submit button this error is prompted
type Status report
message servletcalled.class
description The requested resource (servletcalled.class) is not available.
Thanks in advance

Thanks,
I created a new directory in webapps
s "webapps/test".
Test directory contains
1. callservlet.html file
2. another directory Web-inf (i.e,
webapps/test/Web-inf)
Web-inf directory contains
1. web.xml file
2. another directory classes (i.e,
webapps/test/Web-inf/calsses)
classes directory contains
1. servletcalled.class file
web.xml file contains
<?xml version="1.0" encoding="ISO-8859-1"?>
<!DOCTYPE web-app
PUBLIC "-//Sun Microsystems, Inc.//DTD Web
Web Application 2.3//EN"
"http://java.sun.com/dtd/web-app_2_3.dtd">
<web-app>
<servlet>
<servlet-name>Example</servlet-name>
<servlet-class>Example</servlet-class>
</servlet>
</web-app>
-->should be: <servlet-class>servletcalled</servlet-called>
then in the <web-app> scope define this:
<servlet-mapping>
<servlet-name>Example</servlet-name>
<url-pattern>/servlets/Example</url-pattern>
</servlet-mapping>
>
thanks in advance i am working hard on that but
notable to get the solutionbtw by reading the documentation of tomcat and tutorials of jave on the java site (here), you would have known this!

Execute a servlet

Hello,
I wnt to execute a servlet I use a Tomcat to do it
webapps/mySevletTest/Web-INF/classes/HelloServlet.java
in web.xml
<servlet>
          <servlet-name>HelloServlet</servlet-name>
          <servlet-class>HelloServlet</servlet-class>
</servlet>
<servlet-mapping>
     <servlet-name>HelloServlet</servlet-name>
     <url-pattern>/HelloServlet</url-pattern>
</servlet-mapping>
to execute
http://localhost:8080/mySevletTest/HelloServlet
Error : The requested resource (/ServletTest/HelloServlet) is not available.
why ????
thanks

I have put the class in a package org
package org;
import java.io.*;
import javax.servlet.*;
import javax.servlet.http.*;
public class HelloServlet extends HttpServlet
public void service(HttpServletRequest request, HttpServletResponse response)throws IOException
     response.setContentType("text/html");
     PrintWriter writer = response.getWriter();
     writer.println("<html>\n");
     writer.println("<head>\n");
     writer.println("<title>Test</title>\n");
     writer.println("</head>\n");
     writer.println("<body>\n");
     writer.println("<h1>Hallo Issam</h1>\n");
     writer.println("<br>\n");
     writer.println("<h3>Test for Servlet ist successfull ...</h3>\n");
     writer.println("</body>\n");
     writer.println("</html>\n");
}/WEB-INF/classes/org/HelloServlet.class
the phad of aaplication
webapps/myServletTest/WEB-INF/classes/org/HelloServlet.java
in web.xml
<servlet>
<servlet-name>HelloServlet</servlet-name>
<servlet-class>HelloServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>HelloServlet</servlet-name>
<url-pattern>/HelloServlet</url-pattern>
</servlet-mapping>
I become the same error !!!!!!!!!!
The requested resource (/myServletTest/HelloServlet) is not available.
who ist the error

Running servlets in tomcat server

Hi,
I am not able to execute servlets in tomcat,
When i executed the program html file was running perfectly and when i click on the submit button it is displaying the following error
type Status report
message ServletCalled.class
description The requested resource (ServletCalled.class) is not available.
I followed the below procedure
I created a new directory in webapps "webapps/test".
Test directory contains
1. callservlet.html file
2. another directory Web-inf (i.e, webapps/test/Web-inf)
Web-inf directory contains
1. web.xml file
2. another directory classes (i.e, webapps/test/Web-inf/calsses)
classes directory contains
1. ServletCalled.class file
Html file code
callservlet.html
<html>
<body>
<form method=post action="/ServletCalled/ServletCalled.class">
<input type=submit value="submit">
</form>
<body>
</html>
servlet file
ServletCalled.java contains
public void doPost(HttpServletRequest req,HttpServletResponse res ){
java.io.PrintWriter out = req.getWriter();
out.println("Hi, executed");
web.xml file
<?xml version="1.0" encoding="ISO-8859-1"?>
<!DOCTYPE web-app
PUBLIC "-//Sun Microsystems, Inc.//DTD Web
Web Application 2.3//EN"
"http://java.sun.com/dtd/web-app_2_3.dtd">
<web-app>
<servlet>
<servlet-name>ServletCalled</servlet-name>
<servlet-class>ServletCalled</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>ServletCalled</servlet-name>
<url-pattern>/ServletCalled</url-pattern>
</servlet-mapping>
</web-app>
i used all the options above i changed the <url-pattern> and form tag to (<form action="/ServletCalled" method=get>)but same error persists
Please help me out in this thanks in advance

thanks !! i got the solution

How to run a servlet in tomcat 5.0.

Hi all,
how to run a servlet in tomcat 5.0
please tell me the entire procedure....(directory structure)
step by step....

hi :-)
http://java.sun.com/j2ee/tutorial/1_3-fcs/doc/Servlets.html
or
http://www.google.com.ph/search?hl=en&q=java+servlet+tutorial&btnG=Google+Search&meta=
regards,

Servlet on tomcat 4.1.18

I am facing a problem of running servlets on Tomcat 4.1.18. The problem seems to be in the configuration. In the webapps folder, I created a folder greeting. In that, the WEB-Inf\classes folder has GreetingServlet.class.
webapp\greeting has index.html that has to FORM ACTION set to /greeting/servlet/GreetingServlet.
On clicking the submit button the message I get is that the resource /greeting/servlet/GreetingServlet is not found.
Can anybody help in configuring the server so that the above mentioned servlet gets recognized?
Thanks.
Amitabh.
[email protected]

My application is located at %TOMCAT_HOME%\webapps.
%TOMCAT_HOME%\webapps\greeting\WEB-INF\web.xml has the following:
<web-app>
<servlet>
<servlet-name>greeting</servlet-name>
<servlet-class>GreetingServlet</servlet-class>
</servlet>
</web-app>
%TOMCAT_HOME%\webapps\greeting\index.html has the following:
<FORM ACTION="/greeting/servlet/GreetingServlet" METHOD="POST">
<P> Your name <INPUT TYPE="text" SIZE="40" NAME="name"></P>
</FORM>
Yet the problem persists.
Have I missed some point?
Help/assistance will be appreciated.
Thanks.
Amitabh.
[email protected]

Servlets in Tomcat

I am trying to run servlets using Tomcat. I have them working and displaying but as soon as I make a change to a servelt and re-compile and refresh the browser the change do not take effect. I have to shutdown and restart tocat. Surely this can't be right. can anyone help with correcting this problem?

Lesta,
For convenience there's a Tomcat admin console. The admin console runs through a web browser and allows you to restart an application, restart a context ect. I think you can also install or reinstall entire ears through it now.
There's some setup to do before you can use the admin console. I seem to remember there being an XML user/password file somewhere...
In a production environment you don't want to shutdown and restart the daemon like you are doing. It will just annoy the heck out of your users.
Hope this helps.
-Bryan

Need to enable autoreload feature for servlet in Tomcat

Hello
I wants to enable autoreload feature for servlet in tomcat so that i need not to stop tomcat 4.0 web server again and again
Thanks

http://jakarta.apache.org/tomcat/tomcat-4.1-doc/config/context.html
It is amazing what reading the manual might do for ya.

How to run Servlet in TOMCAT

I am new to Java Servlets. I am trying to run a servlet on TOMCAT but I don't know where to place my Servlet class file. TOMCAT works ok with sample jar file. Please guide.
-- HTML code
<HTML>
<HEAD>
<TITLE> Request Object </TITLE>
</HEAD>
<BODY>
<FORM METHOD="POST" ACTION="/servlet/WelcomeServlet">
Enter your Name: <INPUT TYPE=TEXT NAME="myName">
<INPUT TYPE="SUBMIT" VALUE="Send Name">
</FORM>
</BODY>
</HTML>
-- Servlet Code
import java.io.*;
import javax.servlet.*;
import javax.servlet.http.*;
import java.sql.*;
public class WelcomeServlet extends HttpServlet {
public void doPost(HttpServletRequest request,
HttpServletResponse response)
throws ServletException, IOException {
String Name = request.getParameter("myName");
PrintWriter out = response.getWriter();
String mName = "test";
try {
mName = gName("AAA","VVV");
catch (SQLException ex)
out.println("SQLException");
out.println("Welcome 1.1 " + Name + " !" + " mName " + mName);
public String gName(String inputUserid, String inputPwd)
throws SQLException{
String vname = "Test";
return vname;
thanks
Vineet

I have Tomcat version 4.0 installed on my machine. If you look at the directory where you have Tomcat installed, you should find the directory structure:
tomcat-folder/webapps/root/web-inf/classes
Try placing your class files in the classes folder.

How to Run servlet in Tomcat 5.5.9

hi
How to run servlet in tomcat 5.5.9?how to set context path in server.xml of conf folder in tomcat since there is no context tag in server.xml.
Jiten

Hi ! I have a similar problem, well, it's along the same line ...
I'm using NetBeans 4.1, and i've coded a servlet. Using NetBeans to launch my servlet (with the bundled Tomcat 5.5.7) works fine, however i need to deploy my application unto a Tomcat 5.5.9 server.
Thus, i copied the WAR file generated by NetBeans into the Tomcat 5.5.9 webapps directory, and Tomcat expands it.
Problem is when i run my JSP pages with the form tags, they do not work on the Tomcat 5.5.9 environment. Anyone knows why?
(These work on the NetBeans Tomcat bundle 5.5.7)
My form action :
<form name="index" method="get" action="PageServlet">
My web.xml :
<servlet>
<servlet-name>PageServlet</servlet-name>
<servlet-class>application.PageServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>PageServlet</servlet-name>
<url-pattern>/PageServlet</url-pattern>
</servlet-mapping>
I'm really stumbed on why it doesn't work in Tomcat 5.5.9, any help is greatly appreciated, thanks in advance ^_^

Execute a servlet in tomcat

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