Extract the hierarchy in Parent child format from HP

Hello,
I have a hierarchy within Accounts dimension which I need to move to the other application in the different environment. I donot want to move the whole dimension. I just need to move a hierarchy. Is there a way I can extract a hierarchy in Parent child format with properties and move the same in to the next one.
Thanks in advance for your help.
Cheers,
XXX

Hi,
Below code assumes that you have 2 alias tables and assymetric hierarchy (having 4 to 6 levels) in accounts and all level 0 accounts are 6 digits. If you wish to remove the second alias table from the code simply remove references to it (i.e. aliastbl_id=50030). You can customize the extract top level member by modifying this section: (select object_id from hsp_object where object_name='Total Expenditure')
This outputs the structure in a fixed columnar format having all levels in different columns.
Code:
select o1.object_name as LVL1, o1.object_name as LVL1_DESC_EN, al1.object_name as LVL1_DESC_AR,
o2.object_name as LVL2, o2.object_name as LVL2_DESC_EN, al2.object_name as LVL2_DESC_AR,
o3.object_name as LVL3, al3.object_name as LVL3_DESC_EN, alar3.object_name as LVL3_DESC_AR,
o4.object_name as LVL4, al4.object_name as LVL4_DESC_EN, alar4.object_name as LVL4_DESC_AR,
o5.object_name as LVL5, al5.object_name as LVL5_DESC_EN, alar5.object_name as LVL5_DESC_AR,
o6.object_name as LVL6, al6.object_name as LVL6_DESC_EN, alar6.object_name as LVL6_DESC_AR
from hsp_object o1
left outer join (select * from hsp_alias where aliastbl_id=50030) a1 on o1.object_id=a1.MEMBER_ID left outer join hsp_object al1 on a1.alias_id=al1.object_id
inner join hsp_object o2 on o1.object_id=o2.Parent_ID
left outer join (select * from hsp_alias where aliastbl_id=50030) a2 on o2.object_id=a2.MEMBER_ID left outer join hsp_object al2 on a2.alias_id=al2.object_id
inner join hsp_object o3 on o2.object_id=o3.Parent_ID
left outer join (select * from hsp_alias where aliastbl_id=14) a3 on o3.object_id=a3.MEMBER_ID left outer join hsp_object al3 on a3.alias_id=al3.object_id
left outer join (select * from hsp_alias where aliastbl_id=50030) ar3 on o3.object_id=ar3.MEMBER_ID left outer join hsp_object alar3 on ar3.alias_id=alar3.object_id
inner join hsp_object o4 on o3.object_id=o4.Parent_ID
left outer join (select * from hsp_alias where aliastbl_id=14) a4 on o4.object_id=a4.MEMBER_ID left outer join hsp_object al4 on a4.alias_id=al4.object_id
left outer join (select * from hsp_alias where aliastbl_id=50030) ar4 on o4.object_id=ar4.MEMBER_ID left outer join hsp_object alar4 on ar4.alias_id=alar4.object_id
inner join hsp_object o5 on o4.object_id=o5.Parent_ID
left outer join (select * from hsp_alias where aliastbl_id=14) a5 on o5.object_id=a5.MEMBER_ID left outer join hsp_object al5 on a5.alias_id=al5.object_id
left outer join (select * from hsp_alias where aliastbl_id=50030) ar5 on o5.object_id=ar5.MEMBER_ID left outer join hsp_object alar5 on ar5.alias_id=alar5.object_id
inner join hsp_object o6 on o5.object_id=o6.Parent_ID
left outer join (select * from hsp_alias where aliastbl_id=14) a6 on o6.object_id=a6.MEMBER_ID left outer join hsp_object al6 on a6.alias_id=al6.object_id
left outer join (select * from hsp_alias where aliastbl_id=50030) ar6 on o6.object_id=ar6.MEMBER_ID left outer join hsp_object alar6 on ar6.alias_id=alar6.object_id
where o1.object_id =(select object_id from hsp_object where object_name='Total Expenditure') and
LENGTH(o6.object_name)=6
union all
select o1.object_name as LVL1, o1.object_name as LVL1_DESC_EN, al1.object_name as LVL1_DESC_AR,
o2.object_name as LVL2, o2.object_name as LVL2_DESC_EN, al2.object_name as LVL2_DESC_AR,
o3.object_name as LVL3, al3.object_name as LVL3_DESC_EN, alar3.object_name as LVL3_DESC_AR,
o4.object_name as LVL4, al4.object_name as LVL4_DESC_EN, alar4.object_name as LVL4_DESC_AR,
o5.object_name as LVL5, al5.object_name as LVL5_DESC_EN, alar5.object_name as LVL5_DESC_AR,
o5.object_name as LVL6, al5.object_name as LVL6_DESC_EN, alar5.object_name as LVL6_DESC_AR
from hsp_object o1
left outer join (select * from hsp_alias where aliastbl_id=50030) a1 on o1.object_id=a1.MEMBER_ID left outer join hsp_object al1 on a1.alias_id=al1.object_id
inner join hsp_object o2 on o1.object_id=o2.Parent_ID
left outer join (select * from hsp_alias where aliastbl_id=50030) a2 on o2.object_id=a2.MEMBER_ID left outer join hsp_object al2 on a2.alias_id=al2.object_id
inner join hsp_object o3 on o2.object_id=o3.Parent_ID
left outer join (select * from hsp_alias where aliastbl_id=14) a3 on o3.object_id=a3.MEMBER_ID left outer join hsp_object al3 on a3.alias_id=al3.object_id
left outer join (select * from hsp_alias where aliastbl_id=50030) ar3 on o3.object_id=ar3.MEMBER_ID left outer join hsp_object alar3 on ar3.alias_id=alar3.object_id
inner join hsp_object o4 on o3.object_id=o4.Parent_ID
left outer join (select * from hsp_alias where aliastbl_id=14) a4 on o4.object_id=a4.MEMBER_ID left outer join hsp_object al4 on a4.alias_id=al4.object_id
left outer join (select * from hsp_alias where aliastbl_id=50030) ar4 on o4.object_id=ar4.MEMBER_ID left outer join hsp_object alar4 on ar4.alias_id=alar4.object_id
inner join hsp_object o5 on o4.object_id=o5.Parent_ID
left outer join (select * from hsp_alias where aliastbl_id=14) a5 on o5.object_id=a5.MEMBER_ID left outer join hsp_object al5 on a5.alias_id=al5.object_id
left outer join (select * from hsp_alias where aliastbl_id=50030) ar5 on o5.object_id=ar5.MEMBER_ID left outer join hsp_object alar5 on ar5.alias_id=alar5.object_id
where o1.object_id =(select object_id from hsp_object where object_name='Total Expenditure') and
LENGTH(o5.object_name)=6
union all
select o1.object_name as LVL1, o1.object_name as LVL1_DESC_EN, al1.object_name as LVL1_DESC_AR,
o2.object_name as LVL2, o2.object_name as LVL2_DESC_EN, al2.object_name as LVL2_DESC_AR,
o3.object_name as LVL3, al3.object_name as LVL3_DESC_EN, alar3.object_name as LVL3_DESC_AR,
o4.object_name as LVL4, al4.object_name as LVL4_DESC_EN, alar4.object_name as LVL4_DESC_AR,
o4.object_name as LVL5, al4.object_name as LVL5_DESC_EN, alar4.object_name as LVL5_DESC_AR,
o4.object_name as LVL6, al4.object_name as LVL6_DESC_EN, alar4.object_name as LVL6_DESC_AR
from hsp_object o1
left outer join (select * from hsp_alias where aliastbl_id=50030) a1 on o1.object_id=a1.MEMBER_ID left outer join hsp_object al1 on a1.alias_id=al1.object_id
inner join hsp_object o2 on o1.object_id=o2.Parent_ID
left outer join (select * from hsp_alias where aliastbl_id=50030) a2 on o2.object_id=a2.MEMBER_ID left outer join hsp_object al2 on a2.alias_id=al2.object_id
inner join hsp_object o3 on o2.object_id=o3.Parent_ID
left outer join (select * from hsp_alias where aliastbl_id=14) a3 on o3.object_id=a3.MEMBER_ID left outer join hsp_object al3 on a3.alias_id=al3.object_id
left outer join (select * from hsp_alias where aliastbl_id=50030) ar3 on o3.object_id=ar3.MEMBER_ID left outer join hsp_object alar3 on ar3.alias_id=alar3.object_id
inner join hsp_object o4 on o3.object_id=o4.Parent_ID
left outer join (select * from hsp_alias where aliastbl_id=14) a4 on o4.object_id=a4.MEMBER_ID left outer join hsp_object al4 on a4.alias_id=al4.object_id
left outer join (select * from hsp_alias where aliastbl_id=50030) ar4 on o4.object_id=ar4.MEMBER_ID left outer join hsp_object alar4 on ar4.alias_id=alar4.object_id
where o1.object_id =(select object_id from hsp_object where object_name='Total Expenditure') and
LENGTH(o4.object_name)=6
Cheers,
Alp

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SQL> desc numtable;
numtable TABLE OF NUMBER(38)
SQL> select * from test;
DETAIL_ID   VALUE_ID     PARENT
       282        125        281
       283        126        281
       284        119
       285        127        284
       286        128        284
       301        120
       341       1169        321
       303        130        301
       322       1168        321
       334        123
       335        129        301
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       321        122
       361       1172        334
       362       1171        334
       363        119
       364        120
       365       1170        364
       281        118
       219        125        284
20 rows selected.
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2   vt1 numtable :=
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26   end loop;
27 end;
28 /
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PL/SQL procedure successfully completed.

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,extract(x.xml_data,'/MolDocument/MolTimeSeries/ContractIdentification/@v')
,'SUBMITTED'
,'A96'
,NULL -- acquiring area
,sysdate
FROM xml_DEMO x WHERE
existsnode(x.xml_data,'/MolDocument/DocumentIdentification[@v="MOL_20100331_1500_1600"]') = 1)
For example, there are 3 ContractIdentification tags. Example of 1:
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<?xml version="1.0" encoding="UTF-8"?>
<MolDocument DtdVersion="3" DtdRelease="0">
<DocumentIdentification v="MOL_20100331_1500_1600"/>
<DocumentVersion v="1"/>
<DocumentType v="A43"/>
<SenderIdentification codingScheme="A01" v="17X100Z100Z0001H"/>
<SenderRole v="A35"/>
<ReceiverIdentification codingScheme="A01" v="10XFR-RTE------Q"/>
<ReceiverRole v="A04"/>
<CreationDateTime v="2010-03-31T14:10:00Z"/>
<ValidTimeInterval v="2010-03-31T15:00Z/2010-03-31T16:00Z"/>
<Domain codingScheme="A01" v="10YDOM-1001A001A"/>
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<ContractIdentification v="RTE_20100331_1500_16"/>
<ResourceProvider codingScheme="A01" v="10XFR-RTE------Q"/>
<AcquiringArea codingScheme="A01" v="17Y100Z100Z00013"/>
<ConnectingArea codingScheme="A01" v="10YFR-RTE------C"/>
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<Resolution v="PT60M"/>
<Interval>
<Pos v="1"/>
<Qty v="50"/>
<EnergyPrice v="50.45"/>
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</Period>
</MolTimeSeries>
<MolTimeSeries>
<ContractIdentification v="RTE_20100331_1500_20"/>
<ResourceProvider codingScheme="A01" v="10XFR-RTE------Q"/>
<AcquiringArea codingScheme="A01" v="17Y100Z100Z00013"/>
<ConnectingArea codingScheme="A01" v="10YFR-RTE------C"/>
<AuctionIdentification v="AUCTION_20100331_1500_1600"/>
<BusinessType v="A10"/>
<BidTimeInterval v="2010-03-31T15:00Z/2010-03-31T16:00Z"/>
<MeasureUnitQuantity v="MAW"/>
<Currency v="EUR"/>
<MeasureUnitPrice v="MWH"/>
<Direction v="A02"/>
<MinimumActivationQuantity v="50"/>
<Status v="A06"/>
<Period>
<TimeInterval v="2010-03-31T15:00Z/2010-03-31T16:00Z"/>
<Resolution v="PT60M"/>
<Interval>
<Pos v="1"/>
<Qty v="50"/>
<EnergyPrice v="50.48"/>
</Interval>
</Period>
</MolTimeSeries>
<MolTimeSeries>
<ContractIdentification v="NG_20100331_1500_6"/>
<ResourceProvider codingScheme="A01" v="10X1001A1001A515"/>
<AcquiringArea codingScheme="A01" v="17Y100Z100Z00013"/>
<ConnectingArea codingScheme="A01" v="10YGB----------A"/>
<AuctionIdentification v="AUCTION_20100331_1500_1600"/>
<BusinessType v="A10"/>
<BidTimeInterval v="2010-03-31T15:00Z/2010-03-31T16:00Z"/>
<MeasureUnitQuantity v="MAW"/>
<Currency v="EUR"/>
<MeasureUnitPrice v="MWH"/>
<Direction v="A01"/>
<MinimumActivationQuantity v="50"/>
<Status v="A06"/>
<Period>
<TimeInterval v="2010-03-31T15:00Z/2010-03-31T16:00Z"/>
<Resolution v="PT60M"/>
<Interval>
<Pos v="1"/>
<Qty v="50"/>
<EnergyPrice v="17.0"/>
</Interval>
</Period>
</MolTimeSeries>
</MolDocument>

Hi,
The result I got was:
16RTE_20100331_1500_20NG_20100331_1500_6In the query you tried, you access a single record so you can't expect to get three rows "magically". The EXTRACT function just works as expected, it extracts the requested nodes, but the result is still an XML fragment (a scalar value).
In order to achieve your goal, you have to break the MolTimeSeries sequence into relational rows.
Two similar solutions are possible, XMLTable (10gR2 and up) or Table/XMLSequence.
In your other post you mentioned db version 10.1, so I guess we'll go with XMLSequence :
SELECT 'RTE'
 ,to_date(substr(extractvalue(x.xml_data,'/MolDocument/ValidTimeInterval/@v'),1,16),'yyyy-mm-dd"T"hh24:mi')
 ,decode(extractvalue(x2.column_value,'/MolTimeSeries/Direction/@v'),'A01','Up','Down')
 ,to_number(regexp_substr(extractvalue(x2.column_value,'/MolTimeSeries/ContractIdentification/@v'),'\d+$'))
 ,to_number(extractvalue(x2.column_value,'/MolTimeSeries/Period/Interval/EnergyPrice/@v'))
 ,sysdate
 ,null
 ,null
 ,extractvalue(x2.column_value,'/MolTimeSeries/ContractIdentification/@v')
 ,'SUBMITTED'
 ,'A96'
 ,null
 ,sysdate
FROM xml_demo x,
 table(
 xmlsequence(
 extract(x.xml_data, '/MolDocument/MolTimeSeries')
 ) x2
WHERE existsnode(x.xml_data,'/MolDocument/DocumentIdentification[@v="MOL_20100331_1500_1600"]') = 1;Please also note the use of REGEXP_SUBSTR instead of the regular SUBSTR because it didn't work for "NG_20100331_1500_6".
Hope that helps.
Edited by: odie_63 on 24 juin 2010 21:18 - added regexp comment

Dynamic hierarchy in parent child hierarchy table??

Do you have any experience to handle the requirement of dynamic hierarchy in universe/webi?
We have some data in parent child hierarchy as below u201CCustomeru201D table.
Customer
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Z                  A
Z                  B
A                  AA
B                  BB
AA               AAA
For example, Company Z is the parent company of Company A.
Another table, Amount is the amount value of different Customers.
Amount
ID               Amt
AA               10
AAA            1
BB                2
Is there any functionality in Universe designer to build related Classes and objects, So that the web intelligence documents represent the following report with the drilling results?
When we want to see the ID and Amt, the expected result should be:
Z                13
when we drill down Z
the result should be:
A                11
B                2
when we drill down A:
the result should be:
AA              11
notes **
the level of hierarchy is dynamic
Any suggestion is appreciated. Thanks.

Hi,
The only way to do it is to create recursive derived table that flatten you parent child hierarchy with a given maximum depth.
Here is a sample I built a long time ago to flatten a parent-child hierarchy on Employees table in Foodmart database (SQL Server).
Didier
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     A.supervisor_id_1,
     A.employee_id_1,
     A.full_name_1,
     A.supervisor_id_2,
     A.employee_id_2,
     A.full_name_2,
     A.supervisor_id_3,
     A.employee_id_3,
     A.full_name_3,
     A.supervisor_id_4,
     A.employee_id_4,
     A.full_name_4,
     A.supervisor_id_5,
     A.employee_id_5,
     A.full_name_5,
     A.supervisor_id_6,
     A.employee_id_6,
     A.full_name_6,
     Z.supervisor_id AS supervisor_id_7,
     Z.employee_id AS employee_id_7,
     Z.full_name AS full_name_7
FROM employee Z,
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          A.employee_id_1,
          A.full_name_1,
          A.supervisor_id_2,
          A.employee_id_2,
          A.full_name_2,
          A.supervisor_id_3,
          A.employee_id_3,
          A.full_name_3,
          A.supervisor_id_4,
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          A.supervisor_id_5,
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          Z.employee_id AS employee_id_6,
          Z.full_name AS full_name_6
     FROM employee Z,
          SELECT DISTINCT
               A.supervisor_id_1,
               A.employee_id_1,
               A.full_name_1,
               A.supervisor_id_2,
               A.employee_id_2,
               A.full_name_2,
               A.supervisor_id_3,
               A.employee_id_3,
               A.full_name_3,
               A.supervisor_id_4,
               A.employee_id_4,
               A.full_name_4,
               Z.supervisor_id AS supervisor_id_5,
               Z.employee_id AS employee_id_5,
               Z.full_name AS full_name_5
          FROM employee Z,
               SELECT DISTINCT
                    A.supervisor_id_1,
                    A.employee_id_1,
                    A.full_name_1,
                    A.supervisor_id_2,
                    A.employee_id_2,
                    A.full_name_2,
                    A.supervisor_id_3,
                    A.employee_id_3,
                    A.full_name_3,
                    Z.supervisor_id AS supervisor_id_4,
                    Z.employee_id AS employee_id_4,
                    Z.full_name AS full_name_4
               FROM employee Z,
                    SELECT DISTINCT
                         A.supervisor_id_1,
                         A.employee_id_1,
                         A.full_name_1,
                         A.supervisor_id_2,
                         A.employee_id_2,
                         A.full_name_2,
                         Z.supervisor_id AS supervisor_id_3,
                         Z.employee_id AS employee_id_3,
                         Z.full_name AS full_name_3
                    FROM employee Z,
                         SELECT DISTINCT
                              A.supervisor_id_1,
                              A.employee_id_1,
                              A.full_name_1,
                              Z.supervisor_id AS supervisor_id_2,
                              Z.employee_id AS employee_id_2,
                              Z.full_name AS full_name_2
                         FROM employee Z,
                              SELECT DISTINCT
                                   supervisor_id AS supervisor_id_1,
                                   employee_id AS employee_id_1,
                                   full_name AS full_name_1
                               FROM employee
                               WHERE supervisor_id = 0 OR supervisor_id IS NULL
                         ) A
                         WHERE A.employee_id_1 = Z.supervisor_id
                    ) A
                    WHERE A.employee_id_2 = Z.supervisor_id
               ) A
               WHERE A.employee_id_3 = Z.supervisor_id
          ) A
          WHERE A.employee_id_4 = Z.supervisor_id
     ) A
     WHERE A.employee_id_5 = Z.supervisor_id
) A
WHERE A.employee_id_6 = Z.supervisor_id
UNION
SELECT DISTINCT
     A.employee_id_6 AS employee_id,
     A.supervisor_id_1,
     A.employee_id_1,
     A.full_name_1,
     A.supervisor_id_2,
     A.employee_id_2,
     A.full_name_2,
     A.supervisor_id_3,
     A.employee_id_3,
     A.full_name_3,
     A.supervisor_id_4,
     A.employee_id_4,
     A.full_name_4,
     A.supervisor_id_5,
     A.employee_id_5,
     A.full_name_5,
     A.supervisor_id_6,
     A.employee_id_6,
     A.full_name_6,
     NULL AS supervisor_id_7,
     NULL AS employee_id_7,
     NULL AS full_name_7
FROM employee Z,
     SELECT DISTINCT
          A.supervisor_id_1,
          A.employee_id_1,
          A.full_name_1,
          A.supervisor_id_2,
          A.employee_id_2,
          A.full_name_2,
          A.supervisor_id_3,
          A.employee_id_3,
          A.full_name_3,
          A.supervisor_id_4,
          A.employee_id_4,
          A.full_name_4,
          A.supervisor_id_5,
          A.employee_id_5,
          A.full_name_5,
          Z.supervisor_id AS supervisor_id_6,
          Z.employee_id AS employee_id_6,
          Z.full_name AS full_name_6
     FROM employee Z,
          SELECT DISTINCT
               A.supervisor_id_1,
               A.employee_id_1,
               A.full_name_1,
               A.supervisor_id_2,
               A.employee_id_2,
               A.full_name_2,
               A.supervisor_id_3,
               A.employee_id_3,
               A.full_name_3,
               A.supervisor_id_4,
               A.employee_id_4,
               A.full_name_4,
               Z.supervisor_id AS supervisor_id_5,
               Z.employee_id AS employee_id_5,
               Z.full_name AS full_name_5
          FROM employee Z,
               SELECT DISTINCT
                    A.supervisor_id_1,
                    A.employee_id_1,
                    A.full_name_1,
                    A.supervisor_id_2,
                    A.employee_id_2,
                    A.full_name_2,
                    A.supervisor_id_3,
                    A.employee_id_3,
                    A.full_name_3,
                    Z.supervisor_id AS supervisor_id_4,
                    Z.employee_id AS employee_id_4,
                    Z.full_name AS full_name_4
               FROM employee Z,
                    SELECT DISTINCT
                         A.supervisor_id_1,
                         A.employee_id_1,
                         A.full_name_1,
                         A.supervisor_id_2,
                         A.employee_id_2,
                         A.full_name_2,
                         Z.supervisor_id AS supervisor_id_3,
                         Z.employee_id AS employee_id_3,
                         Z.full_name AS full_name_3
                    FROM employee Z,
                         SELECT DISTINCT
                              A.supervisor_id_1,
                              A.employee_id_1,
                              A.full_name_1,
                              Z.supervisor_id AS supervisor_id_2,
                              Z.employee_id AS employee_id_2,
                              Z.full_name AS full_name_2
                         FROM employee Z,
                              SELECT DISTINCT
                                   supervisor_id AS supervisor_id_1,
                                   employee_id AS employee_id_1,
                                   full_name AS full_name_1
                               FROM employee
                               WHERE supervisor_id = 0 OR supervisor_id IS NULL
                         ) A
                         WHERE A.employee_id_1 = Z.supervisor_id
                    ) A
                    WHERE A.employee_id_2 = Z.supervisor_id
               ) A
               WHERE A.employee_id_3 = Z.supervisor_id
          ) A
          WHERE A.employee_id_4 = Z.supervisor_id
     ) A
     WHERE A.employee_id_5 = Z.supervisor_id
) A
UNION
SELECT DISTINCT
     A.employee_id_5 AS employee_id,
     A.supervisor_id_1,
     A.employee_id_1,
     A.full_name_1,
     A.supervisor_id_2,
     A.employee_id_2,
     A.full_name_2,
     A.supervisor_id_3,
     A.employee_id_3,
     A.full_name_3,
     A.supervisor_id_4,
     A.employee_id_4,
     A.full_name_4,
     A.supervisor_id_5,
     A.employee_id_5,
     A.full_name_5,
     NULL AS supervisor_id_6,
     NULL AS employee_id_6,
     NULL AS full_name_6,
     NULL AS supervisor_id_7,
     NULL AS employee_id_7,
     NULL AS full_name_7
FROM employee Z,
     SELECT DISTINCT
          A.supervisor_id_1,
          A.employee_id_1,
          A.full_name_1,
          A.supervisor_id_2,
          A.employee_id_2,
          A.full_name_2,
          A.supervisor_id_3,
          A.employee_id_3,
          A.full_name_3,
          A.supervisor_id_4,
          A.employee_id_4,
          A.full_name_4,
          Z.supervisor_id AS supervisor_id_5,
          Z.employee_id AS employee_id_5,
          Z.full_name AS full_name_5
     FROM employee Z,
          SELECT DISTINCT
               A.supervisor_id_1,
               A.employee_id_1,
               A.full_name_1,
               A.supervisor_id_2,
               A.employee_id_2,
               A.full_name_2,
               A.supervisor_id_3,
               A.employee_id_3,
               A.full_name_3,
               Z.supervisor_id AS supervisor_id_4,
               Z.employee_id AS employee_id_4,
               Z.full_name AS full_name_4
          FROM employee Z,
               SELECT DISTINCT
                    A.supervisor_id_1,
                    A.employee_id_1,
                    A.full_name_1,
                    A.supervisor_id_2,
                    A.employee_id_2,
                    A.full_name_2,
                    Z.supervisor_id AS supervisor_id_3,
                    Z.employee_id AS employee_id_3,
                    Z.full_name AS full_name_3
               FROM employee Z,
                    SELECT DISTINCT
                         A.supervisor_id_1,
                         A.employee_id_1,
                         A.full_name_1,
                         Z.supervisor_id AS supervisor_id_2,
                         Z.employee_id AS employee_id_2,
                         Z.full_name AS full_name_2
                    FROM employee Z,
                         SELECT DISTINCT
                              supervisor_id AS supervisor_id_1,
                              employee_id AS employee_id_1,
                              full_name AS full_name_1
                          FROM employee
                          WHERE supervisor_id = 0 OR supervisor_id IS NULL
                    ) A
                    WHERE A.employee_id_1 = Z.supervisor_id
               ) A
               WHERE A.employee_id_2 = Z.supervisor_id
          ) A
          WHERE A.employee_id_3 = Z.supervisor_id
     ) A
     WHERE A.employee_id_4 = Z.supervisor_id
) A
UNION
SELECT DISTINCT
     A.employee_id_4 AS employee_id,
     A.supervisor_id_1,
     A.employee_id_1,
     A.full_name_1,
     A.supervisor_id_2,
     A.employee_id_2,
     A.full_name_2,
     A.supervisor_id_3,
     A.employee_id_3,
     A.full_name_3,
     A.supervisor_id_4,
     A.employee_id_4,
     A.full_name_4,
     NULL AS supervisor_id_5,
     NULL AS employee_id_5,
     NULL AS full_name_5,
     NULL AS supervisor_id_6,
     NULL AS employee_id_6,
     NULL AS full_name_6,
     NULL AS supervisor_id_7,
     NULL AS employee_id_7,
     NULL AS full_name_7
FROM employee Z,
     SELECT DISTINCT
          A.supervisor_id_1,
          A.employee_id_1,
          A.full_name_1,
          A.supervisor_id_2,
          A.employee_id_2,
          A.full_name_2,
          A.supervisor_id_3,
          A.employee_id_3,
          A.full_name_3,
          Z.supervisor_id AS supervisor_id_4,
          Z.employee_id AS employee_id_4,
          Z.full_name AS full_name_4
     FROM employee Z,
          SELECT DISTINCT
               A.supervisor_id_1,
               A.employee_id_1,
               A.full_name_1,
               A.supervisor_id_2,
               A.employee_id_2,
               A.full_name_2,
               Z.supervisor_id AS supervisor_id_3,
               Z.employee_id AS employee_id_3,
               Z.full_name AS full_name_3
          FROM employee Z,
               SELECT DISTINCT
                    A.supervisor_id_1,
                    A.employee_id_1,
                    A.full_name_1,
                    Z.supervisor_id AS supervisor_id_2,
                    Z.employee_id AS employee_id_2,
                    Z.full_name AS full_name_2
               FROM employee Z,
                    SELECT DISTINCT
                         supervisor_id AS supervisor_id_1,
                         employee_id AS employee_id_1,
                         full_name AS full_name_1
                     FROM employee
                     WHERE supervisor_id = 0 OR supervisor_id IS NULL
               ) A
               WHERE A.employee_id_1 = Z.supervisor_id
          ) A
          WHERE A.employee_id_2 = Z.supervisor_id
     ) A
     WHERE A.employee_id_3 = Z.supervisor_id
) A
UNION
SELECT DISTINCT
     A.employee_id_3 AS employee_id,
     A.supervisor_id_1,
     A.employee_id_1,
     A.full_name_1,
     A.supervisor_id_2,
     A.employee_id_2,
     A.full_name_2,
     A.supervisor_id_3,
     A.employee_id_3,
     A.full_name_3,
     NULL AS supervisor_id_4,
     NULL AS employee_id_4,
     NULL AS full_name_4,
     NULL AS supervisor_id_5,
     NULL AS employee_id_5,
     NULL AS full_name_5,
     NULL AS supervisor_id_6,
     NULL AS employee_id_6,
     NULL AS full_name_6,
     NULL AS supervisor_id_7,
     NULL AS employee_id_7,
     NULL AS full_name_7
FROM employee Z,
     SELECT DISTINCT
          A.supervisor_id_1,
          A.employee_id_1,
          A.full_name_1,
          A.supervisor_id_2,
          A.employee_id_2,
          A.full_name_2,
          Z.supervisor_id AS supervisor_id_3,
          Z.employee_id AS employee_id_3,
          Z.full_name AS full_name_3
     FROM employee Z,
          SELECT DISTINCT
               A.supervisor_id_1,
               A.employee_id_1,
               A.full_name_1,
               Z.supervisor_id AS supervisor_id_2,
               Z.employee_id AS employee_id_2,
               Z.full_name AS full_name_2
          FROM employee Z,
               SELECT DISTINCT
                    supervisor_id AS supervisor_id_1,
                    employee_id AS employee_id_1,
                    full_name AS full_name_1
                FROM employee
                WHERE supervisor_id = 0 OR supervisor_id IS NULL
          ) A
          WHERE A.employee_id_1 = Z.supervisor_id
     ) A
     WHERE A.employee_id_2 = Z.supervisor_id
) A
UNION
SELECT DISTINCT
     A.employee_id_2 AS employee_id,
     A.supervisor_id_1,
     A.employee_id_1,
     A.full_name_1,
     A.supervisor_id_2,
     A.employee_id_2,
     A.full_name_2,
     NULL AS supervisor_id_3,
     NULL AS employee_id_3,
     NULL AS full_name_3,
     NULL AS supervisor_id_4,
     NULL AS employee_id_4,
     NULL AS full_name_4,
     NULL AS supervisor_id_5,
     NULL AS employee_id_5,
     NULL AS full_name_5,
     NULL AS supervisor_id_6,
     NULL AS employee_id_6,
     NULL AS full_name_6,
     NULL AS supervisor_id_7,
     NULL AS employee_id_7,
     NULL AS full_name_7
FROM employee Z,
     SELECT DISTINCT
          A.supervisor_id_1,
          A.employee_id_1,
          A.full_name_1,
          Z.supervisor_id AS supervisor_id_2,
          Z.employee_id AS employee_id_2,
          Z.full_name AS full_name_2
     FROM employee Z,
          SELECT DISTINCT
               supervisor_id AS supervisor_id_1,
               employee_id AS employee_id_1,
               full_name AS full_name_1
           FROM employee
           WHERE supervisor_id = 0 OR supervisor_id IS NULL
     ) A
     WHERE A.employee_id_1 = Z.supervisor_id
) A
UNION
SELECT DISTINCT
     A.employee_id_1 AS employee_id,
     A.supervisor_id_1,
     A.employee_id_1,
     A.full_name_1,
     NULL AS supervisor_id_2,
     NULL AS employee_id_2,
     NULL AS full_name_2,
     NULL AS supervisor_id_3,
     NULL AS employee_id_3,
     NULL AS full_name_3,
     NULL AS supervisor_id_4,
     NULL AS employee_id_4,
     NULL AS full_name_4,
     NULL AS supervisor_id_5,
     NULL AS employee_id_5,
     NULL AS full_name_5,
     NULL AS supervisor_id_6,
     NULL AS employee_id_6,
     NULL AS full_name_6,
     NULL AS supervisor_id_7,
     NULL AS employee_id_7,
     NULL AS full_name_7
FROM employee Z,
     SELECT DISTINCT
          supervisor_id AS supervisor_id_1,
          employee_id AS employee_id_1,
          full_name AS full_name_1
      FROM employee
      WHERE supervisor_id = 0 OR supervisor_id IS NULL
) A

Getting parent-child data from a single column in a table

Hi,
I have a parent-child data in a column.
Eg:
0
00
01
010
011
1
10
11
These values are present in the single column itself. My need is to get the parent values for the given child value.
For eg: If I am giving the input as 011, the query should return all its parents, i.e. 01 and 0
Could you please give me any inputs on this?
Thanks,
GV

Frank Kulash wrote:
Assuming that each child's id is formed by adding exactly one character to the end of its parent's id:
SELECT     id
FROM     table_x
START WITH     id          = :target_id
CONNECT BY     PRIOR id     LIKE id || '_';
Small tweak to yours Frank if it's just the parents that need identifying...
SQL> ed
Wrote file afiedt.buf
1 with t as (select '0' as x from dual union all
2             select '00' from dual union all
3             select '01' from dual union all
4             select '010' from dual union all
5             select '011' from dual union all
6             select '1' from dual union all
7             select '10' from dual union all
8             select '11' from dual)
9 -- end of test data
10 SELECT     x
11 FROM       t, (select '&required' as req from dual) req
12 WHERE x != req.req
13 START WITH x = req.req
14* CONNECT BY PRIOR x LIKE x || '_'
SQL> /
Enter value for required: 011
old 11: FROM   t, (select '&required' as req from dual) req
new 11: FROM   t, (select '011' as req from dual) req
X
01
0
SQL> /
Enter value for required: 11
old 11: FROM   t, (select '&required' as req from dual) req
new 11: FROM   t, (select '11' as req from dual) req
X
1
SQL>

How to filter parent & child rows from tables while export usingData export

Hi,
I have a requirement of export schema. Assume there is a account details table and account transactions table under schema.They have parent child relation exist. if i filter accounts from account details the corresponding transactions in account transactions table should be filterd.How to achieve this?
Regards,
Venkat Vadlamudi
Mobile:9850499800

Not sure if this is a SQL and PL/SQL question or whether it's an Oracle Apps type question or a Database General.
Whatever, you've posted in the wrong forum (http://forums.oracle.com/forums/ann.jspa?annID=599)
You should post in a more appropriate forum e.g.
PL/SQL
General Database Discussions
etc.
locking this thread

Parent/child records from same table

I want to create a query that is a union such that the 2nd resultset is based on the 1st resultset. I have a table that has parent/child records in the same table.
Table: EVENTS
EVENT_ID
PARENT_EVENT_ID
CREATED_DATE
(other columns)
if PARENT_EVENT_ID is null then it is a parent record, else it is a child record. I want to select all parent records then union them with all the associated child records...something like this:
select * from EVENTS where CREATED_DATE < sysdate - 90 and PARENT_EVENT_ID is null -- All parents
union
select * from EVENTS where PARENT_EVENT_ID in (select EVENT_ID from EVENTS where CREATED_DATE < sysdate - 90 and PARENT_EVENT_ID is null) -- include any children of parents selected from above
This works but it's kind of ugly, I want to avoid using the sub-select in the 2nd because it is a repeat of the 1st statement, is there a way to alias the first statement and just refer to it in the 2nd query?

Hi,
kev374 wrote:
Thanks, one question...
I did a test and it seems the child rows have to also satisfy the parent row's where clause, take this example:
EVENT_ID|PARENT_EVENT_ID|CREATED_DATE
2438 | (null) | April 9 2013
2439 | 2438 | April 11 2013
2440 | 2438 | April 11 2013
select * from EVENTS where CREATED_DATE < sysdate - 9
start with EVENT_ID = 2438
connect by PARENT_EVENT_ID = prior EVENT_IDSo you've changed the condition about only wanting roots and their children, and now you want descendants at all levels.
This pulls in record #2438 (per the sysdate - 9 condition) but 2439 and 2440 are not connected. Is there a way to supress the where clause evaluation for the child records? I just want to pull ALL child records associated with the parent and only want to do the date check on the parent.Since the roots (the only rows you want to exclude) have LEVEL=1, you can get the results you requested like this:
WHERE created_date < SYSDATE - 9
OR LEVEL > 1However, since you're not ruling out the grandchildren and great-grandchildren any more, why wouldn't you just say:
SELECT *
FROM events
WHERE created_date < SYSDATE - 9
OR parent_event_id IS NOT NULL;?
CONNECT BY is slow. Don't use it if you don't need it.
If you x-reference my original query:
select * from EVENTS where CREATED_DATE < sysdate - 90 and PARENT_EVENT_ID is null -- All parents
union
select * from EVENTS where PARENT_EVENT_ID in (select EVENT_ID from EVENTS where CREATED_DATE < sysdate - 90 and PARENT_EVENT_ID is null) -- include any children of parents selected from above
The 2nd select does not apply the created_date < sysdate - 90 on the children but rather pulls in all related children :)Sorry; my mistake. That's what happens when you don't post sample data, and desired results; people can't test their solutions and find mistakes like that.

Send the output/response in CDATA format from OSB

Hi,
I want to send the output in CDATA format from OSB as below.
<DataSet><![CDATA[<Data>
<QueryRes>
<tagA>anil kumar</tagA>
<tagB>Telesales Lead</tagB>
</QueryRes>
</Data>]]></DataSet>
Request your help to acieve the same.

Hi,
I want to send the output in CDATA format from OSB as below.
<DataSet><![CDATA[<Data>
<QueryRes>
<tagA>anil kumar</tagA>
<tagB>Telesales Lead</tagB>
</QueryRes>
</Data>]]></DataSet>
Request your help to acieve the same.

How to extract the hierarchy(in the levels) into BW

Thanks in advance.
Edited by: S MB on May 6, 2009 11:13 AM
Edited by: S MB on May 6, 2009 11:14 AM

hi,
You can create the mapping between the hierarchy datasource in BW to the masterdata object.And then creation of infopackeage and extract the data.
While creating the transfer rules, mapping is to be done to Header and Node i.e, on the top of communication structure you get an option 'Segment' which has dropdown Header/Node. You can map the objects and load the data.
Let me know if you are expecting the same or any further details.
Regards,
Geetha.

Can I delete the hierarchy groups and reload again from R/3

Hello all,
I am having some issue in my reports because of the hierarchy groups. Can i just delete the entire hierarcgy groups from "production" and reload again from R/3 will that cause any issue?
Thanks in advance

Hi,
I think u can delete the Master Data Hierarchies. I dont see any issue in the production .
Rgds,
Ravi.

Extract the name of a digital ID from a smart card and place in a field

In DoD we use Smart Cards, commonly called 'Common Access Card (CAC)', I am wondering if it's possible to extract the name of the user from their CAC, or at least be able to extract the name from a .FDF file. If you go to 'Sign & Certify' from Acrobat 10.x, and then go to 'More Sign & Certify', then click on 'Security Settings', again, this only applies if you have either a Smart Card or digital ID, you will see the security settings menu. Within this menu, you will see the option to 'Export' the file to either an email or save the data to a file. When you click next, you have the option to save as and .fdf file or .p7c file. Is it possible to create a button or a digital signature that will allow me to export the name of the user to a field?

Hi bsabourin1962,
It can be done by creating a button with a script to extract the name of the user.

Extract the hierarchy in Parent child format from HP

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