Extract function

Question

Hi All,
I have a piece of code
DECLARE
V_DOB DATE := '29-FEB-2000';
v_don1 DATE;
BEGIN
SELECT to_date('2003'||lpad(extract(Month FROM V_DOB),2,0)||extract(Day FROM V_DOB), 'YYYYMMDD') into v_don1
FROM DUAL;
dbms_output.put_line(v_don1);
END;The above code is giving error, it is working fine with V_dob as '28-FEB-2000'.
Year 2000 was a leap year so date 29 should be there.
Kindly suggest me what to do?
oracle version : 11.2.0.2.0 Thanks
Edited by: AbSHeik on Nov 16, 2012 10:41 PM

Answer 1

And few more things:
DECLARE
  --"Whenever you assign to a date value, dont assign as string
  --"use TO_DATE, else your code will have a dependency on NLS settings
  /*V_DOB DATE := '29-FEB-2000';*/
  V_DOB DATE := to_date('29-FEB-2000','DD-MON-YYYY');
  v_don1 DATE;
BEGIN
  /*SELECT to_date('2003'||lpad(extract(Month FROM V_DOB),2,0)||
        extract(Day FROM V_DOB), 'YYYYMMDD') into v_don1
  FROM DUAL;*/
  --"You dont need to use SELECT as in above code"
  --"Directly you can assign as below"
  v_don1 := to_date('2004'||
                    lpad(extract(Month FROM V_DOB),2,0)||
                    extract(Day FROM V_DOB), 'YYYYMMDD'
  --"And, whenever you are printing a date, use TO_CHAR
  /*dbms_output.put_line(v_don1);*/
  dbms_output.put_line(to_char(v_don1,'DD-Mon-YYYY'));
END;
{code}
And if your objective is to find out the last day of the same month of a different year, you can use LAST_DAY function
{code}
DECLARE
  V_DOB DATE := to_date('29-FEB-2000','DD-MON-YYYY');
  v_don1 DATE;
BEGIN
  v_don1 := last_day(to_date('2003'||
                    lpad(extract(Month FROM V_DOB),2,0)||
                    '01', 'YYYYMMDD'
  dbms_output.put_line(to_char(v_don1,'DD-Mon-YYYY'));
END;
28-Feb-2003
{code}
{code}
Edited by: jeneesh on Nov 17, 2012 12:46 PM