Extracting images from a DVD

Hello,
I would like to extract a couple of pictures from my holiday dvd, but the grab application doesn't work when the DVD application is running. Can anyone help?
Thx
Greg

Yeah, grab and the like won't let run while DVD is opened. The program I use for that is VCL Media Player. People rant and rave about it, and it is good because of all the formats it plays. I can even have it read from a Video_TS folder, and then grab screen shots from there. Getting the shot you want can be tricky because I can't seem to get the frame-by-frame to work as nicely as in Quicktime, but this is a viable solution, plus its free!

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    %ALDImageFileName: Speicher:image.jpg
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    /T 1
    /W 30
    /H 30
    /M[30 0 0 -30 0 30 ]
    /BC 8
    /D[0 1 0 1 0 1 0 1 ]
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    [AGMIMG_fl 30 string /rs cvx /pop cvx] cvx
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    /O 3
    >>
    %%BeginBinary: 1
    img
    p&G-p!<E*"!<<3"!!!&i!!30$!Vl`q!V$-m!WW3&!r`0#!Wh]h!!20]!WW3$qZ$^!!!!&f!!30$!WE'!
    !WE'$!<<*#nc/[l!W<!#!WW3%h>dNVnGiXl!<<-)!!*'"!<<2f!<*$!!<3)a!!!&t!!*-%kl:\ar;Zm"
    !!2He#6G2G(D[>Z!<*#e!!WKUEK,/l!r`0"!V$.!!Wi?'-t[mD-NjDN!!2Zk!!3#u"T\]4$OR%8!!!&h
    !!<6)*\I@D!\,8pq>g3h%KQP0';ta-rr2ho&-2b3mf3Y*Q/q,jk2D[9"76'h!=o#B!Y,22n,Nn!!!=Q!
    0.ee,0/"XS!VHHl!!E<'!"[l]rrUsd!Ug!r&'a/!k3(mej38#8mJm8&'`/UF'`J.(!"8l.+"o,p/hSe-
    /M8.8!!<6%!i#Yn!<2rs!2Ao^$NZFPk2tpjkND!jP3r;O%29TU'`o-b%e'H-!=:8,0/"h-.kN>(.gkeH
    "T^(Js8W&srrE$$rr;gE!V-4"""*$ljlY^djQYmmi$\'q!W`9(p([Q1nc/dn!#@(:r[nC..kE8)/emgU
    !<IHErs8W(rr<#trr76B!:p1!CZadBk2kmhj65^iD"%E-$5O?k'`&OE$M"0,!<<uh0.ee0/h\e,/h.k2
    !!*+arVm-$s8W)us8J2U!;Z[(L?.U[kN:sflf@0hK^f$D!=T\>'a5?f'c%2YnGit6/1iM*/1iA*.kWFi
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    .gH+F!!+PDrVllsrVlrp.KT,@#QauQip#Ifk3*$4ki:gb-3Nc<$j.4Z'GV>s'bqJt('F(,%06GL/hJ_.
    .k<;..j"f]!!32!rql]tr;WMmmf3c`k2tsgk2tmikEZ,Kn,NJ!'`/UJ'G_,X!V-6i!=L8*/2&S./M&=P
    !!2Ti"9AV]s8N#t"o\JY&c_t$!"-g0j6,RdkNBr!!r2ii!!!]1'a,9f'*84(!"Ar/""YuT/M8Y)!WW3$
    nc0%!!!!Z$s8N#ts76`i!"T,3!!3\bl0.?qjkC7H!!;`lrW!!#!>PMJ!u;Ub!Ug$f!=JlU/M/S*/ggZ#
    !!2Ng$3K)as8N&tjT#8]m/R@3k2b[ck03)j!>?4H'`\p6!!**(r[e6p.kWIZmJm:h!#kk:#.sp7ru_:B
    mJmV6jQ>U%kN:kH!!!)h!!!'!'`\gE'`eC:mf3^r!=pb8/ds9_.h;[J!!u[*s8GIerr6%#m/RGck3(kk
    kNM&%!Up'o!<<*)'bhDfrY5G=!Vufj!"K#0!#mOB.0(kM0,afj!V$-u!<A8^s6B[Es8S8_!U]poKBMCG
    !7'`iKECN@#RhF_'*&[\'b'X5r;[9-!$a!F*W[<7.jP)q!V-4#!<<,As8T>(W;lnB!!!&g!"63skFhmD
    jlEuS!!2Ng#S7^d%KHtR'bTm7!s/H(/-mj['`\n!/1Ukk!"985s8@'?Du]k7%KHP#!"8l0$KC71C'%l,
    jl$a?!!<6%!!3'6!X\o6rY5J8!!2Qh#Ri::0*_I`/1U`S%.4)q5Q:Zg2ukf6s8P=a!V$-t!]]?)jY?ff
    kN:qhmJmFp()7Pf!!N99!!Vcj$l1NL.KKPM/1iIi!!3'!o`,F%!dakFpBL[$pAb/A!Up's!H@5cf`qK\
    hWF!BmJmV%'GV;_!!*`J'FFm3!!WH(!?WpE,Q7ZH+tP;f!!2foq>^W-s8Tn6!!L"8s0r.!!">[bkcXsf
    !3>;FU]CPd!!<]G'bL?E!tZ.^&+9K$!\#`P)?'U>'eM$g!!2Zk!W`9$$g.KhLB.ATL&_2?"7Q9n!RU)n
    I/X*KGN@l9"Rc<t',;8j!!!$,'bhAP!!WQ+!"US5%fQG1%PKFQn,NUm!*fL'9)\en8,rO]!V-4"!rrBu
    jQ/].!WYOLl&b?6"9AcD'aFX;"9oSU%0>nt$NV(q!rr<%"YC_q"7Z@"!<<+Eq@Wc/!#,C9"9&;k!!E?)
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    !!WK)KEM8T"RZ6i$2so,!<<Q0li77k!!30$!<</h!!!'!!!E<'!!!&c!"8o/!!*'#"98E'!WW;h!!!'!
    !!NB'!<<*#n,N[o!<<*#!!!'!!!!&f!!E<&!!*-"!!!'!!!**%o)K!s!!*-$!<<*#!!<-"!Wi?&l2Ueb
    rVup!q#Gp~>
    %%EndBinary
    %%EndObject
    Orginal image Size 553,9 KB
    After decoding the size is only 1,8 KB
    First try.
    public class ASCII85Decode {
    private ByteBuffer buf;
    * initialize the decoder with byte buffer in ASCII85 format
    private ASCII85Decode(ByteBuffer buf) {
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    return (c == ' ' || c == '\t' || c == '\r' || c == '\n'
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    // 0=nul, 12=ff
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    case '\n':
    case '\r':
    case '\t':
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    case '\0':
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    private void putchar(int l) throws IOException {
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    Does anybody have an idea to solve the problem?

    A scan from string function can be used as per the attachment. The double \ ('\\') is in the format string in order to interpret the '\' characters in your input string as literal characters and not special formatting.
    Message Edited by Dennis Knutson on 07-10-2006 03:53 PM
    Attachments:
    Scan From String.JPG ‏5 KB

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